Draw layered software architecture with TikZ

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











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I want to represent a layered software architecture.
There is already an interesting approach on this site. But I can't add small boxes to the bottom (to be exact: one more row, containing two boxes of equal size).



Layered architecture



documentclass[border=2px]standalone
usepackage[utf8]inputenc
usepackagetikz
usetikzlibraryshapes.geometric, arrows, chains, calc

tikzset
 green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
 blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
 yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,


begindocument
begintikzpicture[start chain=1 going right,
 start chain=2 going below, node distance=1mm]
 node [name=r1c1, on chain=1, green] VC++;
 node [name=r1c2, on chain=1, green] VB.NET;
 node [name=r1c3, on chain=1, green] C#.NET;
 node [name=r1c4, on chain=1, green] Others;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
 minimum width=n1-pgflinewidth]
 at (r1c1.south west) COM-API Interface;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;

endtikzpicture
enddocument


This code is not my own. It is copied from the link above.






tikz-pgf







share|improve this question























  • You could use the fit library for the outer line of all nodes and define some node styles.
    – current_user
    2 days ago










  • Could you please elaborate? I don't know anything about TikZ. The code is not mine (I've added a disclaimer now).
    – mike
    2 days ago










  • See my answer. I've done it for you …
    – current_user
    2 days ago














up vote
5
down vote

favorite












I want to represent a layered software architecture.
There is already an interesting approach on this site. But I can't add small boxes to the bottom (to be exact: one more row, containing two boxes of equal size).



Layered architecture



documentclass[border=2px]standalone
usepackage[utf8]inputenc
usepackagetikz
usetikzlibraryshapes.geometric, arrows, chains, calc

tikzset
 green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
 blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
 yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,


begindocument
begintikzpicture[start chain=1 going right,
 start chain=2 going below, node distance=1mm]
 node [name=r1c1, on chain=1, green] VC++;
 node [name=r1c2, on chain=1, green] VB.NET;
 node [name=r1c3, on chain=1, green] C#.NET;
 node [name=r1c4, on chain=1, green] Others;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
 minimum width=n1-pgflinewidth]
 at (r1c1.south west) COM-API Interface;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;

endtikzpicture
enddocument


This code is not my own. It is copied from the link above.






tikz-pgf







share|improve this question























  • You could use the fit library for the outer line of all nodes and define some node styles.
    – current_user
    2 days ago










  • Could you please elaborate? I don't know anything about TikZ. The code is not mine (I've added a disclaimer now).
    – mike
    2 days ago










  • See my answer. I've done it for you …
    – current_user
    2 days ago












up vote
5
down vote

favorite









up vote
5
down vote

favorite











I want to represent a layered software architecture.
There is already an interesting approach on this site. But I can't add small boxes to the bottom (to be exact: one more row, containing two boxes of equal size).



Layered architecture



documentclass[border=2px]standalone
usepackage[utf8]inputenc
usepackagetikz
usetikzlibraryshapes.geometric, arrows, chains, calc

tikzset
 green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
 blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
 yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,


begindocument
begintikzpicture[start chain=1 going right,
 start chain=2 going below, node distance=1mm]
 node [name=r1c1, on chain=1, green] VC++;
 node [name=r1c2, on chain=1, green] VB.NET;
 node [name=r1c3, on chain=1, green] C#.NET;
 node [name=r1c4, on chain=1, green] Others;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
 minimum width=n1-pgflinewidth]
 at (r1c1.south west) COM-API Interface;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;

endtikzpicture
enddocument


This code is not my own. It is copied from the link above.






tikz-pgf







share|improve this question















I want to represent a layered software architecture.
There is already an interesting approach on this site. But I can't add small boxes to the bottom (to be exact: one more row, containing two boxes of equal size).



