Remove files which not named â€œtoday.mdâ€

up vote
2
down vote

favorite

I have the a series of markdown files in the working directory:

$ ls *.md
csv_reader.md egrep.md find.md found_pdfs.md osPathSep_help.md readme.md smtplib_help.md today.md

I want to remove them except "today.md"

#!/usr/local/bin/bash
for i in ./*.md ; do
 if [[ $i != "today.md" ]]; then
 echo $i
 fi
done

Run it and get

$ bash bash/remove_files.sh
./csv_reader.md
./egrep.md
./find.md
./found_pdfs.md
./osPathSep_help.md
./readme.md
./smtplib_help.md
./today.md

Nonetheless, the structured commands are not handy in the command line, how could I accomplish such a task with shorter commands

edited 1 hour ago

Jeff Schaller

34.8k952115

asked 2 hours ago

Sawajiri

1225

New contributor

add a commentÂ |Â

up vote
2
down vote

favorite

I have the a series of markdown files in the working directory:

$ ls *.md
csv_reader.md egrep.md find.md found_pdfs.md osPathSep_help.md readme.md smtplib_help.md today.md

I want to remove them except "today.md"

#!/usr/local/bin/bash
for i in ./*.md ; do
 if [[ $i != "today.md" ]]; then
 echo $i
 fi
done

Run it and get

$ bash bash/remove_files.sh
./csv_reader.md
./egrep.md
./find.md
./found_pdfs.md
./osPathSep_help.md
./readme.md
./smtplib_help.md
./today.md

Nonetheless, the structured commands are not handy in the command line, how could I accomplish such a task with shorter commands

edited 1 hour ago

Jeff Schaller

34.8k952115

asked 2 hours ago

Sawajiri

1225

New contributor

add a commentÂ |Â

up vote
2
down vote

favorite

I have the a series of markdown files in the working directory:

$ ls *.md
csv_reader.md egrep.md find.md found_pdfs.md osPathSep_help.md readme.md smtplib_help.md today.md

I want to remove them except "today.md"

#!/usr/local/bin/bash
for i in ./*.md ; do
 if [[ $i != "today.md" ]]; then
 echo $i
 fi
done

Run it and get

$ bash bash/remove_files.sh
./csv_reader.md
./egrep.md
./find.md
./found_pdfs.md
./osPathSep_help.md
./readme.md
./smtplib_help.md
./today.md

Nonetheless, the structured commands are not handy in the command line, how could I accomplish such a task with shorter commands

edited 1 hour ago

Jeff Schaller

34.8k952115

asked 2 hours ago

Sawajiri

1225

New contributor

I have the a series of markdown files in the working directory:

$ ls *.md
csv_reader.md egrep.md find.md found_pdfs.md osPathSep_help.md readme.md smtplib_help.md today.md

I want to remove them except "today.md"

#!/usr/local/bin/bash
for i in ./*.md ; do
 if [[ $i != "today.md" ]]; then
 echo $i
 fi
done

Run it and get

$ bash bash/remove_files.sh
./csv_reader.md
./egrep.md
./find.md
./found_pdfs.md
./osPathSep_help.md
./readme.md
./smtplib_help.md
./today.md

Nonetheless, the structured commands are not handy in the command line, how could I accomplish such a task with shorter commands

bash shell-script files rm

edited 1 hour ago

Jeff Schaller

34.8k952115

asked 2 hours ago

Sawajiri

1225

New contributor

edited 1 hour ago

Jeff Schaller

34.8k952115

asked 2 hours ago

Sawajiri

1225

New contributor

edited 1 hour ago

Jeff Schaller

34.8k952115

edited 1 hour ago

Jeff Schaller

34.8k952115

edited 1 hour ago

Jeff Schaller

34.8k952115

asked 2 hours ago

Sawajiri

1225

New contributor

asked 2 hours ago

Sawajiri

1225

asked 2 hours ago

Sawajiri

1225

New contributor

Sawajiri is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

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4 Answers
4

active

oldest

votes

up vote
3
down vote

find . -maxdepth 1 -name '*.md' ! -name today.md -type f -print

Should find all the files (-type f) in the current directory (. -- or explicitly put a directory name there) only (-maxdepth 1 prevents following subdirectories) that end in .md (-name '*.md'), excluding (!) the file today.md.

