Mixing
Replace a word in list and append to same list
Clash Royale CLAN TAG#URR8PPP
up vote
14
down vote
favorite
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My List:
city=['Venango Municiplaity', 'Waterford ship','New York']
Expected Result:
city = ['Venango Municiplaity ', 'Waterford ship','New York','Venango','Waterford']
Common_words:
common_words = ['ship','municipality']
Scan all the items in My List and strip the common words and re-insert in the same list as shown in Expected Result.
I'm able to search the items which contains the common words but not sure how to replace that with blank and re-insert in My List.
My code so far:
for item in city:
if(any(x in s.lower() for s in item.split(' ') for x in common_words)) :
python list
asked Aug 22 at 7:23
min2bro
1,83011129
add a comment |Â
up vote
14
down vote
favorite
2
My List:
city=['Venango Municiplaity', 'Waterford ship','New York']
Expected Result:
city = ['Venango Municiplaity ', 'Waterford ship','New York','Venango','Waterford']
Common_words:
common_words = ['ship','municipality']
Scan all the items in My List and strip the common words and re-insert in the same list as shown in Expected Result.
I'm able to search the items which contains the common words but not sure how to replace that with blank and re-insert in My List.
My code so far:
for item in city:
if(any(x in s.lower() for s in item.split(' ') for x in common_words)) :
python list
asked Aug 22 at 7:23
min2bro
1,83011129
1
... why are you splittingitemand usingx in s.lower()for each part ofitem? Provided that elements incommon_wordsdo not contain a space you can simply doif any(x in item.lower() for x in common_words). In this case maybe using regexes is simpler... you just need to do areplaced = re.sub('|'.join(map(re.escape, common_words)), item, flags=re.I) if replaced != item: city.append(replaced).
– Giacomo Alzetta
Aug 22 at 7:33
add a comment |Â
up vote
14
down vote
favorite
2
up vote
14
down vote
favorite
2
2
My List:
city=['Venango Municiplaity', 'Waterford ship','New York']
Expected Result:
city = ['Venango Municiplaity ', 'Waterford ship','New York','Venango','Waterford']
Common_words:
common_words = ['ship','municipality']
Scan all the items in My List and strip the common words and re-insert in the same list as shown in Expected Result.
I'm able to search the items which contains the common words but not sure how to replace that with blank and re-insert in My List.
My code so far:
for item in city:
if(any(x in s.lower() for s in item.split(' ') for x in common_words)) :
python list
asked Aug 22 at 7:23
min2bro
1,83011129
My List:
city=['Venango Municiplaity', 'Waterford ship','New York']
Expected Result:
city = ['Venango Municiplaity ', 'Waterford ship','New York','Venango','Waterford']
Common_words:
common_words = ['ship','municipality']
Scan all the items in My List and strip the common words and re-insert in the same list as shown in Expected Result.
I'm able to search the items which contains the common words but not sure how to replace that with blank and re-insert in My List.
My code so far:
for item in city:
if(any(x in s.lower() for s in item.split(' ') for x in common_words)) :
python list
asked Aug 22 at 7:23
min2bro
1,83011129
asked Aug 22 at 7:23
min2bro
1,83011129
asked Aug 22 at 7:23
min2bro
1,83011129
asked Aug 22 at 7:23
min2bro
1,83011129
1,83011129
1
... why are you splittingitemand usingx in s.lower()for each part ofitem? Provided that elements incommon_wordsdo not contain a space you can simply doif any(x in item.lower() for x in common_words). In this case maybe using regexes is simpler... you just need to do areplaced = re.sub('|'.join(map(re.escape, common_words)), item, flags=re.I) if replaced != item: city.append(replaced).
– Giacomo Alzetta
Aug 22 at 7:33
add a comment |Â
1
... why are you splittingitemand usingx in s.lower()for each part ofitem? Provided that elements incommon_wordsdo not contain a space you can simply doif any(x in item.lower() for x in common_words). In this case maybe using regexes is simpler... you just need to do areplaced = re.sub('|'.join(map(re.escape, common_words)), item, flags=re.I) if replaced != item: city.append(replaced).