Layered architecture



documentclass[border=2px]standalone
usepackage[utf8]inputenc
usepackagetikz
usetikzlibraryshapes.geometric, arrows, chains, calc

tikzset
 green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
 blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
 yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,


begindocument
begintikzpicture[start chain=1 going right,
 start chain=2 going below, node distance=1mm]
 node [name=r1c1, on chain=1, green] VC++;
 node [name=r1c2, on chain=1, green] VB.NET;
 node [name=r1c3, on chain=1, green] C#.NET;
 node [name=r1c4, on chain=1, green] Others;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
 minimum width=n1-pgflinewidth]
 at (r1c1.south west) COM-API Interface;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;

endtikzpicture
enddocument


This code is not my own. It is copied from the link above.






tikz-pgf




tikz-pgf






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago









Bernard

156k763189




156k763189










asked 2 days ago









mike

1865




1865











  • You could use the fit library for the outer line of all nodes and define some node styles.
    – current_user
    2 days ago










  • Could you please elaborate? I don't know anything about TikZ. The code is not mine (I've added a disclaimer now).
    – mike
    2 days ago










  • See my answer. I've done it for you …
    – current_user
    2 days ago
















  • You could use the fit library for the outer line of all nodes and define some node styles.
    – current_user
    2 days ago










  • Could you please elaborate? I don't know anything about TikZ. The code is not mine (I've added a disclaimer now).
    – mike
    2 days ago










  • See my answer. I've done it for you …
    – current_user
    2 days ago















You could use the fit library for the outer line of all nodes and define some node styles.
– current_user
2 days ago




You could use the fit library for the outer line of all nodes and define some node styles.
– current_user
2 days ago












Could you please elaborate? I don't know anything about TikZ. The code is not mine (I've added a disclaimer now).
– mike
2 days ago




Could you please elaborate? I don't know anything about TikZ. The code is not mine (I've added a disclaimer now).
– mike
2 days ago












See my answer. I've done it for you …
– current_user
2 days ago




See my answer. I've done it for you …
– current_user
2 days ago










3 Answers
3






active

oldest

votes

















up vote
6
down vote



accepted










documentclass[border=2px]standalone
usepackage[utf8]inputenc
usepackagetikz
usetikzlibraryshapes.geometric, arrows, chains, calc,positioning

tikzset
 green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
 blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
 yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,
 red/.style=minimum height=1cm, text centered, font=footnotesize, draw=black, fill=red!30


begindocument
begintikzpicture[start chain=1 going right,
 start chain=2 going below, node distance=1mm]
 node [name=r1c1, on chain=1, green] VC++;
 node [name=r1c2, on chain=1, green] VB.NET;
 node [name=r1c3, on chain=1, green] C#.NET;
 node [name=r1c4, on chain=1, green] Others;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
 minimum width=n1-pgflinewidth]
 at (r1c1.south west) COM-API Interface;
 draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
 node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;
 draw let p1=($(r1c4.east)-(r1c1.west)$),
 p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
 node [name=r4c1, on chain=2, red,xshift=-0.25*(n1+2*pgflinewidth-0.5*n2), 
 minimum width=0.5*(n1-pgflinewidth+n2)] Pffft;
 draw let p1=($(r1c4.east)-(r1c1.west)$),
 p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
 node[right=1mm of r4c1,
 name=r4c2, red,minimum width=0.5*(n1-pgflinewidth+n2)] Pfffft;
endtikzpicture
enddocument


enter image description here






share|improve this answer
















  • 2




    +1 for the great ligatures in the last row ;)
    – Max
    2 days ago






  • 2




    @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
    – marmot
    2 days ago







  • 1




    @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
    – Rmano
    2 days ago










  • @Rmano If you drop one f, the meaning changes completely. ;-)
    – marmot
    2 days ago






  • 1




    @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
    – marmot
    yesterday

















up vote
2
down vote













documentclass[border=5pt,tikz]standalone
usetikzlibraryfit,positioning
 tikzstyles1 = [draw,minimum width=.9cm,minimum height=.7cm,fill=green!20]
 tikzstyles2 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=blue!20]
 tikzstyles3 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=yellow!20]
 tikzstyles4 = [draw,minimum width=3cm,minimum height=.7cm,fill=red!20]
begindocument
 begintikzpicture
 node[s1] (a) VC++;
 node[s1,right=.1 of a] (b) VB.NET;
 node[s1,right=.1 of b] (c) C#.NET;
 node[s1,right=.1 of c] (d) Others;
 node[s2,xshift=.87cm,below=.1 of b] (e) COM-API Interface;
 node[s3,below=.1 of e] (f) Autodesk Inventor Application;
 node[s4,below=.1 of f.south west,anchor=west,yshift=-.3cm] (foo) Foo;
 node[s4,right=.1 of foo,anchor=west] (bar) Bar;
 node[draw,fit=(a)(bar)] ;
 endtikzpicture
enddocument


