Parse date time string to DateTime

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How do I parse




2018-10-01T00:00:00Z




Into an instance of DateTime



I've tried:



DateTime.valueOfGmt('2018-10-01T00:00:00Z');
DateTime.parse('2018-10-01T00:00:00Z');
DateTime.valueOf('2018-10-01T00:00:00Z');
DateTime.valueOfGmt('2018-10-01T00:00:00Z');


And I always get error:




ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z











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    up vote
    1
    down vote

    favorite












    How do I parse




    2018-10-01T00:00:00Z




    Into an instance of DateTime



    I've tried:



    DateTime.valueOfGmt('2018-10-01T00:00:00Z');
    DateTime.parse('2018-10-01T00:00:00Z');
    DateTime.valueOf('2018-10-01T00:00:00Z');
    DateTime.valueOfGmt('2018-10-01T00:00:00Z');


    And I always get error:




    ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z











    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      How do I parse




      2018-10-01T00:00:00Z




      Into an instance of DateTime



      I've tried:



      DateTime.valueOfGmt('2018-10-01T00:00:00Z');
      DateTime.parse('2018-10-01T00:00:00Z');
      DateTime.valueOf('2018-10-01T00:00:00Z');
      DateTime.valueOfGmt('2018-10-01T00:00:00Z');


      And I always get error:




      ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z











      share|improve this question













      How do I parse




      2018-10-01T00:00:00Z




      Into an instance of DateTime



      I've tried:



      DateTime.valueOfGmt('2018-10-01T00:00:00Z');
      DateTime.parse('2018-10-01T00:00:00Z');
      DateTime.valueOf('2018-10-01T00:00:00Z');
      DateTime.valueOfGmt('2018-10-01T00:00:00Z');


      And I always get error:




      ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z








      apex datetime






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      asked 24 mins ago









      Robs

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          2 Answers
          2






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          up vote
          3
          down vote













          JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);


          Note the extra set of double quotes - they allow the JSON parser to interpret that value.






          share|improve this answer




















          • +1 Took the characters right out of my text box. 😄
            – sfdcfox
            17 mins ago

















          up vote
          0
          down vote













          As an alternative, you can use a regular expression to get the values into a more digestible form:



          Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
          String exampleTime = '2018-10-01T00:00:00z';
          Matcher m = dt.matcher(exampletime);
          DateTime result;
          if(m.find())
          result = DateTime.newInstanceGMT(
          Integer.valueOf(m.group(1)),
          Integer.valueOf(m.group(2)),
          Integer.valueOf(m.group(3)),
          Integer.valueOf(m.group(4)),
          Integer.valueOf(m.group(5)),
          Integer.valueOf(m.group(6))
          );

          system.debug(result);




          share




















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            2 Answers
            2






            active

            oldest

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            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

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            active

            oldest

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            up vote
            3
            down vote













            JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);


            Note the extra set of double quotes - they allow the JSON parser to interpret that value.






            share|improve this answer




















            • +1 Took the characters right out of my text box. 😄
              – sfdcfox
              17 mins ago














            up vote
            3
            down vote













            JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);


            Note the extra set of double quotes - they allow the JSON parser to interpret that value.






            share|improve this answer




















            • +1 Took the characters right out of my text box. 😄
              – sfdcfox
              17 mins ago












            up vote
            3
            down vote










            up vote
            3
            down vote









            JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);


            Note the extra set of double quotes - they allow the JSON parser to interpret that value.






            share|improve this answer












            JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);


            Note the extra set of double quotes - they allow the JSON parser to interpret that value.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 19 mins ago









            David Reed

            21.5k31640




            21.5k31640











            • +1 Took the characters right out of my text box. 😄
              – sfdcfox
              17 mins ago
















            • +1 Took the characters right out of my text box. 😄
              – sfdcfox
              17 mins ago















            +1 Took the characters right out of my text box. 😄
            – sfdcfox
            17 mins ago




            +1 Took the characters right out of my text box. 😄
            – sfdcfox
            17 mins ago












            up vote
            0
            down vote













            As an alternative, you can use a regular expression to get the values into a more digestible form:



            Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
            String exampleTime = '2018-10-01T00:00:00z';
            Matcher m = dt.matcher(exampletime);
            DateTime result;
            if(m.find())
            result = DateTime.newInstanceGMT(
            Integer.valueOf(m.group(1)),
            Integer.valueOf(m.group(2)),
            Integer.valueOf(m.group(3)),
            Integer.valueOf(m.group(4)),
            Integer.valueOf(m.group(5)),
            Integer.valueOf(m.group(6))
            );

            system.debug(result);




            share
























              up vote
              0
              down vote













              As an alternative, you can use a regular expression to get the values into a more digestible form:



              Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
              String exampleTime = '2018-10-01T00:00:00z';
              Matcher m = dt.matcher(exampletime);
              DateTime result;
              if(m.find())
              result = DateTime.newInstanceGMT(
              Integer.valueOf(m.group(1)),
              Integer.valueOf(m.group(2)),
              Integer.valueOf(m.group(3)),
              Integer.valueOf(m.group(4)),
              Integer.valueOf(m.group(5)),
              Integer.valueOf(m.group(6))
              );

              system.debug(result);




              share






















                up vote
                0
                down vote










                up vote
                0
                down vote









                As an alternative, you can use a regular expression to get the values into a more digestible form:



                Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
                String exampleTime = '2018-10-01T00:00:00z';
                Matcher m = dt.matcher(exampletime);
                DateTime result;
                if(m.find())
                result = DateTime.newInstanceGMT(
                Integer.valueOf(m.group(1)),
                Integer.valueOf(m.group(2)),
                Integer.valueOf(m.group(3)),
                Integer.valueOf(m.group(4)),
                Integer.valueOf(m.group(5)),
                Integer.valueOf(m.group(6))
                );

                system.debug(result);




                share












                As an alternative, you can use a regular expression to get the values into a more digestible form:



                Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
                String exampleTime = '2018-10-01T00:00:00z';
                Matcher m = dt.matcher(exampletime);
                DateTime result;
                if(m.find())
                result = DateTime.newInstanceGMT(
                Integer.valueOf(m.group(1)),
                Integer.valueOf(m.group(2)),
                Integer.valueOf(m.group(3)),
                Integer.valueOf(m.group(4)),
                Integer.valueOf(m.group(5)),
                Integer.valueOf(m.group(6))
                );

                system.debug(result);





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                answered 8 mins ago









                sfdcfox

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