What does 'driving force of the engine' mean?

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I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?

homework-and-exercises newtonian-mechanics forces acceleration

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up vote
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I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?

homework-and-exercises newtonian-mechanics forces acceleration

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edited 1 hour ago

Chair

3,23151933

asked 1 hour ago

Tfue

61

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Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
1
down vote

favorite

up vote
1
down vote

favorite

I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?

homework-and-exercises newtonian-mechanics forces acceleration

share|cite|improve this question

edited 1 hour ago

Chair

3,23151933

asked 1 hour ago

Tfue

61

New contributor

Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

I am given this question: A truck of mass $2000 rm kg$ accelerates from $5 rm m/s$ to $20 rm m/s$ in $5 rm s$. Then i am asked to find the driving force of the engine. So, what does driving force means and is there a difference between finding a force and finding a driving force?

homework-and-exercises newtonian-mechanics forces acceleration

homework-and-exercises newtonian-mechanics forces acceleration

share|cite|improve this question

edited 1 hour ago

Chair

3,23151933

asked 1 hour ago

Tfue

61

New contributor

Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|cite|improve this question

edited 1 hour ago

Chair

3,23151933

asked 1 hour ago

Tfue

61

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Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|cite|improve this question

share|cite|improve this question

edited 1 hour ago

Chair

3,23151933

edited 1 hour ago

Chair

3,23151933

edited 1 hour ago

Chair

3,23151933

3,23151933

asked 1 hour ago

Tfue

61

New contributor

Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

Tfue

61

asked 1 hour ago

Tfue

61

61

New contributor

Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Tfue is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

add a comment | 

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You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.

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answered 1 hour ago

Buzz

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
2
down vote

You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.

share|cite|improve this answer

answered 1 hour ago

Buzz

2,80821321

add a comment | 

up vote
2
down vote

You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.

share|cite|improve this answer

answered 1 hour ago

Buzz

2,80821321

add a comment | 

up vote
2
down vote

up vote
2
down vote

You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.

share|cite|improve this answer

answered 1 hour ago

Buzz

2,80821321

You are just supposed to find the force $F$ that is responsible for accelerating the truck, $F=ma$. The presence of "driving" does not really contribute anything here.

share|cite|improve this answer

answered 1 hour ago

Buzz

2,80821321

share|cite|improve this answer

share|cite|improve this answer

answered 1 hour ago

Buzz

2,80821321

answered 1 hour ago

Buzz

2,80821321

answered 1 hour ago

Buzz

2,80821321

2,80821321

add a comment | 

add a comment | 

Tfue is a new contributor. Be nice, and check out our Code of Conduct.

 

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