Deleting duplicate equations from a list of equations

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Here is a list of algebraicly identical equations, and I like to delete all the duplicate equations from this list and get only one equation. I tried the following:



Clear[ss];
listEqs = 
 x + y == x^2 + z,
 y + z == x^2 + z,
 x + y == z + x^2,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x
 ;

DeleteDuplicates[listEqs]


I got:




 x + y == x^2 + z,
 y + z == x^2 + z, 
 x^2 + z == x + y,
 x^2 + z == y + z



Can someone tell me how to reduce the list to only one equation?



EDIT 1



I noticed a misunderstanding of my question. Here is a second list:



listEqs = 
 y + z == x^2 + z,
 a + b == k + g, 
 x + y == x^2 + z, 
 b + a == g + k,
 x + y == z + x^2,
 a + b == g + k,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x;


The code:



DeleteDuplicatesBy[listEqs, MemberQ@Level[listEqs, -1]]


picks the first element of the list, which is not what I asked. I want the following list to be the output of the code:




y + z == x^2 + z,
a + b == k + g



Basically, I just want to pick the non-identical equations from the list. The desired equations can be placed in the middle, end or beginning of the list. The position of the equations are not the issue.






list-manipulation







share|improve this question























  • in what sense are x + y == x^2 + z and y + z == x^2 + z} "equivalent"?
    – kglr
    19 mins ago















up vote
1
down vote

favorite
1












Here is a list of algebraicly identical equations, and I like to delete all the duplicate equations from this list and get only one equation. I tried the following:



Clear[ss];
listEqs = 
 x + y == x^2 + z,
 y + z == x^2 + z,
 x + y == z + x^2,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x
 ;

DeleteDuplicates[listEqs]


I got:




 x + y == x^2 + z,
 y + z == x^2 + z, 
 x^2 + z == x + y,
 x^2 + z == y + z



Can someone tell me how to reduce the list to only one equation?



EDIT 1



I noticed a misunderstanding of my question. Here is a second list:



listEqs = 
 y + z == x^2 + z,
 a + b == k + g, 
 x + y == x^2 + z, 
 b + a == g + k,
 x + y == z + x^2,
 a + b == g + k,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x;


The code:



DeleteDuplicatesBy[listEqs, MemberQ@Level[listEqs, -1]]


picks the first element of the list, which is not what I asked. I want the following list to be the output of the code:




y + z == x^2 + z,
a + b == k + g



Basically, I just want to pick the non-identical equations from the list. The desired equations can be placed in the middle, end or beginning of the list. The position of the equations are not the issue.






list-manipulation







share|improve this question























  • in what sense are x + y == x^2 + z and y + z == x^2 + z} "equivalent"?
    – kglr
    19 mins ago













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





Here is a list of algebraicly identical equations, and I like to delete all the duplicate equations from this list and get only one equation. I tried the following:



Clear[ss];
listEqs = 
 x + y == x^2 + z,
 y + z == x^2 + z,
 x + y == z + x^2,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x
 ;

DeleteDuplicates[listEqs]


I got:




 x + y == x^2 + z,
 y + z == x^2 + z, 
 x^2 + z == x + y,
 x^2 + z == y + z



Can someone tell me how to reduce the list to only one equation?



EDIT 1



I noticed a misunderstanding of my question. Here is a second list:



listEqs = 
 y + z == x^2 + z,
 a + b == k + g, 
 x + y == x^2 + z, 
 b + a == g + k,
 x + y == z + x^2,
 a + b == g + k,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x;


The code:



DeleteDuplicatesBy[listEqs, MemberQ@Level[listEqs, -1]]


picks the first element of the list, which is not what I asked. I want the following list to be the output of the code:




y + z == x^2 + z,
a + b == k + g



Basically, I just want to pick the non-identical equations from the list. The desired equations can be placed in the middle, end or beginning of the list. The position of the equations are not the issue.






list-manipulation







share|improve this question















Here is a list of algebraicly identical equations, and I like to delete all the duplicate equations from this list and get only one equation. I tried the following:



Clear[ss];
listEqs = 
 x + y == x^2 + z,
 y + z == x^2 + z,
 x + y == z + x^2,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x
 ;

DeleteDuplicates[listEqs]


I got:




 x + y == x^2 + z,
 y + z == x^2 + z, 
 x^2 + z == x + y,
 x^2 + z == y + z



Can someone tell me how to reduce the list to only one equation?