Be sure to include the single quotes around '*.md' so your shell doesn't try to expand that to the list of .md files in the current directory before it executes find.

It will print the list of files to be deleted. Change -print to -delete to delete them instead.

answered 2 hours ago

drewbenn

5,01251835

add a commentÂ |Â

up vote
1
down vote

Use a negative match (requires shopt -s extglob, but possibly already set):

rm !(today).md

(you can first use ls instead of rm to check the result).

Lots of power in extglob, you could also do

rm !(yesterday|today).md

if you wanted to spare two files.

answered 1 hour ago

xenoid

2,1611621

add a commentÂ |Â

up vote
1
down vote

You may find it shorter to use bash's extended globbing feature to exclude the file you don't want:

shopt -s extglob
echo rm -- !(today).md

The above (after removing the echo for testing) says to match anything except today followed by .md.

Your example didn't match dot-files by default; you can change that behavior with shopt dotglob, if desired

Your script didn't work as written because the glob pattern you used (appropriately) prefixed the filenames with ./; therefore, your inner test should have compared against ./today.md.

edited 58 mins ago

answered 1 hour ago

Jeff Schaller

34.8k952115

add a commentÂ |Â

up vote
1
down vote

The above are better solutions, but the reason your code isn't working is because of the comparison.

"./today.md" is not equal to "today.md".

answered 37 mins ago

user208145

1,08621115

add a commentÂ |Â

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4 Answers
4

active

oldest

votes

4 Answers
4

active

oldest

votes

up vote
3
down vote

find . -maxdepth 1 -name '*.md' ! -name today.md -type f -print

Be sure to include the single quotes around '*.md' so your shell doesn't try to expand that to the list of .md files in the current directory before it executes find.

It will print the list of files to be deleted. Change -print to -delete to delete them instead.

answered 2 hours ago

drewbenn

5,01251835

add a commentÂ |Â

up vote
3
down vote

find . -maxdepth 1 -name '*.md' ! -name today.md -type f -print

Be sure to include the single quotes around '*.md' so your shell doesn't try to expand that to the list of .md files in the current directory before it executes find.

It will print the list of files to be deleted. Change -print to -delete to delete them instead.

answered 2 hours ago

drewbenn

5,01251835

add a commentÂ |Â

up vote
3
down vote

find . -maxdepth 1 -name '*.md' ! -name today.md -type f -print

Be sure to include the single quotes around '*.md' so your shell doesn't try to expand that to the list of .md files in the current directory before it executes find.

It will print the list of files to be deleted. Change -print to -delete to delete them instead.

answered 2 hours ago

drewbenn

5,01251835

find . -maxdepth 1 -name '*.md' ! -name today.md -type f -print

Be sure to include the single quotes around '*.md' so your shell doesn't try to expand that to the list of .md files in the current directory before it executes find.

It will print the list of files to be deleted. Change -print to -delete to delete them instead.

answered 2 hours ago

drewbenn

5,01251835

answered 2 hours ago

drewbenn

5,01251835

answered 2 hours ago

drewbenn

5,01251835

answered 2 hours ago

drewbenn

5,01251835

add a commentÂ |Â

up vote
1
down vote

Use a negative match (requires shopt -s extglob, but possibly already set):

rm !(today).md

(you can first use ls instead of rm to check the result).

Lots of power in extglob, you could also do

rm !(yesterday|today).md

if you wanted to spare two files.

answered 1 hour ago

xenoid

2,1611621

add a commentÂ |Â

up vote
1
down vote

Use a negative match (requires shopt -s extglob, but possibly already set):

rm !(today).md

(you can first use ls instead of rm to check the result).

Lots of power in extglob, you could also do

rm !(yesterday|today).md

if you wanted to spare two files.

answered 1 hour ago

xenoid

2,1611621

add a commentÂ |Â

up vote
1
down vote

Use a negative match (requires shopt -s extglob, but possibly already set):

rm !(today).md

(you can first use ls instead of rm to check the result).