Here is the output:



Screenshot






share|improve this answer






















  • I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
    – current_user
    2 days ago






  • 1




    @marmot: What would I do without a marmot nearby me …
    – current_user
    2 days ago










  • I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
    – mike
    2 days ago






  • 1




    I guess the picture I've added was a little misleading in this context. Yes, thank you!
    – mike
    2 days ago






  • 1




    Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
    – TeXnician
    yesterday

















up vote
1
down vote













for fun and exercised, a variation of the nice marmot's answer. by changes in definitions of the styles the code 



documentclass[tikz, margin=3mm]standalone
usetikzlibrarycalc, chains, positioning

tikzset
box/.style args = #1/#2rectangle,
 minimum width=#1, fill=#2!30, draw,
 text width =pgfkeysvalueof/pgf/minimum width-2*pgfkeysvalueof/pgf/inner xsep,
 minimum height=1cm, align=center,
 font=footnotesize,
box/.default = 21mm/green,
 

begindocument
begintikzpicture[
node distance = 2mm and 2mm,
 start chain = going right,
 ]
beginscope[every node/.style=box, on chain]
 node (r1c1) VC++;
 node (r1c2) VB.NET;
 node (r1c3) C#.NET;
 node (r1c4) Others;
endscope
draw let p1 = ($(r1c4.east)-(r1c1.west)$),
 n1 = veclen(x1,y1) in
 node (r2c1) [box=n1/blue,
 below=of $(r1c1.south)!0.5!(r1c4.south)$]
 COM-API Interface
 node (r3c1) [box=n1/yellow, below=of r2c1]
 Autodesk Inventor Application;
draw let p1 = ($(r1c2.east)-(r1c1.west)$),
 n1 =veclen(x1,y1) in
 node (r4c1) [box=n1/red, on chain,
 below right=2mm and 0mm of r1c1.west |- r3c1.south] aaaa
 node (r4c1) [box=n1/red, on chain] bbbb;
endtikzpicture
enddocument


enter image description here






share|improve this answer






















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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    6
    down vote



    accepted










    documentclass[border=2px]standalone
    usepackage[utf8]inputenc
    usepackagetikz
    usetikzlibraryshapes.geometric, arrows, chains, calc,positioning

    tikzset
     green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
     blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
     yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,
     red/.style=minimum height=1cm, text centered, font=footnotesize, draw=black, fill=red!30


    begindocument
    begintikzpicture[start chain=1 going right,
     start chain=2 going below, node distance=1mm]
     node [name=r1c1, on chain=1, green] VC++;
     node [name=r1c2, on chain=1, green] VB.NET;
     node [name=r1c3, on chain=1, green] C#.NET;
     node [name=r1c4, on chain=1, green] Others;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
     minimum width=n1-pgflinewidth]
     at (r1c1.south west) COM-API Interface;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node [name=r4c1, on chain=2, red,xshift=-0.25*(n1+2*pgflinewidth-0.5*n2), 
     minimum width=0.5*(n1-pgflinewidth+n2)] Pffft;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node[right=1mm of r4c1,
     name=r4c2, red,minimum width=0.5*(n1-pgflinewidth+n2)] Pfffft;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer
















    • 2




      +1 for the great ligatures in the last row ;)
      – Max
      2 days ago






    • 2




      @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
      – marmot
      2 days ago







    • 1




      @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
      – Rmano
      2 days ago










    • @Rmano If you drop one f, the meaning changes completely. ;-)
      – marmot
      2 days ago






