Why mixing of colors in paint is black, but mixing of light is white?

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
20
down vote

favorite
4












Mixing of different wavelengths of light results in white, but why is that when paint with different colors are mix results in black?










share|cite|improve this question

















  • 15




    Are you familiar with the additive / subtractive color distinction?
    – Alfred Centauri
    15 hours ago






  • 4




    Just to add to existing answers (not an answer itself) - this is precisely why monitors that produce light use RGB palette while print uses CMY(K). CMY is actually subtracting RGB - if you subtract from white light Red, Green or Blue you get respectively Yellow, Magenta or Cyan. So you're also operating on the same principle of applying the change to only one colour respective to one of the cone types in our eyes at a time. Contrast is added as there are always some wavelengths deflected even if you mix all 3 paints. Thus adding a black to the pallete helps to resolve that (to some level).
    – Ister
    7 hours ago














up vote
20
down vote

favorite
4












Mixing of different wavelengths of light results in white, but why is that when paint with different colors are mix results in black?










share|cite|improve this question

















  • 15




    Are you familiar with the additive / subtractive color distinction?
    – Alfred Centauri
    15 hours ago






  • 4




    Just to add to existing answers (not an answer itself) - this is precisely why monitors that produce light use RGB palette while print uses CMY(K). CMY is actually subtracting RGB - if you subtract from white light Red, Green or Blue you get respectively Yellow, Magenta or Cyan. So you're also operating on the same principle of applying the change to only one colour respective to one of the cone types in our eyes at a time. Contrast is added as there are always some wavelengths deflected even if you mix all 3 paints. Thus adding a black to the pallete helps to resolve that (to some level).
    – Ister
    7 hours ago












up vote
20
down vote

favorite
4









up vote
20
down vote

favorite
4






4





Mixing of different wavelengths of light results in white, but why is that when paint with different colors are mix results in black?










share|cite|improve this question













Mixing of different wavelengths of light results in white, but why is that when paint with different colors are mix results in black?







visible-light photons






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 15 hours ago









Zirc

1067




1067







  • 15




    Are you familiar with the additive / subtractive color distinction?
    – Alfred Centauri
    15 hours ago






  • 4




    Just to add to existing answers (not an answer itself) - this is precisely why monitors that produce light use RGB palette while print uses CMY(K). CMY is actually subtracting RGB - if you subtract from white light Red, Green or Blue you get respectively Yellow, Magenta or Cyan. So you're also operating on the same principle of applying the change to only one colour respective to one of the cone types in our eyes at a time. Contrast is added as there are always some wavelengths deflected even if you mix all 3 paints. Thus adding a black to the pallete helps to resolve that (to some level).
    – Ister
    7 hours ago












  • 15




    Are you familiar with the additive / subtractive color distinction?
    – Alfred Centauri
    15 hours ago






  • 4




    Just to add to existing answers (not an answer itself) - this is precisely why monitors that produce light use RGB palette while print uses CMY(K). CMY is actually subtracting RGB - if you subtract from white light Red, Green or Blue you get respectively Yellow, Magenta or Cyan. So you're also operating on the same principle of applying the change to only one colour respective to one of the cone types in our eyes at a time. Contrast is added as there are always some wavelengths deflected even if you mix all 3 paints. Thus adding a black to the pallete helps to resolve that (to some level).
    – Ister
    7 hours ago







15




15




Are you familiar with the additive / subtractive color distinction?
– Alfred Centauri
15 hours ago




Are you familiar with the additive / subtractive color distinction?
– Alfred Centauri
15 hours ago




4




4




Just to add to existing answers (not an answer itself) - this is precisely why monitors that produce light use RGB palette while print uses CMY(K). CMY is actually subtracting RGB - if you subtract from white light Red, Green or Blue you get respectively Yellow, Magenta or Cyan. So you're also operating on the same principle of applying the change to only one colour respective to one of the cone types in our eyes at a time. Contrast is added as there are always some wavelengths deflected even if you mix all 3 paints. Thus adding a black to the pallete helps to resolve that (to some level).
– Ister
7 hours ago




