Algebras: Homology vs. Resolution as a dg-algebra

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
2
down vote

favorite












My question is what is the relation (if any) between the following two notions.



  1. Starting from an augmented algebra $A$ over a field $k$, one way to compute the homology of $A$ is to find a projective resolution of $k$ as an $A$-module.


  2. On the other hand, one could also see $A$ as a (let's say positively graded) dg-algebra (concentrated in degree 0), and take a cofibrant replacement of $A$ in this category, using the projective model structure.


Both notions give some notions homotopical information about $A$, and I would be interested in knowing if it is possible to deduce one from the other (presumably, to recover a resolution of $k$ from a cofibrant replacement of $A$), at least in "good" cases.



The reason I ask is because I have two very similar constructions building these objects for suitable algebras, and I am wondering whether one of these constructions can be deduced from the other one.










share|cite|improve this question

















  • 1




    You mean the Hochschild homology of $A$?
    – Najib Idrissi
    3 hours ago














up vote
2
down vote

favorite












My question is what is the relation (if any) between the following two notions.



  1. Starting from an augmented algebra $A$ over a field $k$, one way to compute the homology of $A$ is to find a projective resolution of $k$ as an $A$-module.


  2. On the other hand, one could also see $A$ as a (let's say positively graded) dg-algebra (concentrated in degree 0), and take a cofibrant replacement of $A$ in this category, using the projective model structure.


Both notions give some notions homotopical information about $A$, and I would be interested in knowing if it is possible to deduce one from the other (presumably, to recover a resolution of $k$ from a cofibrant replacement of $A$), at least in "good" cases.



The reason I ask is because I have two very similar constructions building these objects for suitable algebras, and I am wondering whether one of these constructions can be deduced from the other one.










share|cite|improve this question

















  • 1




    You mean the Hochschild homology of $A$?
    – Najib Idrissi
    3 hours ago












up vote
2
down vote

favorite









up vote
2
down vote

favorite











My question is what is the relation (if any) between the following two notions.



  1. Starting from an augmented algebra $A$ over a field $k$, one way to compute the homology of $A$ is to find a projective resolution of $k$ as an $A$-module.


  2. On the other hand, one could also see $A$ as a (let's say positively graded) dg-algebra (concentrated in degree 0), and take a cofibrant replacement of $A$ in this category, using the projective model structure.


Both notions give some notions homotopical information about $A$, and I would be interested in knowing if it is possible to deduce one from the other (presumably, to recover a resolution of $k$ from a cofibrant replacement of $A$), at least in "good" cases.



The reason I ask is because I have two very similar constructions building these objects for suitable algebras, and I am wondering whether one of these constructions can be deduced from the other one.










share|cite|improve this question













My question is what is the relation (if any) between the following two notions.



  1. Starting from an augmented algebra $A$ over a field $k$, one way to compute the homology of $A$ is to find a projective resolution of $k$ as an $A$-module.


  2. On the other hand, one could also see $A$ as a (let's say positively graded) dg-algebra (concentrated in degree 0), and take a cofibrant replacement of $A$ in this category, using the projective model structure.


Both notions give some notions homotopical information about $A$, and I would be interested in knowing if it is possible to deduce one from the other (presumably, to recover a resolution of $k$ from a cofibrant replacement of $A$), at least in "good" cases.



The reason I ask is because I have two very similar constructions building these objects for suitable algebras, and I am wondering whether one of these constructions can be deduced from the other one.







homological-algebra dg-algebras






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 4 hours ago









Maxime Lucas

388113




388113







  • 1




    You mean the Hochschild homology of $A$?
    – Najib Idrissi
    3 hours ago












  • 1




    You mean the Hochschild homology of $A$?
    – Najib Idrissi
    3 hours ago







1




1




You mean the Hochschild homology of $A$?
– Najib Idrissi
3 hours ago




You mean the Hochschild homology of $A$?
– Najib Idrissi
3 hours ago










1 Answer
1






active

oldest

votes

















up vote
5
down vote



accepted










From your first description, I guess that what you call "the homology of $A$" is in fact the Hochschild homology of $A$ with constant coefficients, i.e. $HH_*(A;k)$. Please tell me if I got this wrong.



Then yes, it's possible to compute it from a projective resolution of $A$. Suppose that $R xrightarrowsim A$ is a projective resolution of $A$. Let $Omega_R$ be the $R$-module of Kähler differentials. Then you can compute the Hochschild homology of $A$ as the André–Quillen homology, i.e. the homology of the complex:
$$k otimes_A otimes A^op (A otimes_R Omega_R).$$
The object $mathbbL_R/A = A otimes_R Omega_R$ is called the cotangent complex of $A$.






share|cite|improve this answer




















  • PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
    – Najib Idrissi
    3 hours ago











  • This seems to be exactly what I was looking for. Thank you very much!
    – Maxime Lucas
    2 hours ago










Your Answer




StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "504"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f312022%2falgebras-homology-vs-resolution-as-a-dg-algebra%23new-answer', 'question_page');

);

Post as a guest






























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
5
down vote



accepted










From your first description, I guess that what you call "the homology of $A$" is in fact the Hochschild homology of $A$ with constant coefficients, i.e. $HH_*(A;k)$. Please tell me if I got this wrong.