EDIT 1



I noticed a misunderstanding of my question. Here is a second list:



listEqs = 
 y + z == x^2 + z,
 a + b == k + g, 
 x + y == x^2 + z, 
 b + a == g + k,
 x + y == z + x^2,
 a + b == g + k,
 y + z == z + x^2,
 x^2 + z == x + y,
 z + x^2 == x + y,
 x^2 + z == y + z,
 z + x^2 == y + x;


The code:



DeleteDuplicatesBy[listEqs, MemberQ@Level[listEqs, -1]]


picks the first element of the list, which is not what I asked. I want the following list to be the output of the code:




y + z == x^2 + z,
a + b == k + g



Basically, I just want to pick the non-identical equations from the list. The desired equations can be placed in the middle, end or beginning of the list. The position of the equations are not the issue.






list-manipulation




list-manipulation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 11 mins ago

























asked 1 hour ago









Tugrul Temel

43113




43113











  • in what sense are x + y == x^2 + z and y + z == x^2 + z} "equivalent"?
    – kglr
    19 mins ago

















  • in what sense are x + y == x^2 + z and y + z == x^2 + z} "equivalent"?
    – kglr
    19 mins ago
















in what sense are x + y == x^2 + z and y + z == x^2 + z} "equivalent"?
– kglr
19 mins ago





in what sense are x + y == x^2 + z and y + z == x^2 + z} "equivalent"?
– kglr
19 mins ago











1 Answer
1






active

oldest

votes

















up vote
1
down vote



accepted










Maybe



DeleteDuplicatesBy[listEqs, Reduce] (* or *)
DeleteDuplicatesBy[listEqs, Sort]



x + y == x^2 + z, y + z == x^2 + z




For the longer input list:



DeleteDuplicatesBy[listEqs2, Reduce]



y + z == x^2 + z, a + b == g + k, x + y == x^2 + z




In both cases, I can't see how x + y == x^2 + z and y + z == x^2 + z can be "equivalent"`.





share




















  • It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
    – Tugrul Temel
    3 mins ago










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










Maybe



DeleteDuplicatesBy[listEqs, Reduce] (* or *)
DeleteDuplicatesBy[listEqs, Sort]



x + y == x^2 + z, y + z == x^2 + z




For the longer input list:



DeleteDuplicatesBy[listEqs2, Reduce]



y + z == x^2 + z, a + b == g + k, x + y == x^2 + z




In both cases, I can't see how x + y == x^2 + z and y + z == x^2 + z can be "equivalent"`.





share




















  • It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
    – Tugrul Temel
    3 mins ago














up vote
1
down vote



accepted










Maybe



DeleteDuplicatesBy[listEqs, Reduce] (* or *)
DeleteDuplicatesBy[listEqs, Sort]



x + y == x^2 + z, y + z == x^2 + z




For the longer input list:



DeleteDuplicatesBy[listEqs2, Reduce]



y + z == x^2 + z, a + b == g + k, x + y == x^2 + z




In both cases, I can't see how x + y == x^2 + z and y + z == x^2 + z can be "equivalent"`.





share




















  • It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
    – Tugrul Temel
    3 mins ago












up vote
1
down vote



accepted







up vote
1
down vote



accepted






Maybe



DeleteDuplicatesBy[listEqs, Reduce] (* or *)
DeleteDuplicatesBy[listEqs, Sort]



x + y == x^2 + z, y + z == x^2 + z




For the longer input list:



DeleteDuplicatesBy[listEqs2, Reduce]



y + z == x^2 + z, a + b == g + k, x + y == x^2 + z




In both cases, I can't see how x + y == x^2 + z and y + z == x^2 + z can be "equivalent"`.





share












Maybe



DeleteDuplicatesBy[listEqs, Reduce] (* or *)
DeleteDuplicatesBy[listEqs, Sort]



x + y == x^2 + z, y + z == x^2 + z




For the longer input list:



DeleteDuplicatesBy[listEqs2, Reduce]



y + z == x^2 + z, a + b == g + k, x + y == x^2 + z




In both cases, I can't see how x + y == x^2 + z and y + z == x^2 + z can be "equivalent"`.






share











share


share










answered 8 mins ago









kglr

166k8188390




166k8188390











  • It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
    – Tugrul Temel
    3 mins ago
















  • It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
    – Tugrul Temel
    3 mins ago















It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
– Tugrul Temel
3 mins ago




It is a typo. Sorry for confusion, but your answer is the right one and it works for me. Thank you very much.
– Tugrul Temel
3 mins ago

















 

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