Bash: Use exec find option by sorting two file arguments

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4
down vote

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Let's say I want to compare the files with the same filename between these two directories:

 /tmp/datadir/dir1/dir2/

and

 /datadir/dir1/dir2/

It is required to sort them before comparing.

I am currently in the /tmp directory, and I tried to run this find with the exec option:

find datadir -type f -exec sdiff -s <( sort ) <( sort "/" ) ;

But, it gives me an error

sort: open failed: : No such file or directory

sort: open failed: /: No such file or directory

However, the below command works fine, but the data is not sorted for proper comparison.

find data -type f -exec sdiff -s "/" ;

How can I fix this problem?

edited Aug 7 at 15:41

Peter Mortensen

79148

asked Aug 7 at 14:01

Kaushik Nayak

21316

add a commentÂ |Â

up vote
4
down vote

favorite

Let's say I want to compare the files with the same filename between these two directories:

 /tmp/datadir/dir1/dir2/

and

 /datadir/dir1/dir2/

It is required to sort them before comparing.

I am currently in the /tmp directory, and I tried to run this find with the exec option:

find datadir -type f -exec sdiff -s <( sort ) <( sort "/" ) ;

But, it gives me an error

sort: open failed: : No such file or directory

sort: open failed: /: No such file or directory

However, the below command works fine, but the data is not sorted for proper comparison.

find data -type f -exec sdiff -s "/" ;

How can I fix this problem?

edited Aug 7 at 15:41

Peter Mortensen

79148

asked Aug 7 at 14:01

Kaushik Nayak

21316

add a commentÂ |Â

up vote
4
down vote

favorite

Let's say I want to compare the files with the same filename between these two directories:

 /tmp/datadir/dir1/dir2/

and

 /datadir/dir1/dir2/

It is required to sort them before comparing.

I am currently in the /tmp directory, and I tried to run this find with the exec option:

find datadir -type f -exec sdiff -s <( sort ) <( sort "/" ) ;

But, it gives me an error

sort: open failed: : No such file or directory

sort: open failed: /: No such file or directory

However, the below command works fine, but the data is not sorted for proper comparison.

find data -type f -exec sdiff -s "/" ;

How can I fix this problem?

edited Aug 7 at 15:41

Peter Mortensen

79148

asked Aug 7 at 14:01

Kaushik Nayak

21316

Let's say I want to compare the files with the same filename between these two directories:

 /tmp/datadir/dir1/dir2/

and

 /datadir/dir1/dir2/

It is required to sort them before comparing.

I am currently in the /tmp directory, and I tried to run this find with the exec option:

find datadir -type f -exec sdiff -s <( sort ) <( sort "/" ) ;

But, it gives me an error

sort: open failed: : No such file or directory

sort: open failed: /: No such file or directory

However, the below command works fine, but the data is not sorted for proper comparison.

find data -type f -exec sdiff -s "/" ;

How can I fix this problem?

edited Aug 7 at 15:41

Peter Mortensen

79148

asked Aug 7 at 14:01

Kaushik Nayak

21316

edited Aug 7 at 15:41

Peter Mortensen

79148

edited Aug 7 at 15:41

Peter Mortensen

79148

edited Aug 7 at 15:41

Peter Mortensen

79148

asked Aug 7 at 14:01

Kaushik Nayak

21316

asked Aug 7 at 14:01

Kaushik Nayak

21316

asked Aug 7 at 14:01

Kaushik Nayak

21316

add a commentÂ |Â

2 Answers
2

active

oldest

votes

up vote
10
down vote

accepted

The replacement of is done by find and happens after the evaluation of the process substitution (<(Ã¢Â€Â¦)) and such in your code.

