ksh - subtract 5 minutes from current time

up vote
3
down vote

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I need to get the date and time of the command date minus 5 mins.

date:
29 Aug 2018 21:56:01

result:
29 Aug 2018 21:51:02

I tried to search on the Internet/forums but most of it involved using the -d option and what I have doesn't support the -d option.

This one works on Bash but I need something that works on ksh.

$ printf "%(%d %h %Y %H:%M:%S)Tn" $(( $(printf "%(%s)T") - 5 * 60 ))

edited Sep 3 at 6:06

slmâ™¦

237k65486659

asked Sep 3 at 4:46

WaldenSchmidt

182

What ksh version do you have? ksh --version. And can you also use perl or python?
â€“Â chaos
Sep 3 at 5:34

ksh --version is not working for me. I can use perl.
â€“Â WaldenSchmidt
Sep 3 at 5:43

chaos is indulging in a little GNU Think. (-: The PD Korn shell does not support --version. Neither does the MirBSD Korn shell. The bigger clue as to whether one is using 93 Korn is the 93 in the name of the command, ksh93 as it usually is, not ksh as chaos said (which is PD Korn on several operating systems, not 93 Korn).
â€“Â JdeBP
Sep 3 at 10:44

Why are you demonstrating a 4:59 difference when the title says 5 minutes?
â€“Â Jeff Schaller
Sep 3 at 11:47

add a commentÂ |Â

up vote
3
down vote

favorite

I need to get the date and time of the command date minus 5 mins.

date:
29 Aug 2018 21:56:01

result:
29 Aug 2018 21:51:02

I tried to search on the Internet/forums but most of it involved using the -d option and what I have doesn't support the -d option.

This one works on Bash but I need something that works on ksh.

$ printf "%(%d %h %Y %H:%M:%S)Tn" $(( $(printf "%(%s)T") - 5 * 60 ))

edited Sep 3 at 6:06

slmâ™¦

237k65486659

asked Sep 3 at 4:46

WaldenSchmidt

182

What ksh version do you have? ksh --version. And can you also use perl or python?
â€“Â chaos
Sep 3 at 5:34

ksh --version is not working for me. I can use perl.
â€“Â WaldenSchmidt
Sep 3 at 5:43

chaos is indulging in a little GNU Think. (-: The PD Korn shell does not support --version. Neither does the MirBSD Korn shell. The bigger clue as to whether one is using 93 Korn is the 93 in the name of the command, ksh93 as it usually is, not ksh as chaos said (which is PD Korn on several operating systems, not 93 Korn).
â€“Â JdeBP
Sep 3 at 10:44

Why are you demonstrating a 4:59 difference when the title says 5 minutes?
â€“Â Jeff Schaller
Sep 3 at 11:47

add a commentÂ |Â

up vote
3
down vote

favorite

I need to get the date and time of the command date minus 5 mins.

date:
29 Aug 2018 21:56:01

result:
29 Aug 2018 21:51:02

I tried to search on the Internet/forums but most of it involved using the -d option and what I have doesn't support the -d option.

This one works on Bash but I need something that works on ksh.

$ printf "%(%d %h %Y %H:%M:%S)Tn" $(( $(printf "%(%s)T") - 5 * 60 ))

edited Sep 3 at 6:06

slmâ™¦

237k65486659

asked Sep 3 at 4:46

WaldenSchmidt

182

I need to get the date and time of the command date minus 5 mins.

date:
29 Aug 2018 21:56:01

result:
29 Aug 2018 21:51:02

I tried to search on the Internet/forums but most of it involved using the -d option and what I have doesn't support the -d option.

This one works on Bash but I need something that works on ksh.

$ printf "%(%d %h %Y %H:%M:%S)Tn" $(( $(printf "%(%s)T") - 5 * 60 ))

edited Sep 3 at 6:06

slmâ™¦

237k65486659

asked Sep 3 at 4:46

WaldenSchmidt

182

edited Sep 3 at 6:06

slmâ™¦

237k65486659

edited Sep 3 at 6:06

slmâ™¦

237k65486659

edited Sep 3 at 6:06

slmâ™¦

237k65486659

asked Sep 3 at 4:46

WaldenSchmidt

182

asked Sep 3 at 4:46

WaldenSchmidt

182

asked Sep 3 at 4:46

WaldenSchmidt

182

What ksh version do you have? ksh --version. And can you also use perl or python?
â€“Â chaos
Sep 3 at 5:34

ksh --version is not working for me. I can use perl.
â€“Â WaldenSchmidt
Sep 3 at 5:43

chaos is indulging in a little GNU Think. (-: The PD Korn shell does not support --version. Neither does the MirBSD Korn shell. The bigger clue as to whether one is using 93 Korn is the 93 in the name of the command, ksh93 as it usually is, not ksh as chaos said (which is PD Korn on several operating systems, not 93 Korn).
â€“Â JdeBP
Sep 3 at 10:44

