Mixing
Brackets and omitted argument in a function
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Sometimes, it is useful in math notations to write $u(x,cdot)$ where the second argument of the function u is intentionally omitted. However, the above instruction generates a fairly questionable spacing between cdot and ). For instance, $u(L,cdot,)$ is slightly nicer. What is the right way to code the above function in LateX?
spacing
asked 47 mins ago
pluton
7,757959125
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up vote
6
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Sometimes, it is useful in math notations to write $u(x,cdot)$ where the second argument of the function u is intentionally omitted. However, the above instruction generates a fairly questionable spacing between cdot and ). For instance, $u(L,cdot,)$ is slightly nicer. What is the right way to code the above function in LateX?
spacing
asked 47 mins ago
pluton
7,757959125
add a comment |Â
up vote
6
down vote
favorite
up vote
6
down vote
favorite
Sometimes, it is useful in math notations to write $u(x,cdot)$ where the second argument of the function u is intentionally omitted. However, the above instruction generates a fairly questionable spacing between cdot and ). For instance, $u(L,cdot,)$ is slightly nicer. What is the right way to code the above function in LateX?
spacing
asked 47 mins ago
pluton
7,757959125
Sometimes, it is useful in math notations to write $u(x,cdot)$ where the second argument of the function u is intentionally omitted. However, the above instruction generates a fairly questionable spacing between cdot and ). For instance, $u(L,cdot,)$ is slightly nicer. What is the right way to code the above function in LateX?
spacing
spacing
asked 47 mins ago
pluton
7,757959125
asked 47 mins ago
pluton
7,757959125
asked 47 mins ago
pluton
7,757959125
asked 47 mins ago
pluton
7,757959125
asked 47 mins ago
pluton
7,757959125
7,757959125
add a comment |Â
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
6
down vote
accepted
I suggest first of all to make a specific command for it, so you don't forget what spacing you have decided for.
I show several possible definitions, choose the one you prefer.
documentclassarticle
usepackageamsmath
newcommandblankcdot
begindocument
$u(x,cdot)$
$u(x,cdot,)$
$u(x,blank)$
renewcommandblankmspace1mucdotmspace1mu
$u(x,blank)$
renewcommandblankmspace2mucdotmspace2mu
$u(x,blank)$
renewcommandblank-
$u(x,blank)$
enddocument
The last redefinition shows how you can comply with a fussy coauthor who doesn't like the dot and prefers a dash. Using a personal command makes the change very easy.
Some explanations. Since cdot is a binary operation symbol, if TeX finds it immediately before or after punctuation or immediately before or after a delimiter (in your case two conditions apply), it considers it an ordinary symbol. Thus you get
,<thin space><dot>)
Adding , will make
,<thin space><dot><thin space>)
On the other hand, if you have u(cdot,y), you get
(<dot>,
with no spacing at all. The definition with cdot will consider cdot as a binary operation, with empty operands, so we get
,<thin space><med space><dot><med space>)
Using mspace1mucdotmspace1mu the dot is considered as ordinary, because it has no operands on either side. So you get
,<thin space><1mu><dot><1mu>)
and
(<1mu><dot><1mu>,
in the first variable case. The asymmetry is desired.
answered 32 mins ago
egreg
690k8518373085
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
accepted
I suggest first of all to make a specific command for it, so you don't forget what spacing you have decided for.
I show several possible definitions, choose the one you prefer.
documentclassarticle
usepackageamsmath
newcommandblankcdot
begindocument
$u(x,cdot)$
$u(x,cdot,)$
$u(x,blank)$
renewcommandblankmspace1mucdotmspace1mu
$u(x,blank)$
renewcommandblankmspace2mucdotmspace2mu
$u(x,blank)$
renewcommandblank-
$u(x,blank)$
enddocument
The last redefinition shows how you can comply with a fussy coauthor who doesn't like the dot and prefers a dash. Using a personal command makes the change very easy.
Some explanations. Since cdot is a binary operation symbol, if TeX finds it immediately before or after punctuation or immediately before or after a delimiter (in your case two conditions apply), it considers it an ordinary symbol. Thus you get
,<thin space><dot>)
Adding , will make
,<thin space><dot><thin space>)
On the other hand, if you have u(cdot,y), you get
(<dot>,
with no spacing at all. The definition with cdot will consider cdot as a binary operation, with empty operands, so we get
,<thin space><med space><dot><med space>)
Using mspace1mucdotmspace1mu the dot is considered as ordinary, because it has no operands on either side. So you get
,<thin space><1mu><dot><1mu>)
and
(<1mu><dot><1mu>,
in the first variable case. The asymmetry is desired.
answered 32 mins ago
egreg
690k8518373085
add a comment |Â
up vote
6
down vote
accepted
I suggest first of all to make a specific command for it, so you don't forget what spacing you have decided for.