– Giacomo Alzetta
Aug 22 at 7:33
1
1
... why are you splitting
item and using x in s.lower() for each part of item? Provided that elements in common_words do not contain a space you can simply do if any(x in item.lower() for x in common_words). In this case maybe using regexes is simpler... you just need to do a replaced = re.sub('|'.join(map(re.escape, common_words)), item, flags=re.I) if replaced != item: city.append(replaced).– Giacomo Alzetta
Aug 22 at 7:33
... why are you splitting
item and using x in s.lower() for each part of item? Provided that elements in common_words do not contain a space you can simply do if any(x in item.lower() for x in common_words). In this case maybe using regexes is simpler... you just need to do a replaced = re.sub('|'.join(map(re.escape, common_words)), item, flags=re.I) if replaced != item: city.append(replaced).– Giacomo Alzetta
Aug 22 at 7:33
add a comment |Â
8 Answers
8
active
oldest
votes
up vote
6
down vote
accepted
I have made a small code that works as expected:
city=['Venango Municiplaity', 'Waterford ship','New York']
comwo = ['ship','municipality']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(ii,""))
print(city)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Waterford ']
Note:
The list you have made contains incorrect spelling.
Look at list city's first element VenangoMuniciplaity and second element of common_words municipality
Edit:
So if you also want to replace the space (if any) behind the word then I have made a separate code:
city=['Village home', 'Villagehome','New York']
comwo = ['home']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(" "+ii,"")) if city[i].replace(" "+ii,"") != city[i] else city.append(city[i].replace(ii,""))
print(city)
Output:
['Village home', 'Villagehome', 'New York', 'Village', 'Village']
answered Aug 22 at 7:29
Black Thunder
1,278425
2
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
add a comment |Â
up vote
6
down vote
I suggest you the following solution, using re.sub with flags=re.IGNORECASE to strip the common words ignoring the case:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
toAppend =
for c in city:
for cw in common_words:
if cw.lower() in c.lower().split():
toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())
city += toAppend
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
And here is the ONE-LINE STYLE solution using list comprehension, short but a bit less readable:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Laurent H.
3,7411530
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
@min2bro then changeif cw.lower() in c.lower():toif cw.lower() in map(lambda x: x.lower(), c.split()):Take a look
– Ev. Kounis
Aug 22 at 7:53
You're right ! I have updated my answer withif cw.lower() in c.lower().split()instead ofif cw.lower() in c.lower(). Thanks a lot.
– Laurent H.
Aug 22 at 8:00
add a comment |Â
up vote
5
down vote
You can try it, create new list to save there data should be added to your original list, and then concatenate result:
In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']
In [2]: common_words = ['ship', 'municiplaity']
In [3]: list_add =
In [4]: for item in city:
...: item_words = [s.lower() for s in item.split(' ')]
...: if set(common_words) & set(item_words):
...: new_item = [s for s in item.split(' ') if s.lower() not in common_words]
...: list_add.append(" ".join(new_item))
...:
In [5]: city + list_add
Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:36
Bear Brown
11k81637
add a comment |Â
up vote
4
down vote
This is one approach using Regex.
Demo:
import re
city=['Venango Municiplaity', 'Waterford ship','New York']
common_words = ['ship','municiplaity']
common_words = "(" + "|".join(common_words) + ")"
res =
for i in city:
if re.search(common_words, i, flags=re.IGNORECASE):
res.append(i.strip().split()[0])
print(city + res)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:35
Rakesh
32.7k103568
1
You shouldmap(re.escape, common_words)to handle words containing "special characters".
– Giacomo Alzetta
Aug 22 at 7:36
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
parti.strip().split()[0]is what I am not a fan of.
– Ev. Kounis
Aug 22 at 7:52
add a comment |Â
up vote
3
down vote
Put results in separate list and then use list.extend() to append contents of result list to original list
cities = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'municipality']
add_list =
for city in cities:
rl =
triggered = False
for city_word in city.split():
if city_word.lower() in common_words:
triggered = True
else:
rl.append(city_word)
if triggered:
add_list.append(' '.join(rl))
cities.extend(add_list)
print(cities)
answered Aug 22 at 7:41
leotrubach
1,03669
add a comment |Â
up vote
3
down vote
You can use a list comprehension in order to detect if an item contains something to add to the city list.
