Use 2, 0, 1 and 8 to make 71
Clash Royale CLAN TAG#URR8PPP
up vote
4
down vote
favorite
Use all and only the digits $2,0,1,8$ once each to make the number $71$.
Allowed operations; anything not on this list is banned:
$+,-,times,div, ()$ (parentheses and/or choose function)
Concatenation; only applied to the original digits e.g $(8-1)||(2-0!)$ is not allowed
$!$ single factorial (none of that double factorial + weird stuff otherwise you could do something like $12!!!!!!=12times6$ and that's a bit cheat)
Exponentiation, although the exponent must be 'made' as well
Sqrt (free of cost); nth roots however require you to be able to make the number 'n'
Decimal point: like concatenation, this can only be applied to the original digits. Sorry to those who attempted this before -- unlike in some questions, I'm requiring that any decimal point needs an integer part before it (wikipedia: ..used to separate the integer part from the fractional part of a number)
Sorry I know PSE is being plagued with these but I couldn't resist.
mathematics calculation-puzzle formation-of-numbers arithmetic
 |Â
show 1 more comment
up vote
4
down vote
favorite
Use all and only the digits $2,0,1,8$ once each to make the number $71$.
Allowed operations; anything not on this list is banned:
$+,-,times,div, ()$ (parentheses and/or choose function)
Concatenation; only applied to the original digits e.g $(8-1)||(2-0!)$ is not allowed
$!$ single factorial (none of that double factorial + weird stuff otherwise you could do something like $12!!!!!!=12times6$ and that's a bit cheat)
Exponentiation, although the exponent must be 'made' as well
Sqrt (free of cost); nth roots however require you to be able to make the number 'n'
Decimal point: like concatenation, this can only be applied to the original digits. Sorry to those who attempted this before -- unlike in some questions, I'm requiring that any decimal point needs an integer part before it (wikipedia: ..used to separate the integer part from the fractional part of a number)
Sorry I know PSE is being plagued with these but I couldn't resist.
mathematics calculation-puzzle formation-of-numbers arithmetic
2
how is 12!!!!!!=12×6?
– Rotsor
Sep 9 at 13:32
@Rotsor Sextuple factorial (not allowed in this puzzle).
– EKons
Sep 9 at 18:10
@ΈÃÂικΚÉνÃÄανÄÃŒÀοÅλοÂ, it's just a question how does it work, mathematically.
– rus9384
2 days ago
@rus9384 It's a matter of (totally wrong, in my opinion) notation; don't try to split the $!$s to find some meaning which makes more sense. ;-)
– EKons
2 days ago
Is $(N!)!$ allowed?
– rus9384
2 days ago
 |Â
show 1 more comment
up vote
4
down vote
favorite
up vote
4
down vote
favorite
Use all and only the digits $2,0,1,8$ once each to make the number $71$.
Allowed operations; anything not on this list is banned:
$+,-,times,div, ()$ (parentheses and/or choose function)
Concatenation; only applied to the original digits e.g $(8-1)||(2-0!)$ is not allowed
$!$ single factorial (none of that double factorial + weird stuff otherwise you could do something like $12!!!!!!=12times6$ and that's a bit cheat)
Exponentiation, although the exponent must be 'made' as well
Sqrt (free of cost); nth roots however require you to be able to make the number 'n'
Decimal point: like concatenation, this can only be applied to the original digits. Sorry to those who attempted this before -- unlike in some questions, I'm requiring that any decimal point needs an integer part before it (wikipedia: ..used to separate the integer part from the fractional part of a number)
Sorry I know PSE is being plagued with these but I couldn't resist.
mathematics calculation-puzzle formation-of-numbers arithmetic
Use all and only the digits $2,0,1,8$ once each to make the number $71$.
Allowed operations; anything not on this list is banned:
$+,-,times,div, ()$ (parentheses and/or choose function)
Concatenation; only applied to the original digits e.g $(8-1)||(2-0!)$ is not allowed
$!$ single factorial (none of that double factorial + weird stuff otherwise you could do something like $12!!!!!!=12times6$ and that's a bit cheat)
Exponentiation, although the exponent must be 'made' as well
Sqrt (free of cost); nth roots however require you to be able to make the number 'n'
Decimal point: like concatenation, this can only be applied to the original digits. Sorry to those who attempted this before -- unlike in some questions, I'm requiring that any decimal point needs an integer part before it (wikipedia: ..used to separate the integer part from the fractional part of a number)
Sorry I know PSE is being plagued with these but I couldn't resist.
mathematics calculation-puzzle formation-of-numbers arithmetic
mathematics calculation-puzzle formation-of-numbers arithmetic
edited Sep 9 at 9:32
Shahriar Mahmud Sajid
2,474526
2,474526
asked Sep 9 at 5:43


Wen1now
6,74812279
6,74812279
2
how is 12!!!!!!=12×6?
– Rotsor
Sep 9 at 13:32
@Rotsor Sextuple factorial (not allowed in this puzzle).
– EKons
Sep 9 at 18:10
@ΈÃÂικΚÉνÃÄανÄÃŒÀοÅλοÂ, it's just a question how does it work, mathematically.
– rus9384
2 days ago
@rus9384 It's a matter of (totally wrong, in my opinion) notation; don't try to split the $!$s to find some meaning which makes more sense. ;-)
– EKons
2 days ago
Is $(N!)!$ allowed?
