Add a space after a ending dot of a sentence

Clash Royale CLAN TAG#URR8PPP

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How can I add a space after the ending dot of a sentence ? So dots like "1.2" should be unaffected. Also if there is already a space, then there should not be a space added.

text= "This is a sample text. Just 1.2 to test.To add a space after the dot...Okay."

Result:

text= "This is a sample text. Just 1.2 to test. To add a space after the dot... Okay."

string-manipulation

share|improve this question

edited 10 mins ago

asked 34 mins ago

james

691518

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Just for answerers sake, can you be more precise about the rules? Clearly not each dot is affected. And other exceptions (or not) come to my mind too e.g. "1.2", "...".
  – Kuba♦
  11 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba This is true. I will add some more details
  – james
  10 mins ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote

favorite

How can I add a space after the ending dot of a sentence ? So dots like "1.2" should be unaffected. Also if there is already a space, then there should not be a space added.

text= "This is a sample text. Just 1.2 to test.To add a space after the dot...Okay."

Result:

text= "This is a sample text. Just 1.2 to test. To add a space after the dot... Okay."

string-manipulation

share|improve this question

edited 10 mins ago

asked 34 mins ago

james

691518

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Just for answerers sake, can you be more precise about the rules? Clearly not each dot is affected. And other exceptions (or not) come to my mind too e.g. "1.2", "...".
  – Kuba♦
  11 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba This is true. I will add some more details
  – james
  10 mins ago
  
  

  
  
  
  

add a comment | 

up vote
3
down vote

favorite

up vote
3
down vote

favorite

How can I add a space after the ending dot of a sentence ? So dots like "1.2" should be unaffected. Also if there is already a space, then there should not be a space added.

text= "This is a sample text. Just 1.2 to test.To add a space after the dot...Okay."

Result:

text= "This is a sample text. Just 1.2 to test. To add a space after the dot... Okay."

string-manipulation

share|improve this question

edited 10 mins ago

asked 34 mins ago

james

691518

How can I add a space after the ending dot of a sentence ? So dots like "1.2" should be unaffected. Also if there is already a space, then there should not be a space added.

text= "This is a sample text. Just 1.2 to test.To add a space after the dot...Okay."

Result:

text= "This is a sample text. Just 1.2 to test. To add a space after the dot... Okay."

string-manipulation

string-manipulation

share|improve this question

edited 10 mins ago

asked 34 mins ago

james

691518

share|improve this question

edited 10 mins ago

asked 34 mins ago

james

691518

share|improve this question

share|improve this question

edited 10 mins ago

edited 10 mins ago

edited 10 mins ago

asked 34 mins ago

james

691518

asked 34 mins ago

james

691518

asked 34 mins ago

james

691518

691518

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Just for answerers sake, can you be more precise about the rules? Clearly not each dot is affected. And other exceptions (or not) come to my mind too e.g. "1.2", "...".
  – Kuba♦
  11 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba This is true. I will add some more details
  – james
  10 mins ago
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Just for answerers sake, can you be more precise about the rules? Clearly not each dot is affected. And other exceptions (or not) come to my mind too e.g. "1.2", "...".
  – Kuba♦
  11 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @Kuba This is true. I will add some more details
  – james
  10 mins ago
  
  

  
  
  
  

1

1

Just for answerers sake, can you be more precise about the rules? Clearly not each dot is affected. And other exceptions (or not) come to my mind too e.g. "1.2", "...".
– Kuba♦
11 mins ago

Just for answerers sake, can you be more precise about the rules? Clearly not each dot is affected. And other exceptions (or not) come to my mind too e.g. "1.2", "...".
– Kuba♦
11 mins ago

@Kuba This is true. I will add some more details
– james
10 mins ago

@Kuba This is true. I will add some more details
– james
10 mins ago

add a comment | 

4 Answers
4

active

oldest

votes

up vote
1
down vote

StringReplace[StringReplace[text, "." -> ". "], ". " ~~ EndOfString -> "."]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

answered 25 mins ago

Chris Degnen

21.5k23382

add a comment | 

up vote
1
down vote

StringReplace[text, 
 WordBoundary ~~ "." ~~ Except[WhitespaceCharacter, WordBoundary] :> ". "]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Or