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
items_to_add =
for item in city:
toAddition = [word for word in item.split() if word.lower() not in common_words]
if ' '.join(toAddition) != item:
items_to_add.append(' '.join(toAddition))
print(city + items_to_add)
Output
['Venango municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
fiddling with the initial list changes the problem a bit in this case. havingmunicipalityinstead ofmunicipalitymakes it considerably easier.
– Ev. Kounis
Aug 22 at 7:43
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up vote
0
down vote
Just for fun, here's a not robust or particular efficient method
city = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'Municipality']
city + [dict([_.split() for _ in city] + [list(reversed(_.split())) for _ in city]).get(_, '') for _ in common_words]
>>> ['Venango Municipality', 'Waterford ship', 'New York', 'Waterford', 'Venango']
answered Aug 22 at 15:56
bphi
2,13511021
add a comment |Â
up vote
0
down vote
An approach with re module:
import re
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
print(city)
for item in city:
word_list = str(item).split(" ")
for word in word_list:
if word.lower() in common_words:
word_list.remove(word)
city.extend(word_list)
continue
print(city)
output:
['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 28 at 9:41
josephzhong
11
add a comment |Â
8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
6
down vote
accepted
I have made a small code that works as expected:
city=['Venango Municiplaity', 'Waterford ship','New York']
comwo = ['ship','municipality']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(ii,""))
print(city)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Waterford ']
Note:
The list you have made contains incorrect spelling.
Look at list city's first element VenangoMuniciplaity and second element of common_words municipality
Edit:
So if you also want to replace the space (if any) behind the word then I have made a separate code:
city=['Village home', 'Villagehome','New York']
comwo = ['home']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(" "+ii,"")) if city[i].replace(" "+ii,"") != city[i] else city.append(city[i].replace(ii,""))
print(city)
Output:
['Village home', 'Villagehome', 'New York', 'Village', 'Village']
answered Aug 22 at 7:29
Black Thunder
1,278425
2
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
add a comment |Â
up vote
6
down vote
accepted
I have made a small code that works as expected:
city=['Venango Municiplaity', 'Waterford ship','New York']
comwo = ['ship','municipality']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(ii,""))
print(city)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Waterford ']
Note:
The list you have made contains incorrect spelling.
Look at list city's first element VenangoMuniciplaity and second element of common_words municipality
Edit:
So if you also want to replace the space (if any) behind the word then I have made a separate code:
city=['Village home', 'Villagehome','New York']
comwo = ['home']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(" "+ii,"")) if city[i].replace(" "+ii,"") != city[i] else city.append(city[i].replace(ii,""))
print(city)
Output:
['Village home', 'Villagehome', 'New York', 'Village', 'Village']
answered Aug 22 at 7:29
Black Thunder
1,278425
2
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
add a comment |Â
up vote
6
down vote
accepted
up vote
6
down vote
accepted
I have made a small code that works as expected:
city=['Venango Municiplaity', 'Waterford ship','New York']
comwo = ['ship','municipality']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(ii,""))
print(city)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Waterford ']
Note:
The list you have made contains incorrect spelling.
Look at list city's first element VenangoMuniciplaity and second element of common_words municipality
Edit:
So if you also want to replace the space (if any) behind the word then I have made a separate code:
city=['Village home', 'Villagehome','New York']
comwo = ['home']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(" "+ii,"")) if city[i].replace(" "+ii,"") != city[i] else city.append(city[i].replace(ii,""))
print(city)
Output:
['Village home', 'Villagehome', 'New York', 'Village', 'Village']
answered Aug 22 at 7:29
Black Thunder
1,278425
I have made a small code that works as expected:
city=['Venango Municiplaity', 'Waterford ship','New York']
comwo = ['ship','municipality']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(ii,""))
print(city)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Waterford ']
Note:
The list you have made contains incorrect spelling.
