tikz : too much white space over tikzpicture

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MWE .

I do not understand why there is too much blank space on the image.Any advice on how to fix it .Thx

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
fbox
 begintikzpicture
 tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endtikzpicture

enddocument

Output of the previous code

asked 56 mins ago

robintux

263

add a commentÂ |Â

up vote
2
down vote

favorite

MWE .

I do not understand why there is too much blank space on the image.Any advice on how to fix it .Thx

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
fbox
 begintikzpicture
 tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endtikzpicture

enddocument

Output of the previous code

asked 56 mins ago

robintux

263

add a commentÂ |Â

up vote
2
down vote

favorite

MWE .

I do not understand why there is too much blank space on the image.Any advice on how to fix it .Thx

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
fbox
 begintikzpicture
 tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endtikzpicture

enddocument

Output of the previous code

asked 56 mins ago

robintux

263

MWE .

I do not understand why there is too much blank space on the image.Any advice on how to fix it .Thx

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
fbox
 begintikzpicture
 tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endtikzpicture

enddocument

Output of the previous code

tikz-pgf tkz-euclide

asked 56 mins ago

robintux

263

asked 56 mins ago

robintux

263

asked 56 mins ago

robintux

263

asked 56 mins ago

robintux

263

asked 56 mins ago

robintux

263

add a commentÂ |Â

2 Answers
2

active

oldest

votes

up vote
3
down vote

I didn't try to track down the exact source of the problem, but it is a known problem, that the bounding box not only takes into account all visible objects, but also coordinates used in the computation of paths etc. I think this might also be the issue here.

As a workaround, remove tkzInittkzClip[space = 1] and wrap everything which should not influence the bounding box in a pgfinterruptboundingbox environment.

If you want the bounding box to be a bit bigger than the triangle, you could add path ([xshift=-1cm,yshift=-1cm]current bounding box.south west) ([xshift=1cm,yshift=1cm]current bounding box.north east); as suggested by @marmot in his comment below.

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
pgfplotssetcompat=1.16
begindocument
fbox
 begintikzpicture
% tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endpgfinterruptboundingbox
 path ([xshift=-1cm,yshift=-1cm]current bounding box.south west) ([xshift=1cm,yshift=1cm]current bounding box.north east);
 endtikzpicture

enddocument

enter image description here

edited 36 mins ago

answered 45 mins ago

samcarter

78.9k787253

@marmot Added. Thanks a lot for the suggestion
â€“Â samcarter
36 mins ago

add a commentÂ |Â

up vote
1
down vote

In addition to the solution given by @samcarter, it is enough to frame the figure with a rectangle draw(-1,-1)rectangle(11,7); without using a fbox to solve this problem.

Edit: thanks a lot to marmot who saw the error I hadn't seen!

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
%fbox
 begintikzpicture
 tkzInit[xmax=10,ymax=6]
 tkzClip[space = 1]
 draw(-1,-1)rectangle(11,7);
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 %beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 %endpgfinterruptboundingbox
 endtikzpicture
%
enddocument

euclide

edited 22 secs ago

answered 19 mins ago

AndrÃ©C

4,072833

1

Sorry, all your proposal does is to add a hard coded rectangle. The bounding box is still too large since it also has the points in that are relevant to the path construction. To see what I mean, add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); at the end of the tikz code. I work with pdflatex.
â€“Â marmot
9 mins ago

@marmot When I compile the document this way with pdflatex on MikTex I get the result shown. What are you working with?
â€“Â AndrÃ©C
6 mins ago

1

Could you please add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); just before endtikzpicture and show what you get then?
â€“Â marmot
4 mins ago

add a commentÂ |Â

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2 Answers
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active

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2 Answers
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active

oldest

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up vote
3
down vote

As a workaround, remove tkzInittkzClip[space = 1] and wrap everything which should not influence the bounding box in a pgfinterruptboundingbox environment.

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
pgfplotssetcompat=1.16
begindocument
fbox
 begintikzpicture
% tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endpgfinterruptboundingbox
 path ([xshift=-1cm,yshift=-1cm]current bounding box.south west) ([xshift=1cm,yshift=1cm]current bounding box.north east);
 endtikzpicture

enddocument

enter image description here

edited 36 mins ago

answered 45 mins ago

samcarter

78.9k787253

@marmot Added. Thanks a lot for the suggestion
â€“Â samcarter
36 mins ago

add a commentÂ |Â

up vote
3
down vote

As a workaround, remove tkzInittkzClip[space = 1] and wrap everything which should not influence the bounding box in a pgfinterruptboundingbox environment.