    • 1




      @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
      – marmot
      yesterday














    up vote
    6
    down vote



    accepted










    documentclass[border=2px]standalone
    usepackage[utf8]inputenc
    usepackagetikz
    usetikzlibraryshapes.geometric, arrows, chains, calc,positioning

    tikzset
     green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
     blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
     yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,
     red/.style=minimum height=1cm, text centered, font=footnotesize, draw=black, fill=red!30


    begindocument
    begintikzpicture[start chain=1 going right,
     start chain=2 going below, node distance=1mm]
     node [name=r1c1, on chain=1, green] VC++;
     node [name=r1c2, on chain=1, green] VB.NET;
     node [name=r1c3, on chain=1, green] C#.NET;
     node [name=r1c4, on chain=1, green] Others;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
     minimum width=n1-pgflinewidth]
     at (r1c1.south west) COM-API Interface;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node [name=r4c1, on chain=2, red,xshift=-0.25*(n1+2*pgflinewidth-0.5*n2), 
     minimum width=0.5*(n1-pgflinewidth+n2)] Pffft;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node[right=1mm of r4c1,
     name=r4c2, red,minimum width=0.5*(n1-pgflinewidth+n2)] Pfffft;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer
















    • 2




      +1 for the great ligatures in the last row ;)
      – Max
      2 days ago






    • 2




      @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
      – marmot
      2 days ago







    • 1




      @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
      – Rmano
      2 days ago










    • @Rmano If you drop one f, the meaning changes completely. ;-)
      – marmot
      2 days ago






    • 1




      @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
      – marmot
      yesterday












    up vote
    6
    down vote



    accepted







    up vote
    6
    down vote



    accepted






    documentclass[border=2px]standalone
    usepackage[utf8]inputenc
    usepackagetikz
    usetikzlibraryshapes.geometric, arrows, chains, calc,positioning

    tikzset
     green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
     blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
     yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,
     red/.style=minimum height=1cm, text centered, font=footnotesize, draw=black, fill=red!30


    begindocument
    begintikzpicture[start chain=1 going right,
     start chain=2 going below, node distance=1mm]
     node [name=r1c1, on chain=1, green] VC++;
     node [name=r1c2, on chain=1, green] VB.NET;
     node [name=r1c3, on chain=1, green] C#.NET;
     node [name=r1c4, on chain=1, green] Others;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
     minimum width=n1-pgflinewidth]
     at (r1c1.south west) COM-API Interface;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node [name=r4c1, on chain=2, red,xshift=-0.25*(n1+2*pgflinewidth-0.5*n2), 
     minimum width=0.5*(n1-pgflinewidth+n2)] Pffft;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node[right=1mm of r4c1,
     name=r4c2, red,minimum width=0.5*(n1-pgflinewidth+n2)] Pfffft;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer












    documentclass[border=2px]standalone
    usepackage[utf8]inputenc
    usepackagetikz
    usetikzlibraryshapes.geometric, arrows, chains, calc,positioning

    tikzset
     green/.style = draw, rectangle, minimum width=2cm, minimum height=1cm, text centered, text width=1.2cm, font=footnotesize, draw=black, fill=green!30,
     blue/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=blue!30,
     yellow/.style = draw, rectangle, minimum width=8cm+3pgflinewidth, minimum height=1cm, text centered, text width=5.0cm, font=footnotesize, draw=black, fill=yellow!30,
     red/.style=minimum height=1cm, text centered, font=footnotesize, draw=black, fill=red!30


    begindocument
    begintikzpicture[start chain=1 going right,
     start chain=2 going below, node distance=1mm]
     node [name=r1c1, on chain=1, green] VC++;
     node [name=r1c2, on chain=1, green] VB.NET;
     node [name=r1c3, on chain=1, green] C#.NET;
     node [name=r1c4, on chain=1, green] Others;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r2c1, on chain=2, blue, anchor=north west, yshift=-1mm,
     minimum width=n1-pgflinewidth]
     at (r1c1.south west) COM-API Interface;
     draw let p1=($(r1c4.east)-(r1c1.west)$), n1 = veclen(x1,y1) in
     node [name=r3c1, on chain=2, yellow, minimum width=n1-pgflinewidth] Autodesk Inventor Application;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node [name=r4c1, on chain=2, red,xshift=-0.25*(n1+2*pgflinewidth-0.5*n2), 
     minimum width=0.5*(n1-pgflinewidth+n2)] Pffft;
     draw let p1=($(r1c4.east)-(r1c1.west)$),
     p2=($(r1c1.east)-(r1c2.west)$), n1 =veclen(x1,y1),n2=x2 in
     node[right=1mm of r4c1,
     name=r4c2, red,minimum width=0.5*(n1-pgflinewidth+n2)] Pfffft;
    endtikzpicture
    enddocument