Just to add to existing answers (not an answer itself) - this is precisely why monitors that produce light use RGB palette while print uses CMY(K). CMY is actually subtracting RGB - if you subtract from white light Red, Green or Blue you get respectively Yellow, Magenta or Cyan. So you're also operating on the same principle of applying the change to only one colour respective to one of the cone types in our eyes at a time. Contrast is added as there are always some wavelengths deflected even if you mix all 3 paints. Thus adding a black to the pallete helps to resolve that (to some level).
– Ister
7 hours ago










2 Answers
2






active

oldest

votes

















up vote
34
down vote



accepted










Mixing light does result in white, but this happens due to how paint works. Paint has color not because it's emitting light, but because it's absorbing colors other than the one that's supposed to be the paint's color. As such, when you mix paints, they absorb more and more of the spectrum, resulting in black.






share|cite|improve this answer
















  • 1




    What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
    – LLlAMnYP
    5 hours ago






  • 1




    @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
    – Gabriel Golfetti
    5 hours ago






  • 2




    You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
    – orion
    2 hours ago


















up vote
13
down vote













Mixing light is additive since you are adding electromagnetic waves with different wavelengths together.



The color of materials as paint relies on a different principle. Only certain wavelengths of the impinging light get scattered back and the rest gets absorbed. For example, red paint only scatters back the red wavelengths and absorbs the others. (This also means if you light the red paint with blue light, you will not see much). Now if you mix all colors of paint, the whole (visible) spectrum of the impinging light will get absorbed. Hence, paint is subtractive.
(This is also the reason why black paint gets warmer than white paint; the absorbed light is converted into heat energy).






share|cite|improve this answer




















    Your Answer




    StackExchange.ifUsing("editor", function ()
    return StackExchange.using("mathjaxEditing", function ()
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    );
    );
    , "mathjax-editing");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "151"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    convertImagesToLinks: false,
    noModals: false,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













     

    draft saved


    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f428402%2fwhy-mixing-of-colors-in-paint-is-black-but-mixing-of-light-is-white%23new-answer', 'question_page');

    );

    Post as a guest






























    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    34
    down vote



    accepted










    Mixing light does result in white, but this happens due to how paint works. Paint has color not because it's emitting light, but because it's absorbing colors other than the one that's supposed to be the paint's color. As such, when you mix paints, they absorb more and more of the spectrum, resulting in black.






    share|cite|improve this answer
















    • 1




      What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
      – LLlAMnYP
      5 hours ago






    • 1




      @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
      – Gabriel Golfetti
      5 hours ago






    • 2




      You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
      – orion
      2 hours ago















    up vote
    34
    down vote



    accepted










    Mixing light does result in white, but this happens due to how paint works. Paint has color not because it's emitting light, but because it's absorbing colors other than the one that's supposed to be the paint's color. As such, when you mix paints, they absorb more and more of the spectrum, resulting in black.






    share|cite|improve this answer
















    • 1




      What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
      – LLlAMnYP
      5 hours ago






    • 1




      @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
      – Gabriel Golfetti
      5 hours ago






    • 2




      You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
      – orion
      2 hours ago













    up vote
    34
    down vote



    accepted







    up vote
    34
    down vote



    accepted






    Mixing light does result in white, but this happens due to how paint works. Paint has color not because it's emitting light, but because it's absorbing colors other than the one that's supposed to be the paint's color. As such, when you mix paints, they absorb more and more of the spectrum, resulting in black.






    share|cite|improve this answer












    Mixing light does result in white, but this happens due to how paint works. Paint has color not because it's emitting light, but because it's absorbing colors other than the one that's supposed to be the paint's color. As such, when you mix paints, they absorb more and more of the spectrum, resulting in black.







    share|cite|improve this answer












    share|cite|improve this answer



    share|cite|improve this answer










    answered 15 hours ago









    Gabriel Golfetti

    971413




    971413







    • 1




      What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
      – LLlAMnYP
      5 hours ago






    • 1




      @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
      – Gabriel Golfetti
      5 hours ago






    • 2




      You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
      – orion
      2 hours ago













    • 1




      What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
      – LLlAMnYP
      5 hours ago