I show several possible definitions, choose the one you prefer.
documentclassarticle
usepackageamsmath
newcommandblankcdot
begindocument
$u(x,cdot)$
$u(x,cdot,)$
$u(x,blank)$
renewcommandblankmspace1mucdotmspace1mu
$u(x,blank)$
renewcommandblankmspace2mucdotmspace2mu
$u(x,blank)$
renewcommandblank-
$u(x,blank)$
enddocument
The last redefinition shows how you can comply with a fussy coauthor who doesn't like the dot and prefers a dash. Using a personal command makes the change very easy.
Some explanations. Since cdot is a binary operation symbol, if TeX finds it immediately before or after punctuation or immediately before or after a delimiter (in your case two conditions apply), it considers it an ordinary symbol. Thus you get
,<thin space><dot>)
Adding , will make
,<thin space><dot><thin space>)
On the other hand, if you have u(cdot,y), you get
(<dot>,
with no spacing at all. The definition with cdot will consider cdot as a binary operation, with empty operands, so we get
,<thin space><med space><dot><med space>)
Using mspace1mucdotmspace1mu the dot is considered as ordinary, because it has no operands on either side. So you get
,<thin space><1mu><dot><1mu>)
and
(<1mu><dot><1mu>,
in the first variable case. The asymmetry is desired.
answered 32 mins ago
egreg
690k8518373085
add a comment |Â
up vote
6
down vote
accepted
up vote
6
down vote
accepted
I suggest first of all to make a specific command for it, so you don't forget what spacing you have decided for.
I show several possible definitions, choose the one you prefer.
documentclassarticle
usepackageamsmath
newcommandblankcdot
begindocument
$u(x,cdot)$
$u(x,cdot,)$
$u(x,blank)$
renewcommandblankmspace1mucdotmspace1mu
$u(x,blank)$
renewcommandblankmspace2mucdotmspace2mu
$u(x,blank)$
renewcommandblank-
$u(x,blank)$
enddocument
The last redefinition shows how you can comply with a fussy coauthor who doesn't like the dot and prefers a dash. Using a personal command makes the change very easy.
Some explanations. Since cdot is a binary operation symbol, if TeX finds it immediately before or after punctuation or immediately before or after a delimiter (in your case two conditions apply), it considers it an ordinary symbol. Thus you get
,<thin space><dot>)
Adding , will make
,<thin space><dot><thin space>)
On the other hand, if you have u(cdot,y), you get
(<dot>,
with no spacing at all. The definition with cdot will consider cdot as a binary operation, with empty operands, so we get
,<thin space><med space><dot><med space>)
Using mspace1mucdotmspace1mu the dot is considered as ordinary, because it has no operands on either side. So you get
,<thin space><1mu><dot><1mu>)
and
(<1mu><dot><1mu>,
in the first variable case. The asymmetry is desired.
answered 32 mins ago
egreg
690k8518373085
I suggest first of all to make a specific command for it, so you don't forget what spacing you have decided for.
I show several possible definitions, choose the one you prefer.
documentclassarticle
usepackageamsmath
newcommandblankcdot
begindocument
$u(x,cdot)$
$u(x,cdot,)$
$u(x,blank)$
renewcommandblankmspace1mucdotmspace1mu
$u(x,blank)$
renewcommandblankmspace2mucdotmspace2mu
$u(x,blank)$
renewcommandblank-
$u(x,blank)$
enddocument
The last redefinition shows how you can comply with a fussy coauthor who doesn't like the dot and prefers a dash. Using a personal command makes the change very easy.
Some explanations. Since cdot is a binary operation symbol, if TeX finds it immediately before or after punctuation or immediately before or after a delimiter (in your case two conditions apply), it considers it an ordinary symbol. Thus you get
,<thin space><dot>)
Adding , will make
,<thin space><dot><thin space>)
On the other hand, if you have u(cdot,y), you get
(<dot>,
with no spacing at all. The definition with cdot will consider cdot as a binary operation, with empty operands, so we get
,<thin space><med space><dot><med space>)
Using mspace1mucdotmspace1mu the dot is considered as ordinary, because it has no operands on either side. So you get
,<thin space><1mu><dot><1mu>)
and
(<1mu><dot><1mu>,
in the first variable case. The asymmetry is desired.
answered 32 mins ago
egreg
690k8518373085
edited 22 mins ago
answered 32 mins ago
egreg
690k8518373085
answered 32 mins ago
egreg
690k8518373085
answered 32 mins ago
egreg
690k8518373085
690k8518373085
add a comment |Â
add a comment |Â
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