    enter image description here







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 2 days ago









    marmot

    56.8k462124




    56.8k462124







    • 2




      +1 for the great ligatures in the last row ;)
      – Max
      2 days ago






    • 2




      @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
      – marmot
      2 days ago







    • 1




      @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
      – Rmano
      2 days ago










    • @Rmano If you drop one f, the meaning changes completely. ;-)
      – marmot
      2 days ago






    • 1




      @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
      – marmot
      yesterday












    • 2




      +1 for the great ligatures in the last row ;)
      – Max
      2 days ago






    • 2




      @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
      – marmot
      2 days ago







    • 1




      @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
      – Rmano
      2 days ago










    • @Rmano If you drop one f, the meaning changes completely. ;-)
      – marmot
      2 days ago






    • 1




      @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
      – marmot
      yesterday







    2




    2




    +1 for the great ligatures in the last row ;)
    – Max
    2 days ago




    +1 for the great ligatures in the last row ;)
    – Max
    2 days ago




    2




    2




    @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
    – marmot
    2 days ago





    @Max This is marmot language. You need to pronounce it as "Pffft". ;-)
    – marmot
    2 days ago





    1




    1




    @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
    – Rmano
    2 days ago




    @marmot but... but... that's Billy the (lobotomized) cat! abcs-of-art.blogspot.com/2007/09/… ;-P
    – Rmano
    2 days ago












    @Rmano If you drop one f, the meaning changes completely. ;-)
    – marmot
    2 days ago




    @Rmano If you drop one f, the meaning changes completely. ;-)
    – marmot
    2 days ago




    1




    1




    @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
    – marmot
    yesterday




    @mike Not, this is the calc syntax. What it does is to set the first point, p1, to the difference between (r1c4.east) and (r1c1.west). With this syntax, x1 will be the x-value of that difference, and y1 the y-value. n1 and n2 are then numbers derived from these coordinates. Specifically, n1 is the length (veclen) of the difference, and n2 is just the x-value of the second point p2. I use the values to compute the shifts of the red boxes and their widths. So if you change the green boxes, the red boxes will automatically adjust themselves.
    – marmot
    yesterday










    up vote
    2
    down vote













    documentclass[border=5pt,tikz]standalone
    usetikzlibraryfit,positioning
     tikzstyles1 = [draw,minimum width=.9cm,minimum height=.7cm,fill=green!20]
     tikzstyles2 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=blue!20]
     tikzstyles3 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=yellow!20]
     tikzstyles4 = [draw,minimum width=3cm,minimum height=.7cm,fill=red!20]
    begindocument
     begintikzpicture
     node[s1] (a) VC++;
     node[s1,right=.1 of a] (b) VB.NET;
     node[s1,right=.1 of b] (c) C#.NET;
     node[s1,right=.1 of c] (d) Others;
     node[s2,xshift=.87cm,below=.1 of b] (e) COM-API Interface;
     node[s3,below=.1 of e] (f) Autodesk Inventor Application;
     node[s4,below=.1 of f.south west,anchor=west,yshift=-.3cm] (foo) Foo;
     node[s4,right=.1 of foo,anchor=west] (bar) Bar;
     node[draw,fit=(a)(bar)] ;
     endtikzpicture
    enddocument


    Here is the output:



    Screenshot






    share|improve this answer






















    • I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
      – current_user
      2 days ago






    • 1




      @marmot: What would I do without a marmot nearby me …
      – current_user
      2 days ago










    • I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
      – mike
      2 days ago






    • 1




      I guess the picture I've added was a little misleading in this context. Yes, thank you!
      – mike
      2 days ago






