Parse date time string to Apex DateTime

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up vote
2
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How do I parse

2018-10-01T00:00:00Z

Into an instance of DateTime

I've tried:

DateTime.valueOfGmt('2018-10-01T00:00:00Z');
DateTime.parse('2018-10-01T00:00:00Z');
DateTime.valueOf('2018-10-01T00:00:00Z');
DateTime.valueOfGmt('2018-10-01T00:00:00Z');

And I always get error:

ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z

apex datetime

share|improve this question

edited 11 mins ago

asked 1 hour ago

Robs

1,195424

add a comment | 

up vote
2
down vote

favorite

How do I parse

2018-10-01T00:00:00Z

Into an instance of DateTime

I've tried:

DateTime.valueOfGmt('2018-10-01T00:00:00Z');
DateTime.parse('2018-10-01T00:00:00Z');
DateTime.valueOf('2018-10-01T00:00:00Z');
DateTime.valueOfGmt('2018-10-01T00:00:00Z');

And I always get error:

ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z

apex datetime

share|improve this question

edited 11 mins ago

asked 1 hour ago

Robs

1,195424

add a comment | 

up vote
2
down vote

favorite

up vote
2
down vote

favorite

How do I parse

2018-10-01T00:00:00Z

Into an instance of DateTime

I've tried:

DateTime.valueOfGmt('2018-10-01T00:00:00Z');
DateTime.parse('2018-10-01T00:00:00Z');
DateTime.valueOf('2018-10-01T00:00:00Z');
DateTime.valueOfGmt('2018-10-01T00:00:00Z');

And I always get error:

ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z

apex datetime

share|improve this question

edited 11 mins ago

asked 1 hour ago

Robs

1,195424

How do I parse

2018-10-01T00:00:00Z

Into an instance of DateTime

I've tried:

DateTime.valueOfGmt('2018-10-01T00:00:00Z');
DateTime.parse('2018-10-01T00:00:00Z');
DateTime.valueOf('2018-10-01T00:00:00Z');
DateTime.valueOfGmt('2018-10-01T00:00:00Z');

And I always get error:

ERROR: System.TypeException: Invalid date/time: 2018-10-01T00:00:00Z

apex datetime

apex datetime

share|improve this question

edited 11 mins ago

asked 1 hour ago

Robs

1,195424

share|improve this question

edited 11 mins ago

asked 1 hour ago

Robs

1,195424

share|improve this question

share|improve this question

edited 11 mins ago

edited 11 mins ago

edited 11 mins ago

asked 1 hour ago

Robs

1,195424

asked 1 hour ago

Robs

1,195424

asked 1 hour ago

Robs

1,195424

1,195424

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
5
down vote



accepted

JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);

Note the extra set of double quotes - they allow the JSON parser to interpret that value.

share|improve this answer

answered 1 hour ago

David Reed

21.5k31640

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  +1 Took the characters right out of my text box. 😄
  – sfdcfox
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
2
down vote

As an alternative, you can use a regular expression to get the values into a more digestible form:

Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
String exampleTime = '2018-10-01T00:00:00z';
Matcher m = dt.matcher(exampletime);
DateTime result;
if(m.find()) 
 result = DateTime.newInstanceGMT(
 Integer.valueOf(m.group(1)),
 Integer.valueOf(m.group(2)),
 Integer.valueOf(m.group(3)),
 Integer.valueOf(m.group(4)),
 Integer.valueOf(m.group(5)),
 Integer.valueOf(m.group(6)) 
 );

system.debug(result);

share|improve this answer

answered 1 hour ago

sfdcfox

232k10179395

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
5
down vote



accepted

JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);

Note the extra set of double quotes - they allow the JSON parser to interpret that value.

share|improve this answer

answered 1 hour ago

David Reed

21.5k31640

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  +1 Took the characters right out of my text box. 😄
  – sfdcfox
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote



accepted

JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);

Note the extra set of double quotes - they allow the JSON parser to interpret that value.

share|improve this answer

answered 1 hour ago

David Reed

21.5k31640

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  +1 Took the characters right out of my text box. 😄
  – sfdcfox
  1 hour ago
  

  
  
  
  

add a comment | 

up vote
5
down vote



accepted

up vote
5
down vote



accepted

JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);

