Mixing
why is friction acting towards the centre in a level curved road? [duplicate]
Clash Royale CLAN TAG#URR8PPP
up vote
0
down vote
favorite
This question already has an answer here:
Friction of a Car in Motion
4 answers
We all know that friction is a force that opposes motion and is applied in the opposite direction of motion, but in a leveled curved road it becomes the centripetal force and pulls towards the center. Why?
newtonian-mechanics forces friction free-body-diagram centripetal-force
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
asked Sep 2 at 16:02
Daksh Miglani
1285
marked as duplicate by sammy gerbil, Jon Custer, John Rennie newtonian-mechanics
Users with the  newtonian-mechanics badge can single-handedly close newtonian-mechanics questions as duplicates and reopen them as needed.
StackExchange.ready(function()
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();
);
);
);
Sep 6 at 4:59
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |Â
up vote
0
down vote
favorite
This question already has an answer here:
Friction of a Car in Motion
4 answers
We all know that friction is a force that opposes motion and is applied in the opposite direction of motion, but in a leveled curved road it becomes the centripetal force and pulls towards the center. Why?
newtonian-mechanics forces friction free-body-diagram centripetal-force
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
asked Sep 2 at 16:02
Daksh Miglani
1285
marked as duplicate by sammy gerbil, Jon Custer, John Rennie newtonian-mechanics
Users with the  newtonian-mechanics badge can single-handedly close newtonian-mechanics questions as duplicates and reopen them as needed.
StackExchange.ready(function()
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();
);
);
);
Sep 6 at 4:59
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
By definition, circular motion requires a force that constantly points toward the center of the circle. If the friction force on the car pointed in any other direction, the path would not be circular.
– David White
Sep 5 at 17:35
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
This question already has an answer here:
Friction of a Car in Motion
4 answers
We all know that friction is a force that opposes motion and is applied in the opposite direction of motion, but in a leveled curved road it becomes the centripetal force and pulls towards the center. Why?
newtonian-mechanics forces friction free-body-diagram centripetal-force
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
asked Sep 2 at 16:02
Daksh Miglani
1285
This question already has an answer here:
Friction of a Car in Motion
4 answers
We all know that friction is a force that opposes motion and is applied in the opposite direction of motion, but in a leveled curved road it becomes the centripetal force and pulls towards the center. Why?
This question already has an answer here:
Friction of a Car in Motion
4 answers
newtonian-mechanics forces friction free-body-diagram centripetal-force
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
asked Sep 2 at 16:02
Daksh Miglani
1285
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
edited Sep 5 at 16:42
sammy gerbil
21.3k42355
21.3k42355
asked Sep 2 at 16:02
Daksh Miglani
1285
asked Sep 2 at 16:02
Daksh Miglani
1285
asked Sep 2 at 16:02
Daksh Miglani
1285
1285
marked as duplicate by sammy gerbil, Jon Custer, John Rennie newtonian-mechanics
Users with the  newtonian-mechanics badge can single-handedly close newtonian-mechanics questions as duplicates and reopen them as needed.
StackExchange.ready(function()
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();
);
);
);
Sep 6 at 4:59
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by sammy gerbil, Jon Custer, John Rennie newtonian-mechanics
Users with the  newtonian-mechanics badge can single-handedly close newtonian-mechanics questions as duplicates and reopen them as needed.
StackExchange.ready(function()
if (StackExchange.options.isMobile) return;
$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');
$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
transient: false,
position: my: 'bottom left', at: 'top center', offsetTop: -7 ,
dismissable: false,
relativeToBody: true
);
,
function()
StackExchange.helpers.removeMessages();
);
);
);
Sep 6 at 4:59
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
1
By definition, circular motion requires a force that constantly points toward the center of the circle. If the friction force on the car pointed in any other direction, the path would not be circular.
– David White
Sep 5 at 17:35
add a comment |Â
1
By definition, circular motion requires a force that constantly points toward the center of the circle. If the friction force on the car pointed in any other direction, the path would not be circular.
