looping through JSON array in shell script

Clash Royale CLAN TAG#URR8PPP

up vote
1
down vote

favorite

1

Below is the curl command output (file information about branch), need script or command to print file name , filetype and size.

I have tried with jq but was able fetch single value ( jq '.values.size')

 "path": 
 "components": ,
 "name": "",
 "toString": ""
 ,
 "revision": "master",
 "children": 
 "size": 5,
 "limit": 500,
 "isLastPage": true,
 "values": [
 
 "path": 
 "components": [
 ".gitignore"
 ],
 "parent": "",
 "name": ".gitignore",
 "extension": "gitignore",
 "toString": ".gitignore"
 ,
 "contentId": "c9e472ef4e603480cdd85012b01bd5f4eddc86c6",
 "type": "FILE",
 "size": 224
 ,
 
 "path": 
 "components": [
 "Jenkinsfile"
 ],
 "parent": "",
 "name": "Jenkinsfile",
 "toString": "Jenkinsfile"
 ,
 "contentId": "e878a88eed6b19b2eb0852c39bfd290151b865a4",
 "type": "FILE",
 "size": 1396
 ,
 
 "path": 
 "components": [
 "README.md"
 ],
 "parent": "",
 "name": "README.md",
 "extension": "md",
 "toString": "README.md"
 ,
 "contentId": "05782ad495bfe11e00a77c30ea3ce17c7fa39606",
 "type": "FILE",
 "size": 237
 ,
 
 "path": 
 "components": [
 "pom.xml"
 ],
 "parent": "",
 "name": "pom.xml",
 "extension": "xml",
 "toString": "pom.xml"
 ,
 "contentId": "9cd4887f8fc8c2ecc69ca08508b0f5d7b019dafd",
 "type": "FILE",
 "size": 2548
 ,
 
 "path": 
 "components": [
 "src"
 ],
 "parent": "",
 "name": "src",
 "toString": "src"
 ,
 "node": "395c71003030308d1e4148b7786e9f331c269bdf",
 "type": "DIRECTORY"
 
 ],
 "start": 0
 

expected output should be something like below

.gitignore FILE 224

Jenkinsfile FILE 1396

Thanks in advance :)

shell scripting json

share|improve this question

edited 39 mins ago

asked 46 mins ago

Sugatur Deekshith S N

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

up vote
1
down vote

favorite

1

Below is the curl command output (file information about branch), need script or command to print file name , filetype and size.

I have tried with jq but was able fetch single value ( jq '.values.size')

 "path": 
 "components": ,
 "name": "",
 "toString": ""
 ,
 "revision": "master",
 "children": 
 "size": 5,
 "limit": 500,
 "isLastPage": true,
 "values": [
 
 "path": 
 "components": [
 ".gitignore"
 ],
 "parent": "",
 "name": ".gitignore",
 "extension": "gitignore",
 "toString": ".gitignore"
 ,
 "contentId": "c9e472ef4e603480cdd85012b01bd5f4eddc86c6",
 "type": "FILE",
 "size": 224
 ,
 
 "path": 
 "components": [
 "Jenkinsfile"
 ],
 "parent": "",
 "name": "Jenkinsfile",
 "toString": "Jenkinsfile"
 ,
 "contentId": "e878a88eed6b19b2eb0852c39bfd290151b865a4",
 "type": "FILE",
 "size": 1396
 ,
 
 "path": 
 "components": [
 "README.md"
 ],
 "parent": "",
 "name": "README.md",
 "extension": "md",
 "toString": "README.md"
 ,
 "contentId": "05782ad495bfe11e00a77c30ea3ce17c7fa39606",
 "type": "FILE",
 "size": 237
 ,
 
 "path": 
 "components": [
 "pom.xml"
 ],
 "parent": "",
 "name": "pom.xml",
 "extension": "xml",
 "toString": "pom.xml"
 ,
 "contentId": "9cd4887f8fc8c2ecc69ca08508b0f5d7b019dafd",
 "type": "FILE",
 "size": 2548
 ,
 
 "path": 
 "components": [
 "src"
 ],
 "parent": "",
 "name": "src",
 "toString": "src"
 ,
 "node": "395c71003030308d1e4148b7786e9f331c269bdf",
 "type": "DIRECTORY"
 
 ],
 "start": 0
 

expected output should be something like below

.gitignore FILE 224

Jenkinsfile FILE 1396

Thanks in advance :)

shell scripting json

share|improve this question

edited 39 mins ago

asked 46 mins ago

Sugatur Deekshith S N

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

up vote
1
down vote

favorite

1

up vote
1
down vote

favorite

1

1

Below is the curl command output (file information about branch), need script or command to print file name , filetype and size.

