Trapezoidal Rule problem with logarithm
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Evaluate $int_0^1fracdx1+x$ using Trapezoidal rule for integration and hence find the value of log2.
I solved the first part having interval 0.125 $int_0^1fracdx1+x = 0.694075$; however, how do I find the value of log2 in this context?
numerical-methods
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up vote
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Evaluate $int_0^1fracdx1+x$ using Trapezoidal rule for integration and hence find the value of log2.
I solved the first part having interval 0.125 $int_0^1fracdx1+x = 0.694075$; however, how do I find the value of log2 in this context?
numerical-methods
New contributor
Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
Evaluate $int_0^1fracdx1+x$ using Trapezoidal rule for integration and hence find the value of log2.
I solved the first part having interval 0.125 $int_0^1fracdx1+x = 0.694075$; however, how do I find the value of log2 in this context?
numerical-methods
New contributor
Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Evaluate $int_0^1fracdx1+x$ using Trapezoidal rule for integration and hence find the value of log2.
I solved the first part having interval 0.125 $int_0^1fracdx1+x = 0.694075$; however, how do I find the value of log2 in this context?
numerical-methods
numerical-methods
New contributor
Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 3 hours ago


Dipendra Shrestha
141
141
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Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Dipendra Shrestha is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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2 Answers
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You have already found the value of $log(2)$. Congrats!
Hint:
$$int_0^1fracmathrmdx1+x=log(2)$$
So there you have your context and what you have found is the value of the integration i.e. $log(2)$ by using numerical methods (Trapezoidal rule).
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$$int_a^b frac11+xdx=log_e(1+x)|_a^b=log_e(1+b) - log_e(1+a)=log_efrac1+b1+a$$
For $a=0$ and $b=1$ this goes to $log_e2$
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
You have already found the value of $log(2)$. Congrats!
Hint:
$$int_0^1fracmathrmdx1+x=log(2)$$
So there you have your context and what you have found is the value of the integration i.e. $log(2)$ by using numerical methods (Trapezoidal rule).
add a comment |Â
up vote
2
down vote
You have already found the value of $log(2)$. Congrats!
Hint:
$$int_0^1fracmathrmdx1+x=log(2)$$
So there you have your context and what you have found is the value of the integration i.e. $log(2)$ by using numerical methods (Trapezoidal rule).
add a comment |Â
up vote
2
down vote
up vote
2
down vote
You have already found the value of $log(2)$. Congrats!
Hint:
$$int_0^1fracmathrmdx1+x=log(2)$$
So there you have your context and what you have found is the value of the integration i.e. $log(2)$ by using numerical methods (Trapezoidal rule).
You have already found the value of $log(2)$. Congrats!
Hint:
$$int_0^1fracmathrmdx1+x=log(2)$$
So there you have your context and what you have found is the value of the integration i.e. $log(2)$ by using numerical methods (Trapezoidal rule).
edited 2 hours ago
answered 3 hours ago


paulplusx
922217
922217
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up vote
1
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$$int_a^b frac11+xdx=log_e(1+x)|_a^b=log_e(1+b) - log_e(1+a)=log_efrac1+b1+a$$
For $a=0$ and $b=1$ this goes to $log_e2$
add a comment |Â
up vote
1
down vote
$$int_a^b frac11+xdx=log_e(1+x)|_a^b=log_e(1+b) - log_e(1+a)=log_efrac1+b1+a$$
For $a=0$ and $b=1$ this goes to $log_e2$
add a comment |Â
up vote
1
down vote
up vote
1
down vote
$$int_a^b frac11+xdx=log_e(1+x)|_a^b=log_e(1+b) - log_e(1+a)=log_efrac1+b1+a$$
For $a=0$ and $b=1$ this goes to $log_e2$
$$int_a^b frac11+xdx=log_e(1+x)|_a^b=log_e(1+b) - log_e(1+a)=log_efrac1+b1+a$$
For $a=0$ and $b=1$ this goes to $log_e2$
answered 1 hour ago
Derek
989613
989613
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Dipendra Shrestha is a new contributor. Be nice, and check out our Code of Conduct.
Dipendra Shrestha is a new contributor. Be nice, and check out our Code of Conduct.
Dipendra Shrestha is a new contributor. Be nice, and check out our Code of Conduct.
Dipendra Shrestha is a new contributor. Be nice, and check out our Code of Conduct.
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