– David White
Sep 5 at 17:35
1
1
By definition, circular motion requires a force that constantly points toward the center of the circle. If the friction force on the car pointed in any other direction, the path would not be circular.
– David White
Sep 5 at 17:35
By definition, circular motion requires a force that constantly points toward the center of the circle. If the friction force on the car pointed in any other direction, the path would not be circular.
– David White
Sep 5 at 17:35
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
4
down vote
accepted
According to the Newton's first law, in the absence of an external force, a car would move along a straight line. When the front wheels of the car are turned to follow a curved road, the car is blocked from moving straight by the friction, serving as that external force.
So, we can say that, if it was not for the friction force, opposing the natural straight movement of the car, the car would not be able to turn or stay on a curved road.
The direction of the friction force is normal to the wheels and their trajectory. So, we can say that the friction force acts along the radius of the trajectory curve, pointing to its center, which makes it a centripetal force.
answered Sep 2 at 17:36
V.F.
7,3362621
add a comment |Â
up vote
1
down vote
Friction doesn't necessarily oppose motion. It only opposes relative motion, we could call it sliding.
- Imagine driving on ice and trying to turn. The cars wheels may turn but the ice is too slippery so the car just continues straight ahead. The turned wheel simply slide over the surface.
- If you instead drive in asphalt, then a friction appears which will prevent you from continuing to slide. The friction will be perpendicular to the turned wheel, because this is the direction in which sliding is to be prevented.
Therefore a not straight ahead friction appears.
If you continue and keep the turning, then the sideways friction component causes a circular motion.
answered Sep 2 at 16:26
Steeven
24.3k557100
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
According to the Newton's first law, in the absence of an external force, a car would move along a straight line. When the front wheels of the car are turned to follow a curved road, the car is blocked from moving straight by the friction, serving as that external force.
So, we can say that, if it was not for the friction force, opposing the natural straight movement of the car, the car would not be able to turn or stay on a curved road.
The direction of the friction force is normal to the wheels and their trajectory. So, we can say that the friction force acts along the radius of the trajectory curve, pointing to its center, which makes it a centripetal force.
answered Sep 2 at 17:36
V.F.
7,3362621
add a comment |Â
up vote
4
down vote
accepted
According to the Newton's first law, in the absence of an external force, a car would move along a straight line. When the front wheels of the car are turned to follow a curved road, the car is blocked from moving straight by the friction, serving as that external force.
So, we can say that, if it was not for the friction force, opposing the natural straight movement of the car, the car would not be able to turn or stay on a curved road.
The direction of the friction force is normal to the wheels and their trajectory. So, we can say that the friction force acts along the radius of the trajectory curve, pointing to its center, which makes it a centripetal force.
answered Sep 2 at 17:36
V.F.
7,3362621
add a comment |Â
up vote
4
down vote
accepted
up vote
4
down vote
accepted
According to the Newton's first law, in the absence of an external force, a car would move along a straight line. When the front wheels of the car are turned to follow a curved road, the car is blocked from moving straight by the friction, serving as that external force.
So, we can say that, if it was not for the friction force, opposing the natural straight movement of the car, the car would not be able to turn or stay on a curved road.
The direction of the friction force is normal to the wheels and their trajectory. So, we can say that the friction force acts along the radius of the trajectory curve, pointing to its center, which makes it a centripetal force.
answered Sep 2 at 17:36
V.F.
7,3362621
According to the Newton's first law, in the absence of an external force, a car would move along a straight line. When the front wheels of the car are turned to follow a curved road, the car is blocked from moving straight by the friction, serving as that external force.
So, we can say that, if it was not for the friction force, opposing the natural straight movement of the car, the car would not be able to turn or stay on a curved road.
The direction of the friction force is normal to the wheels and their trajectory. So, we can say that the friction force acts along the radius of the trajectory curve, pointing to its center, which makes it a centripetal force.
answered Sep 2 at 17:36
V.F.
