Simple puts() function in x64 assembly

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I'm trying to write as simple I/O library in x64 using linux syscalls



section .text
strlen:
xor rdx, rdx
.loop:
cmp [rsi + rdx], 0
je .exit
inc rdx
jmp .loop
.exit:
ret ; value in rdx

puts:
; string passed through rsi
mov rax, 1 ; WRITE syscall
mov rdi, 1 ; fd for stdout
call strlen
syscall









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    up vote
    2
    down vote

    favorite












    I'm trying to write as simple I/O library in x64 using linux syscalls



    section .text
    strlen:
    xor rdx, rdx
    .loop:
    cmp [rsi + rdx], 0
    je .exit
    inc rdx
    jmp .loop
    .exit:
    ret ; value in rdx

    puts:
    ; string passed through rsi
    mov rax, 1 ; WRITE syscall
    mov rdi, 1 ; fd for stdout
    call strlen
    syscall









    share|improve this question

























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I'm trying to write as simple I/O library in x64 using linux syscalls



      section .text
      strlen:
      xor rdx, rdx
      .loop:
      cmp [rsi + rdx], 0
      je .exit
      inc rdx
      jmp .loop
      .exit:
      ret ; value in rdx

      puts:
      ; string passed through rsi
      mov rax, 1 ; WRITE syscall
      mov rdi, 1 ; fd for stdout
      call strlen
      syscall









      share|improve this question















      I'm trying to write as simple I/O library in x64 using linux syscalls



      section .text
      strlen:
      xor rdx, rdx
      .loop:
      cmp [rsi + rdx], 0
      je .exit
      inc rdx
      jmp .loop
      .exit:
      ret ; value in rdx

      puts:
      ; string passed through rsi
      mov rax, 1 ; WRITE syscall
      mov rdi, 1 ; fd for stdout
      call strlen
      syscall






      strings io linux assembly x86






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      edited 16 mins ago

























      asked 4 hours ago









      Meme myself and a very creepy

      514




      514




















          1 Answer
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          up vote
          2
          down vote













          Your loop uses 2 jumps (je/jmp) on every iteration! Jumping is expensive, so a solution that needs only 1 jump (jne) will be more effective.



          strlen:
          xor rdx, rdx
          dec rdx ; This compensates for the INC that is happening first.
          .next:
          inc rdx
          cmp byte [rsi + rdx], 0
          jne .next
          ret



          Do keep things logically together. There's no point in setting RAX before the call to strlen.



          puts:
          ; string passed through rsi
          call strlen ; Result is in RDX

          mov rax, 1
          syscall





          share|improve this answer




















          • Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
            – Meme myself and a very creepy
            19 mins ago











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          up vote
          2
          down vote













          Your loop uses 2 jumps (je/jmp) on every iteration! Jumping is expensive, so a solution that needs only 1 jump (jne) will be more effective.



          strlen:
          xor rdx, rdx
          dec rdx ; This compensates for the INC that is happening first.
          .next:
          inc rdx
          cmp byte [rsi + rdx], 0
          jne .next
          ret



          Do keep things logically together. There's no point in setting RAX before the call to strlen.



          puts:
          ; string passed through rsi
          call strlen ; Result is in RDX

          mov rax, 1
          syscall





          share|improve this answer




















          • Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
            – Meme myself and a very creepy
            19 mins ago















          up vote
          2
          down vote













          Your loop uses 2 jumps (je/jmp) on every iteration! Jumping is expensive, so a solution that needs only 1 jump (jne) will be more effective.



          strlen:
          xor rdx, rdx
          dec rdx ; This compensates for the INC that is happening first.
          .next:
          inc rdx
          cmp byte [rsi + rdx], 0
          jne .next
          ret



          Do keep things logically together. There's no point in setting RAX before the call to strlen.



          puts:
          ; string passed through rsi
          call strlen ; Result is in RDX

          mov rax, 1
          syscall





          share|improve this answer




















          • Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
            – Meme myself and a very creepy
            19 mins ago













          up vote
          2
          down vote










          up vote
          2
          down vote









          Your loop uses 2 jumps (je/jmp) on every iteration! Jumping is expensive, so a solution that needs only 1 jump (jne) will be more effective.



          strlen:
          xor rdx, rdx
          dec rdx ; This compensates for the INC that is happening first.
          .next:
          inc rdx
          cmp byte [rsi + rdx], 0
          jne .next
          ret



          Do keep things logically together. There's no point in setting RAX before the call to strlen.



          puts:
          ; string passed through rsi
          call strlen ; Result is in RDX

          mov rax, 1
          syscall





          share|improve this answer












          Your loop uses 2 jumps (je/jmp) on every iteration! Jumping is expensive, so a solution that needs only 1 jump (jne) will be more effective.



          strlen:
          xor rdx, rdx
          dec rdx ; This compensates for the INC that is happening first.
          .next:
          inc rdx
          cmp byte [rsi + rdx], 0
          jne .next
          ret



          Do keep things logically together. There's no point in setting RAX before the call to strlen.



          puts:
          ; string passed through rsi
          call strlen ; Result is in RDX

          mov rax, 1
          syscall






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 3 hours ago









          Fifoernik

          30027




          30027











          • Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
            – Meme myself and a very creepy
            19 mins ago

















          • Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
            – Meme myself and a very creepy
            19 mins ago
















          Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
          – Meme myself and a very creepy
          19 mins ago





          Would it be best to make an generalization of this and cal it fputs then have puts just mov rdi, 1 and call puts?
          – Meme myself and a very creepy
          19 mins ago


















           

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