Using bash -c:

find datadir -type f -exec 
 bash -c 'sdiff -s <( sort "$1" ) <( sort "/$1" )' bash ;

Or to avoid running one bash instance per file:

find datadir -type f -exec bash -c '
 for file do
 sdiff -s <( sort "$file" ) <( sort "/$file" )
 done' bash +

edited Aug 7 at 14:17

StÃ©phane Chazelas

282k53520854

answered Aug 7 at 14:06

phk

3,80852147

add a commentÂ |Â

up vote
1
down vote

You could consider using the -r (recursive) option that does all the sorting and recursing for you.

answered Aug 7 at 17:42

RalfFriedl

2,8451519

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
10
down vote

accepted

The replacement of is done by find and happens after the evaluation of the process substitution (<(Ã¢Â€Â¦)) and such in your code.

Using bash -c:

find datadir -type f -exec 
 bash -c 'sdiff -s <( sort "$1" ) <( sort "/$1" )' bash ;

Or to avoid running one bash instance per file:

find datadir -type f -exec bash -c '
 for file do
 sdiff -s <( sort "$file" ) <( sort "/$file" )
 done' bash +

edited Aug 7 at 14:17

StÃ©phane Chazelas

282k53520854

answered Aug 7 at 14:06

phk

3,80852147

add a commentÂ |Â

up vote
10
down vote

accepted

The replacement of is done by find and happens after the evaluation of the process substitution (<(Ã¢Â€Â¦)) and such in your code.

Using bash -c:

find datadir -type f -exec 
 bash -c 'sdiff -s <( sort "$1" ) <( sort "/$1" )' bash ;

Or to avoid running one bash instance per file:

find datadir -type f -exec bash -c '
 for file do
 sdiff -s <( sort "$file" ) <( sort "/$file" )
 done' bash +

edited Aug 7 at 14:17

StÃ©phane Chazelas

282k53520854

answered Aug 7 at 14:06

phk

3,80852147

add a commentÂ |Â

up vote
10
down vote

accepted

The replacement of is done by find and happens after the evaluation of the process substitution (<(Ã¢Â€Â¦)) and such in your code.

Using bash -c:

find datadir -type f -exec 
 bash -c 'sdiff -s <( sort "$1" ) <( sort "/$1" )' bash ;

Or to avoid running one bash instance per file:

find datadir -type f -exec bash -c '
 for file do
 sdiff -s <( sort "$file" ) <( sort "/$file" )
 done' bash +

edited Aug 7 at 14:17

StÃ©phane Chazelas

282k53520854

answered Aug 7 at 14:06

phk

3,80852147

The replacement of is done by find and happens after the evaluation of the process substitution (<(Ã¢Â€Â¦)) and such in your code.

Using bash -c:

find datadir -type f -exec 
 bash -c 'sdiff -s <( sort "$1" ) <( sort "/$1" )' bash ;

Or to avoid running one bash instance per file:

find datadir -type f -exec bash -c '
 for file do
 sdiff -s <( sort "$file" ) <( sort "/$file" )
 done' bash +

edited Aug 7 at 14:17

282k53520854

answered Aug 7 at 14:06

phk

3,80852147

edited Aug 7 at 14:17

282k53520854

edited Aug 7 at 14:17

282k53520854

edited Aug 7 at 14:17

282k53520854

answered Aug 7 at 14:06

phk

3,80852147

answered Aug 7 at 14:06

phk

3,80852147

answered Aug 7 at 14:06

phk

3,80852147

add a commentÂ |Â

up vote
1
down vote

You could consider using the -r (recursive) option that does all the sorting and recursing for you.

answered Aug 7 at 17:42

RalfFriedl

2,8451519

add a commentÂ |Â

up vote
1
down vote

You could consider using the -r (recursive) option that does all the sorting and recursing for you.

answered Aug 7 at 17:42

RalfFriedl

2,8451519

add a commentÂ |Â

up vote
1
down vote

You could consider using the -r (recursive) option that does all the sorting and recursing for you.

answered Aug 7 at 17:42

RalfFriedl

2,8451519

You could consider using the -r (recursive) option that does all the sorting and recursing for you.

answered Aug 7 at 17:42

RalfFriedl

2,8451519

answered Aug 7 at 17:42

RalfFriedl

2,8451519

answered Aug 7 at 17:42

RalfFriedl

2,8451519

answered Aug 7 at 17:42

RalfFriedl

2,8451519

add a commentÂ |Â

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