How to align the plot legends in the following way?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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Consider example



 ContourPlot[(x - 2)^2 + (y - 2)^2 == 
 12, (x + 2)^3 + (y + 2)^3 ==8, x, -4, 4, y, -4, 4, 
 PlotLegends -> 
 Placed[Style["Region 1", 20], Style["Region 2", 20], 0.7, 0.82]]


The result is the picture on the left. Could you please tell me to change the colour of the legend text and set for each plot legend set its own coordinate, see the picture on the right?



enter image description here






plotting syntax legending







share|improve this question

























    up vote
    1
    down vote

    favorite












    Consider example



     ContourPlot[(x - 2)^2 + (y - 2)^2 == 
     12, (x + 2)^3 + (y + 2)^3 ==8, x, -4, 4, y, -4, 4, 
     PlotLegends -> 
     Placed[Style["Region 1", 20], Style["Region 2", 20], 0.7, 0.82]]


    The result is the picture on the left. Could you please tell me to change the colour of the legend text and set for each plot legend set its own coordinate, see the picture on the right?



    enter image description here






    plotting syntax legending







    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      Consider example



       ContourPlot[(x - 2)^2 + (y - 2)^2 == 
       12, (x + 2)^3 + (y + 2)^3 ==8, x, -4, 4, y, -4, 4, 
       PlotLegends -> 
       Placed[Style["Region 1", 20], Style["Region 2", 20], 0.7, 0.82]]


      The result is the picture on the left. Could you please tell me to change the colour of the legend text and set for each plot legend set its own coordinate, see the picture on the right?



      enter image description here






      plotting syntax legending







      share|improve this question













      Consider example



       ContourPlot[(x - 2)^2 + (y - 2)^2 == 
       12, (x + 2)^3 + (y + 2)^3 ==8, x, -4, 4, y, -4, 4, 
       PlotLegends -> 
       Placed[Style["Region 1", 20], Style["Region 2", 20], 0.7, 0.82]]


      The result is the picture on the left. Could you please tell me to change the colour of the legend text and set for each plot legend set its own coordinate, see the picture on the right?



      enter image description here






      plotting syntax legending




      plotting syntax legending






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 5 hours ago









      John Taylor

      682211




      682211




















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          3
          down vote



          accepted










          Try this:



          Show[
           ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 
           8, x, -4, 4, y, -4, 4, ContourStyle -> Blue, Orange],
           Graphics[Text[Style["Region 1", 20, Blue], Scaled[0.8, 0.8]],

           Text[Style["Region 2", 20, Orange], Scaled[0.2, 0.2]]
           ]
           ]


          enter image description here



          Done. Have fun!






          share|improve this answer




















          • Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
            – b.gatessucks
            5 hours ago

















          up vote
          2
          down vote













          labels = Style[#, 20] & /@ "Region 1", "Region 2";
          colors = ColorData[97] /@ 1, 2;
          positions = 7, 7 / 10, 1, 1 / 4;

          ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 8, 
           x, -4, 4, y, -4, 4, 
           PlotLegends -> ( Placed[Style@##2, #] & @@@ Transpose[positions, labels, colors])]


          enter image description here






          share|improve this answer
















          • 1




            Nice answer, first time I've ever seen ##n used.
            – N.J.Evans
            9 mins ago










          Your Answer





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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          3
          down vote



          accepted










          Try this:



          Show[
           ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 
           8, x, -4, 4, y, -4, 4, ContourStyle -> Blue, Orange],
           Graphics[Text[Style["Region 1", 20, Blue], Scaled[0.8, 0.8]],

           Text[Style["Region 2", 20, Orange], Scaled[0.2, 0.2]]
           ]
           ]


          enter image description here



          Done. Have fun!






          share|improve this answer




















          • Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
            – b.gatessucks
            5 hours ago














          up vote
          3
          down vote



          accepted










          Try this:



          Show[
           ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 
           8, x, -4, 4, y, -4, 4, ContourStyle -> Blue, Orange],
           Graphics[Text[Style["Region 1", 20, Blue], Scaled[0.8, 0.8]],

           Text[Style["Region 2", 20, Orange], Scaled[0.2, 0.2]]
           ]
           ]


          enter image description here



          Done. Have fun!






