How can I add lines to document every four lines?

up vote
4
down vote

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I want to add a new line every four lines of a document.

For example:

abc
def
ghi
jkl
mno
pqr
stu
vw
xyz

should become:

abc
def
ghi
jkl

mno 
pqr
stu
vw

xyz

edited 5 mins ago

Isaac

7,89711137

asked 40 mins ago

Advil

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up vote
4
down vote

favorite

I want to add a new line every four lines of a document.

For example:

abc
def
ghi
jkl
mno
pqr
stu
vw
xyz

should become:

abc
def
ghi
jkl

mno 
pqr
stu
vw

xyz

edited 5 mins ago

Isaac

7,89711137

asked 40 mins ago

Advil

211

New contributor

add a commentÂ |Â

up vote
4
down vote

favorite

I want to add a new line every four lines of a document.

For example:

abc
def
ghi
jkl
mno
pqr
stu
vw
xyz

should become:

abc
def
ghi
jkl

mno 
pqr
stu
vw

xyz

edited 5 mins ago

Isaac

7,89711137

asked 40 mins ago

Advil

211

New contributor

I want to add a new line every four lines of a document.

For example:

abc
def
ghi
jkl
mno
pqr
stu
vw
xyz

should become:

abc
def
ghi
jkl

mno 
pqr
stu
vw

xyz

text-processing

edited 5 mins ago

Isaac

7,89711137

asked 40 mins ago

Advil

211

New contributor

edited 5 mins ago

Isaac

7,89711137

asked 40 mins ago

Advil

211

New contributor

edited 5 mins ago

Isaac

7,89711137

edited 5 mins ago

Isaac

7,89711137

edited 5 mins ago

Isaac

7,89711137

asked 40 mins ago

Advil

211

New contributor

asked 40 mins ago

Advil

211

asked 40 mins ago

Advil

211

New contributor

Advil is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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2 Answers
2

active

oldest

votes

up vote
3
down vote

try this command:

awk ' print; NR % 4 == 0 print ""; '

answered 37 mins ago

Goro

7,72753371

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up vote
2
down vote

With (GNU) sed:

sed '0~4G'

man sed explains ~ as:

first ~ step

Match every step'th line starting with line first. For example, ``sed -n 1~2p'' will print all the odd-numbered lines in the input stream, and the address 2~5 will match every fifth line, starting with the second. first can be zero; in this case, sed operates as if it were equal to step. (This is an extension.)

With awk, probably:

awk '1 ; NR%4==0 printf"n" '

edited 4 mins ago

answered 31 mins ago

Isaac

7,89711137

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
3
down vote

try this command:

awk ' print; NR % 4 == 0 print ""; '

answered 37 mins ago

Goro

7,72753371

add a commentÂ |Â

up vote
3
down vote

try this command:

awk ' print; NR % 4 == 0 print ""; '

answered 37 mins ago

Goro

7,72753371

add a commentÂ |Â

up vote
3
down vote

try this command:

awk ' print; NR % 4 == 0 print ""; '

answered 37 mins ago

Goro

7,72753371

try this command:

awk ' print; NR % 4 == 0 print ""; '

answered 37 mins ago

Goro

7,72753371

answered 37 mins ago

Goro

7,72753371

answered 37 mins ago

Goro

7,72753371

answered 37 mins ago

Goro

7,72753371

add a commentÂ |Â

up vote
2
down vote

With (GNU) sed:

sed '0~4G'

man sed explains ~ as:

first ~ step

Match every step'th line starting with line first. For example, ``sed -n 1~2p'' will print all the odd-numbered lines in the input stream, and the address 2~5 will match every fifth line, starting with the second. first can be zero; in this case, sed operates as if it were equal to step. (This is an extension.)

With awk, probably:

awk '1 ; NR%4==0 printf"n" '

edited 4 mins ago

answered 31 mins ago

Isaac

7,89711137

add a commentÂ |Â

up vote
2
down vote

With (GNU) sed:

sed '0~4G'

man sed explains ~ as:

first ~ step

Match every step'th line starting with line first. For example, ``sed -n 1~2p'' will print all the odd-numbered lines in the input stream, and the address 2~5 will match every fifth line, starting with the second. first can be zero; in this case, sed operates as if it were equal to step. (This is an extension.)

With awk, probably:

awk '1 ; NR%4==0 printf"n" '

edited 4 mins ago

answered 31 mins ago

Isaac

7,89711137

add a commentÂ |Â

up vote
2
down vote

With (GNU) sed:

sed '0~4G'

man sed explains ~ as:

first ~ step

Match every step'th line starting with line first. For example, ``sed -n 1~2p'' will print all the odd-numbered lines in the input stream, and the address 2~5 will match every fifth line, starting with the second. first can be zero; in this case, sed operates as if it were equal to step. (This is an extension.)

With awk, probably:

awk '1 ; NR%4==0 printf"n" '

edited 4 mins ago

answered 31 mins ago

Isaac

7,89711137

With (GNU) sed:

sed '0~4G'

man sed explains ~ as:

first ~ step

Match every step'th line starting with line first. For example, ``sed -n 1~2p'' will print all the odd-numbered lines in the input stream, and the address 2~5 will match every fifth line, starting with the second. first can be zero; in this case, sed operates as if it were equal to step. (This is an extension.)

With awk, probably:

awk '1 ; NR%4==0 printf"n" '

edited 4 mins ago

answered 31 mins ago

Isaac

7,89711137

edited 4 mins ago

answered 31 mins ago

Isaac

7,89711137

answered 31 mins ago

Isaac

7,89711137

answered 31 mins ago

Isaac

7,89711137

add a commentÂ |Â

Advil is a new contributor. Be nice, and check out our Code of Conduct.

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