Test a transistor with a multimeter

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I used the guide at https://vetco.net/blog/test-a-transistor-with-a-multimeter/2017-05-04-12-25-37-07 to test a transistor with my DMM. The NPN transistor I used to test is the "mospec tip130 No11D" and it was off from the circuit.



My question is that, STEP 3 (Emitter to Base) failed to show “OL” (Over Limit). Instead I read about ~1.2V. I used another same transistor that I am sure that it works on the circuit and I still get the same reading. Is the transistor a) bad b) wrong test c) good for some reason ?






transistors pcb multimeter npn test







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    up vote
    1
    down vote

    favorite












    I used the guide at https://vetco.net/blog/test-a-transistor-with-a-multimeter/2017-05-04-12-25-37-07 to test a transistor with my DMM. The NPN transistor I used to test is the "mospec tip130 No11D" and it was off from the circuit.



    My question is that, STEP 3 (Emitter to Base) failed to show “OL” (Over Limit). Instead I read about ~1.2V. I used another same transistor that I am sure that it works on the circuit and I still get the same reading. Is the transistor a) bad b) wrong test c) good for some reason ?






    transistors pcb multimeter npn test







    share|improve this question

























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I used the guide at https://vetco.net/blog/test-a-transistor-with-a-multimeter/2017-05-04-12-25-37-07 to test a transistor with my DMM. The NPN transistor I used to test is the "mospec tip130 No11D" and it was off from the circuit.



      My question is that, STEP 3 (Emitter to Base) failed to show “OL” (Over Limit). Instead I read about ~1.2V. I used another same transistor that I am sure that it works on the circuit and I still get the same reading. Is the transistor a) bad b) wrong test c) good for some reason ?






      transistors pcb multimeter npn test







      share|improve this question















      I used the guide at https://vetco.net/blog/test-a-transistor-with-a-multimeter/2017-05-04-12-25-37-07 to test a transistor with my DMM. The NPN transistor I used to test is the "mospec tip130 No11D" and it was off from the circuit.



      My question is that, STEP 3 (Emitter to Base) failed to show “OL” (Over Limit). Instead I read about ~1.2V. I used another same transistor that I am sure that it works on the circuit and I still get the same reading. Is the transistor a) bad b) wrong test c) good for some reason ?






      transistors pcb multimeter npn test




      transistors pcb multimeter npn test






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      edited 2 hours ago

























      asked 2 hours ago









      Maverick

      1085




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          1 Answer
          1






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          up vote
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          accepted










          Instead I can read about ~1.2V



          That makes perfect sense as the TIP130 is a Darlington transistor.



          It has an internal schematic like:



          enter image description here



          Note how between base and emitter there are actually two BE junctions in series, added up those two would have a forward voltage of around 1.2 V.



          Also note the additional diode between collector and emitter, it is only present in some Darlington transistors. Most "single" bipolar transistors don't have this diode.






          share|improve this answer
















          • 1




            I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
            – Maverick
            2 hours ago






          • 1




            Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
            – Maverick
            2 hours ago







          • 1




            Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
            – Bimpelrekkie
            1 hour ago











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          1 Answer
          1






          active

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          up vote
          4
          down vote



          accepted










          Instead I can read about ~1.2V



          That makes perfect sense as the TIP130 is a Darlington transistor.



          It has an internal schematic like:



          enter image description here



          Note how between base and emitter there are actually two BE junctions in series, added up those two would have a forward voltage of around 1.2 V.



          Also note the additional diode between collector and emitter, it is only present in some Darlington transistors. Most "single" bipolar transistors don't have this diode.






          share|improve this answer
















          • 1




            I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
            – Maverick
            2 hours ago






          • 1




            Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
            – Maverick
            2 hours ago







          • 1




            Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
            – Bimpelrekkie
            1 hour ago















          up vote
          4
          down vote



          accepted










          Instead I can read about ~1.2V



          That makes perfect sense as the TIP130 is a Darlington transistor.



          It has an internal schematic like:



          enter image description here



          Note how between base and emitter there are actually two BE junctions in series, added up those two would have a forward voltage of around 1.2 V.



          Also note the additional diode between collector and emitter, it is only present in some Darlington transistors. Most "single" bipolar transistors don't have this diode.






          share|improve this answer
















          • 1




            I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
            – Maverick
            2 hours ago






          • 1




            Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
            – Maverick
            2 hours ago







          • 1




            Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
            – Bimpelrekkie
            1 hour ago













          up vote
          4
          down vote



          accepted







          up vote
          4
          down vote



          accepted






          Instead I can read about ~1.2V



          That makes perfect sense as the TIP130 is a Darlington transistor.



          It has an internal schematic like:



          enter image description here



          Note how between base and emitter there are actually two BE junctions in series, added up those two would have a forward voltage of around 1.2 V.



          Also note the additional diode between collector and emitter, it is only present in some Darlington transistors. Most "single" bipolar transistors don't have this diode.






          share|improve this answer












          Instead I can read about ~1.2V



          That makes perfect sense as the TIP130 is a Darlington transistor.



          It has an internal schematic like:



          enter image description here



          Note how between base and emitter there are actually two BE junctions in series, added up those two would have a forward voltage of around 1.2 V.



          Also note the additional diode between collector and emitter, it is only present in some Darlington transistors. Most "single" bipolar transistors don't have this diode.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 hours ago









          Bimpelrekkie

          42.9k23793




          42.9k23793







          • 1




            I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
            – Maverick
            2 hours ago






          • 1




            Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
            – Maverick
            2 hours ago







          • 1




            Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
            – Bimpelrekkie
            1 hour ago













          • 1




            I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
            – Maverick
            2 hours ago






          • 1




            Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
            – Maverick
            2 hours ago







          • 1




            Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
            – Bimpelrekkie
            1 hour ago








          1




          1




          I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
          – Maverick
          2 hours ago




          I suspected the darlington connection that I read in the datasheet, but I dont have the experience to understand if that matters in this case. Thanx !
          – Maverick
          2 hours ago




          1




          1




          Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
          – Maverick
          2 hours ago





          Looking the schematic.... shouldn't I have also some voltage between Emmiter (+ proble) and Collector (- proble)?
          – Maverick
          2 hours ago





          1




          1




          Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
          – Bimpelrekkie
          1 hour ago





          Yes, that's the diode. If you probe + at emitter and - at collector you should measure around 0.6 V. If you probe the other way round (- at emitter and + at collector) you should get "OL" as then there should be no conduction at all.
          – Bimpelrekkie
          1 hour ago


















           

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