I have tried with jq but was able fetch single value ( jq '.values.size')

 "path": 
 "components": ,
 "name": "",
 "toString": ""
 ,
 "revision": "master",
 "children": 
 "size": 5,
 "limit": 500,
 "isLastPage": true,
 "values": [
 
 "path": 
 "components": [
 ".gitignore"
 ],
 "parent": "",
 "name": ".gitignore",
 "extension": "gitignore",
 "toString": ".gitignore"
 ,
 "contentId": "c9e472ef4e603480cdd85012b01bd5f4eddc86c6",
 "type": "FILE",
 "size": 224
 ,
 
 "path": 
 "components": [
 "Jenkinsfile"
 ],
 "parent": "",
 "name": "Jenkinsfile",
 "toString": "Jenkinsfile"
 ,
 "contentId": "e878a88eed6b19b2eb0852c39bfd290151b865a4",
 "type": "FILE",
 "size": 1396
 ,
 
 "path": 
 "components": [
 "README.md"
 ],
 "parent": "",
 "name": "README.md",
 "extension": "md",
 "toString": "README.md"
 ,
 "contentId": "05782ad495bfe11e00a77c30ea3ce17c7fa39606",
 "type": "FILE",
 "size": 237
 ,
 
 "path": 
 "components": [
 "pom.xml"
 ],
 "parent": "",
 "name": "pom.xml",
 "extension": "xml",
 "toString": "pom.xml"
 ,
 "contentId": "9cd4887f8fc8c2ecc69ca08508b0f5d7b019dafd",
 "type": "FILE",
 "size": 2548
 ,
 
 "path": 
 "components": [
 "src"
 ],
 "parent": "",
 "name": "src",
 "toString": "src"
 ,
 "node": "395c71003030308d1e4148b7786e9f331c269bdf",
 "type": "DIRECTORY"
 
 ],
 "start": 0
 

expected output should be something like below

.gitignore FILE 224

Jenkinsfile FILE 1396

Thanks in advance :)

shell scripting json

share|improve this question

edited 39 mins ago

asked 46 mins ago

Sugatur Deekshith S N

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Below is the curl command output (file information about branch), need script or command to print file name , filetype and size.

I have tried with jq but was able fetch single value ( jq '.values.size')

 "path": 
 "components": ,
 "name": "",
 "toString": ""
 ,
 "revision": "master",
 "children": 
 "size": 5,
 "limit": 500,
 "isLastPage": true,
 "values": [
 
 "path": 
 "components": [
 ".gitignore"
 ],
 "parent": "",
 "name": ".gitignore",
 "extension": "gitignore",
 "toString": ".gitignore"
 ,
 "contentId": "c9e472ef4e603480cdd85012b01bd5f4eddc86c6",
 "type": "FILE",
 "size": 224
 ,
 
 "path": 
 "components": [
 "Jenkinsfile"
 ],
 "parent": "",
 "name": "Jenkinsfile",
 "toString": "Jenkinsfile"
 ,
 "contentId": "e878a88eed6b19b2eb0852c39bfd290151b865a4",
 "type": "FILE",
 "size": 1396
 ,
 
 "path": 
 "components": [
 "README.md"
 ],
 "parent": "",
 "name": "README.md",
 "extension": "md",
 "toString": "README.md"
 ,
 "contentId": "05782ad495bfe11e00a77c30ea3ce17c7fa39606",
 "type": "FILE",
 "size": 237
 ,
 
 "path": 
 "components": [
 "pom.xml"
 ],
 "parent": "",
 "name": "pom.xml",
 "extension": "xml",
 "toString": "pom.xml"
 ,
 "contentId": "9cd4887f8fc8c2ecc69ca08508b0f5d7b019dafd",
 "type": "FILE",
 "size": 2548
 ,
 
 "path": 
 "components": [
 "src"
 ],
 "parent": "",
 "name": "src",
 "toString": "src"
 ,
 "node": "395c71003030308d1e4148b7786e9f331c269bdf",
 "type": "DIRECTORY"
 
 ],
 "start": 0
 

expected output should be something like below

.gitignore FILE 224

Jenkinsfile FILE 1396

Thanks in advance :)

shell scripting json

shell scripting json

share|improve this question

edited 39 mins ago

asked 46 mins ago

Sugatur Deekshith S N

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 39 mins ago

asked 46 mins ago

Sugatur Deekshith S N

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

share|improve this question

edited 39 mins ago

edited 39 mins ago

edited 39 mins ago

asked 46 mins ago

Sugatur Deekshith S N

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 46 mins ago

Sugatur Deekshith S N

62

asked 46 mins ago

Sugatur Deekshith S N

62

62

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

Sugatur Deekshith S N is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
3
down vote

Extracting the members

jq -c '.children.values|[.path.components[0],.type,.size]'

• 
  .children.values outputs every member of the array .values.


