Defining abstract varieties and their morphisms over a finitely generated subfield of the base field

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Let $k$ be an algebraically closed field.
By a finitely generated subfield of $k$ I mean a subfield $k_0subset k$ that is finitely generated over the prime subfield of $k$ (that is, over $mathbb Q$ or $mathbb F_p$).



I need a reference or a proof for the following (well-known? evident?) proposition:




Proposition.
Let
$$fcolon Xto V$$
be a morphism of $k$-varieties.
Then the triple $(X,Y,f)$ can be defined over a finitely generated subfield of $k$.
In other words, there exists a finitely generated subfield $k_0subset k$
and a morphism of $k_0$-varieties
$$f_0colon X_0to Y_0$$
such that
$(X_0,Y_0,f_0)times_k_0 k$ is isomorphic to $(X,Y,f)$.




A referee asked me to prove this assertion. I know how to prove this for affine and projective varieties, but not for abstract varieties.










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    up vote
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    down vote

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    Let $k$ be an algebraically closed field.
    By a finitely generated subfield of $k$ I mean a subfield $k_0subset k$ that is finitely generated over the prime subfield of $k$ (that is, over $mathbb Q$ or $mathbb F_p$).



    I need a reference or a proof for the following (well-known? evident?) proposition:




    Proposition.
    Let
    $$fcolon Xto V$$
    be a morphism of $k$-varieties.
    Then the triple $(X,Y,f)$ can be defined over a finitely generated subfield of $k$.
    In other words, there exists a finitely generated subfield $k_0subset k$
    and a morphism of $k_0$-varieties
    $$f_0colon X_0to Y_0$$
    such that
    $(X_0,Y_0,f_0)times_k_0 k$ is isomorphic to $(X,Y,f)$.




    A referee asked me to prove this assertion. I know how to prove this for affine and projective varieties, but not for abstract varieties.










    share|cite|improve this question























      up vote
      3
      down vote

      favorite









      up vote
      3
      down vote

      favorite











      Let $k$ be an algebraically closed field.
      By a finitely generated subfield of $k$ I mean a subfield $k_0subset k$ that is finitely generated over the prime subfield of $k$ (that is, over $mathbb Q$ or $mathbb F_p$).



      I need a reference or a proof for the following (well-known? evident?) proposition:




      Proposition.
      Let
      $$fcolon Xto V$$
      be a morphism of $k$-varieties.
      Then the triple $(X,Y,f)$ can be defined over a finitely generated subfield of $k$.
      In other words, there exists a finitely generated subfield $k_0subset k$
      and a morphism of $k_0$-varieties
      $$f_0colon X_0to Y_0$$
      such that
      $(X_0,Y_0,f_0)times_k_0 k$ is isomorphic to $(X,Y,f)$.




      A referee asked me to prove this assertion. I know how to prove this for affine and projective varieties, but not for abstract varieties.










      share|cite|improve this question













      Let $k$ be an algebraically closed field.
      By a finitely generated subfield of $k$ I mean a subfield $k_0subset k$ that is finitely generated over the prime subfield of $k$ (that is, over $mathbb Q$ or $mathbb F_p$).



      I need a reference or a proof for the following (well-known? evident?) proposition:




      Proposition.
      Let
      $$fcolon Xto V$$
      be a morphism of $k$-varieties.
      Then the triple $(X,Y,f)$ can be defined over a finitely generated subfield of $k$.
      In other words, there exists a finitely generated subfield $k_0subset k$
      and a morphism of $k_0$-varieties
      $$f_0colon X_0to Y_0$$
      such that
      $(X_0,Y_0,f_0)times_k_0 k$ is isomorphic to $(X,Y,f)$.




      A referee asked me to prove this assertion. I know how to prove this for affine and projective varieties, but not for abstract varieties.







      ag.algebraic-geometry arithmetic-geometry schemes






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      asked 1 hour ago









      Mikhail Borovoi

      5,6541641




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          This is treated (in much greater generality) in EGA IV$_3$, Théorème 8.8.2. The existence of $X_0$ and $Y_0$ follows from part (ii), whereas the existence of $f_0$ is part (i).



          References.



          [EGA IV$_3$] A. Grothendieck, Éléments de géométrie algébrique. IV: Étude locale des schémas et des morphismes de schémas. (Troisième partie). Publ. Math., Inst. Hautes Étud. Sci. 28, 1-255 (1966). ZBL0144.19904. DOI: 10.1007/BF02684343






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            1 Answer
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            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            6
            down vote













            This is treated (in much greater generality) in EGA IV$_3$, Théorème 8.8.2. The existence of $X_0$ and $Y_0$ follows from part (ii), whereas the existence of $f_0$ is part (i).



            References.



            [EGA IV$_3$] A. Grothendieck, Éléments de géométrie algébrique. IV: Étude locale des schémas et des morphismes de schémas. (Troisième partie). Publ. Math., Inst. Hautes Étud. Sci. 28, 1-255 (1966). ZBL0144.19904. DOI: 10.1007/BF02684343






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              up vote
              6
              down vote













              This is treated (in much greater generality) in EGA IV$_3$, Théorème 8.8.2. The existence of $X_0$ and $Y_0$ follows from part (ii), whereas the existence of $f_0$ is part (i).



              References.



              [EGA IV$_3$] A. Grothendieck, Éléments de géométrie algébrique. IV: Étude locale des schémas et des morphismes de schémas. (Troisième partie). Publ. Math., Inst. Hautes Étud. Sci. 28, 1-255 (1966). ZBL0144.19904. DOI: 10.1007/BF02684343






              share|cite|improve this answer






















                up vote
                6
                down vote










                up vote
                6
                down vote









                This is treated (in much greater generality) in EGA IV$_3$, Théorème 8.8.2. The existence of $X_0$ and $Y_0$ follows from part (ii), whereas the existence of $f_0$ is part (i).



                References.



                [EGA IV$_3$] A. Grothendieck, Éléments de géométrie algébrique. IV: Étude locale des schémas et des morphismes de schémas. (Troisième partie). Publ. Math., Inst. Hautes Étud. Sci. 28, 1-255 (1966). ZBL0144.19904. DOI: 10.1007/BF02684343






                share|cite|improve this answer












                This is treated (in much greater generality) in EGA IV$_3$, Théorème 8.8.2. The existence of $X_0$ and $Y_0$ follows from part (ii), whereas the existence of $f_0$ is part (i).



                References.



                [EGA IV$_3$] A. Grothendieck, Éléments de géométrie algébrique. IV: Étude locale des schémas et des morphismes de schémas. (Troisième partie). Publ. Math., Inst. Hautes Étud. Sci. 28, 1-255 (1966). ZBL0144.19904. DOI: 10.1007/BF02684343







                share|cite|improve this answer












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                answered 54 mins ago









                R. van Dobben de Bruyn

                9,38122858




                9,38122858



























                     

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