calculated Voltage explanation

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The blue highlighted values are the answers, but can sombody explain how my teacher got 120v for the 4k resistor and 60v for the 2k resistor? the only one I could figure out is the right side where I showed 1 calcuation....



circuit



I was running through practice problems that my teacher provided for us to prep for the coming exam... but I cant understand how he came to those voltage values.



Thank you in advance.






circuit-analysis







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    up vote
    1
    down vote

    favorite












    The blue highlighted values are the answers, but can sombody explain how my teacher got 120v for the 4k resistor and 60v for the 2k resistor? the only one I could figure out is the right side where I showed 1 calcuation....



    circuit



    I was running through practice problems that my teacher provided for us to prep for the coming exam... but I cant understand how he came to those voltage values.



    Thank you in advance.






    circuit-analysis







    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      The blue highlighted values are the answers, but can sombody explain how my teacher got 120v for the 4k resistor and 60v for the 2k resistor? the only one I could figure out is the right side where I showed 1 calcuation....



      circuit



      I was running through practice problems that my teacher provided for us to prep for the coming exam... but I cant understand how he came to those voltage values.



      Thank you in advance.






      circuit-analysis







      share|improve this question













      The blue highlighted values are the answers, but can sombody explain how my teacher got 120v for the 4k resistor and 60v for the 2k resistor? the only one I could figure out is the right side where I showed 1 calcuation....



      circuit



      I was running through practice problems that my teacher provided for us to prep for the coming exam... but I cant understand how he came to those voltage values.



      Thank you in advance.






      circuit-analysis




      circuit-analysis






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      asked 1 hour ago









      LKim

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          If two resistors are in series then they have the same current. Also, the $30mA$ current source is in series with the $2kOmega$ and $4kOmega$ resistors. Therefore the $4kOmega$ resistor has $30mA$. By Ohm's Law $4kOmega * 30mA = 120V$. Likewise for the $2kOmega$ resistor: $2kOmega * 30mA = 60V$.






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            1 Answer
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            If two resistors are in series then they have the same current. Also, the $30mA$ current source is in series with the $2kOmega$ and $4kOmega$ resistors. Therefore the $4kOmega$ resistor has $30mA$. By Ohm's Law $4kOmega * 30mA = 120V$. Likewise for the $2kOmega$ resistor: $2kOmega * 30mA = 60V$.






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              up vote
              2
              down vote



              accepted










              If two resistors are in series then they have the same current. Also, the $30mA$ current source is in series with the $2kOmega$ and $4kOmega$ resistors. Therefore the $4kOmega$ resistor has $30mA$. By Ohm's Law $4kOmega * 30mA = 120V$. Likewise for the $2kOmega$ resistor: $2kOmega * 30mA = 60V$.






              share|improve this answer






















                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                If two resistors are in series then they have the same current. Also, the $30mA$ current source is in series with the $2kOmega$ and $4kOmega$ resistors. Therefore the $4kOmega$ resistor has $30mA$. By Ohm's Law $4kOmega * 30mA = 120V$. Likewise for the $2kOmega$ resistor: $2kOmega * 30mA = 60V$.






                share|improve this answer












                If two resistors are in series then they have the same current. Also, the $30mA$ current source is in series with the $2kOmega$ and $4kOmega$ resistors. Therefore the $4kOmega$ resistor has $30mA$. By Ohm's Law $4kOmega * 30mA = 120V$. Likewise for the $2kOmega$ resistor: $2kOmega * 30mA = 60V$.







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                answered 1 hour ago









                DavOS

                16911




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