Mixing
Capture all numbers up to three digits
Clash Royale CLAN TAG#URR8PPP
up vote
8
down vote
favorite
I have the following string:
1 2 134 2009
And I'd like to capture the strings with between 1-3 digits, so the result should be:
['1', '2', '134']
What I have now captures those, but also captures the "first 3" digits in strings that contain more than 3 digits. This is the current regex I have:
>>> re.findall(r'd1,3', '1 2 134 2009')
['1', '2', '134', '200', '9']
# or a bit closer --
>>> re.findall(r'd1,3(?!d)', '1 2 134 2009')
['1', '2', '134', '009']
What would be the correct way to make sure that another digit doesn't immediate proceed it?
python regex
asked 41 mins ago
David L
2788
add a comment |Â
up vote
8
down vote
favorite
I have the following string:
1 2 134 2009
And I'd like to capture the strings with between 1-3 digits, so the result should be:
['1', '2', '134']
What I have now captures those, but also captures the "first 3" digits in strings that contain more than 3 digits. This is the current regex I have:
>>> re.findall(r'd1,3', '1 2 134 2009')
['1', '2', '134', '200', '9']
# or a bit closer --
>>> re.findall(r'd1,3(?!d)', '1 2 134 2009')
['1', '2', '134', '009']
What would be the correct way to make sure that another digit doesn't immediate proceed it?
python regex
asked 41 mins ago
David L
2788
1
What is the logic to match123in['1', '2', '123']
– The fourth bird
38 mins ago
@Thefourthbird I suppose that it would be a 'self-contained number', for example if someone looked the above string they could see that 4 numbers were contained in it. Not sure if I can give a more rigorous explanation.
– David L
36 mins ago
1
@Thefourthbird oh I see. Sorry that was a typo -- fixed.
– David L
34 mins ago
add a comment |Â
up vote
8
down vote
favorite
up vote
8
down vote
favorite
I have the following string:
1 2 134 2009
And I'd like to capture the strings with between 1-3 digits, so the result should be:
['1', '2', '134']
What I have now captures those, but also captures the "first 3" digits in strings that contain more than 3 digits. This is the current regex I have:
>>> re.findall(r'd1,3', '1 2 134 2009')
['1', '2', '134', '200', '9']
# or a bit closer --
>>> re.findall(r'd1,3(?!d)', '1 2 134 2009')
['1', '2', '134', '009']
What would be the correct way to make sure that another digit doesn't immediate proceed it?
python regex
asked 41 mins ago
David L
2788
I have the following string:
1 2 134 2009
And I'd like to capture the strings with between 1-3 digits, so the result should be:
['1', '2', '134']
What I have now captures those, but also captures the "first 3" digits in strings that contain more than 3 digits. This is the current regex I have:
>>> re.findall(r'd1,3', '1 2 134 2009')
['1', '2', '134', '200', '9']
# or a bit closer --
>>> re.findall(r'd1,3(?!d)', '1 2 134 2009')
['1', '2', '134', '009']
What would be the correct way to make sure that another digit doesn't immediate proceed it?
python regex
python regex
asked 41 mins ago
David L
2788
asked 41 mins ago
David L
2788
edited 34 mins ago
asked 41 mins ago
David L
2788
asked 41 mins ago
David L
2788
asked 41 mins ago
David L
2788
2788
1
What is the logic to match123in['1', '2', '123']
– The fourth bird
38 mins ago
@Thefourthbird I suppose that it would be a 'self-contained number', for example if someone looked the above string they could see that 4 numbers were contained in it. Not sure if I can give a more rigorous explanation.
– David L
36 mins ago
1
@Thefourthbird oh I see. Sorry that was a typo -- fixed.
– David L
34 mins ago
add a comment |Â
1
What is the logic to match123in['1', '2', '123']
– The fourth bird
38 mins ago
@Thefourthbird I suppose that it would be a 'self-contained number', for example if someone looked the above string they could see that 4 numbers were contained in it. Not sure if I can give a more rigorous explanation.
– David L
36 mins ago
1
@Thefourthbird oh I see. Sorry that was a typo -- fixed.