StringReplace[text, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Both solutions correctly handle the cases when there already is a whitespace character after the dot:

text2 = "This is a sample text. Just to test.To add a space after the dot. Okay.";

StringReplace[text2, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

edited 8 mins ago

answered 22 mins ago

Alexey Popkov

37.9k4104259

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

StringReplace[text, "." ~~a:Except[DigitCharacter|WhitespaceCharacter|"."] :> ". "<> a]

"This is a sample text. Just 1.2 to test. To add a space after the
dot... Okay."

share|improve this answer

edited 4 mins ago

answered 15 mins ago

kglr

169k8192395

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, just did.
  – kglr
  2 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

StringReplace[text, RegularExpression["(\w\.)(\w)"] -> "$1 $2"]

"\w" means word characters, including letters, digits and the underscore _. "\." means a period literally. So the regular expression means to find a string pattern with length three: a word character followed by a period and followed by a word character.

Parentheses mean a group, and "$n" where n is an integer represents contents in the n-th group.

So the whole operation is to add a blank between the two groups after locating them by the string pattern.

---

Update for the new string:

StringReplace[text, RegularExpression["([a-zA-Z]\.+)([a-zA-Z])"] -> "$1 $2"]

share|improve this answer

edited 3 mins ago

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
  – james
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james OK, let me add some explanations.
  – Î‘λέξανδρος Ζεγγ
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your explanation.
  – james
  6 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james But you changed the problem?
  – Î‘λέξανδρος Ζεγγ
  5 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
  – james
  4 mins ago
  

  
  
  
  

 | 
show 1 more comment

Your Answer

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
1
down vote

StringReplace[StringReplace[text, "." -> ". "], ". " ~~ EndOfString -> "."]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

answered 25 mins ago

Chris Degnen

21.5k23382

add a comment | 

up vote
1
down vote

StringReplace[StringReplace[text, "." -> ". "], ". " ~~ EndOfString -> "."]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

answered 25 mins ago

Chris Degnen

21.5k23382

add a comment | 

up vote
1
down vote

up vote
1
down vote

StringReplace[StringReplace[text, "." -> ". "], ". " ~~ EndOfString -> "."]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

answered 25 mins ago

Chris Degnen

21.5k23382

StringReplace[StringReplace[text, "." -> ". "], ". " ~~ EndOfString -> "."]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

answered 25 mins ago

Chris Degnen

21.5k23382

share|improve this answer

share|improve this answer

answered 25 mins ago

Chris Degnen

21.5k23382

answered 25 mins ago

Chris Degnen

21.5k23382

answered 25 mins ago

Chris Degnen

21.5k23382

21.5k23382

add a comment | 

add a comment | 

up vote
1
down vote

StringReplace[text, 
 WordBoundary ~~ "." ~~ Except[WhitespaceCharacter, WordBoundary] :> ". "]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Or

StringReplace[text, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Both solutions correctly handle the cases when there already is a whitespace character after the dot:

text2 = "This is a sample text. Just to test.To add a space after the dot. Okay.";

StringReplace[text2, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

edited 8 mins ago

answered 22 mins ago

Alexey Popkov

37.9k4104259

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

StringReplace[text, 
 WordBoundary ~~ "." ~~ Except[WhitespaceCharacter, WordBoundary] :> ". "]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Or

StringReplace[text, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Both solutions correctly handle the cases when there already is a whitespace character after the dot:

text2 = "This is a sample text. Just to test.To add a space after the dot. Okay.";

StringReplace[text2, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

edited 8 mins ago

answered 22 mins ago

Alexey Popkov

37.9k4104259

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

up vote
1
down vote

StringReplace[text, 
 WordBoundary ~~ "." ~~ Except[WhitespaceCharacter, WordBoundary] :> ". "]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Or

StringReplace[text, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Both solutions correctly handle the cases when there already is a whitespace character after the dot:

text2 = "This is a sample text. Just to test.To add a space after the dot. Okay.";

StringReplace[text2, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

edited 8 mins ago

answered 22 mins ago

Alexey Popkov

37.9k4104259

StringReplace[text, 
 WordBoundary ~~ "." ~~ Except[WhitespaceCharacter, WordBoundary] :> ". "]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Or