Look at list city's first element VenangoMuniciplaity and second element of common_words municipality
Edit:
So if you also want to replace the space (if any) behind the word then I have made a separate code:
city=['Village home', 'Villagehome','New York']
comwo = ['home']
for i, c in enumerate(city):
for ii in comwo:
if ii in c:
city.append(city[i].replace(" "+ii,"")) if city[i].replace(" "+ii,"") != city[i] else city.append(city[i].replace(ii,""))
print(city)
Output:
['Village home', 'Villagehome', 'New York', 'Village', 'Village']
answered Aug 22 at 7:29
Black Thunder
1,278425
edited Aug 30 at 9:02
answered Aug 22 at 7:29
Black Thunder
1,278425
answered Aug 22 at 7:29
Black Thunder
1,278425
answered Aug 22 at 7:29
Black Thunder
1,278425
1,278425
2
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
add a comment |Â
2
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
2
2
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@min2bro it replaces the words within the words as well, for example : Villageship to village. And it does not strip trailing whitespaces. And it is case-sensitive.
– Laurent H.
Aug 22 at 8:10
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
@LaurentH. Check the edit.
– Black Thunder
Aug 23 at 6:35
add a comment |Â
up vote
6
down vote
I suggest you the following solution, using re.sub with flags=re.IGNORECASE to strip the common words ignoring the case:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
toAppend =
for c in city:
for cw in common_words:
if cw.lower() in c.lower().split():
toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())
city += toAppend
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
And here is the ONE-LINE STYLE solution using list comprehension, short but a bit less readable:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Laurent H.
3,7411530
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
@min2bro then changeif cw.lower() in c.lower():toif cw.lower() in map(lambda x: x.lower(), c.split()):Take a look
– Ev. Kounis
Aug 22 at 7:53
You're right ! I have updated my answer withif cw.lower() in c.lower().split()instead ofif cw.lower() in c.lower(). Thanks a lot.
– Laurent H.
Aug 22 at 8:00
add a comment |Â
up vote
6
down vote
I suggest you the following solution, using re.sub with flags=re.IGNORECASE to strip the common words ignoring the case:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
toAppend =
for c in city:
for cw in common_words:
if cw.lower() in c.lower().split():
toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())
city += toAppend
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
And here is the ONE-LINE STYLE solution using list comprehension, short but a bit less readable:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Laurent H.
3,7411530
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
@min2bro then changeif cw.lower() in c.lower():toif cw.lower() in map(lambda x: x.lower(), c.split()):Take a look
– Ev. Kounis
Aug 22 at 7:53
You're right ! I have updated my answer withif cw.lower() in c.lower().split()instead ofif cw.lower() in c.lower(). Thanks a lot.
– Laurent H.
Aug 22 at 8:00
add a comment |Â
up vote
6
down vote
up vote
6
down vote
I suggest you the following solution, using re.sub with flags=re.IGNORECASE to strip the common words ignoring the case:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
toAppend =
for c in city:
for cw in common_words:
if cw.lower() in c.lower().split():
toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())
city += toAppend
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
And here is the ONE-LINE STYLE solution using list comprehension, short but a bit less readable:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Laurent H.
3,7411530
I suggest you the following solution, using re.sub with flags=re.IGNORECASE to strip the common words ignoring the case:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
toAppend =
for c in city:
for cw in common_words:
if cw.lower() in c.lower().split():
toAppend.append(re.sub(cw, "", c, flags=re.IGNORECASE).strip())
city += toAppend
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
And here is the ONE-LINE STYLE solution using list comprehension, short but a bit less readable:
import re
city = ['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
city += [re.sub(cw, "", c, flags=re.IGNORECASE).strip() for c in city for cw in common_words if cw.lower() in c.lower().split()]
print(city) # ['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Laurent H.
3,7411530
edited Aug 22 at 8:17
answered Aug 22 at 7:40
Laurent H.
3,7411530
answered Aug 22 at 7:40
Laurent H.
3,7411530
answered Aug 22 at 7:40
Laurent H.
