Mixing
Shortest way from pointers to nodes
Clash Royale CLAN TAG#URR8PPP
up vote
5
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Is there a way that the pointers from the callouts use the shortest possible way to the nodes? So this is somehow an optimization problem ;-)
This is my code. The callout part is copied from here.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Edit: My question is how I can optimize the distance from the callout to where the pointers touch the nodes. In the image the green line is shorter than the red one. How do I find the coordinate of the point of the node which is closest to the callout?
tikz-pgf
asked Sep 9 at 20:01
ESV
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
5
down vote
favorite
Is there a way that the pointers from the callouts use the shortest possible way to the nodes? So this is somehow an optimization problem ;-)
This is my code. The callout part is copied from here.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Edit: My question is how I can optimize the distance from the callout to where the pointers touch the nodes. In the image the green line is shorter than the red one. How do I find the coordinate of the point of the node which is closest to the callout?
tikz-pgf
asked Sep 9 at 20:01
ESV
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
pgfpointshapebordermight solve part of your question. For instance the shortest path fromblahto the blue circle is fromblah.south easttopgfpointshapeborderblue circleblah.south east. For shortest paths between rectangles, they are usually from corner to corner.
– Symbol 1
Sep 9 at 20:11
add a comment |Â
up vote
5
down vote
favorite
up vote
5
down vote
favorite
Is there a way that the pointers from the callouts use the shortest possible way to the nodes? So this is somehow an optimization problem ;-)
This is my code. The callout part is copied from here.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Edit: My question is how I can optimize the distance from the callout to where the pointers touch the nodes. In the image the green line is shorter than the red one. How do I find the coordinate of the point of the node which is closest to the callout?
tikz-pgf
asked Sep 9 at 20:01
ESV
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Is there a way that the pointers from the callouts use the shortest possible way to the nodes? So this is somehow an optimization problem ;-)
This is my code. The callout part is copied from here.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Edit: My question is how I can optimize the distance from the callout to where the pointers touch the nodes. In the image the green line is shorter than the red one. How do I find the coordinate of the point of the node which is closest to the callout?
tikz-pgf
tikz-pgf
asked Sep 9 at 20:01
ESV
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Sep 9 at 20:01
ESV
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Sep 9 at 20:55
asked Sep 9 at 20:01
ESV
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Sep 9 at 20:01
ESV
263
asked Sep 9 at 20:01
ESV
263
263
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ESV is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
pgfpointshapebordermight solve part of your question. For instance the shortest path fromblahto the blue circle is fromblah.south easttopgfpointshapeborderblue circleblah.south east. For shortest paths between rectangles, they are usually from corner to corner.
– Symbol 1
Sep 9 at 20:11
add a comment |Â
2
pgfpointshapebordermight solve part of your question. For instance the shortest path fromblahto the blue circle is fromblah.south easttopgfpointshapeborderblue circleblah.south east. For shortest paths between rectangles, they are usually from corner to corner.
– Symbol 1
Sep 9 at 20:11
2
2
pgfpointshapeborder might solve part of your question. For instance the shortest path from blah to the blue circle is from blah.south east to pgfpointshapeborderblue circleblah.south east. For shortest paths between rectangles, they are usually from corner to corner.– Symbol 1
Sep 9 at 20:11
pgfpointshapeborder might solve part of your question. For instance the shortest path from blah to the blue circle is from blah.south east to pgfpointshapeborderblue circleblah.south east. For shortest paths between rectangles, they are usually from corner to corner.– Symbol 1
Sep 9 at 20:11
add a comment |Â
2 Answers
2
active
oldest
votes
up vote
3
down vote
One possibility that is not a real optimization, but can be approached is to use the fit library. This library creates a node that contains all the coordinates. This node is the smallest bounding box that contains all the coordinates.
Once this is done, we can for example place the callout in the center of this bounding box.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
usetikzlibraryfit
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
node[draw=red, fit=(1) (2) (3)](fit) box;
path[custom style] (fit) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Output:
answered Sep 9 at 20:21
AndréC
3,084728
+1.barycentric cs:from the pgfmanual section 13.2.2 might also be a nice option.
– marmot
Sep 9 at 20:24
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
add a comment |Â
up vote
0
down vote
This is only a temporary post till AndréC wakes up. You can do that rather easily using the fact that you already load the calc library, but this code redefines the syntax, i.e. you can no longer put brackets around the pointers.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
let p1=($(target.center)-(callout)$),n1=atan2(y1,x1)+180
in
($(callout)!2pt!-90:(target.center)$)--(target.n1) --
($(callout)!2pt!90:(target.center)$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=1,2,3]blah blah;
endtikzpicture
enddocument
answered Sep 9 at 21:20
marmot
56.8k462124
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
@ESV In this version, you could just give the coordinates names withcoordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer usingpgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.
– marmot
2 days ago
@marmot Feel free to answer this question, I don't know enough about thesystem layerto answer this problem.
– AndréC
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
add a comment |Â
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
One possibility that is not a real optimization, but can be approached is to use the fit library. This library creates a node that contains all the coordinates. This node is the smallest bounding box that contains all the coordinates.
Once this is done, we can for example place the callout in the center of this bounding box.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
usetikzlibraryfit
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
node[draw=red, fit=(1) (2) (3)](fit) box;
path[custom style] (fit) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Output:
answered Sep 9 at 20:21
AndréC
3,084728
+1.barycentric cs:from the pgfmanual section 13.2.2 might also be a nice option.
– marmot
Sep 9 at 20:24
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
add a comment |Â
up vote
3
down vote
One possibility that is not a real optimization, but can be approached is to use the fit library. This library creates a node that contains all the coordinates. This node is the smallest bounding box that contains all the coordinates.
