Mixing
Alphabets and Numbers? : Another Grandpa Mystery
Clash Royale CLAN TAG#URR8PPP
up vote
3
down vote
favorite
Now we all know how crazy Grandpa is when it comes to Math. He says to me:
"Use your imagination and tell me,
If
Seven + L = Zero
And
Zero - C = One
Then
Three + I = ?
I have no idea!â€Â
riddle lateral-thinking
edited 1 hour ago
El-Guest
15.1k3272
asked 1 hour ago
DEEM
4,1451179
add a comment |Â
up vote
3
down vote
favorite
Now we all know how crazy Grandpa is when it comes to Math. He says to me:
"Use your imagination and tell me,
If
Seven + L = Zero
And
Zero - C = One
Then
Three + I = ?
I have no idea!â€Â
riddle lateral-thinking
edited 1 hour ago
El-Guest
15.1k3272
asked 1 hour ago
DEEM
4,1451179
1
Is the ** a formating error?
– PotatoLatte
1 hour ago
@PotatoLatte Maybe, maybe not :P
– user477343
50 mins ago
Well, since it got fixed, no?
– PotatoLatte
41 mins ago
It probably does not have to do with the numbers themselves, as they use the words instead of the numbers
– PotatoLatte
40 mins ago
It was fixed by me because I assumed this was the intention. If DEEM wishes to change it, they may roll it back.
– El-Guest
40 mins ago
add a comment |Â
up vote
3
down vote
favorite
up vote
3
down vote
favorite
Now we all know how crazy Grandpa is when it comes to Math. He says to me:
"Use your imagination and tell me,
If
Seven + L = Zero
And
Zero - C = One
Then
Three + I = ?
I have no idea!â€Â
riddle lateral-thinking
edited 1 hour ago
El-Guest
15.1k3272
asked 1 hour ago
DEEM
4,1451179
Now we all know how crazy Grandpa is when it comes to Math. He says to me:
"Use your imagination and tell me,
If
Seven + L = Zero
And
Zero - C = One
Then
Three + I = ?
I have no idea!â€Â
riddle lateral-thinking
riddle lateral-thinking
edited 1 hour ago
El-Guest
15.1k3272
asked 1 hour ago
DEEM
4,1451179
edited 1 hour ago
El-Guest
15.1k3272
asked 1 hour ago
DEEM
4,1451179
edited 1 hour ago
El-Guest
15.1k3272
edited 1 hour ago
El-Guest
15.1k3272
edited 1 hour ago
El-Guest
15.1k3272
15.1k3272
asked 1 hour ago
DEEM
4,1451179
asked 1 hour ago
DEEM
4,1451179
asked 1 hour ago
DEEM
4,1451179
4,1451179
1
Is the ** a formating error?
– PotatoLatte
1 hour ago
@PotatoLatte Maybe, maybe not :P
– user477343
50 mins ago
Well, since it got fixed, no?
– PotatoLatte
41 mins ago
It probably does not have to do with the numbers themselves, as they use the words instead of the numbers
– PotatoLatte
40 mins ago
It was fixed by me because I assumed this was the intention. If DEEM wishes to change it, they may roll it back.
– El-Guest
40 mins ago
add a comment |Â
1
Is the ** a formating error?
– PotatoLatte
1 hour ago
@PotatoLatte Maybe, maybe not :P
– user477343
50 mins ago
Well, since it got fixed, no?
– PotatoLatte
41 mins ago
It probably does not have to do with the numbers themselves, as they use the words instead of the numbers
– PotatoLatte
40 mins ago
It was fixed by me because I assumed this was the intention. If DEEM wishes to change it, they may roll it back.
– El-Guest
40 mins ago
1
1
Is the ** a formating error?
– PotatoLatte
1 hour ago
Is the ** a formating error?
– PotatoLatte
1 hour ago
@PotatoLatte Maybe, maybe not :P
– user477343
50 mins ago
@PotatoLatte Maybe, maybe not :P
– user477343
50 mins ago
Well, since it got fixed, no?
– PotatoLatte
41 mins ago
Well, since it got fixed, no?
– PotatoLatte
41 mins ago
It probably does not have to do with the numbers themselves, as they use the words instead of the numbers
– PotatoLatte
40 mins ago
It probably does not have to do with the numbers themselves, as they use the words instead of the numbers
– PotatoLatte
40 mins ago
It was fixed by me because I assumed this was the intention. If DEEM wishes to change it, they may roll it back.
– El-Guest
40 mins ago
It was fixed by me because I assumed this was the intention. If DEEM wishes to change it, they may roll it back.