3,7411530
3,7411530
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
@min2bro then changeif cw.lower() in c.lower():toif cw.lower() in map(lambda x: x.lower(), c.split()):Take a look
– Ev. Kounis
Aug 22 at 7:53
You're right ! I have updated my answer withif cw.lower() in c.lower().split()instead ofif cw.lower() in c.lower(). Thanks a lot.
– Laurent H.
Aug 22 at 8:00
add a comment |Â
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
@min2bro then changeif cw.lower() in c.lower():toif cw.lower() in map(lambda x: x.lower(), c.split()):Take a look
– Ev. Kounis
Aug 22 at 7:53
You're right ! I have updated my answer withif cw.lower() in c.lower().split()instead ofif cw.lower() in c.lower(). Thanks a lot.
– Laurent H.
Aug 22 at 8:00
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
it replace the words within the words as well, for example : Villageship to village
– min2bro
Aug 22 at 7:48
@min2bro then change
if cw.lower() in c.lower(): to if cw.lower() in map(lambda x: x.lower(), c.split()): Take a look– Ev. Kounis
Aug 22 at 7:53
@min2bro then change
if cw.lower() in c.lower(): to if cw.lower() in map(lambda x: x.lower(), c.split()): Take a look– Ev. Kounis
Aug 22 at 7:53
You're right ! I have updated my answer with
if cw.lower() in c.lower().split() instead of if cw.lower() in c.lower(). Thanks a lot.– Laurent H.
Aug 22 at 8:00
You're right ! I have updated my answer with
if cw.lower() in c.lower().split() instead of if cw.lower() in c.lower(). Thanks a lot.– Laurent H.
Aug 22 at 8:00
add a comment |Â
up vote
5
down vote
You can try it, create new list to save there data should be added to your original list, and then concatenate result:
In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']
In [2]: common_words = ['ship', 'municiplaity']
In [3]: list_add =
In [4]: for item in city:
...: item_words = [s.lower() for s in item.split(' ')]
...: if set(common_words) & set(item_words):
...: new_item = [s for s in item.split(' ') if s.lower() not in common_words]
...: list_add.append(" ".join(new_item))
...:
In [5]: city + list_add
Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:36
Bear Brown
11k81637
add a comment |Â
up vote
5
down vote
You can try it, create new list to save there data should be added to your original list, and then concatenate result:
In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']
In [2]: common_words = ['ship', 'municiplaity']
In [3]: list_add =
In [4]: for item in city:
...: item_words = [s.lower() for s in item.split(' ')]
...: if set(common_words) & set(item_words):
...: new_item = [s for s in item.split(' ') if s.lower() not in common_words]
...: list_add.append(" ".join(new_item))
...:
In [5]: city + list_add
Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:36
Bear Brown
11k81637
add a comment |Â
up vote
5
down vote
up vote
5
down vote
You can try it, create new list to save there data should be added to your original list, and then concatenate result:
In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']
In [2]: common_words = ['ship', 'municiplaity']
In [3]: list_add =
In [4]: for item in city:
...: item_words = [s.lower() for s in item.split(' ')]
...: if set(common_words) & set(item_words):
...: new_item = [s for s in item.split(' ') if s.lower() not in common_words]
...: list_add.append(" ".join(new_item))
...:
In [5]: city + list_add
Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:36
Bear Brown
11k81637
You can try it, create new list to save there data should be added to your original list, and then concatenate result:
In [1]: city=['Venango Municiplaity', 'Waterford ship','New York']
In [2]: common_words = ['ship', 'municiplaity']
In [3]: list_add =
In [4]: for item in city:
...: item_words = [s.lower() for s in item.split(' ')]
...: if set(common_words) & set(item_words):
...: new_item = [s for s in item.split(' ') if s.lower() not in common_words]
...: list_add.append(" ".join(new_item))
...:
In [5]: city + list_add
Out[5]: ['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:36
Bear Brown
11k81637
answered Aug 22 at 7:36
Bear Brown
11k81637
answered Aug 22 at 7:36
Bear Brown
11k81637
answered Aug 22 at 7:36
Bear Brown
11k81637
11k81637
add a comment |Â
add a comment |Â
up vote
4
down vote
This is one approach using Regex.