• 
  | pipes the previous result through the next filter, rather like a shell pipe


• 
  [...,...,...] makes all the terms inside appear in a single array


• The -c option produces "compact" format ie. one object per line

Result:

[".gitignore","FILE",224]
["Jenkinsfile","FILE",1396]
["README.md","FILE",237]
...

Formatting the result

If you want to output a neatly-aligned table, that's a task better handled by other tools, such as column or paste.

jq -c '.children.values|[.path.components[0],.type,.size]' | column -t -s',"'

• 
  -t tells column to guess the number of columns based on the input


• 
  -s... specifies the delimiter character(s)

Result:

.gitignore FILE 224
Jenkinsfile FILE 1396
README.md FILE 237

This relies on the characters [, ], , and " not appearing in your filenames, which is not a safe assumption.

paste can also arrange multiple inputs side-by-side. For this, we can remove the JSON structures altogether, and output raw lines (hat-tip to @muru):

jq -r '.children.values|.path.components[0],.type,.size' | paste - - -

paste - - - means 3 columns, all read from the the same source. This time, the only assumption is that the filenames don't contain newlines.

share|improve this answer

edited 2 mins ago

answered 28 mins ago

JigglyNaga

3,222626

• 
  
  
  

  
  

  
  
  
  
  
  

  
  add " to -s and you have the exact output that OP wants
  – RoVo
  17 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
  – muru
  16 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
  – Sugatur Deekshith S N
  10 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  then you can use my answer ;-)
  – RoVo
  9 mins ago
  

  
  
  
  

add a comment | 

up vote
0
down vote

For the use case provided in the Question, @JigglyNaga's answer is probably better than this, but for some more complicated task, you could also loop through the list items using keys:

for k in $(jq '.children.values | keys | .' file); do
 ...
done

So e.g. you might use:

for k in $(jq '.children.values | keys | .' file); do
 value=$(jq -r ".children.values[$k]" file);
 name=$(echo "$value" | jq -r '.path.name');
 type=$(echo "$value" | jq -r '.type');
 size=$(echo "$value" | jq -r '.size');
 printf '%st%st%sn' "$name" "$type" "$size";
done | column -t -s$'t'

share|improve this answer

edited 10 mins ago

answered 15 mins ago

RoVo

2,132213

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
3
down vote

Extracting the members

jq -c '.children.values|[.path.components[0],.type,.size]'

• 
  .children.values outputs every member of the array .values.


• 
  | pipes the previous result through the next filter, rather like a shell pipe


• 
  [...,...,...] makes all the terms inside appear in a single array


• The -c option produces "compact" format ie. one object per line

Result:

[".gitignore","FILE",224]
["Jenkinsfile","FILE",1396]
["README.md","FILE",237]
...

Formatting the result

If you want to output a neatly-aligned table, that's a task better handled by other tools, such as column or paste.

jq -c '.children.values|[.path.components[0],.type,.size]' | column -t -s',"'

• 
  -t tells column to guess the number of columns based on the input


• 
  -s... specifies the delimiter character(s)

Result:

.gitignore FILE 224
Jenkinsfile FILE 1396
README.md FILE 237

This relies on the characters [, ], , and " not appearing in your filenames, which is not a safe assumption.

paste can also arrange multiple inputs side-by-side. For this, we can remove the JSON structures altogether, and output raw lines (hat-tip to @muru):

jq -r '.children.values|.path.components[0],.type,.size' | paste - - -

paste - - - means 3 columns, all read from the the same source. This time, the only assumption is that the filenames don't contain newlines.

share|improve this answer

edited 2 mins ago

answered 28 mins ago

JigglyNaga

3,222626

• 
  
  
  

  
  

  
  
  
  
  
  

  
  add " to -s and you have the exact output that OP wants
  – RoVo
  17 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
  – muru
  16 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
  – Sugatur Deekshith S N
  10 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  then you can use my answer ;-)
  – RoVo
  9 mins ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

Extracting the members

jq -c '.children.values|[.path.components[0],.type,.size]'

• 
  .children.values outputs every member of the array .values.


• 
  | pipes the previous result through the next filter, rather like a shell pipe


• 
  [...,...,...] makes all the terms inside appear in a single array


• The -c option produces "compact" format ie. one object per line

Result:

[".gitignore","FILE",224]
["Jenkinsfile","FILE",1396]
["README.md","FILE",237]
...