– El-Guest
40 mins ago
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
4
down vote
Based on DEEM’s hint, the answer is
Eight.
I think this is because
When you look at the digital number for 7, and add an L to the left of it, you get L7 which looks like a digital Zero. When you look at a digital Zero and remove a C from the left of it, you get a digital One. When you take a digital 3 and add an I to the left of it, you get a digital Eight.
answered 25 mins ago
El-Guest
15.1k3272
1
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
add a comment |Â
up vote
3
down vote
I think it should be
One, also.
The function is
$f(x) = (x+1) pmod 2$, where $x$ is the result of the addition or subtraction when you convert the letters to Roman numerals.
So:
For $x = mboxSeven+L = 7+50=57$, $f(x) = (57+1) pmod 2 = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = (-100+1) pmod 2 = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = (4+1) pmod 2 = 1 = rm One$.
Of course, the answer could also be
Zero.
If the function was
$f(x) = H(-x)$, where $H$ is the Heaviside function, equal to 1 for $xgeq 0$ and 0 for $x<0$.
Then
For $x = mboxSeven+L = 7+50=57$, $f(x) = H(-57) = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = H(-(-100)) = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = H(-4) = 0 = rm Zero$.
edited 46 mins ago
user477343
2,5281748
answered 1 hour ago
El-Guest
15.1k3272
1
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the commandpmod 2and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands likemboxandtextetc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)
– user477343
44 mins ago
1
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
1
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
 |Â
show 1 more comment
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
Based on DEEM’s hint, the answer is
Eight.
I think this is because
When you look at the digital number for 7, and add an L to the left of it, you get L7 which looks like a digital Zero. When you look at a digital Zero and remove a C from the left of it, you get a digital One. When you take a digital 3 and add an I to the left of it, you get a digital Eight.
answered 25 mins ago
El-Guest
15.1k3272
1
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
add a comment |Â
up vote
4
down vote
Based on DEEM’s hint, the answer is
Eight.
I think this is because
When you look at the digital number for 7, and add an L to the left of it, you get L7 which looks like a digital Zero. When you look at a digital Zero and remove a C from the left of it, you get a digital One. When you take a digital 3 and add an I to the left of it, you get a digital Eight.
answered 25 mins ago
El-Guest
15.1k3272
1
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
add a comment |Â
up vote
4
down vote
up vote
4
down vote
Based on DEEM’s hint, the answer is
Eight.
I think this is because
When you look at the digital number for 7, and add an L to the left of it, you get L7 which looks like a digital Zero. When you look at a digital Zero and remove a C from the left of it, you get a digital One. When you take a digital 3 and add an I to the left of it, you get a digital Eight.
answered 25 mins ago
El-Guest
15.1k3272
Based on DEEM’s hint, the answer is
Eight.
I think this is because
When you look at the digital number for 7, and add an L to the left of it, you get L7 which looks like a digital Zero. When you look at a digital Zero and remove a C from the left of it, you get a digital One. When you take a digital 3 and add an I to the left of it, you get a digital Eight.
answered 25 mins ago
El-Guest
15.1k3272
answered 25 mins ago
El-Guest
15.1k3272
answered 25 mins ago
El-Guest
15.1k3272
answered 25 mins ago
El-Guest
15.1k3272
15.1k3272
1
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
add a comment |Â
1
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
1
1
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
Damn, I reached my daily voting limit (DVL).
– user477343
22 mins ago
add a comment |Â
up vote
3
down vote
I think it should be
One, also.
The function is
$f(x) = (x+1) pmod 2$, where $x$ is the result of the addition or subtraction when you convert the letters to Roman numerals.
So:
For $x = mboxSeven+L = 7+50=57$, $f(x) = (57+1) pmod 2 = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = (-100+1) pmod 2 = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = (4+1) pmod 2 = 1 = rm One$.
Of course, the answer could also be
Zero.
If the function was
$f(x) = H(-x)$, where $H$ is the Heaviside function, equal to 1 for $xgeq 0$ and 0 for $x<0$.
Then
For $x = mboxSeven+L = 7+50=57$, $f(x) = H(-57) = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = H(-(-100)) = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = H(-4) = 0 = rm Zero$.
edited 46 mins ago
user477343
2,5281748
answered 1 hour ago
El-Guest
15.1k3272
1
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the commandpmod 2and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands likemboxandtextetc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)
– user477343
44 mins ago
1
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
1
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
 |Â
show 1 more comment
up vote
3
down vote
I think it should be
One, also.
The function is
$f(x) = (x+1) pmod 2$, where $x$ is the result of the addition or subtraction when you convert the letters to Roman numerals.