Why are you demonstrating a 4:59 difference when the title says 5 minutes?
â€“Â Jeff Schaller
Sep 3 at 11:47

add a commentÂ |Â

What ksh version do you have? ksh --version. And can you also use perl or python?
â€“Â chaos
Sep 3 at 5:34

ksh --version is not working for me. I can use perl.
â€“Â WaldenSchmidt
Sep 3 at 5:43

chaos is indulging in a little GNU Think. (-: The PD Korn shell does not support --version. Neither does the MirBSD Korn shell. The bigger clue as to whether one is using 93 Korn is the 93 in the name of the command, ksh93 as it usually is, not ksh as chaos said (which is PD Korn on several operating systems, not 93 Korn).
â€“Â JdeBP
Sep 3 at 10:44

Why are you demonstrating a 4:59 difference when the title says 5 minutes?
â€“Â Jeff Schaller
Sep 3 at 11:47

What ksh version do you have? ksh --version. And can you also use perl or python?
â€“Â chaos
Sep 3 at 5:34

ksh --version is not working for me. I can use perl.
â€“Â WaldenSchmidt
Sep 3 at 5:43

chaos is indulging in a little GNU Think. (-: The PD Korn shell does not support --version. Neither does the MirBSD Korn shell. The bigger clue as to whether one is using 93 Korn is the 93 in the name of the command, ksh93 as it usually is, not ksh as chaos said (which is PD Korn on several operating systems, not 93 Korn).
â€“Â JdeBP
Sep 3 at 10:44

Why are you demonstrating a 4:59 difference when the title says 5 minutes?
â€“Â Jeff Schaller
Sep 3 at 11:47

add a commentÂ |Â

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You could use perl:

echo $(( $(printf "%(%s)T") - 5 * 60 )) | perl -lne 'print scalar localtime $_'

Or in pure perl:

perl -le 'print scalar localtime(time()-5*60)'

To format use strftime():

perl -MPOSIX=strftime -le 'print strftime("%d %h %Y %H:%M:%S", localtime(time()-5*60))'

edited Sep 3 at 6:08

answered Sep 3 at 5:52

chaos

33.9k768112

The second one works. Thanks! Im not familiar with perl. How can I convert it to match the format above?
â€“Â WaldenSchmidt
Sep 3 at 6:05

@WaldenSchmidt see my edit
â€“Â chaos
Sep 3 at 6:08

Thanks man! This is perfect!
â€“Â WaldenSchmidt
Sep 3 at 6:09

add a commentÂ |Â

up vote
5
down vote

bash actually copied the %(...)T format from ksh93 but only a small subset.

That's much more powerful in ksh93.

$ date; printf '%(%c)Tn' 'exactly five minutes ago'
Mon 3 Sep 08:08:32 BST 2018
Mon Sep 3 08:03:32 2018

bash only supports Unix epoch times (or -1 for now, though with recent versions you can also get now with a missing argument) while ksh93 supports complex relative (including English like above, crontab, at, ISO 8601:2004 durations) or absolute time specifications (see the test data in the source for some examples).

In ksh93, if you want to pass an epoch time, you use a # prefix:

$ printf '%(%c)Tn' '#0'
Thu Jan 1 00:00:00 1970

(though here, it happens to give the incorrect time for me in a British timezone where epoch time 0 was at 1am)

edited Sep 3 at 9:47

answered Sep 3 at 7:09

StÃ©phane Chazelas

283k53521857

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You could use perl:

echo $(( $(printf "%(%s)T") - 5 * 60 )) | perl -lne 'print scalar localtime $_'

Or in pure perl:

perl -le 'print scalar localtime(time()-5*60)'

To format use strftime():

perl -MPOSIX=strftime -le 'print strftime("%d %h %Y %H:%M:%S", localtime(time()-5*60))'

edited Sep 3 at 6:08

answered Sep 3 at 5:52

chaos

33.9k768112

The second one works. Thanks! Im not familiar with perl. How can I convert it to match the format above?
â€“Â WaldenSchmidt
Sep 3 at 6:05

@WaldenSchmidt see my edit
â€“Â chaos
Sep 3 at 6:08

Thanks man! This is perfect!
â€“Â WaldenSchmidt
Sep 3 at 6:09

add a commentÂ |Â

up vote
2
down vote

accepted

You could use perl:

echo $(( $(printf "%(%s)T") - 5 * 60 )) | perl -lne 'print scalar localtime $_'

Or in pure perl:

perl -le 'print scalar localtime(time()-5*60)'

To format use strftime():

perl -MPOSIX=strftime -le 'print strftime("%d %h %Y %H:%M:%S", localtime(time()-5*60))'

edited Sep 3 at 6:08

answered Sep 3 at 5:52

chaos

33.9k768112

The second one works. Thanks! Im not familiar with perl. How can I convert it to match the format above?
â€“Â WaldenSchmidt
Sep 3 at 6:05

@WaldenSchmidt see my edit
â€“Â chaos
Sep 3 at 6:08

Thanks man! This is perfect!
â€“Â WaldenSchmidt
Sep 3 at 6:09

add a commentÂ |Â

up vote
2
down vote

accepted

You could use perl:

echo $(( $(printf "%(%s)T") - 5 * 60 )) | perl -lne 'print scalar localtime $_'