Formatting the result

If you want to output a neatly-aligned table, that's a task better handled by other tools, such as column or paste.

jq -c '.children.values|[.path.components[0],.type,.size]' | column -t -s',"'

• 
  -t tells column to guess the number of columns based on the input


• 
  -s... specifies the delimiter character(s)

Result:

.gitignore FILE 224
Jenkinsfile FILE 1396
README.md FILE 237

This relies on the characters [, ], , and " not appearing in your filenames, which is not a safe assumption.

paste can also arrange multiple inputs side-by-side. For this, we can remove the JSON structures altogether, and output raw lines (hat-tip to @muru):

jq -r '.children.values|.path.components[0],.type,.size' | paste - - -

paste - - - means 3 columns, all read from the the same source. This time, the only assumption is that the filenames don't contain newlines.

share|improve this answer

edited 2 mins ago

answered 28 mins ago

JigglyNaga

3,222626

• 
  
  
  

  
  

  
  
  
  
  
  

  
  add " to -s and you have the exact output that OP wants
  – RoVo
  17 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
  – muru
  16 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
  – Sugatur Deekshith S N
  10 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  then you can use my answer ;-)
  – RoVo
  9 mins ago
  

  
  
  
  

add a comment | 

up vote
3
down vote

up vote
3
down vote

Extracting the members

jq -c '.children.values|[.path.components[0],.type,.size]'

• 
  .children.values outputs every member of the array .values.


• 
  | pipes the previous result through the next filter, rather like a shell pipe


• 
  [...,...,...] makes all the terms inside appear in a single array


• The -c option produces "compact" format ie. one object per line

Result:

[".gitignore","FILE",224]
["Jenkinsfile","FILE",1396]
["README.md","FILE",237]
...

Formatting the result

If you want to output a neatly-aligned table, that's a task better handled by other tools, such as column or paste.

jq -c '.children.values|[.path.components[0],.type,.size]' | column -t -s',"'

• 
  -t tells column to guess the number of columns based on the input


• 
  -s... specifies the delimiter character(s)

Result:

.gitignore FILE 224
Jenkinsfile FILE 1396
README.md FILE 237

This relies on the characters [, ], , and " not appearing in your filenames, which is not a safe assumption.

paste can also arrange multiple inputs side-by-side. For this, we can remove the JSON structures altogether, and output raw lines (hat-tip to @muru):

jq -r '.children.values|.path.components[0],.type,.size' | paste - - -

paste - - - means 3 columns, all read from the the same source. This time, the only assumption is that the filenames don't contain newlines.

share|improve this answer

edited 2 mins ago

answered 28 mins ago

JigglyNaga

3,222626

Extracting the members

jq -c '.children.values|[.path.components[0],.type,.size]'

• 
  .children.values outputs every member of the array .values.


• 
  | pipes the previous result through the next filter, rather like a shell pipe


• 
  [...,...,...] makes all the terms inside appear in a single array


• The -c option produces "compact" format ie. one object per line

Result:

[".gitignore","FILE",224]
["Jenkinsfile","FILE",1396]
["README.md","FILE",237]
...

Formatting the result

If you want to output a neatly-aligned table, that's a task better handled by other tools, such as column or paste.

jq -c '.children.values|[.path.components[0],.type,.size]' | column -t -s',"'

• 
  -t tells column to guess the number of columns based on the input


• 
  -s... specifies the delimiter character(s)

Result:

.gitignore FILE 224
Jenkinsfile FILE 1396
README.md FILE 237

This relies on the characters [, ], , and " not appearing in your filenames, which is not a safe assumption.

paste can also arrange multiple inputs side-by-side. For this, we can remove the JSON structures altogether, and output raw lines (hat-tip to @muru):

jq -r '.children.values|.path.components[0],.type,.size' | paste - - -

paste - - - means 3 columns, all read from the the same source. This time, the only assumption is that the filenames don't contain newlines.

share|improve this answer

edited 2 mins ago

answered 28 mins ago

JigglyNaga

3,222626

share|improve this answer

share|improve this answer

edited 2 mins ago

edited 2 mins ago

edited 2 mins ago

answered 28 mins ago

JigglyNaga

3,222626

answered 28 mins ago

JigglyNaga

3,222626

answered 28 mins ago

JigglyNaga

3,222626

3,222626

• 
  
  
  

  
  

  
  
  
  