So:
For $x = mboxSeven+L = 7+50=57$, $f(x) = (57+1) pmod 2 = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = (-100+1) pmod 2 = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = (4+1) pmod 2 = 1 = rm One$.
Of course, the answer could also be
Zero.
If the function was
$f(x) = H(-x)$, where $H$ is the Heaviside function, equal to 1 for $xgeq 0$ and 0 for $x<0$.
Then
For $x = mboxSeven+L = 7+50=57$, $f(x) = H(-57) = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = H(-(-100)) = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = H(-4) = 0 = rm Zero$.
edited 46 mins ago
user477343
2,5281748
answered 1 hour ago
El-Guest
15.1k3272
1
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the commandpmod 2and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands likemboxandtextetc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)
– user477343
44 mins ago
1
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
1
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
 |Â
show 1 more comment
up vote
3
down vote
up vote
3
down vote
I think it should be
One, also.
The function is
$f(x) = (x+1) pmod 2$, where $x$ is the result of the addition or subtraction when you convert the letters to Roman numerals.
So:
For $x = mboxSeven+L = 7+50=57$, $f(x) = (57+1) pmod 2 = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = (-100+1) pmod 2 = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = (4+1) pmod 2 = 1 = rm One$.
Of course, the answer could also be
Zero.
If the function was
$f(x) = H(-x)$, where $H$ is the Heaviside function, equal to 1 for $xgeq 0$ and 0 for $x<0$.
Then
For $x = mboxSeven+L = 7+50=57$, $f(x) = H(-57) = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = H(-(-100)) = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = H(-4) = 0 = rm Zero$.
edited 46 mins ago
user477343
2,5281748
answered 1 hour ago
El-Guest
15.1k3272
I think it should be
One, also.
The function is
$f(x) = (x+1) pmod 2$, where $x$ is the result of the addition or subtraction when you convert the letters to Roman numerals.
So:
For $x = mboxSeven+L = 7+50=57$, $f(x) = (57+1) pmod 2 = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = (-100+1) pmod 2 = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = (4+1) pmod 2 = 1 = rm One$.
Of course, the answer could also be
Zero.
If the function was
$f(x) = H(-x)$, where $H$ is the Heaviside function, equal to 1 for $xgeq 0$ and 0 for $x<0$.
Then
For $x = mboxSeven+L = 7+50=57$, $f(x) = H(-57) = 0 = rm Zero$.
For $x = textZero-C = 0-100=-100$, $f(x) = H(-(-100)) = 1 = rm One$.
For $x= mathrmThree + I = 3+1 = 4$, $f(x) = H(-4) = 0 = rm Zero$.
edited 46 mins ago
user477343
2,5281748
answered 1 hour ago
El-Guest
15.1k3272
edited 46 mins ago
user477343
2,5281748
edited 46 mins ago
user477343
2,5281748
edited 46 mins ago
user477343
2,5281748
2,5281748
answered 1 hour ago
El-Guest
15.1k3272
answered 1 hour ago
El-Guest
15.1k3272
answered 1 hour ago
El-Guest
15.1k3272
15.1k3272
1
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the commandpmod 2and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands likemboxandtextetc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)
– user477343
44 mins ago
1
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
1
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
 |Â
show 1 more comment
1
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the commandpmod 2and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands likemboxandtextetc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)
– user477343
44 mins ago
1
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
1
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
1
1
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
Please note that there is no MATH tag on this @El-Guest
– DEEM
54 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the command
pmod 2 and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands like mbox and text etc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)– user477343
44 mins ago
I have edited this post by carrying out the following actions: changed $mod2$ to $pmod 2$ via the command
pmod 2 and I also changed $this~font$ to $rm underlinethis~font$ with multiple commands like mbox and text etc (see which one you prefer). (The underline is not part of the actual font, but provides an emphasis.) Do you approve of this edit? :)– user477343
44 mins ago
1
1
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
Yes, but I figured there was some lateral thinking involved in deriving this answer! Back to the drawing board!
– El-Guest
42 mins ago
1
1
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
Thank you, @user477343! Much appreciated!
– El-Guest
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
No problemo! $(+1)$ :D
– user477343
41 mins ago
 |Â
show 1 more comment
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1
Is the ** a formating error?
– PotatoLatte
1 hour ago
@PotatoLatte Maybe, maybe not :P
– user477343
50 mins ago
Well, since it got fixed, no?
– PotatoLatte
41 mins ago
It probably does not have to do with the numbers themselves, as they use the words instead of the numbers
– PotatoLatte
40 mins ago
It was fixed by me because I assumed this was the intention. If DEEM wishes to change it, they may roll it back.
– El-Guest
40 mins ago