Demo:
import re
city=['Venango Municiplaity', 'Waterford ship','New York']
common_words = ['ship','municiplaity']
common_words = "(" + "|".join(common_words) + ")"
res =
for i in city:
if re.search(common_words, i, flags=re.IGNORECASE):
res.append(i.strip().split()[0])
print(city + res)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:35
Rakesh
32.7k103568
1
You shouldmap(re.escape, common_words)to handle words containing "special characters".
– Giacomo Alzetta
Aug 22 at 7:36
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
parti.strip().split()[0]is what I am not a fan of.
– Ev. Kounis
Aug 22 at 7:52
add a comment |Â
up vote
4
down vote
This is one approach using Regex.
Demo:
import re
city=['Venango Municiplaity', 'Waterford ship','New York']
common_words = ['ship','municiplaity']
common_words = "(" + "|".join(common_words) + ")"
res =
for i in city:
if re.search(common_words, i, flags=re.IGNORECASE):
res.append(i.strip().split()[0])
print(city + res)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:35
Rakesh
32.7k103568
1
You shouldmap(re.escape, common_words)to handle words containing "special characters".
– Giacomo Alzetta
Aug 22 at 7:36
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
parti.strip().split()[0]is what I am not a fan of.
– Ev. Kounis
Aug 22 at 7:52
add a comment |Â
up vote
4
down vote
up vote
4
down vote
This is one approach using Regex.
Demo:
import re
city=['Venango Municiplaity', 'Waterford ship','New York']
common_words = ['ship','municiplaity']
common_words = "(" + "|".join(common_words) + ")"
res =
for i in city:
if re.search(common_words, i, flags=re.IGNORECASE):
res.append(i.strip().split()[0])
print(city + res)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:35
Rakesh
32.7k103568
This is one approach using Regex.
Demo:
import re
city=['Venango Municiplaity', 'Waterford ship','New York']
common_words = ['ship','municiplaity']
common_words = "(" + "|".join(common_words) + ")"
res =
for i in city:
if re.search(common_words, i, flags=re.IGNORECASE):
res.append(i.strip().split()[0])
print(city + res)
Output:
['Venango Municiplaity', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:35
Rakesh
32.7k103568
answered Aug 22 at 7:35
Rakesh
32.7k103568
answered Aug 22 at 7:35
Rakesh
32.7k103568
answered Aug 22 at 7:35
Rakesh
32.7k103568
32.7k103568
1
You shouldmap(re.escape, common_words)to handle words containing "special characters".
– Giacomo Alzetta
Aug 22 at 7:36
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
parti.strip().split()[0]is what I am not a fan of.
– Ev. Kounis
Aug 22 at 7:52
add a comment |Â
1
You shouldmap(re.escape, common_words)to handle words containing "special characters".
– Giacomo Alzetta
Aug 22 at 7:36
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
parti.strip().split()[0]is what I am not a fan of.
– Ev. Kounis
Aug 22 at 7:52
1
1
You should
map(re.escape, common_words) to handle words containing "special characters".– Giacomo Alzetta
Aug 22 at 7:36
You should
map(re.escape, common_words) to handle words containing "special characters".– Giacomo Alzetta
Aug 22 at 7:36
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
if there is an item villageship, it re-inserts it, I just wanted to replace a word in the city.