  
  

  
  add " to -s and you have the exact output that OP wants
  – RoVo
  17 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
  – muru
  16 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
  – Sugatur Deekshith S N
  10 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  then you can use my answer ;-)
  – RoVo
  9 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  add " to -s and you have the exact output that OP wants
  – RoVo
  17 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
  – muru
  16 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
  – Sugatur Deekshith S N
  10 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  then you can use my answer ;-)
  – RoVo
  9 mins ago
  

  
  
  
  

add " to -s and you have the exact output that OP wants
– RoVo
17 mins ago

add " to -s and you have the exact output that OP wants
– RoVo
17 mins ago

1

1

Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
– muru
16 mins ago

Or if entries won't have newlines in them: jq -r '.children.values | .path.components[0],.type,.size' | paste - - -
– muru
16 mins ago

@JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
– Sugatur Deekshith S N
10 mins ago

@JigglyNaga thanks for the detailed answer but I have one more question assume if I want store size value in variable how would I do that , because I want to convert those size values to MB
– Sugatur Deekshith S N
10 mins ago

then you can use my answer ;-)
– RoVo
9 mins ago

then you can use my answer ;-)
– RoVo
9 mins ago

add a comment | 

up vote
0
down vote

For the use case provided in the Question, @JigglyNaga's answer is probably better than this, but for some more complicated task, you could also loop through the list items using keys:

for k in $(jq '.children.values | keys | .' file); do
 ...
done

So e.g. you might use:

for k in $(jq '.children.values | keys | .' file); do
 value=$(jq -r ".children.values[$k]" file);
 name=$(echo "$value" | jq -r '.path.name');
 type=$(echo "$value" | jq -r '.type');
 size=$(echo "$value" | jq -r '.size');
 printf '%st%st%sn' "$name" "$type" "$size";
done | column -t -s$'t'

share|improve this answer

edited 10 mins ago

answered 15 mins ago

RoVo

2,132213

add a comment | 

up vote
0
down vote

For the use case provided in the Question, @JigglyNaga's answer is probably better than this, but for some more complicated task, you could also loop through the list items using keys:

for k in $(jq '.children.values | keys | .' file); do
 ...
done

So e.g. you might use:

for k in $(jq '.children.values | keys | .' file); do
 value=$(jq -r ".children.values[$k]" file);
 name=$(echo "$value" | jq -r '.path.name');
 type=$(echo "$value" | jq -r '.type');
 size=$(echo "$value" | jq -r '.size');
 printf '%st%st%sn' "$name" "$type" "$size";
done | column -t -s$'t'

share|improve this answer

edited 10 mins ago

answered 15 mins ago

RoVo

2,132213

add a comment | 

up vote
0
down vote

up vote
0
down vote

For the use case provided in the Question, @JigglyNaga's answer is probably better than this, but for some more complicated task, you could also loop through the list items using keys:

for k in $(jq '.children.values | keys | .' file); do
 ...
done

So e.g. you might use:

for k in $(jq '.children.values | keys | .' file); do
 value=$(jq -r ".children.values[$k]" file);
 name=$(echo "$value" | jq -r '.path.name');
 type=$(echo "$value" | jq -r '.type');
 size=$(echo "$value" | jq -r '.size');
 printf '%st%st%sn' "$name" "$type" "$size";
done | column -t -s$'t'

share|improve this answer

edited 10 mins ago

answered 15 mins ago

RoVo

2,132213

For the use case provided in the Question, @JigglyNaga's answer is probably better than this, but for some more complicated task, you could also loop through the list items using keys:

for k in $(jq '.children.values | keys | .' file); do
 ...
done

So e.g. you might use:

for k in $(jq '.children.values | keys | .' file); do
 value=$(jq -r ".children.values[$k]" file);
 name=$(echo "$value" | jq -r '.path.name');
 type=$(echo "$value" | jq -r '.type');
 size=$(echo "$value" | jq -r '.size');
 printf '%st%st%sn' "$name" "$type" "$size";
done | column -t -s$'t'

share|improve this answer

edited 10 mins ago

answered 15 mins ago

RoVo

2,132213

share|improve this answer

share|improve this answer

edited 10 mins ago

edited 10 mins ago

edited 10 mins ago

answered 15 mins ago

RoVo

2,132213

answered 15 mins ago

RoVo

2,132213

answered 15 mins ago

RoVo

2,132213

2,132213

add a comment | 

add a comment | 

Sugatur Deekshith S N is a new contributor. Be nice, and check out our Code of Conduct.

 

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Sugatur Deekshith S N is a new contributor. Be nice, and check out our Code of Conduct.

Sugatur Deekshith S N is a new contributor. Be nice, and check out our Code of Conduct.

Sugatur Deekshith S N is a new contributor. Be nice, and check out our Code of Conduct.

 

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