          share|improve this answer




















          • Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
            – b.gatessucks
            5 hours ago












          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          Try this:



          Show[
           ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 
           8, x, -4, 4, y, -4, 4, ContourStyle -> Blue, Orange],
           Graphics[Text[Style["Region 1", 20, Blue], Scaled[0.8, 0.8]],

           Text[Style["Region 2", 20, Orange], Scaled[0.2, 0.2]]
           ]
           ]


          enter image description here



          Done. Have fun!






          share|improve this answer












          Try this:



          Show[
           ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 
           8, x, -4, 4, y, -4, 4, ContourStyle -> Blue, Orange],
           Graphics[Text[Style["Region 1", 20, Blue], Scaled[0.8, 0.8]],

           Text[Style["Region 2", 20, Orange], Scaled[0.2, 0.2]]
           ]
           ]


          enter image description here



          Done. Have fun!







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 5 hours ago









          Alexei Boulbitch

          20.8k2369




          20.8k2369











          • Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
            – b.gatessucks
            5 hours ago
















          • Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
            – b.gatessucks
            5 hours ago















          Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
          – b.gatessucks
          5 hours ago




          Maybe a bit more "authomatic": Show[ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, x, -4, 4, y, -4, 4, ContourStyle -> Blue, PlotLegends -> Placed["Region 1", Right, Top]], ContourPlot[(x + 2)^3 + (y + 2)^3 == 8, x, -4, 4, y, -4, 4, ContourStyle -> Orange, PlotLegends -> Placed["Region 2", Left, Bottom]]]
          – b.gatessucks
          5 hours ago










          up vote
          2
          down vote













          labels = Style[#, 20] & /@ "Region 1", "Region 2";
          colors = ColorData[97] /@ 1, 2;
          positions = 7, 7 / 10, 1, 1 / 4;

          ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 8, 
           x, -4, 4, y, -4, 4, 
           PlotLegends -> ( Placed[Style@##2, #] & @@@ Transpose[positions, labels, colors])]


          enter image description here






          share|improve this answer
















          • 1




            Nice answer, first time I've ever seen ##n used.
            – N.J.Evans
            9 mins ago














          up vote
          2
          down vote













          labels = Style[#, 20] & /@ "Region 1", "Region 2";
          colors = ColorData[97] /@ 1, 2;
          positions = 7, 7 / 10, 1, 1 / 4;

          ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 8, 
           x, -4, 4, y, -4, 4, 
           PlotLegends -> ( Placed[Style@##2, #] & @@@ Transpose[positions, labels, colors])]


          enter image description here






          share|improve this answer
















          • 1




            Nice answer, first time I've ever seen ##n used.
            – N.J.Evans
            9 mins ago












          up vote
          2
          down vote










          up vote
          2
          down vote









          labels = Style[#, 20] & /@ "Region 1", "Region 2";
          colors = ColorData[97] /@ 1, 2;
          positions = 7, 7 / 10, 1, 1 / 4;

          ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 8, 
           x, -4, 4, y, -4, 4, 
           PlotLegends -> ( Placed[Style@##2, #] & @@@ Transpose[positions, labels, colors])]


          enter image description here






          share|improve this answer












          labels = Style[#, 20] & /@ "Region 1", "Region 2";
          colors = ColorData[97] /@ 1, 2;
          positions = 7, 7 / 10, 1, 1 / 4;

          ContourPlot[(x - 2)^2 + (y - 2)^2 == 12, (x + 2)^3 + (y + 2)^3 == 8, 
           x, -4, 4, y, -4, 4, 
           PlotLegends -> ( Placed[Style@##2, #] & @@@ Transpose[positions, labels, colors])]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 12 mins ago









          kglr

          169k8192395




          169k8192395







          • 1




            Nice answer, first time I've ever seen ##n used.
            – N.J.Evans
            9 mins ago












          • 1




            Nice answer, first time I've ever seen ##n used.
            – N.J.Evans
            9 mins ago







          1




          1




          Nice answer, first time I've ever seen ##n used.
          – N.J.Evans
          9 mins ago




          Nice answer, first time I've ever seen ##n used.
          – N.J.Evans
          9 mins ago

















           

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