Note the extra set of double quotes - they allow the JSON parser to interpret that value.

share|improve this answer

answered 1 hour ago

David Reed

21.5k31640

JSON.deserialize('"2018-10-01T00:00:00Z"', DateTime.class);

Note the extra set of double quotes - they allow the JSON parser to interpret that value.

share|improve this answer

answered 1 hour ago

David Reed

21.5k31640

share|improve this answer

share|improve this answer

answered 1 hour ago

David Reed

21.5k31640

answered 1 hour ago

David Reed

21.5k31640

answered 1 hour ago

David Reed

21.5k31640

21.5k31640

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  +1 Took the characters right out of my text box. 😄
  – sfdcfox
  1 hour ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  +1 Took the characters right out of my text box. 😄
  – sfdcfox
  1 hour ago
  

  
  
  
  

1

1

+1 Took the characters right out of my text box. 😄
– sfdcfox
1 hour ago

+1 Took the characters right out of my text box. 😄
– sfdcfox
1 hour ago

add a comment | 

up vote
2
down vote

As an alternative, you can use a regular expression to get the values into a more digestible form:

Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
String exampleTime = '2018-10-01T00:00:00z';
Matcher m = dt.matcher(exampletime);
DateTime result;
if(m.find()) 
 result = DateTime.newInstanceGMT(
 Integer.valueOf(m.group(1)),
 Integer.valueOf(m.group(2)),
 Integer.valueOf(m.group(3)),
 Integer.valueOf(m.group(4)),
 Integer.valueOf(m.group(5)),
 Integer.valueOf(m.group(6)) 
 );

system.debug(result);

share|improve this answer

answered 1 hour ago

sfdcfox

232k10179395

add a comment | 

up vote
2
down vote

As an alternative, you can use a regular expression to get the values into a more digestible form:

Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
String exampleTime = '2018-10-01T00:00:00z';
Matcher m = dt.matcher(exampletime);
DateTime result;
if(m.find()) 
 result = DateTime.newInstanceGMT(
 Integer.valueOf(m.group(1)),
 Integer.valueOf(m.group(2)),
 Integer.valueOf(m.group(3)),
 Integer.valueOf(m.group(4)),
 Integer.valueOf(m.group(5)),
 Integer.valueOf(m.group(6)) 
 );

system.debug(result);

share|improve this answer

answered 1 hour ago

sfdcfox

232k10179395

add a comment | 

up vote
2
down vote

up vote
2
down vote

As an alternative, you can use a regular expression to get the values into a more digestible form:

Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
String exampleTime = '2018-10-01T00:00:00z';
Matcher m = dt.matcher(exampletime);
DateTime result;
if(m.find()) 
 result = DateTime.newInstanceGMT(
 Integer.valueOf(m.group(1)),
 Integer.valueOf(m.group(2)),
 Integer.valueOf(m.group(3)),
 Integer.valueOf(m.group(4)),
 Integer.valueOf(m.group(5)),
 Integer.valueOf(m.group(6)) 
 );

system.debug(result);

share|improve this answer

answered 1 hour ago

sfdcfox

232k10179395

As an alternative, you can use a regular expression to get the values into a more digestible form:

Pattern dt = Pattern.compile('(?i)(\d4)-(\d2)-(\d2)T(\d2):(\d2):(\d2)Z');
String exampleTime = '2018-10-01T00:00:00z';
Matcher m = dt.matcher(exampletime);
DateTime result;
if(m.find()) 
 result = DateTime.newInstanceGMT(
 Integer.valueOf(m.group(1)),
 Integer.valueOf(m.group(2)),
 Integer.valueOf(m.group(3)),
 Integer.valueOf(m.group(4)),
 Integer.valueOf(m.group(5)),
 Integer.valueOf(m.group(6)) 
 );

system.debug(result);

share|improve this answer

answered 1 hour ago

sfdcfox

232k10179395

share|improve this answer

share|improve this answer

answered 1 hour ago

sfdcfox

232k10179395

answered 1 hour ago

sfdcfox

232k10179395

answered 1 hour ago

sfdcfox

232k10179395

232k10179395

add a comment | 

add a comment | 

 

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