– min2bro
Aug 22 at 7:51
part
i.strip().split()[0] is what I am not a fan of.– Ev. Kounis
Aug 22 at 7:52
part
i.strip().split()[0] is what I am not a fan of.– Ev. Kounis
Aug 22 at 7:52
add a comment |Â
up vote
3
down vote
Put results in separate list and then use list.extend() to append contents of result list to original list
cities = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'municipality']
add_list =
for city in cities:
rl =
triggered = False
for city_word in city.split():
if city_word.lower() in common_words:
triggered = True
else:
rl.append(city_word)
if triggered:
add_list.append(' '.join(rl))
cities.extend(add_list)
print(cities)
answered Aug 22 at 7:41
leotrubach
1,03669
add a comment |Â
up vote
3
down vote
Put results in separate list and then use list.extend() to append contents of result list to original list
cities = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'municipality']
add_list =
for city in cities:
rl =
triggered = False
for city_word in city.split():
if city_word.lower() in common_words:
triggered = True
else:
rl.append(city_word)
if triggered:
add_list.append(' '.join(rl))
cities.extend(add_list)
print(cities)
answered Aug 22 at 7:41
leotrubach
1,03669
add a comment |Â
up vote
3
down vote
up vote
3
down vote
Put results in separate list and then use list.extend() to append contents of result list to original list
cities = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'municipality']
add_list =
for city in cities:
rl =
triggered = False
for city_word in city.split():
if city_word.lower() in common_words:
triggered = True
else:
rl.append(city_word)
if triggered:
add_list.append(' '.join(rl))
cities.extend(add_list)
print(cities)
answered Aug 22 at 7:41
leotrubach
1,03669
Put results in separate list and then use list.extend() to append contents of result list to original list
cities = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'municipality']
add_list =
for city in cities:
rl =
triggered = False
for city_word in city.split():
if city_word.lower() in common_words:
triggered = True
else:
rl.append(city_word)
if triggered:
add_list.append(' '.join(rl))
cities.extend(add_list)
print(cities)
answered Aug 22 at 7:41
leotrubach
1,03669
answered Aug 22 at 7:41
leotrubach
1,03669
answered Aug 22 at 7:41
leotrubach
1,03669
answered Aug 22 at 7:41
leotrubach
1,03669
1,03669
add a comment |Â
add a comment |Â
up vote
3
down vote
You can use a list comprehension in order to detect if an item contains something to add to the city list.
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
items_to_add =
for item in city:
toAddition = [word for word in item.split() if word.lower() not in common_words]
if ' '.join(toAddition) != item:
items_to_add.append(' '.join(toAddition))
print(city + items_to_add)
Output
['Venango municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
fiddling with the initial list changes the problem a bit in this case. havingmunicipalityinstead ofmunicipalitymakes it considerably easier.
– Ev. Kounis
Aug 22 at 7:43
add a comment |Â
up vote
3
down vote
You can use a list comprehension in order to detect if an item contains something to add to the city list.
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
items_to_add =
for item in city:
toAddition = [word for word in item.split() if word.lower() not in common_words]
if ' '.join(toAddition) != item:
items_to_add.append(' '.join(toAddition))
print(city + items_to_add)
Output
['Venango municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
fiddling with the initial list changes the problem a bit in this case. havingmunicipalityinstead ofmunicipalitymakes it considerably easier.
– Ev. Kounis
Aug 22 at 7:43
add a comment |Â
up vote
3
down vote
up vote
3
down vote
You can use a list comprehension in order to detect if an item contains something to add to the city list.
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
items_to_add =
for item in city:
toAddition = [word for word in item.split() if word.lower() not in common_words]
if ' '.join(toAddition) != item:
items_to_add.append(' '.join(toAddition))
print(city + items_to_add)
Output
['Venango municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
You can use a list comprehension in order to detect if an item contains something to add to the city list.
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
items_to_add =
for item in city:
toAddition = [word for word in item.split() if word.lower() not in common_words]
if ' '.join(toAddition) != item:
items_to_add.append(' '.join(toAddition))
print(city + items_to_add)
Output
['Venango municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
edited Aug 22 at 7:45
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
answered Aug 22 at 7:40
Mihai Alexandru-Ionut
27.4k63363
27.4k63363
fiddling with the initial list changes the problem a bit in this case. havingmunicipalityinstead ofmunicipalitymakes it considerably easier.
– Ev. Kounis
Aug 22 at 7:43
add a comment |Â
fiddling with the initial list changes the problem a bit in this case. havingmunicipalityinstead ofmunicipalitymakes it considerably easier.
