Print one word more than one charter on new line using awk, sed, grep

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












I have a text file, I want to print every word (more than one character) on new line. If a word consist of a single character, it must be handled as part of the following word and printed with it on a new line. If it is in the middle between two words it must follow the second word. example:



Unix & Linux Stack Exchange is a question and answer site for users of Linux,


output 



Unix
& Linux
Stack
Exchange
is 
a question 
and 
answer 
site
for
users
of
Linux





text-processing awk sed grep







share|improve this question























  • What do you mean by "if it is in the middle between two words it must follow the second word"? What should happen to a one character word if there's no word following it?
    – choroba
    4 hours ago










  • This is strongly related to unix.stackexchange.com/q/472204/4667 -- is this the same homework?
    – glenn jackman
    1 hour ago














up vote
1
down vote

favorite












I have a text file, I want to print every word (more than one character) on new line. If a word consist of a single character, it must be handled as part of the following word and printed with it on a new line. If it is in the middle between two words it must follow the second word. example:



Unix & Linux Stack Exchange is a question and answer site for users of Linux,


output 



Unix
& Linux
Stack
Exchange
is 
a question 
and 
answer 
site
for
users
of
Linux





text-processing awk sed grep







share|improve this question























  • What do you mean by "if it is in the middle between two words it must follow the second word"? What should happen to a one character word if there's no word following it?
    – choroba
    4 hours ago










  • This is strongly related to unix.stackexchange.com/q/472204/4667 -- is this the same homework?
    – glenn jackman
    1 hour ago












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I have a text file, I want to print every word (more than one character) on new line. If a word consist of a single character, it must be handled as part of the following word and printed with it on a new line. If it is in the middle between two words it must follow the second word. example:



Unix & Linux Stack Exchange is a question and answer site for users of Linux,


output 



Unix
& Linux
Stack
Exchange
is 
a question 
and 
answer 
site
for
users
of
Linux





text-processing awk sed grep







share|improve this question















I have a text file, I want to print every word (more than one character) on new line. If a word consist of a single character, it must be handled as part of the following word and printed with it on a new line. If it is in the middle between two words it must follow the second word. example:



Unix & Linux Stack Exchange is a question and answer site for users of Linux,


output 



Unix
& Linux
Stack
Exchange
is 
a question 
and 
answer 
site
for
users
of
Linux





text-processing awk sed grep




text-processing awk sed grep






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 4 hours ago









choroba

24.9k34168




24.9k34168










asked 5 hours ago









Zahi

1106




1106











  • What do you mean by "if it is in the middle between two words it must follow the second word"? What should happen to a one character word if there's no word following it?
    – choroba
    4 hours ago










  • This is strongly related to unix.stackexchange.com/q/472204/4667 -- is this the same homework?
    – glenn jackman
    1 hour ago
















  • What do you mean by "if it is in the middle between two words it must follow the second word"? What should happen to a one character word if there's no word following it?
    – choroba
    4 hours ago










  • This is strongly related to unix.stackexchange.com/q/472204/4667 -- is this the same homework?
    – glenn jackman
    1 hour ago















What do you mean by "if it is in the middle between two words it must follow the second word"? What should happen to a one character word if there's no word following it?
– choroba
4 hours ago




What do you mean by "if it is in the middle between two words it must follow the second word"? What should happen to a one character word if there's no word following it?
– choroba
4 hours ago












This is strongly related to unix.stackexchange.com/q/472204/4667 -- is this the same homework?
– glenn jackman
1 hour ago




This is strongly related to unix.stackexchange.com/q/472204/4667 -- is this the same homework?
– glenn jackman
1 hour ago










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










I'd reach for Perl-flavoured regex here:



$ echo "$s" | grep -Po '((^|s)KSs+)?S2,'
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


You can do the same with extended regex, but as it doesn't have pcre's lookarounds, you end up capturing the leading space:



$ echo "$s" | grep -Eo '((^|[[:blank:]])[^[:blank:]][[:blank:]]+)?[^[:blank:]]2,'
Unix
 & Linux
Stack
Exchange
is
 a question
and
answer
site
for
users
of
Linux,


I would have liked to use a word boundary marker prior to the 1-character word, but & is not a word character, so the word boundary is not useful.