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
pgfplotssetcompat=1.16
begindocument
fbox
 begintikzpicture
% tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endpgfinterruptboundingbox
 path ([xshift=-1cm,yshift=-1cm]current bounding box.south west) ([xshift=1cm,yshift=1cm]current bounding box.north east);
 endtikzpicture

enddocument

enter image description here

edited 36 mins ago

answered 45 mins ago

samcarter

78.9k787253

@marmot Added. Thanks a lot for the suggestion
â€“Â samcarter
36 mins ago

add a commentÂ |Â

up vote
3
down vote

As a workaround, remove tkzInittkzClip[space = 1] and wrap everything which should not influence the bounding box in a pgfinterruptboundingbox environment.

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
pgfplotssetcompat=1.16
begindocument
fbox
 begintikzpicture
% tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endpgfinterruptboundingbox
 path ([xshift=-1cm,yshift=-1cm]current bounding box.south west) ([xshift=1cm,yshift=1cm]current bounding box.north east);
 endtikzpicture

enddocument

enter image description here

edited 36 mins ago

answered 45 mins ago

samcarter

78.9k787253

As a workaround, remove tkzInittkzClip[space = 1] and wrap everything which should not influence the bounding box in a pgfinterruptboundingbox environment.

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
pgfplotssetcompat=1.16
begindocument
fbox
 begintikzpicture
% tkzInittkzClip[space = 1]
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 endpgfinterruptboundingbox
 path ([xshift=-1cm,yshift=-1cm]current bounding box.south west) ([xshift=1cm,yshift=1cm]current bounding box.north east);
 endtikzpicture

enddocument

enter image description here

edited 36 mins ago

answered 45 mins ago

samcarter

78.9k787253

edited 36 mins ago

answered 45 mins ago

samcarter

78.9k787253

answered 45 mins ago

samcarter

78.9k787253

answered 45 mins ago

samcarter

78.9k787253

@marmot Added. Thanks a lot for the suggestion
â€“Â samcarter
36 mins ago

add a commentÂ |Â

@marmot Added. Thanks a lot for the suggestion
â€“Â samcarter
36 mins ago

@marmot Added. Thanks a lot for the suggestion
â€“Â samcarter
36 mins ago

add a commentÂ |Â

up vote
1
down vote

In addition to the solution given by @samcarter, it is enough to frame the figure with a rectangle draw(-1,-1)rectangle(11,7); without using a fbox to solve this problem.

Edit: thanks a lot to marmot who saw the error I hadn't seen!

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
%fbox
 begintikzpicture
 tkzInit[xmax=10,ymax=6]
 tkzClip[space = 1]
 draw(-1,-1)rectangle(11,7);
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 %beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 %endpgfinterruptboundingbox
 endtikzpicture
%
enddocument

euclide

edited 22 secs ago

answered 19 mins ago

AndrÃ©C

4,072833

1

Sorry, all your proposal does is to add a hard coded rectangle. The bounding box is still too large since it also has the points in that are relevant to the path construction. To see what I mean, add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); at the end of the tikz code. I work with pdflatex.
â€“Â marmot
9 mins ago

@marmot When I compile the document this way with pdflatex on MikTex I get the result shown. What are you working with?
â€“Â AndrÃ©C
6 mins ago

1

Could you please add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); just before endtikzpicture and show what you get then?
â€“Â marmot
4 mins ago

add a commentÂ |Â

up vote
1
down vote

In addition to the solution given by @samcarter, it is enough to frame the figure with a rectangle draw(-1,-1)rectangle(11,7); without using a fbox to solve this problem.

Edit: thanks a lot to marmot who saw the error I hadn't seen!

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
%fbox
 begintikzpicture
 tkzInit[xmax=10,ymax=6]
 tkzClip[space = 1]
 draw(-1,-1)rectangle(11,7);
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 %beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 %endpgfinterruptboundingbox
 endtikzpicture
%
enddocument

euclide

edited 22 secs ago

answered 19 mins ago

AndrÃ©C

4,072833

1

Sorry, all your proposal does is to add a hard coded rectangle. The bounding box is still too large since it also has the points in that are relevant to the path construction. To see what I mean, add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); at the end of the tikz code. I work with pdflatex.
â€“Â marmot
9 mins ago

@marmot When I compile the document this way with pdflatex on MikTex I get the result shown. What are you working with?
â€“Â AndrÃ©C
6 mins ago

1

Could you please add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); just before endtikzpicture and show what you get then?
â€“Â marmot
4 mins ago

add a commentÂ |Â

up vote
1
down vote

In addition to the solution given by @samcarter, it is enough to frame the figure with a rectangle draw(-1,-1)rectangle(11,7); without using a fbox to solve this problem.

