Why do we study Cantor Set?
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For finding counter examples. That does not sound convincing enough, at least not always. Why as a object in its own right the study of Cantor Set has merit ?
mathematical-analysis
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For finding counter examples. That does not sound convincing enough, at least not always. Why as a object in its own right the study of Cantor Set has merit ?
mathematical-analysis
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up vote
1
down vote
favorite
up vote
1
down vote
favorite
For finding counter examples. That does not sound convincing enough, at least not always. Why as a object in its own right the study of Cantor Set has merit ?
mathematical-analysis
For finding counter examples. That does not sound convincing enough, at least not always. Why as a object in its own right the study of Cantor Set has merit ?
mathematical-analysis
mathematical-analysis
asked 7 hours ago
Vagabond
1913
1913
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in beginning real analysis: to counter the naive notion that a "closed set" is a union of closed intervals, plus a few single points.
In beginning Lebesgue measure: the easiest example of an uncountable set of measure zero
In general topology: sets homeomorphic to the Cantor set are useful in proofs
Fractal geometry: many fractals are homeomorphic to the Cantor set. Mandelbrot calls such a thing a Cantor dust to suggest its appearance.
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
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I think that you may be selling short the value of a counterexample! They are quite useful for making sure that you have not proven too much. i.e. When you have a plausible but only semi-formal argument, how do you tell if it is worth the effort in making it rigorous? Checking against counterexamples is often a useful step.
Still, there are relations to unbounded paths in an infinite binary tree without leaves. That is, suppose that you start at the root and write $0.$, thought of as a ternary number. As we travel to the left or right, write a $0$ or $2$, respectively, for the following digit. Continuing on we get a ternary expansion defining a real number in the Cantor set. Correspondingly, the ternary expansion of an element of the Cantor set gives rise to a path from the root in the tree.
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
in beginning real analysis: to counter the naive notion that a "closed set" is a union of closed intervals, plus a few single points.
In beginning Lebesgue measure: the easiest example of an uncountable set of measure zero
In general topology: sets homeomorphic to the Cantor set are useful in proofs
Fractal geometry: many fractals are homeomorphic to the Cantor set. Mandelbrot calls such a thing a Cantor dust to suggest its appearance.
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
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up vote
3
down vote
in beginning real analysis: to counter the naive notion that a "closed set" is a union of closed intervals, plus a few single points.
In beginning Lebesgue measure: the easiest example of an uncountable set of measure zero
In general topology: sets homeomorphic to the Cantor set are useful in proofs
Fractal geometry: many fractals are homeomorphic to the Cantor set. Mandelbrot calls such a thing a Cantor dust to suggest its appearance.
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
add a comment |Â
up vote
3
down vote
up vote
3
down vote
in beginning real analysis: to counter the naive notion that a "closed set" is a union of closed intervals, plus a few single points.
In beginning Lebesgue measure: the easiest example of an uncountable set of measure zero
In general topology: sets homeomorphic to the Cantor set are useful in proofs
Fractal geometry: many fractals are homeomorphic to the Cantor set. Mandelbrot calls such a thing a Cantor dust to suggest its appearance.
in beginning real analysis: to counter the naive notion that a "closed set" is a union of closed intervals, plus a few single points.
In beginning Lebesgue measure: the easiest example of an uncountable set of measure zero
In general topology: sets homeomorphic to the Cantor set are useful in proofs
Fractal geometry: many fractals are homeomorphic to the Cantor set. Mandelbrot calls such a thing a Cantor dust to suggest its appearance.
answered 1 hour ago
Gerald Edgar
3,04411013
3,04411013
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
add a comment |Â
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
Can one claim and substantiate that the study of cantor set is something fundamental and not just a source of ready counterexample ?
â Vagabond
1 hour ago
add a comment |Â
up vote
0
down vote
I think that you may be selling short the value of a counterexample! They are quite useful for making sure that you have not proven too much. i.e. When you have a plausible but only semi-formal argument, how do you tell if it is worth the effort in making it rigorous? Checking against counterexamples is often a useful step.
Still, there are relations to unbounded paths in an infinite binary tree without leaves. That is, suppose that you start at the root and write $0.$, thought of as a ternary number. As we travel to the left or right, write a $0$ or $2$, respectively, for the following digit. Continuing on we get a ternary expansion defining a real number in the Cantor set. Correspondingly, the ternary expansion of an element of the Cantor set gives rise to a path from the root in the tree.
add a comment |Â
up vote
0
down vote
I think that you may be selling short the value of a counterexample! They are quite useful for making sure that you have not proven too much. i.e. When you have a plausible but only semi-formal argument, how do you tell if it is worth the effort in making it rigorous? Checking against counterexamples is often a useful step.
Still, there are relations to unbounded paths in an infinite binary tree without leaves. That is, suppose that you start at the root and write $0.$, thought of as a ternary number. As we travel to the left or right, write a $0$ or $2$, respectively, for the following digit. Continuing on we get a ternary expansion defining a real number in the Cantor set. Correspondingly, the ternary expansion of an element of the Cantor set gives rise to a path from the root in the tree.
add a comment |Â
up vote
0
down vote
up vote
0
down vote
I think that you may be selling short the value of a counterexample! They are quite useful for making sure that you have not proven too much. i.e. When you have a plausible but only semi-formal argument, how do you tell if it is worth the effort in making it rigorous? Checking against counterexamples is often a useful step.
Still, there are relations to unbounded paths in an infinite binary tree without leaves. That is, suppose that you start at the root and write $0.$, thought of as a ternary number. As we travel to the left or right, write a $0$ or $2$, respectively, for the following digit. Continuing on we get a ternary expansion defining a real number in the Cantor set. Correspondingly, the ternary expansion of an element of the Cantor set gives rise to a path from the root in the tree.
I think that you may be selling short the value of a counterexample! They are quite useful for making sure that you have not proven too much. i.e. When you have a plausible but only semi-formal argument, how do you tell if it is worth the effort in making it rigorous? Checking against counterexamples is often a useful step.
Still, there are relations to unbounded paths in an infinite binary tree without leaves. That is, suppose that you start at the root and write $0.$, thought of as a ternary number. As we travel to the left or right, write a $0$ or $2$, respectively, for the following digit. Continuing on we get a ternary expansion defining a real number in the Cantor set. Correspondingly, the ternary expansion of an element of the Cantor set gives rise to a path from the root in the tree.
answered 6 mins ago
Adam
2,135717
2,135717
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