    • 1




      Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
      – TeXnician
      yesterday














    up vote
    2
    down vote













    documentclass[border=5pt,tikz]standalone
    usetikzlibraryfit,positioning
     tikzstyles1 = [draw,minimum width=.9cm,minimum height=.7cm,fill=green!20]
     tikzstyles2 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=blue!20]
     tikzstyles3 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=yellow!20]
     tikzstyles4 = [draw,minimum width=3cm,minimum height=.7cm,fill=red!20]
    begindocument
     begintikzpicture
     node[s1] (a) VC++;
     node[s1,right=.1 of a] (b) VB.NET;
     node[s1,right=.1 of b] (c) C#.NET;
     node[s1,right=.1 of c] (d) Others;
     node[s2,xshift=.87cm,below=.1 of b] (e) COM-API Interface;
     node[s3,below=.1 of e] (f) Autodesk Inventor Application;
     node[s4,below=.1 of f.south west,anchor=west,yshift=-.3cm] (foo) Foo;
     node[s4,right=.1 of foo,anchor=west] (bar) Bar;
     node[draw,fit=(a)(bar)] ;
     endtikzpicture
    enddocument


    Here is the output:



    Screenshot






    share|improve this answer






















    • I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
      – current_user
      2 days ago






    • 1




      @marmot: What would I do without a marmot nearby me …
      – current_user
      2 days ago










    • I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
      – mike
      2 days ago






    • 1




      I guess the picture I've added was a little misleading in this context. Yes, thank you!
      – mike
      2 days ago






    • 1




      Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
      – TeXnician
      yesterday












    up vote
    2
    down vote










    up vote
    2
    down vote









    documentclass[border=5pt,tikz]standalone
    usetikzlibraryfit,positioning
     tikzstyles1 = [draw,minimum width=.9cm,minimum height=.7cm,fill=green!20]
     tikzstyles2 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=blue!20]
     tikzstyles3 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=yellow!20]
     tikzstyles4 = [draw,minimum width=3cm,minimum height=.7cm,fill=red!20]
    begindocument
     begintikzpicture
     node[s1] (a) VC++;
     node[s1,right=.1 of a] (b) VB.NET;
     node[s1,right=.1 of b] (c) C#.NET;
     node[s1,right=.1 of c] (d) Others;
     node[s2,xshift=.87cm,below=.1 of b] (e) COM-API Interface;
     node[s3,below=.1 of e] (f) Autodesk Inventor Application;
     node[s4,below=.1 of f.south west,anchor=west,yshift=-.3cm] (foo) Foo;
     node[s4,right=.1 of foo,anchor=west] (bar) Bar;
     node[draw,fit=(a)(bar)] ;
     endtikzpicture
    enddocument


    Here is the output:



    Screenshot






    share|improve this answer














    documentclass[border=5pt,tikz]standalone
    usetikzlibraryfit,positioning
     tikzstyles1 = [draw,minimum width=.9cm,minimum height=.7cm,fill=green!20]
     tikzstyles2 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=blue!20]
     tikzstyles3 = [draw,minimum width=6.15cm,minimum height=.7cm,fill=yellow!20]
     tikzstyles4 = [draw,minimum width=3cm,minimum height=.7cm,fill=red!20]
    begindocument
     begintikzpicture
     node[s1] (a) VC++;
     node[s1,right=.1 of a] (b) VB.NET;
     node[s1,right=.1 of b] (c) C#.NET;
     node[s1,right=.1 of c] (d) Others;
     node[s2,xshift=.87cm,below=.1 of b] (e) COM-API Interface;
     node[s3,below=.1 of e] (f) Autodesk Inventor Application;
     node[s4,below=.1 of f.south west,anchor=west,yshift=-.3cm] (foo) Foo;
     node[s4,right=.1 of foo,anchor=west] (bar) Bar;
     node[draw,fit=(a)(bar)] ;
     endtikzpicture
    enddocument


    Here is the output:



    Screenshot







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 days ago

























    answered 2 days ago









    current_user

    2,5741428




    2,5741428











    • I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
      – current_user
      2 days ago






    • 1




      @marmot: What would I do without a marmot nearby me …
      – current_user
      2 days ago










    • I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
      – mike
      2 days ago