StringReplace[text, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

Both solutions correctly handle the cases when there already is a whitespace character after the dot:

text2 = "This is a sample text. Just to test.To add a space after the dot. Okay.";

StringReplace[text2, a : WordCharacter ~~ "." ~~ b : WordCharacter :> a <> ". " <> b]

"This is a sample text. Just to test. To add a space after the dot. Okay."

share|improve this answer

edited 8 mins ago

answered 22 mins ago

Alexey Popkov

37.9k4104259

share|improve this answer

share|improve this answer

edited 8 mins ago

edited 8 mins ago

edited 8 mins ago

answered 22 mins ago

Alexey Popkov

37.9k4104259

answered 22 mins ago

Alexey Popkov

37.9k4104259

answered 22 mins ago

Alexey Popkov

37.9k4104259

37.9k4104259

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  

Thanks a lot. Can you also try the new sample text that I added to the question ?
– james
6 mins ago

Thanks a lot. Can you also try the new sample text that I added to the question ?
– james
6 mins ago

add a comment | 

up vote
1
down vote

StringReplace[text, "." ~~a:Except[DigitCharacter|WhitespaceCharacter|"."] :> ". "<> a]

"This is a sample text. Just 1.2 to test. To add a space after the
dot... Okay."

share|improve this answer

edited 4 mins ago

answered 15 mins ago

kglr

169k8192395

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, just did.
  – kglr
  2 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

StringReplace[text, "." ~~a:Except[DigitCharacter|WhitespaceCharacter|"."] :> ". "<> a]

"This is a sample text. Just 1.2 to test. To add a space after the
dot... Okay."

share|improve this answer

edited 4 mins ago

answered 15 mins ago

kglr

169k8192395

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, just did.
  – kglr
  2 mins ago
  

  
  
  
  

add a comment | 

up vote
1
down vote

up vote
1
down vote

StringReplace[text, "." ~~a:Except[DigitCharacter|WhitespaceCharacter|"."] :> ". "<> a]

"This is a sample text. Just 1.2 to test. To add a space after the
dot... Okay."

share|improve this answer

edited 4 mins ago

answered 15 mins ago

kglr

169k8192395

StringReplace[text, "." ~~a:Except[DigitCharacter|WhitespaceCharacter|"."] :> ". "<> a]

"This is a sample text. Just 1.2 to test. To add a space after the
dot... Okay."

share|improve this answer

edited 4 mins ago

answered 15 mins ago

kglr

169k8192395

share|improve this answer

share|improve this answer

edited 4 mins ago

edited 4 mins ago

edited 4 mins ago

answered 15 mins ago

kglr

169k8192395

answered 15 mins ago

kglr

169k8192395

answered 15 mins ago

kglr

169k8192395

169k8192395

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, just did.
  – kglr
  2 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a lot. Can you also try the new sample text that I added to the question ?
  – james
  6 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james, just did.
  – kglr
  2 mins ago
  

  
  
  
  

Thanks a lot. Can you also try the new sample text that I added to the question ?
– james
6 mins ago

Thanks a lot. Can you also try the new sample text that I added to the question ?
– james
6 mins ago

@james, just did.
– kglr
2 mins ago

@james, just did.
– kglr
2 mins ago

add a comment | 

up vote
1
down vote

StringReplace[text, RegularExpression["(\w\.)(\w)"] -> "$1 $2"]

"\w" means word characters, including letters, digits and the underscore _. "\." means a period literally. So the regular expression means to find a string pattern with length three: a word character followed by a period and followed by a word character.

Parentheses mean a group, and "$n" where n is an integer represents contents in the n-th group.

So the whole operation is to add a blank between the two groups after locating them by the string pattern.

