One Point Compactification - Why just one?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
1
down vote

favorite












I'm reading about one point compactifcation in Munkres. I follow the proof saying that locally compact Hausdorff spaces have one point compactifications. However, I don't understand why the compactification only needs to be one point. Does the same idea work for finitely many added points (or even adding in countably many, or arbitrary amount of points) and assigning the appropriate topology?










share|cite|improve this question

















  • 1




    One point is enough, but you could throw in more. Do you doubt whether one is enough, or did you want to ask about cases where more are added to get a compact space?
    – hardmath
    4 hours ago










  • The latter - can you get compactification by adding more than one point? I'm guessing anything is possible with the appropriate topology. But I don't know if there's a more precise answer - I just learned this a couple hours ago.
    – yoshi
    4 hours ago






  • 1




    There are lots of natural compactifications. The two extremes are the 1-pt (minimal) and the Stone-Cech (maximal). But others, like the so-called "end-point compactification" may seem more natural and typically lie somewhere in between. Look 'em up.
    – MPW
    4 hours ago











  • Start with the compact unit disk and remove a couple of points from the boundary. Then the original compact disc is a compactification of the resulting space by as many points as you removed.
    – Hagen von Eitzen
    3 hours ago










  • Elsewhere in that book, you can read about the Stone-Cech compactification.
    – Lord Shark the Unknown
    1 hour ago














up vote
1
down vote

favorite












I'm reading about one point compactifcation in Munkres. I follow the proof saying that locally compact Hausdorff spaces have one point compactifications. However, I don't understand why the compactification only needs to be one point. Does the same idea work for finitely many added points (or even adding in countably many, or arbitrary amount of points) and assigning the appropriate topology?










share|cite|improve this question

















  • 1




    One point is enough, but you could throw in more. Do you doubt whether one is enough, or did you want to ask about cases where more are added to get a compact space?
    – hardmath
    4 hours ago










  • The latter - can you get compactification by adding more than one point? I'm guessing anything is possible with the appropriate topology. But I don't know if there's a more precise answer - I just learned this a couple hours ago.
    – yoshi
    4 hours ago






  • 1




    There are lots of natural compactifications. The two extremes are the 1-pt (minimal) and the Stone-Cech (maximal). But others, like the so-called "end-point compactification" may seem more natural and typically lie somewhere in between. Look 'em up.
    – MPW
    4 hours ago











  • Start with the compact unit disk and remove a couple of points from the boundary. Then the original compact disc is a compactification of the resulting space by as many points as you removed.
    – Hagen von Eitzen
    3 hours ago










  • Elsewhere in that book, you can read about the Stone-Cech compactification.
    – Lord Shark the Unknown
    1 hour ago












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm reading about one point compactifcation in Munkres. I follow the proof saying that locally compact Hausdorff spaces have one point compactifications. However, I don't understand why the compactification only needs to be one point. Does the same idea work for finitely many added points (or even adding in countably many, or arbitrary amount of points) and assigning the appropriate topology?










share|cite|improve this question













I'm reading about one point compactifcation in Munkres. I follow the proof saying that locally compact Hausdorff spaces have one point compactifications. However, I don't understand why the compactification only needs to be one point. Does the same idea work for finitely many added points (or even adding in countably many, or arbitrary amount of points) and assigning the appropriate topology?







general-topology






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 4 hours ago









yoshi

1,066817




1,066817







  • 1




    One point is enough, but you could throw in more. Do you doubt whether one is enough, or did you want to ask about cases where more are added to get a compact space?
    – hardmath
    4 hours ago










  • The latter - can you get compactification by adding more than one point? I'm guessing anything is possible with the appropriate topology. But I don't know if there's a more precise answer - I just learned this a couple hours ago.
    – yoshi
    4 hours ago






  • 1




    There are lots of natural compactifications. The two extremes are the 1-pt (minimal) and the Stone-Cech (maximal). But others, like the so-called "end-point compactification" may seem more natural and typically lie somewhere in between. Look 'em up.
    – MPW
    4 hours ago











  • Start with the compact unit disk and remove a couple of points from the boundary. Then the original compact disc is a compactification of the resulting space by as many points as you removed.
    – Hagen von Eitzen
    3 hours ago










  • Elsewhere in that book, you can read about the Stone-Cech compactification.
    – Lord Shark the Unknown
    1 hour ago












  • 1




    One point is enough, but you could throw in more. Do you doubt whether one is enough, or did you want to ask about cases where more are added to get a compact space?
    – hardmath
    4 hours ago










  • The latter - can you get compactification by adding more than one point? I'm guessing anything is possible with the appropriate topology. But I don't know if there's a more precise answer - I just learned this a couple hours ago.
    – yoshi
    4 hours ago






  • 1




    There are lots of natural compactifications. The two extremes are the 1-pt (minimal) and the Stone-Cech (maximal). But others, like the so-called "end-point compactification" may seem more natural and typically lie somewhere in between. Look 'em up.
    – MPW
    4 hours ago











  • Start with the compact unit disk and remove a couple of points from the boundary. Then the original compact disc is a compactification of the resulting space by as many points as you removed.
    – Hagen von Eitzen
    3 hours ago










  • Elsewhere in that book, you can read about the Stone-Cech compactification.
    – Lord Shark the Unknown
    1 hour ago







1




1




One point is enough, but you could throw in more. Do you doubt whether one is enough, or did you want to ask about cases where more are added to get a compact space?
– hardmath
4 hours ago




One point is enough, but you could throw in more. Do you doubt whether one is enough, or did you want to ask about cases where more are added to get a compact space?
– hardmath
4 hours ago