    • 1




      I guess the picture I've added was a little misleading in this context. Yes, thank you!
      – mike
      2 days ago






    • 1




      Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
      – TeXnician
      yesterday
















    • I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
      – current_user
      2 days ago






    • 1




      @marmot: What would I do without a marmot nearby me …
      – current_user
      2 days ago










    • I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
      – mike
      2 days ago






    • 1




      I guess the picture I've added was a little misleading in this context. Yes, thank you!
      – mike
      2 days ago






    • 1




      Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
      – TeXnician
      yesterday















    I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
    – current_user
    2 days ago




    I've got this ugly bug again. Could please someone format my code and add at the top of the text my famous "Hello!"? Thank you!
    – current_user
    2 days ago




    1




    1




    @marmot: What would I do without a marmot nearby me …
    – current_user
    2 days ago




    @marmot: What would I do without a marmot nearby me …
    – current_user
    2 days ago












    I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
    – mike
    2 days ago




    I've have to compliment you, because the code looks really clean. But I wanted to add one more row below containing two boxes of equal size. Is that possible with your solution? I guess I have to define s4?
    – mike
    2 days ago




    1




    1




    I guess the picture I've added was a little misleading in this context. Yes, thank you!
    – mike
    2 days ago




    I guess the picture I've added was a little misleading in this context. Yes, thank you!
    – mike
    2 days ago




    1




    1




    Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
    – TeXnician
    yesterday




    Looks good, but concerning the code you might want to use tikzset instead of tikzstyle (see tex.stackexchange.com/a/52379).
    – TeXnician
    yesterday










    up vote
    1
    down vote













    for fun and exercised, a variation of the nice marmot's answer. by changes in definitions of the styles the code 



    documentclass[tikz, margin=3mm]standalone
    usetikzlibrarycalc, chains, positioning

    tikzset
    box/.style args = #1/#2rectangle,
     minimum width=#1, fill=#2!30, draw,
     text width =pgfkeysvalueof/pgf/minimum width-2*pgfkeysvalueof/pgf/inner xsep,
     minimum height=1cm, align=center,
     font=footnotesize,
    box/.default = 21mm/green,
     

    begindocument
    begintikzpicture[
    node distance = 2mm and 2mm,
     start chain = going right,
     ]
    beginscope[every node/.style=box, on chain]
     node (r1c1) VC++;
     node (r1c2) VB.NET;
     node (r1c3) C#.NET;
     node (r1c4) Others;
    endscope
    draw let p1 = ($(r1c4.east)-(r1c1.west)$),
     n1 = veclen(x1,y1) in
     node (r2c1) [box=n1/blue,
     below=of $(r1c1.south)!0.5!(r1c4.south)$]
     COM-API Interface
     node (r3c1) [box=n1/yellow, below=of r2c1]
     Autodesk Inventor Application;
    draw let p1 = ($(r1c2.east)-(r1c1.west)$),
     n1 =veclen(x1,y1) in
     node (r4c1) [box=n1/red, on chain,
     below right=2mm and 0mm of r1c1.west |- r3c1.south] aaaa
     node (r4c1) [box=n1/red, on chain] bbbb;
    endtikzpicture
    enddocument


    enter image description here






    share|improve this answer


























      up vote
      1
      down vote













      for fun and exercised, a variation of the nice marmot's answer. by changes in definitions of the styles the code 



      documentclass[tikz, margin=3mm]standalone
      usetikzlibrarycalc, chains, positioning

      tikzset
      box/.style args = #1/#2rectangle,
       minimum width=#1, fill=#2!30, draw,
       text width =pgfkeysvalueof/pgf/minimum width-2*pgfkeysvalueof/pgf/inner xsep,
       minimum height=1cm, align=center,
       font=footnotesize,
      box/.default = 21mm/green,
       