– Ev. Kounis
Aug 22 at 7:43
fiddling with the initial list changes the problem a bit in this case. having
municipality instead of municipality makes it considerably easier.– Ev. Kounis
Aug 22 at 7:43
fiddling with the initial list changes the problem a bit in this case. having
municipality instead of municipality makes it considerably easier.– Ev. Kounis
Aug 22 at 7:43
add a comment |Â
up vote
0
down vote
Just for fun, here's a not robust or particular efficient method
city = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'Municipality']
city + [dict([_.split() for _ in city] + [list(reversed(_.split())) for _ in city]).get(_, '') for _ in common_words]
>>> ['Venango Municipality', 'Waterford ship', 'New York', 'Waterford', 'Venango']
answered Aug 22 at 15:56
bphi
2,13511021
add a comment |Â
up vote
0
down vote
Just for fun, here's a not robust or particular efficient method
city = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'Municipality']
city + [dict([_.split() for _ in city] + [list(reversed(_.split())) for _ in city]).get(_, '') for _ in common_words]
>>> ['Venango Municipality', 'Waterford ship', 'New York', 'Waterford', 'Venango']
answered Aug 22 at 15:56
bphi
2,13511021
add a comment |Â
up vote
0
down vote
up vote
0
down vote
Just for fun, here's a not robust or particular efficient method
city = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'Municipality']
city + [dict([_.split() for _ in city] + [list(reversed(_.split())) for _ in city]).get(_, '') for _ in common_words]
>>> ['Venango Municipality', 'Waterford ship', 'New York', 'Waterford', 'Venango']
answered Aug 22 at 15:56
bphi
2,13511021
Just for fun, here's a not robust or particular efficient method
city = ['Venango Municipality', 'Waterford ship', 'New York']
common_words = ['ship', 'Municipality']
city + [dict([_.split() for _ in city] + [list(reversed(_.split())) for _ in city]).get(_, '') for _ in common_words]
>>> ['Venango Municipality', 'Waterford ship', 'New York', 'Waterford', 'Venango']
answered Aug 22 at 15:56
bphi
2,13511021
answered Aug 22 at 15:56
bphi
2,13511021
answered Aug 22 at 15:56
bphi
2,13511021
answered Aug 22 at 15:56
bphi
2,13511021
2,13511021
add a comment |Â
add a comment |Â
up vote
0
down vote
An approach with re module:
import re
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
print(city)
for item in city:
word_list = str(item).split(" ")
for word in word_list:
if word.lower() in common_words:
word_list.remove(word)
city.extend(word_list)
continue
print(city)
output:
['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 28 at 9:41
josephzhong
11
add a comment |Â
up vote
0
down vote
An approach with re module:
import re
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
print(city)
for item in city:
word_list = str(item).split(" ")
for word in word_list:
if word.lower() in common_words:
word_list.remove(word)
city.extend(word_list)
continue
print(city)
output:
['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 28 at 9:41
josephzhong
11
add a comment |Â
up vote
0
down vote
up vote
0
down vote
An approach with re module:
import re
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
print(city)
for item in city:
word_list = str(item).split(" ")
for word in word_list:
if word.lower() in common_words:
word_list.remove(word)
city.extend(word_list)
continue
print(city)
output:
['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 28 at 9:41
josephzhong
11
An approach with re module:
import re
city=['Venango Municipality', 'Waterford ship','New York']
common_words = ['ship','municipality']
print(city)
for item in city:
word_list = str(item).split(" ")
for word in word_list:
if word.lower() in common_words:
word_list.remove(word)
city.extend(word_list)
continue
print(city)
output:
['Venango Municipality', 'Waterford ship', 'New York', 'Venango', 'Waterford']
answered Aug 28 at 9:41
josephzhong
11
answered Aug 28 at 9:41
josephzhong
11
answered Aug 28 at 9:41
josephzhong
11
answered Aug 28 at 9:41
josephzhong
11
11
add a comment |Â
add a comment |Â
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1
... why are you splitting
itemand usingx in s.lower()for each part ofitem? Provided that elements incommon_wordsdo not contain a space you can simply doif any(x in item.lower() for x in common_words). In this case maybe using regexes is simpler... you just need to do areplaced = re.sub('|'.join(map(re.escape, common_words)), item, flags=re.I) if replaced != item: city.append(replaced).– Giacomo Alzetta
Aug 22 at 7:33