The latter - can you get compactification by adding more than one point? I'm guessing anything is possible with the appropriate topology. But I don't know if there's a more precise answer - I just learned this a couple hours ago.
– yoshi
4 hours ago




The latter - can you get compactification by adding more than one point? I'm guessing anything is possible with the appropriate topology. But I don't know if there's a more precise answer - I just learned this a couple hours ago.
– yoshi
4 hours ago




1




1




There are lots of natural compactifications. The two extremes are the 1-pt (minimal) and the Stone-Cech (maximal). But others, like the so-called "end-point compactification" may seem more natural and typically lie somewhere in between. Look 'em up.
– MPW
4 hours ago





There are lots of natural compactifications. The two extremes are the 1-pt (minimal) and the Stone-Cech (maximal). But others, like the so-called "end-point compactification" may seem more natural and typically lie somewhere in between. Look 'em up.
– MPW
4 hours ago













Start with the compact unit disk and remove a couple of points from the boundary. Then the original compact disc is a compactification of the resulting space by as many points as you removed.
– Hagen von Eitzen
3 hours ago




Start with the compact unit disk and remove a couple of points from the boundary. Then the original compact disc is a compactification of the resulting space by as many points as you removed.
– Hagen von Eitzen
3 hours ago












Elsewhere in that book, you can read about the Stone-Cech compactification.
– Lord Shark the Unknown
1 hour ago




Elsewhere in that book, you can read about the Stone-Cech compactification.
– Lord Shark the Unknown
1 hour ago










1 Answer
1






active

oldest

votes

















up vote
5
down vote



accepted










It does not need one point. One point suffices to compactify a locally compact space. A compactification can add a lot of extra points (extreme examples are some Cech Stone compactifications) but locally compact spaces are special because they alone have a "minimal compactification". Having only one point in this so-called "remainder" (the "extra point(s)" we have added) is often handy (we can easily extend some continuous functions from $X$ to its one-point compactification e.g., which is used in functional analysis etc) and intuitive (Riemann sphere for the complex plane e.g.). If a space has a compactification with a closed remainder (e.g. a finite one) then $X$ must have been a locally compact (as $X$ is then homeomorphic to an open subset of a compact (Hausdorff) space to start with.






share|cite|improve this answer




















    Your Answer




    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "69"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: true,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2943815%2fone-point-compactification-why-just-one%23new-answer', 'question_page');

    );

    Post as a guest






























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    5
    down vote



    accepted










    It does not need one point. One point suffices to compactify a locally compact space. A compactification can add a lot of extra points (extreme examples are some Cech Stone compactifications) but locally compact spaces are special because they alone have a "minimal compactification". Having only one point in this so-called "remainder" (the "extra point(s)" we have added) is often handy (we can easily extend some continuous functions from $X$ to its one-point compactification e.g., which is used in functional analysis etc) and intuitive (Riemann sphere for the complex plane e.g.). If a space has a compactification with a closed remainder (e.g. a finite one) then $X$ must have been a locally compact (as $X$ is then homeomorphic to an open subset of a compact (Hausdorff) space to start with.






    share|cite|improve this answer
























      up vote
      5
      down vote



      accepted










      It does not need one point. One point suffices to compactify a locally compact space. A compactification can add a lot of extra points (extreme examples are some Cech Stone compactifications) but locally compact spaces are special because they alone have a "minimal compactification". Having only one point in this so-called "remainder" (the "extra point(s)" we have added) is often handy (we can easily extend some continuous functions from $X$ to its one-point compactification e.g., which is used in functional analysis etc) and intuitive (Riemann sphere for the complex plane e.g.). If a space has a compactification with a closed remainder (e.g. a finite one) then $X$ must have been a locally compact (as $X$ is then homeomorphic to an open subset of a compact (Hausdorff) space to start with.






      share|cite|improve this answer






















        up vote
        5
        down vote



        accepted







        up vote
        5
        down vote



        accepted






        It does not need one point. One point suffices to compactify a locally compact space. A compactification can add a lot of extra points (extreme examples are some Cech Stone compactifications) but locally compact spaces are special because they alone have a "minimal compactification". Having only one point in this so-called "remainder" (the "extra point(s)" we have added) is often handy (we can easily extend some continuous functions from $X$ to its one-point compactification e.g., which is used in functional analysis etc) and intuitive (Riemann sphere for the complex plane e.g.). If a space has a compactification with a closed remainder (e.g. a finite one) then $X$ must have been a locally compact (as $X$ is then homeomorphic to an open subset of a compact (Hausdorff) space to start with.






        share|cite|improve this answer












        It does not need one point. One point suffices to compactify a locally compact space. A compactification can add a lot of extra points (extreme examples are some Cech Stone compactifications) but locally compact spaces are special because they alone have a "minimal compactification". Having only one point in this so-called "remainder" (the "extra point(s)" we have added) is often handy (we can easily extend some continuous functions from $X$ to its one-point compactification e.g., which is used in functional analysis etc) and intuitive (Riemann sphere for the complex plane e.g.). If a space has a compactification with a closed remainder (e.g. a finite one) then $X$ must have been a locally compact (as $X$ is then homeomorphic to an open subset of a compact (Hausdorff) space to start with.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 4 hours ago









        Henno Brandsma

        95.8k343104




        95.8k343104



























             

            draft saved


            draft discarded















































             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f2943815%2fone-point-compactification-why-just-one%23new-answer', 'question_page');

            );

            Post as a guest













































































            Comments

            Popular posts from this blog

            Long meetings (6-7 hours a day): Being “babysat” by supervisor

            Is the Concept of Multiple Fantasy Races Scientifically Flawed? [closed]

            Confectionery