Lots of power in extglob, you could also do

rm !(yesterday|today).md

if you wanted to spare two files.

answered 1 hour ago

xenoid

2,1611621

Use a negative match (requires shopt -s extglob, but possibly already set):

rm !(today).md

(you can first use ls instead of rm to check the result).

Lots of power in extglob, you could also do

rm !(yesterday|today).md

if you wanted to spare two files.

answered 1 hour ago

xenoid

2,1611621

answered 1 hour ago

xenoid

2,1611621

answered 1 hour ago

xenoid

2,1611621

answered 1 hour ago

xenoid

2,1611621

add a commentÂ |Â

up vote
1
down vote

You may find it shorter to use bash's extended globbing feature to exclude the file you don't want:

shopt -s extglob
echo rm -- !(today).md

The above (after removing the echo for testing) says to match anything except today followed by .md.

Your example didn't match dot-files by default; you can change that behavior with shopt dotglob, if desired

Your script didn't work as written because the glob pattern you used (appropriately) prefixed the filenames with ./; therefore, your inner test should have compared against ./today.md.

edited 58 mins ago

answered 1 hour ago

Jeff Schaller

34.8k952115

add a commentÂ |Â

up vote
1
down vote

You may find it shorter to use bash's extended globbing feature to exclude the file you don't want:

shopt -s extglob
echo rm -- !(today).md

The above (after removing the echo for testing) says to match anything except today followed by .md.

Your example didn't match dot-files by default; you can change that behavior with shopt dotglob, if desired

Your script didn't work as written because the glob pattern you used (appropriately) prefixed the filenames with ./; therefore, your inner test should have compared against ./today.md.

edited 58 mins ago

answered 1 hour ago

Jeff Schaller

34.8k952115

add a commentÂ |Â

up vote
1
down vote

You may find it shorter to use bash's extended globbing feature to exclude the file you don't want:

shopt -s extglob
echo rm -- !(today).md

The above (after removing the echo for testing) says to match anything except today followed by .md.

Your example didn't match dot-files by default; you can change that behavior with shopt dotglob, if desired

Your script didn't work as written because the glob pattern you used (appropriately) prefixed the filenames with ./; therefore, your inner test should have compared against ./today.md.

edited 58 mins ago

answered 1 hour ago

Jeff Schaller

34.8k952115

You may find it shorter to use bash's extended globbing feature to exclude the file you don't want:

shopt -s extglob
echo rm -- !(today).md

The above (after removing the echo for testing) says to match anything except today followed by .md.

Your example didn't match dot-files by default; you can change that behavior with shopt dotglob, if desired

Your script didn't work as written because the glob pattern you used (appropriately) prefixed the filenames with ./; therefore, your inner test should have compared against ./today.md.

edited 58 mins ago

answered 1 hour ago

Jeff Schaller

34.8k952115

edited 58 mins ago

answered 1 hour ago

Jeff Schaller

34.8k952115

answered 1 hour ago

Jeff Schaller

34.8k952115

answered 1 hour ago

Jeff Schaller

34.8k952115

add a commentÂ |Â

up vote
1
down vote

The above are better solutions, but the reason your code isn't working is because of the comparison.

"./today.md" is not equal to "today.md".

answered 37 mins ago

user208145

1,08621115

add a commentÂ |Â

up vote
1
down vote

The above are better solutions, but the reason your code isn't working is because of the comparison.

"./today.md" is not equal to "today.md".

answered 37 mins ago

user208145

1,08621115

add a commentÂ |Â

up vote
1
down vote

The above are better solutions, but the reason your code isn't working is because of the comparison.

"./today.md" is not equal to "today.md".

answered 37 mins ago

user208145

1,08621115

The above are better solutions, but the reason your code isn't working is because of the comparison.

"./today.md" is not equal to "today.md".

answered 37 mins ago

user208145

1,08621115

answered 37 mins ago

user208145

1,08621115

answered 37 mins ago

user208145

1,08621115

answered 37 mins ago

user208145

1,08621115

add a commentÂ |Â

Sawajiri is a new contributor. Be nice, and check out our Code of Conduct.

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