Edit: thanks a lot to marmot who saw the error I hadn't seen!

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
%fbox
 begintikzpicture
 tkzInit[xmax=10,ymax=6]
 tkzClip[space = 1]
 draw(-1,-1)rectangle(11,7);
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 %beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 %endpgfinterruptboundingbox
 endtikzpicture
%
enddocument

euclide

edited 22 secs ago

answered 19 mins ago

AndrÃ©C

4,072833

In addition to the solution given by @samcarter, it is enough to frame the figure with a rectangle draw(-1,-1)rectangle(11,7); without using a fbox to solve this problem.

Edit: thanks a lot to marmot who saw the error I hadn't seen!

documentclassarticle
usepackagetkz-euclide
usetkzobjall
usepackagepgfplots
usetikzlibrarycalc,patterns,angles,quotes,arrows,intersections,through,backgrounds,arrows.meta,positioning,math,babel
begindocument
%fbox
 begintikzpicture
 tkzInit[xmax=10,ymax=6]
 tkzClip[space = 1]
 draw(-1,-1)rectangle(11,7);
 tkzPoint[pos = left](0,0)A
 tkzPoint[pos = above](4,6)B
 tkzPoint[pos = right](10,0)C
 tkzDrawPolygon(A,B,C)
 %beginpgfinterruptboundingbox
 tkzInCenter(A,B,C) tkzGetPointI
 tkzDefPointBy[projection=onto B--C](I)
 tkzGetPointH
 tkzDefPointBy[projection=onto A--C](I)
 tkzGetPointK
 tkzDefPointBy[projection=onto A--B](I)
 tkzGetPointL
 tkzDrawSegments[dotted](I,L I,H I,K)
 tkzDrawSegments[dashed](I,A I,B I,C)
 tkzDrawCircle(I,H)
 tkzMarkRightAngles%
 [fill=gray!10,](I,L,B B,H,I C,K,I)
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--B--H; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = L--B--I; 
 tkzLabelAngle[pos=0.7,](H,B,I)$alpha$;
 tkzLabelAngle[pos=0.7,](L,B,I)$alpha$;

 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = K--A--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.7,angle radius=0.5cm]angle = I--A--L; 
 tkzLabelAngle[pos=0.7,](L,A,I)$beta$;
 tkzLabelAngle[pos=0.7,](I,A,K)$beta$;


 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = H--C--I; 
 pic[draw=black,text=black,-,angle eccentricity=0.1,angle radius=0.7cm]angle = I--C--K; 
 tkzLabelAngle[pos=1,](H,C,I)$gamma$;
 tkzLabelAngle[pos=1,](I,C,K)$gamma$;
 %endpgfinterruptboundingbox
 endtikzpicture
%
enddocument

euclide

edited 22 secs ago

answered 19 mins ago

AndrÃ©C

4,072833

edited 22 secs ago

answered 19 mins ago

AndrÃ©C

4,072833

answered 19 mins ago

AndrÃ©C

4,072833

answered 19 mins ago

AndrÃ©C

4,072833

1

Sorry, all your proposal does is to add a hard coded rectangle. The bounding box is still too large since it also has the points in that are relevant to the path construction. To see what I mean, add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); at the end of the tikz code. I work with pdflatex.
â€“Â marmot
9 mins ago

@marmot When I compile the document this way with pdflatex on MikTex I get the result shown. What are you working with?
â€“Â AndrÃ©C
6 mins ago

1

Could you please add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); just before endtikzpicture and show what you get then?
â€“Â marmot
4 mins ago

add a commentÂ |Â

1

Sorry, all your proposal does is to add a hard coded rectangle. The bounding box is still too large since it also has the points in that are relevant to the path construction. To see what I mean, add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); at the end of the tikz code. I work with pdflatex.
â€“Â marmot
9 mins ago

@marmot When I compile the document this way with pdflatex on MikTex I get the result shown. What are you working with?
â€“Â AndrÃ©C
6 mins ago

1

Could you please add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); just before endtikzpicture and show what you get then?
â€“Â marmot
4 mins ago

Sorry, all your proposal does is to add a hard coded rectangle. The bounding box is still too large since it also has the points in that are relevant to the path construction. To see what I mean, add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); at the end of the tikz code. I work with pdflatex.
â€“Â marmot
9 mins ago

@marmot When I compile the document this way with pdflatex on MikTex I get the result shown. What are you working with?
â€“Â AndrÃ©C
6 mins ago

Could you please add draw[red] (current bounding box.south west) rectangle (current bounding box.north east); just before endtikzpicture and show what you get then?
â€“Â marmot
4 mins ago

add a commentÂ |Â

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