---

Update for the new string:

StringReplace[text, RegularExpression["([a-zA-Z]\.+)([a-zA-Z])"] -> "$1 $2"]

share|improve this answer

edited 3 mins ago

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
  – james
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james OK, let me add some explanations.
  – Î‘λέξανδρος Ζεγγ
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your explanation.
  – james
  6 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james But you changed the problem?
  – Î‘λέξανδρος Ζεγγ
  5 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
  – james
  4 mins ago
  

  
  
  
  

 | 
show 1 more comment

up vote
1
down vote

StringReplace[text, RegularExpression["(\w\.)(\w)"] -> "$1 $2"]

"\w" means word characters, including letters, digits and the underscore _. "\." means a period literally. So the regular expression means to find a string pattern with length three: a word character followed by a period and followed by a word character.

Parentheses mean a group, and "$n" where n is an integer represents contents in the n-th group.

So the whole operation is to add a blank between the two groups after locating them by the string pattern.

---

Update for the new string:

StringReplace[text, RegularExpression["([a-zA-Z]\.+)([a-zA-Z])"] -> "$1 $2"]

share|improve this answer

edited 3 mins ago

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
  – james
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james OK, let me add some explanations.
  – Î‘λέξανδρος Ζεγγ
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your explanation.
  – james
  6 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james But you changed the problem?
  – Î‘λέξανδρος Ζεγγ
  5 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
  – james
  4 mins ago
  

  
  
  
  

 | 
show 1 more comment

up vote
1
down vote

up vote
1
down vote

StringReplace[text, RegularExpression["(\w\.)(\w)"] -> "$1 $2"]

"\w" means word characters, including letters, digits and the underscore _. "\." means a period literally. So the regular expression means to find a string pattern with length three: a word character followed by a period and followed by a word character.

Parentheses mean a group, and "$n" where n is an integer represents contents in the n-th group.

So the whole operation is to add a blank between the two groups after locating them by the string pattern.

---

Update for the new string:

StringReplace[text, RegularExpression["([a-zA-Z]\.+)([a-zA-Z])"] -> "$1 $2"]

share|improve this answer

edited 3 mins ago

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

StringReplace[text, RegularExpression["(\w\.)(\w)"] -> "$1 $2"]

"\w" means word characters, including letters, digits and the underscore _. "\." means a period literally. So the regular expression means to find a string pattern with length three: a word character followed by a period and followed by a word character.

Parentheses mean a group, and "$n" where n is an integer represents contents in the n-th group.

So the whole operation is to add a blank between the two groups after locating them by the string pattern.

---

Update for the new string:

StringReplace[text, RegularExpression["([a-zA-Z]\.+)([a-zA-Z])"] -> "$1 $2"]

share|improve this answer

edited 3 mins ago

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

share|improve this answer

share|improve this answer

edited 3 mins ago

edited 3 mins ago

edited 3 mins ago

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

answered 31 mins ago

Αλέξανδρος Ζεγγ

3,0991927

3,0991927

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
  – james
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james OK, let me add some explanations.
  – Î‘λέξανδρος Ζεγγ
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your explanation.
  – james
  6 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james But you changed the problem?
  – Î‘λέξανδρος Ζεγγ
  5 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
  – james
  4 mins ago
  

  
  
  
  

 | 
show 1 more comment

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
  – james
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james OK, let me add some explanations.
  – Î‘λέξανδρος Ζεγγ
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thank you very much for your explanation.
  – james
  6 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @james But you changed the problem?
  – Î‘λέξανδρος Ζεγγ
  5 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
  – james
  4 mins ago
  

  
  
  
  

Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
– james
28 mins ago

Awesome ! Thanks a lot ! Could you just add one or two comments about the terms withing the RegularExpression function ? I don't quite understand how you did it. Thanks !
– james
28 mins ago

@james OK, let me add some explanations.
– Î‘λέξανδρος Ζεγγ
28 mins ago

@james OK, let me add some explanations.
– Î‘λέξανδρος Ζεγγ
28 mins ago

Thank you very much for your explanation.
– james
6 mins ago

Thank you very much for your explanation.
– james
6 mins ago

@james But you changed the problem?
– Î‘λέξανδρος Ζεγγ
5 mins ago

@james But you changed the problem?
– Î‘λέξανδρος Ζεγγ
5 mins ago

Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
– james
4 mins ago

Kuba's comment made me realize that there is actually more to the question that I thought, and that I need to be more specific.
– james
4 mins ago

 | 
show 1 more comment

 

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