– David L
34 mins ago
1
1
What is the logic to match
123 in ['1', '2', '123']– The fourth bird
38 mins ago
What is the logic to match
123 in ['1', '2', '123']– The fourth bird
38 mins ago
@Thefourthbird I suppose that it would be a 'self-contained number', for example if someone looked the above string they could see that 4 numbers were contained in it. Not sure if I can give a more rigorous explanation.
– David L
36 mins ago
@Thefourthbird I suppose that it would be a 'self-contained number', for example if someone looked the above string they could see that 4 numbers were contained in it. Not sure if I can give a more rigorous explanation.
– David L
36 mins ago
1
1
@Thefourthbird oh I see. Sorry that was a typo -- fixed.
– David L
34 mins ago
@Thefourthbird oh I see. Sorry that was a typo -- fixed.
– David L
34 mins ago
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
10
down vote
accepted
Add word boundaries:
import re
result = re.findall(r'bd1,3b', '1 2 134 2009')
print(result)
Output
['1', '2', '134']
From the documentation b:
Matches the empty string, but only at the beginning or end of a word.
A word is defined as a sequence of word characters. Note that
formally, b is defined as the boundary between a w and a W
character (or vice versa), or between w and the beginning/end of the
string. This means that r'bfoob' matches 'foo', 'foo.', '(foo)',
'bar foo baz' but not 'foobar' or 'foo3'.
By default Unicode alphanumerics are the ones used in Unicode
patterns, but this can be changed by using the ASCII flag. Word
boundaries are determined by the current locale if the LOCALE flag is
used. Inside a character range, b represents the backspace character,
for compatibility with Python’s string literals.
answered 38 mins ago
Daniel Mesejo
6,6901621
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
add a comment |Â
up vote
5
down vote
If there are only digits separated by whitespace in your string, using re is overkill. You can simply split the string and check the length of the substrings.
>>> numbers = '1 2 134 2009'
>>> [n for n in numbers.split() if len(n) <= 3]
>>> ['1', '2', '134']
answered 35 mins ago
timgeb
42.1k105681
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
10
down vote
accepted
Add word boundaries:
import re
result = re.findall(r'bd1,3b', '1 2 134 2009')
print(result)
Output
['1', '2', '134']
From the documentation b:
Matches the empty string, but only at the beginning or end of a word.
A word is defined as a sequence of word characters. Note that
formally, b is defined as the boundary between a w and a W
character (or vice versa), or between w and the beginning/end of the
string. This means that r'bfoob' matches 'foo', 'foo.', '(foo)',
'bar foo baz' but not 'foobar' or 'foo3'.
By default Unicode alphanumerics are the ones used in Unicode
patterns, but this can be changed by using the ASCII flag. Word
boundaries are determined by the current locale if the LOCALE flag is
used. Inside a character range, b represents the backspace character,
for compatibility with Python’s string literals.
answered 38 mins ago
Daniel Mesejo
6,6901621
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
add a comment |Â
up vote
10
down vote
accepted
Add word boundaries:
import re
result = re.findall(r'bd1,3b', '1 2 134 2009')
print(result)
Output
['1', '2', '134']
From the documentation b:
Matches the empty string, but only at the beginning or end of a word.
A word is defined as a sequence of word characters. Note that
formally, b is defined as the boundary between a w and a W
character (or vice versa), or between w and the beginning/end of the
string. This means that r'bfoob' matches 'foo', 'foo.', '(foo)',
'bar foo baz' but not 'foobar' or 'foo3'.
By default Unicode alphanumerics are the ones used in Unicode
patterns, but this can be changed by using the ASCII flag. Word
boundaries are determined by the current locale if the LOCALE flag is
used. Inside a character range, b represents the backspace character,
for compatibility with Python’s string literals.
answered 38 mins ago
Daniel Mesejo
6,6901621
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
add a comment |Â
up vote
10
down vote
accepted
up vote
10
down vote
accepted
Add word boundaries:
import re
result = re.findall(r'bd1,3b', '1 2 134 2009')
print(result)
Output
['1', '2', '134']
From the documentation b:
Matches the empty string, but only at the beginning or end of a word.