Then yes, it's possible to compute it from a projective resolution of $A$. Suppose that $R xrightarrowsim A$ is a projective resolution of $A$. Let $Omega_R$ be the $R$-module of Kähler differentials. Then you can compute the Hochschild homology of $A$ as the André–Quillen homology, i.e. the homology of the complex:
$$k otimes_A otimes A^op (A otimes_R Omega_R).$$
The object $mathbbL_R/A = A otimes_R Omega_R$ is called the cotangent complex of $A$.






share|cite|improve this answer




















  • PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
    – Najib Idrissi
    3 hours ago











  • This seems to be exactly what I was looking for. Thank you very much!
    – Maxime Lucas
    2 hours ago














up vote
5
down vote



accepted










From your first description, I guess that what you call "the homology of $A$" is in fact the Hochschild homology of $A$ with constant coefficients, i.e. $HH_*(A;k)$. Please tell me if I got this wrong.



Then yes, it's possible to compute it from a projective resolution of $A$. Suppose that $R xrightarrowsim A$ is a projective resolution of $A$. Let $Omega_R$ be the $R$-module of Kähler differentials. Then you can compute the Hochschild homology of $A$ as the André–Quillen homology, i.e. the homology of the complex:
$$k otimes_A otimes A^op (A otimes_R Omega_R).$$
The object $mathbbL_R/A = A otimes_R Omega_R$ is called the cotangent complex of $A$.






share|cite|improve this answer




















  • PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
    – Najib Idrissi
    3 hours ago











  • This seems to be exactly what I was looking for. Thank you very much!
    – Maxime Lucas
    2 hours ago












up vote
5
down vote



accepted







up vote
5
down vote



accepted






From your first description, I guess that what you call "the homology of $A$" is in fact the Hochschild homology of $A$ with constant coefficients, i.e. $HH_*(A;k)$. Please tell me if I got this wrong.



Then yes, it's possible to compute it from a projective resolution of $A$. Suppose that $R xrightarrowsim A$ is a projective resolution of $A$. Let $Omega_R$ be the $R$-module of Kähler differentials. Then you can compute the Hochschild homology of $A$ as the André–Quillen homology, i.e. the homology of the complex:
$$k otimes_A otimes A^op (A otimes_R Omega_R).$$
The object $mathbbL_R/A = A otimes_R Omega_R$ is called the cotangent complex of $A$.






share|cite|improve this answer












From your first description, I guess that what you call "the homology of $A$" is in fact the Hochschild homology of $A$ with constant coefficients, i.e. $HH_*(A;k)$. Please tell me if I got this wrong.



Then yes, it's possible to compute it from a projective resolution of $A$. Suppose that $R xrightarrowsim A$ is a projective resolution of $A$. Let $Omega_R$ be the $R$-module of Kähler differentials. Then you can compute the Hochschild homology of $A$ as the André–Quillen homology, i.e. the homology of the complex:
$$k otimes_A otimes A^op (A otimes_R Omega_R).$$
The object $mathbbL_R/A = A otimes_R Omega_R$ is called the cotangent complex of $A$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered 3 hours ago









Najib Idrissi

1,3511026




1,3511026











  • PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
    – Najib Idrissi
    3 hours ago











  • This seems to be exactly what I was looking for. Thank you very much!
    – Maxime Lucas
    2 hours ago
















  • PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
    – Najib Idrissi
    3 hours ago











  • This seems to be exactly what I was looking for. Thank you very much!
    – Maxime Lucas
    2 hours ago















PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
– Najib Idrissi
3 hours ago





PS: it works for any operad. You can compute the Harrison homology of a commutative algebra, the Chevalley–Eilenberg homology of a Lie algebra, etc, as the analogue of the André–Quillen homology. See e.g. Chapter 12 of the book Algebraic Operads (Loday & Vallette) and the references therein.
– Najib Idrissi
3 hours ago













This seems to be exactly what I was looking for. Thank you very much!
– Maxime Lucas
2 hours ago




This seems to be exactly what I was looking for. Thank you very much!
– Maxime Lucas
2 hours ago

















 

draft saved


draft discarded















































 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathoverflow.net%2fquestions%2f312022%2falgebras-homology-vs-resolution-as-a-dg-algebra%23new-answer', 'question_page');

);

Post as a guest













































































Comments

Popular posts from this blog

What does second last employer means? [closed]

Installing NextGIS Connect into QGIS 3?

One-line joke