      begindocument
      begintikzpicture[
      node distance = 2mm and 2mm,
       start chain = going right,
       ]
      beginscope[every node/.style=box, on chain]
       node (r1c1) VC++;
       node (r1c2) VB.NET;
       node (r1c3) C#.NET;
       node (r1c4) Others;
      endscope
      draw let p1 = ($(r1c4.east)-(r1c1.west)$),
       n1 = veclen(x1,y1) in
       node (r2c1) [box=n1/blue,
       below=of $(r1c1.south)!0.5!(r1c4.south)$]
       COM-API Interface
       node (r3c1) [box=n1/yellow, below=of r2c1]
       Autodesk Inventor Application;
      draw let p1 = ($(r1c2.east)-(r1c1.west)$),
       n1 =veclen(x1,y1) in
       node (r4c1) [box=n1/red, on chain,
       below right=2mm and 0mm of r1c1.west |- r3c1.south] aaaa
       node (r4c1) [box=n1/red, on chain] bbbb;
      endtikzpicture
      enddocument


      enter image description here






      share|improve this answer
























        up vote
        1
        down vote










        up vote
        1
        down vote









        for fun and exercised, a variation of the nice marmot's answer. by changes in definitions of the styles the code 



        documentclass[tikz, margin=3mm]standalone
        usetikzlibrarycalc, chains, positioning

        tikzset
        box/.style args = #1/#2rectangle,
         minimum width=#1, fill=#2!30, draw,
         text width =pgfkeysvalueof/pgf/minimum width-2*pgfkeysvalueof/pgf/inner xsep,
         minimum height=1cm, align=center,
         font=footnotesize,
        box/.default = 21mm/green,
         

        begindocument
        begintikzpicture[
        node distance = 2mm and 2mm,
         start chain = going right,
         ]
        beginscope[every node/.style=box, on chain]
         node (r1c1) VC++;
         node (r1c2) VB.NET;
         node (r1c3) C#.NET;
         node (r1c4) Others;
        endscope
        draw let p1 = ($(r1c4.east)-(r1c1.west)$),
         n1 = veclen(x1,y1) in
         node (r2c1) [box=n1/blue,
         below=of $(r1c1.south)!0.5!(r1c4.south)$]
         COM-API Interface
         node (r3c1) [box=n1/yellow, below=of r2c1]
         Autodesk Inventor Application;
        draw let p1 = ($(r1c2.east)-(r1c1.west)$),
         n1 =veclen(x1,y1) in
         node (r4c1) [box=n1/red, on chain,
         below right=2mm and 0mm of r1c1.west |- r3c1.south] aaaa
         node (r4c1) [box=n1/red, on chain] bbbb;
        endtikzpicture
        enddocument


        enter image description here






        share|improve this answer














        for fun and exercised, a variation of the nice marmot's answer. by changes in definitions of the styles the code 



        documentclass[tikz, margin=3mm]standalone
        usetikzlibrarycalc, chains, positioning

        tikzset
        box/.style args = #1/#2rectangle,
         minimum width=#1, fill=#2!30, draw,
         text width =pgfkeysvalueof/pgf/minimum width-2*pgfkeysvalueof/pgf/inner xsep,
         minimum height=1cm, align=center,
         font=footnotesize,
        box/.default = 21mm/green,
         

        begindocument
        begintikzpicture[
        node distance = 2mm and 2mm,
         start chain = going right,
         ]
        beginscope[every node/.style=box, on chain]
         node (r1c1) VC++;
         node (r1c2) VB.NET;
         node (r1c3) C#.NET;
         node (r1c4) Others;
        endscope
        draw let p1 = ($(r1c4.east)-(r1c1.west)$),
         n1 = veclen(x1,y1) in
         node (r2c1) [box=n1/blue,
         below=of $(r1c1.south)!0.5!(r1c4.south)$]
         COM-API Interface
         node (r3c1) [box=n1/yellow, below=of r2c1]
         Autodesk Inventor Application;
        draw let p1 = ($(r1c2.east)-(r1c1.west)$),
         n1 =veclen(x1,y1) in
         node (r4c1) [box=n1/red, on chain,
         below right=2mm and 0mm of r1c1.west |- r3c1.south] aaaa
         node (r4c1) [box=n1/red, on chain] bbbb;
        endtikzpicture
        enddocument


        enter image description here







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 2 days ago









        mike

        1865




        1865










        answered 2 days ago









        Zarko

        112k861150




        112k861150



























             

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