A word is defined as a sequence of word characters. Note that
formally, b is defined as the boundary between a w and a W
character (or vice versa), or between w and the beginning/end of the
string. This means that r'bfoob' matches 'foo', 'foo.', '(foo)',
'bar foo baz' but not 'foobar' or 'foo3'.
By default Unicode alphanumerics are the ones used in Unicode
patterns, but this can be changed by using the ASCII flag. Word
boundaries are determined by the current locale if the LOCALE flag is
used. Inside a character range, b represents the backspace character,
for compatibility with Python’s string literals.
answered 38 mins ago
Daniel Mesejo
6,6901621
Add word boundaries:
import re
result = re.findall(r'bd1,3b', '1 2 134 2009')
print(result)
Output
['1', '2', '134']
From the documentation b:
Matches the empty string, but only at the beginning or end of a word.
A word is defined as a sequence of word characters. Note that
formally, b is defined as the boundary between a w and a W
character (or vice versa), or between w and the beginning/end of the
string. This means that r'bfoob' matches 'foo', 'foo.', '(foo)',
'bar foo baz' but not 'foobar' or 'foo3'.
By default Unicode alphanumerics are the ones used in Unicode
patterns, but this can be changed by using the ASCII flag. Word
boundaries are determined by the current locale if the LOCALE flag is
used. Inside a character range, b represents the backspace character,
for compatibility with Python’s string literals.
answered 38 mins ago
Daniel Mesejo
6,6901621
edited 30 mins ago
answered 38 mins ago
Daniel Mesejo
6,6901621
answered 38 mins ago
Daniel Mesejo
6,6901621
answered 38 mins ago
Daniel Mesejo
6,6901621
6,6901621
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
add a comment |Â
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
thanks for this. For a 'word boundary', what does this include other than a space?
– David L
36 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
@DavidL Updated the answer!
– Daniel Mesejo
30 mins ago
add a comment |Â
up vote
5
down vote
If there are only digits separated by whitespace in your string, using re is overkill. You can simply split the string and check the length of the substrings.
>>> numbers = '1 2 134 2009'
>>> [n for n in numbers.split() if len(n) <= 3]
>>> ['1', '2', '134']
answered 35 mins ago
timgeb
42.1k105681
add a comment |Â
up vote
5
down vote
If there are only digits separated by whitespace in your string, using re is overkill. You can simply split the string and check the length of the substrings.
>>> numbers = '1 2 134 2009'
>>> [n for n in numbers.split() if len(n) <= 3]
>>> ['1', '2', '134']
answered 35 mins ago
timgeb
42.1k105681
add a comment |Â
up vote
5
down vote
up vote
5
down vote
If there are only digits separated by whitespace in your string, using re is overkill. You can simply split the string and check the length of the substrings.
>>> numbers = '1 2 134 2009'
>>> [n for n in numbers.split() if len(n) <= 3]
>>> ['1', '2', '134']
answered 35 mins ago
timgeb
42.1k105681
If there are only digits separated by whitespace in your string, using re is overkill. You can simply split the string and check the length of the substrings.
>>> numbers = '1 2 134 2009'
>>> [n for n in numbers.split() if len(n) <= 3]
>>> ['1', '2', '134']
answered 35 mins ago
timgeb
42.1k105681
answered 35 mins ago
timgeb
42.1k105681
answered 35 mins ago
timgeb
42.1k105681
answered 35 mins ago
timgeb
42.1k105681
42.1k105681
add a comment |Â
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53196561%2fcapture-all-numbers-up-to-three-digits%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
1
What is the logic to match
123in['1', '2', '123']– The fourth bird
38 mins ago
@Thefourthbird I suppose that it would be a 'self-contained number', for example if someone looked the above string they could see that 4 numbers were contained in it. Not sure if I can give a more rigorous explanation.
– David L
36 mins ago
1
@Thefourthbird oh I see. Sorry that was a typo -- fixed.
– David L
34 mins ago