share|improve this answer




















  • I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
    – Zahi
    23 mins ago

















up vote
1
down vote













How about 



sed -r 's/([^ ]2,) /1n/g' file
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


Check if a space is preceded by 2 or more non-space char pattern, and substitute by "back reference" pattern plus <LF> char.






share|improve this answer






















  • Very elegant solution
    – glenn jackman
    1 hour ago










  • Thank you sir for he answer
    – Zahi
    21 mins ago










Your Answer







StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f472262%2fprint-one-word-more-than-one-charter-on-new-line-using-awk-sed-grep%23new-answer', 'question_page');

);

Post as a guest

















2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










I'd reach for Perl-flavoured regex here:



$ echo "$s" | grep -Po '((^|s)KSs+)?S2,'
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


You can do the same with extended regex, but as it doesn't have pcre's lookarounds, you end up capturing the leading space:



$ echo "$s" | grep -Eo '((^|[[:blank:]])[^[:blank:]][[:blank:]]+)?[^[:blank:]]2,'
Unix
 & Linux
Stack
Exchange
is
 a question
and
answer
site
for
users
of
Linux,


I would have liked to use a word boundary marker prior to the 1-character word, but & is not a word character, so the word boundary is not useful.






share|improve this answer




















  • I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
    – Zahi
    23 mins ago














up vote
3
down vote



accepted










I'd reach for Perl-flavoured regex here:



$ echo "$s" | grep -Po '((^|s)KSs+)?S2,'
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


You can do the same with extended regex, but as it doesn't have pcre's lookarounds, you end up capturing the leading space:



$ echo "$s" | grep -Eo '((^|[[:blank:]])[^[:blank:]][[:blank:]]+)?[^[:blank:]]2,'
Unix
 & Linux
Stack
Exchange
is
 a question
and
answer
site
for
users
of
Linux,


I would have liked to use a word boundary marker prior to the 1-character word, but & is not a word character, so the word boundary is not useful.






share|improve this answer




















  • I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
    – Zahi
    23 mins ago












up vote
3
down vote



accepted







up vote
3
down vote



accepted






I'd reach for Perl-flavoured regex here:



$ echo "$s" | grep -Po '((^|s)KSs+)?S2,'
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


You can do the same with extended regex, but as it doesn't have pcre's lookarounds, you end up capturing the leading space:



$ echo "$s" | grep -Eo '((^|[[:blank:]])[^[:blank:]][[:blank:]]+)?[^[:blank:]]2,'
Unix
 & Linux
Stack
Exchange
is
 a question
and
answer
site
for
users
of
Linux,


I would have liked to use a word boundary marker prior to the 1-character word, but & is not a word character, so the word boundary is not useful.






share|improve this answer












I'd reach for Perl-flavoured regex here:



$ echo "$s" | grep -Po '((^|s)KSs+)?S2,'
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


You can do the same with extended regex, but as it doesn't have pcre's lookarounds, you end up capturing the leading space:



$ echo "$s" | grep -Eo '((^|[[:blank:]])[^[:blank:]][[:blank:]]+)?[^[:blank:]]2,'
Unix
 & Linux
Stack
Exchange
is
 a question
and
answer
site
for
users
of
Linux,


I would have liked to use a word boundary marker prior to the 1-character word, but & is not a word character, so the word boundary is not useful.







share|improve this answer












share|improve this answer



share|improve this answer










answered 1 hour ago









glenn jackman

48.2k365105




48.2k365105











  • I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
    – Zahi
    23 mins ago
















  • I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
    – Zahi
    23 mins ago















I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
– Zahi
23 mins ago




I really appreciate the answer. Very helpful! I Googled so much but I was not aware that there was similar question out there. thanks for sharing! Can I use the same regex in an awk statement?
– Zahi
23 mins ago












up vote
1
down vote













How about 



sed -r 's/([^ ]2,) /1n/g' file
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


Check if a space is preceded by 2 or more non-space char pattern, and substitute by "back reference" pattern plus <LF> char.






share|improve this answer






















  • Very elegant solution
    – glenn jackman
    1 hour ago










  • Thank you sir for he answer
    – Zahi
    21 mins ago














up vote
1
down vote













How about 



sed -r 's/([^ ]2,) /1n/g' file
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