– rus9384
2 days ago
 |Â
show 1 more comment
2
how is 12!!!!!!=12×6?
– Rotsor
Sep 9 at 13:32
@Rotsor Sextuple factorial (not allowed in this puzzle).
– EKons
Sep 9 at 18:10
@ΈÃÂικΚÉνÃÄανÄÃŒÀοÅλοÂ, it's just a question how does it work, mathematically.
– rus9384
2 days ago
@rus9384 It's a matter of (totally wrong, in my opinion) notation; don't try to split the $!$s to find some meaning which makes more sense. ;-)
– EKons
2 days ago
Is $(N!)!$ allowed?
– rus9384
2 days ago
2
2
how is 12!!!!!!=12×6?
– Rotsor
Sep 9 at 13:32
how is 12!!!!!!=12×6?
– Rotsor
Sep 9 at 13:32
@Rotsor Sextuple factorial (not allowed in this puzzle).
– EKons
Sep 9 at 18:10
@Rotsor Sextuple factorial (not allowed in this puzzle).
– EKons
Sep 9 at 18:10
@ΈÃÂικΚÉνÃÄανÄÃŒÀοÅλοÂ, it's just a question how does it work, mathematically.
– rus9384
2 days ago
@ΈÃÂικΚÉνÃÄανÄÃŒÀοÅλοÂ, it's just a question how does it work, mathematically.
– rus9384
2 days ago
@rus9384 It's a matter of (totally wrong, in my opinion) notation; don't try to split the $!$s to find some meaning which makes more sense. ;-)
– EKons
2 days ago
@rus9384 It's a matter of (totally wrong, in my opinion) notation; don't try to split the $!$s to find some meaning which makes more sense. ;-)
– EKons
2 days ago
Is $(N!)!$ allowed?
– rus9384
2 days ago
Is $(N!)!$ allowed?
– rus9384
2 days ago
 |Â
show 1 more comment
2 Answers
2
active
oldest
votes
up vote
17
down vote
accepted
How about:
$$sqrt(8-1)!+2-0! $$ I found this by chance when noticing that $71^2 = 5041$ was extremely close to $7! = 5040$.
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
1
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
 |Â
show 2 more comments
up vote
9
down vote
$$.1times(8-2)!-0! = .1times6!-1 = 72-1 = 71$$
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
17
down vote
accepted
How about:
$$sqrt(8-1)!+2-0! $$ I found this by chance when noticing that $71^2 = 5041$ was extremely close to $7! = 5040$.
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
1
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
 |Â
show 2 more comments
up vote
17
down vote
accepted
How about:
$$sqrt(8-1)!+2-0! $$ I found this by chance when noticing that $71^2 = 5041$ was extremely close to $7! = 5040$.
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
1
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
 |Â
show 2 more comments
up vote
17
down vote
accepted
up vote
17
down vote
accepted
How about:
$$sqrt(8-1)!+2-0! $$ I found this by chance when noticing that $71^2 = 5041$ was extremely close to $7! = 5040$.
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
How about:
$$sqrt(8-1)!+2-0! $$ I found this by chance when noticing that $71^2 = 5041$ was extremely close to $7! = 5040$.
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Sep 9 at 9:28
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Sep 9 at 6:22
Toby Mak
2864
2864
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Toby Mak is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
1
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
 |Â
show 2 more comments
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
1
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
Please hide your hint.
– Hack Saw
Sep 9 at 8:58
1
1
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
@HackSaw Do you mean like this?
– Toby Mak
Sep 9 at 9:28
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
I tried brute-forcing this using my computer, and this solution (including hundreds of variations) was the only one it could find using the rules.
– LegionMammal978
Sep 9 at 18:50
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
@LegionMammal978 Wow, thanks for confirming! I must have been extremely lucky to find this.
– Toby Mak
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
That is, to be more specific, any solution that does not use this strategy will likely need at least 5 unary operators (negation, factorials, square roots).
– LegionMammal978
2 days ago
 |Â
show 2 more comments
up vote
9
down vote
$$.1times(8-2)!-0! = .1times6!-1 = 72-1 = 71$$
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
add a comment |Â
up vote
9
down vote
$$.1times(8-2)!-0! = .1times6!-1 = 72-1 = 71$$
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
add a comment |Â
up vote
9
down vote
up vote
9
down vote
$$.1times(8-2)!-0! = .1times6!-1 = 72-1 = 71$$
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$$.1times(8-2)!-0! = .1times6!-1 = 72-1 = 71$$
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Sep 9 at 5:58
Ian Miller
30015
30015
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Ian Miller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
add a comment |Â
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
Hi there, welcome to Puzzling :) I'm real sorry -- I forgot to specify that the decimal point needs an integral part before it. +1 anyway
– Wen1now
Sep 9 at 8:08
add a comment |Â
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2
how is 12!!!!!!=12×6?
– Rotsor
Sep 9 at 13:32
@Rotsor Sextuple factorial (not allowed in this puzzle).
– EKons
Sep 9 at 18:10
@ΈÃÂικΚÉνÃÄανÄÃŒÀοÅλοÂ, it's just a question how does it work, mathematically.
– rus9384
2 days ago
@rus9384 It's a matter of (totally wrong, in my opinion) notation; don't try to split the $!$s to find some meaning which makes more sense. ;-)
– EKons
2 days ago
Is $(N!)!$ allowed?
– rus9384
2 days ago