Or in pure perl:

perl -le 'print scalar localtime(time()-5*60)'

To format use strftime():

perl -MPOSIX=strftime -le 'print strftime("%d %h %Y %H:%M:%S", localtime(time()-5*60))'

edited Sep 3 at 6:08

answered Sep 3 at 5:52

chaos

33.9k768112

You could use perl:

echo $(( $(printf "%(%s)T") - 5 * 60 )) | perl -lne 'print scalar localtime $_'

Or in pure perl:

perl -le 'print scalar localtime(time()-5*60)'

To format use strftime():

perl -MPOSIX=strftime -le 'print strftime("%d %h %Y %H:%M:%S", localtime(time()-5*60))'

edited Sep 3 at 6:08

answered Sep 3 at 5:52

chaos

33.9k768112

edited Sep 3 at 6:08

answered Sep 3 at 5:52

chaos

33.9k768112

answered Sep 3 at 5:52

chaos

33.9k768112

answered Sep 3 at 5:52

chaos

33.9k768112

The second one works. Thanks! Im not familiar with perl. How can I convert it to match the format above?
â€“Â WaldenSchmidt
Sep 3 at 6:05

@WaldenSchmidt see my edit
â€“Â chaos
Sep 3 at 6:08

Thanks man! This is perfect!
â€“Â WaldenSchmidt
Sep 3 at 6:09

add a commentÂ |Â

The second one works. Thanks! Im not familiar with perl. How can I convert it to match the format above?
â€“Â WaldenSchmidt
Sep 3 at 6:05

@WaldenSchmidt see my edit
â€“Â chaos
Sep 3 at 6:08

Thanks man! This is perfect!
â€“Â WaldenSchmidt
Sep 3 at 6:09

The second one works. Thanks! Im not familiar with perl. How can I convert it to match the format above?
â€“Â WaldenSchmidt
Sep 3 at 6:05

@WaldenSchmidt see my edit
â€“Â chaos
Sep 3 at 6:08

Thanks man! This is perfect!
â€“Â WaldenSchmidt
Sep 3 at 6:09

add a commentÂ |Â

up vote
5
down vote

bash actually copied the %(...)T format from ksh93 but only a small subset.

That's much more powerful in ksh93.

$ date; printf '%(%c)Tn' 'exactly five minutes ago'
Mon 3 Sep 08:08:32 BST 2018
Mon Sep 3 08:03:32 2018

In ksh93, if you want to pass an epoch time, you use a # prefix:

$ printf '%(%c)Tn' '#0'
Thu Jan 1 00:00:00 1970

(though here, it happens to give the incorrect time for me in a British timezone where epoch time 0 was at 1am)

edited Sep 3 at 9:47

answered Sep 3 at 7:09

283k53521857

add a commentÂ |Â

up vote
5
down vote

bash actually copied the %(...)T format from ksh93 but only a small subset.

That's much more powerful in ksh93.

$ date; printf '%(%c)Tn' 'exactly five minutes ago'
Mon 3 Sep 08:08:32 BST 2018
Mon Sep 3 08:03:32 2018

In ksh93, if you want to pass an epoch time, you use a # prefix:

$ printf '%(%c)Tn' '#0'
Thu Jan 1 00:00:00 1970

(though here, it happens to give the incorrect time for me in a British timezone where epoch time 0 was at 1am)

edited Sep 3 at 9:47

answered Sep 3 at 7:09

283k53521857

add a commentÂ |Â

up vote
5
down vote

bash actually copied the %(...)T format from ksh93 but only a small subset.

That's much more powerful in ksh93.

$ date; printf '%(%c)Tn' 'exactly five minutes ago'
Mon 3 Sep 08:08:32 BST 2018
Mon Sep 3 08:03:32 2018

In ksh93, if you want to pass an epoch time, you use a # prefix:

$ printf '%(%c)Tn' '#0'
Thu Jan 1 00:00:00 1970

(though here, it happens to give the incorrect time for me in a British timezone where epoch time 0 was at 1am)

edited Sep 3 at 9:47

answered Sep 3 at 7:09

283k53521857

bash actually copied the %(...)T format from ksh93 but only a small subset.

That's much more powerful in ksh93.

$ date; printf '%(%c)Tn' 'exactly five minutes ago'
Mon 3 Sep 08:08:32 BST 2018
Mon Sep 3 08:03:32 2018

In ksh93, if you want to pass an epoch time, you use a # prefix:

$ printf '%(%c)Tn' '#0'
Thu Jan 1 00:00:00 1970

(though here, it happens to give the incorrect time for me in a British timezone where epoch time 0 was at 1am)

edited Sep 3 at 9:47

answered Sep 3 at 7:09

283k53521857

edited Sep 3 at 9:47

answered Sep 3 at 7:09

283k53521857

answered Sep 3 at 7:09

283k53521857

answered Sep 3 at 7:09

283k53521857

add a commentÂ |Â

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