7,3362621
answered Sep 2 at 17:36
V.F.
7,3362621
answered Sep 2 at 17:36
V.F.
7,3362621
answered Sep 2 at 17:36
V.F.
7,3362621
7,3362621
add a comment |Â
add a comment |Â
up vote
1
down vote
Friction doesn't necessarily oppose motion. It only opposes relative motion, we could call it sliding.
- Imagine driving on ice and trying to turn. The cars wheels may turn but the ice is too slippery so the car just continues straight ahead. The turned wheel simply slide over the surface.
- If you instead drive in asphalt, then a friction appears which will prevent you from continuing to slide. The friction will be perpendicular to the turned wheel, because this is the direction in which sliding is to be prevented.
Therefore a not straight ahead friction appears.
If you continue and keep the turning, then the sideways friction component causes a circular motion.
answered Sep 2 at 16:26
Steeven
24.3k557100
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
add a comment |Â
up vote
1
down vote
Friction doesn't necessarily oppose motion. It only opposes relative motion, we could call it sliding.
- Imagine driving on ice and trying to turn. The cars wheels may turn but the ice is too slippery so the car just continues straight ahead. The turned wheel simply slide over the surface.
- If you instead drive in asphalt, then a friction appears which will prevent you from continuing to slide. The friction will be perpendicular to the turned wheel, because this is the direction in which sliding is to be prevented.
Therefore a not straight ahead friction appears.
If you continue and keep the turning, then the sideways friction component causes a circular motion.
answered Sep 2 at 16:26
Steeven
24.3k557100
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Friction doesn't necessarily oppose motion. It only opposes relative motion, we could call it sliding.
- Imagine driving on ice and trying to turn. The cars wheels may turn but the ice is too slippery so the car just continues straight ahead. The turned wheel simply slide over the surface.
- If you instead drive in asphalt, then a friction appears which will prevent you from continuing to slide. The friction will be perpendicular to the turned wheel, because this is the direction in which sliding is to be prevented.
Therefore a not straight ahead friction appears.
If you continue and keep the turning, then the sideways friction component causes a circular motion.
answered Sep 2 at 16:26
Steeven
24.3k557100
Friction doesn't necessarily oppose motion. It only opposes relative motion, we could call it sliding.
- Imagine driving on ice and trying to turn. The cars wheels may turn but the ice is too slippery so the car just continues straight ahead. The turned wheel simply slide over the surface.
- If you instead drive in asphalt, then a friction appears which will prevent you from continuing to slide. The friction will be perpendicular to the turned wheel, because this is the direction in which sliding is to be prevented.
Therefore a not straight ahead friction appears.
If you continue and keep the turning, then the sideways friction component causes a circular motion.
answered Sep 2 at 16:26
Steeven
24.3k557100
edited Sep 2 at 16:28
answered Sep 2 at 16:26
Steeven
24.3k557100
answered Sep 2 at 16:26
Steeven
24.3k557100
answered Sep 2 at 16:26
Steeven
24.3k557100
24.3k557100
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
add a comment |Â
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
what's asphalt?
– Daksh Miglani
Sep 2 at 16:27
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
but i mean the car is going straight, so friction should be towards the backward direction, or even opposite of sliding. then why is friction = sliding?
– Daksh Miglani
Sep 2 at 16:28
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
@DakshMiglani The car is not going straight if the road is curved. Then is following the road along this curved path. By asphalt I just mean the ground/road.
– Steeven
Sep 2 at 16:30
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
why does the car even slide outwards?
– Daksh Miglani
Sep 2 at 16:40
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
@DakshMiglani I am not sure what you mean. The car follows the curved path because it follows the road. It doesn't slide out.
– Steeven
Sep 2 at 16:59
add a comment |Â
1
By definition, circular motion requires a force that constantly points toward the center of the circle. If the friction force on the car pointed in any other direction, the path would not be circular.
– David White
Sep 5 at 17:35