Check if a space is preceded by 2 or more non-space char pattern, and substitute by "back reference" pattern plus <LF> char.






share|improve this answer






















  • Very elegant solution
    – glenn jackman
    1 hour ago










  • Thank you sir for he answer
    – Zahi
    21 mins ago












up vote
1
down vote










up vote
1
down vote









How about 



sed -r 's/([^ ]2,) /1n/g' file
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


Check if a space is preceded by 2 or more non-space char pattern, and substitute by "back reference" pattern plus <LF> char.






share|improve this answer














How about 



sed -r 's/([^ ]2,) /1n/g' file
Unix
& Linux
Stack
Exchange
is
a question
and
answer
site
for
users
of
Linux,


Check if a space is preceded by 2 or more non-space char pattern, and substitute by "back reference" pattern plus <LF> char.







share|improve this answer














share|improve this answer



share|improve this answer








edited 1 hour ago

























answered 4 hours ago









RudiC

1,5449




1,5449











  • Very elegant solution
    – glenn jackman
    1 hour ago










  • Thank you sir for he answer
    – Zahi
    21 mins ago
















  • Very elegant solution
    – glenn jackman
    1 hour ago










  • Thank you sir for he answer
    – Zahi
    21 mins ago















Very elegant solution
– glenn jackman
1 hour ago




Very elegant solution
– glenn jackman
1 hour ago












Thank you sir for he answer
– Zahi
21 mins ago




Thank you sir for he answer
– Zahi
21 mins ago

















 

draft saved


draft discarded















































 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f472262%2fprint-one-word-more-than-one-charter-on-new-line-using-awk-sed-grep%23new-answer', 'question_page');

);

Post as a guest
































































Comments

Post a Comment

Popular posts from this blog

Long meetings (6-7 hours a day): Being “babysat” by supervisor

Image
Clash Royale CLAN TAG #URR8PPP .everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty margin-bottom:0; up vote 31 down vote favorite 4 I hold a PhD in mechanical engineering with a 7 year background in self-guided, self-paced research including 2 years as a graduate level course instructor and a subject matter expert for various engineering projects in a university setting in the United States. For the last 10-11 months, I am working in a research industry in France where my task is to debug C++ spaghetti code written over a period of several years by my current supervisor. It is a team of 2: just I and my supervisor. Diurnally, I am posed with a "bug of the day" to get out of this C++ code. My supervisor generally gives me about 15-30 minutes to solve it and then accosts me about whether or not the task is completed and then rinses and repeats this until the end of the day. Off-late, my supervisor has been holding 6-7 hour long "meetin
Read more

Is the Concept of Multiple Fantasy Races Scientifically Flawed? [closed]

Image
Clash Royale CLAN TAG #URR8PPP up vote 2 down vote favorite Many fantasy worlds have multiple humanoid species (elves, orcs, humans, etc) living in the same world, in addition to that, they often have the ability to interbreed. And I can't help but question their believability... fantasy-races reproduction interspecies-relations share | improve this question edited Aug 9 at 14:46 Michael Kjörling ♦ 21.1k 10 85 161 asked Aug 9 at 13:13 Chlodio 118 6 closed as unclear what you're asking by MichaelK, Gryphon, John, Vincent, Frostfyre Aug 9 at 15:25 Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question. 3 Stack Exchange exist to
Read more

Confectionery

Image
Prepared foods made with a lot of sugar or other cabohydrates "Sweetmeat" redirects here. For the racehorse, see Sweetmeat (horse). Not to be confused with Sweetbread. This Kransekake is a traditional Scandinavian baker's confection. Confectionery is the art of making confections , which are food items that are rich in sugar and carbohydrates. Exact definitions are difficult. [1] In general, though, confectionery is divided into two broad and somewhat overlapping categories, bakers' confections and sugar confections. [2] Bakers' confectionery, also called flour confections , includes principally sweet pastries, cakes, and similar baked goods. Sugar confectionery includes candies ( sweets in British English), candied nuts, chocolates, chewing gum, bubble gum, pastillage, and other confections that are made primarily of sugar. In some cases, chocolate confections (confections made of chocolate) are treated as a separate category, as are sugar-free versions of
Read more