    • 1




      @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
      – Gabriel Golfetti
      5 hours ago






    • 2




      You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
      – orion
      2 hours ago








    1




    1




    What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
    – LLlAMnYP
    5 hours ago




    What is not immediately obvious, is that one paint reflects one color, another reflects another, so shouldn't a mix of paints reflect all colors, resulting in white?
    – LLlAMnYP
    5 hours ago




    1




    1




    @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
    – Gabriel Golfetti
    5 hours ago




    @LLlAMnYP Good point, and it's almost what happens. If you could plot a spectrum of the reflected light, it would be almost perfectly balanced. But the thing is, so much energy is absorbed by the paint that it barely reflects enough power at all. A very dim white light is just gray (i.e. black).
    – Gabriel Golfetti
    5 hours ago




    2




    2




    You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
    – orion
    2 hours ago





    You can get both. If you are mixing paints, then what one doesn't aborb, another one does (so they just take away incrementally from the same light until nothing is left). But if you put pixels of different colors side by side, you get halftone printing, and you see average colour, which is the same hue, but brighter because none of the dots absorbs it all. However one has to be careful about mixing and black colour: the subtractive mixing model breaks down at high concentrations - it's no longer linear, and you usually get brownish tone.
    – orion
    2 hours ago











    up vote
    13
    down vote













    Mixing light is additive since you are adding electromagnetic waves with different wavelengths together.



    The color of materials as paint relies on a different principle. Only certain wavelengths of the impinging light get scattered back and the rest gets absorbed. For example, red paint only scatters back the red wavelengths and absorbs the others. (This also means if you light the red paint with blue light, you will not see much). Now if you mix all colors of paint, the whole (visible) spectrum of the impinging light will get absorbed. Hence, paint is subtractive.
    (This is also the reason why black paint gets warmer than white paint; the absorbed light is converted into heat energy).






    share|cite|improve this answer
























      up vote
      13
      down vote













      Mixing light is additive since you are adding electromagnetic waves with different wavelengths together.



      The color of materials as paint relies on a different principle. Only certain wavelengths of the impinging light get scattered back and the rest gets absorbed. For example, red paint only scatters back the red wavelengths and absorbs the others. (This also means if you light the red paint with blue light, you will not see much). Now if you mix all colors of paint, the whole (visible) spectrum of the impinging light will get absorbed. Hence, paint is subtractive.
      (This is also the reason why black paint gets warmer than white paint; the absorbed light is converted into heat energy).






      share|cite|improve this answer






















        up vote
        13
        down vote










        up vote
        13
        down vote









        Mixing light is additive since you are adding electromagnetic waves with different wavelengths together.



        The color of materials as paint relies on a different principle. Only certain wavelengths of the impinging light get scattered back and the rest gets absorbed. For example, red paint only scatters back the red wavelengths and absorbs the others. (This also means if you light the red paint with blue light, you will not see much). Now if you mix all colors of paint, the whole (visible) spectrum of the impinging light will get absorbed. Hence, paint is subtractive.
        (This is also the reason why black paint gets warmer than white paint; the absorbed light is converted into heat energy).






        share|cite|improve this answer












        Mixing light is additive since you are adding electromagnetic waves with different wavelengths together.



        The color of materials as paint relies on a different principle. Only certain wavelengths of the impinging light get scattered back and the rest gets absorbed. For example, red paint only scatters back the red wavelengths and absorbs the others. (This also means if you light the red paint with blue light, you will not see much). Now if you mix all colors of paint, the whole (visible) spectrum of the impinging light will get absorbed. Hence, paint is subtractive.
        (This is also the reason why black paint gets warmer than white paint; the absorbed light is converted into heat energy).







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered 14 hours ago









        EuklidAlexandria

        43718




        43718



























             

            draft saved


            draft discarded















































             


            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f428402%2fwhy-mixing-of-colors-in-paint-is-black-but-mixing-of-light-is-white%23new-answer', 'question_page');

            );

            Post as a guest













































































            Comments

            Popular posts from this blog

            What does second last employer means? [closed]

            List of Gilmore Girls characters

            One-line joke