Once this is done, we can for example place the callout in the center of this bounding box.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
usetikzlibraryfit
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
node[draw=red, fit=(1) (2) (3)](fit) box;
path[custom style] (fit) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Output:
answered Sep 9 at 20:21
AndréC
3,084728
+1.barycentric cs:from the pgfmanual section 13.2.2 might also be a nice option.
– marmot
Sep 9 at 20:24
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
add a comment |Â
up vote
3
down vote
up vote
3
down vote
One possibility that is not a real optimization, but can be approached is to use the fit library. This library creates a node that contains all the coordinates. This node is the smallest bounding box that contains all the coordinates.
Once this is done, we can for example place the callout in the center of this bounding box.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
usetikzlibraryfit
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
node[draw=red, fit=(1) (2) (3)](fit) box;
path[custom style] (fit) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Output:
answered Sep 9 at 20:21
AndréC
3,084728
One possibility that is not a real optimization, but can be approached is to use the fit library. This library creates a node that contains all the coordinates. This node is the smallest bounding box that contains all the coordinates.
Once this is done, we can for example place the callout in the center of this bounding box.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
usetikzlibraryfit
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
($(callout)!2pt!-90:target$)--target --($(callout)!2pt!90:target$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
node[draw=red, fit=(1) (2) (3)](fit) box;
path[custom style] (fit) node[callouts=(1.east),(2.west),(3.north west)]blah blah;
endtikzpicture
enddocument
Output:
answered Sep 9 at 20:21
AndréC
3,084728
answered Sep 9 at 20:21
AndréC
3,084728
answered Sep 9 at 20:21
AndréC
3,084728
answered Sep 9 at 20:21
AndréC
3,084728
3,084728
+1.barycentric cs:from the pgfmanual section 13.2.2 might also be a nice option.
– marmot
Sep 9 at 20:24
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
add a comment |Â
+1.barycentric cs:from the pgfmanual section 13.2.2 might also be a nice option.
– marmot
Sep 9 at 20:24
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
+1.
barycentric cs: from the pgfmanual section 13.2.2 might also be a nice option.– marmot
Sep 9 at 20:24
+1.
barycentric cs: from the pgfmanual section 13.2.2 might also be a nice option.– marmot
Sep 9 at 20:24
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
@marmot Yes, that's exactly what I was thinking. I let you write this solution which will be more beautiful because I have to go to sleep.
– AndréC
Sep 9 at 20:28
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
No, please add it to your nice answer. There is no point in having two "competing" answers here. ;-) I will then remove my comments.
– marmot
Sep 9 at 20:31
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
Thanks for your answers. Apparently my question hasn't been clear enough (I'm sorry, I find it quite difficult to describe it). I hope it's clear now what I am after.
– ESV
Sep 9 at 20:56
add a comment |Â
up vote
0
down vote
This is only a temporary post till AndréC wakes up. You can do that rather easily using the fact that you already load the calc library, but this code redefines the syntax, i.e. you can no longer put brackets around the pointers.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
let p1=($(target.center)-(callout)$),n1=atan2(y1,x1)+180
in
($(callout)!2pt!-90:(target.center)$)--(target.n1) --
($(callout)!2pt!90:(target.center)$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=1,2,3]blah blah;
endtikzpicture
enddocument
answered Sep 9 at 21:20
marmot
56.8k462124
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
@ESV In this version, you could just give the coordinates names withcoordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer usingpgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.
– marmot
2 days ago
@marmot Feel free to answer this question, I don't know enough about thesystem layerto answer this problem.
– AndréC
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
add a comment |Â
up vote
0
down vote
This is only a temporary post till AndréC wakes up. You can do that rather easily using the fact that you already load the calc library, but this code redefines the syntax, i.e. you can no longer put brackets around the pointers.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
let p1=($(target.center)-(callout)$),n1=atan2(y1,x1)+180
in
($(callout)!2pt!-90:(target.center)$)--(target.n1) --
($(callout)!2pt!90:(target.center)$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=1,2,3]blah blah;
endtikzpicture
enddocument
answered Sep 9 at 21:20
marmot
56.8k462124
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
@ESV In this version, you could just give the coordinates names withcoordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer usingpgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.
– marmot
2 days ago
@marmot Feel free to answer this question, I don't know enough about thesystem layerto answer this problem.
– AndréC
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
add a comment |Â
up vote
0
down vote
up vote
0
down vote
This is only a temporary post till AndréC wakes up. You can do that rather easily using the fact that you already load the calc library, but this code redefines the syntax, i.e. you can no longer put brackets around the pointers.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
let p1=($(target.center)-(callout)$),n1=atan2(y1,x1)+180
in
($(callout)!2pt!-90:(target.center)$)--(target.n1) --
($(callout)!2pt!90:(target.center)$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=1,2,3]blah blah;
endtikzpicture
enddocument
answered Sep 9 at 21:20
marmot
56.8k462124
This is only a temporary post till AndréC wakes up. You can do that rather easily using the fact that you already load the calc library, but this code redefines the syntax, i.e. you can no longer put brackets around the pointers.
documentclass[border=10mm]standalone
usepackagetikz
usepackage[utf8]inputenc
usepackage[T1]fontenc
usetikzlibrarypositioning,chains, shapes.geometric,decorations.pathreplacing,calc,shadows.blur,shapes
tikzset
add path/.style =
decoration=show path construction,
moveto code=
xdefsavedpathsavedpath (tikzinputsegmentfirst)
,
lineto code=
xdefsavedpathsavedpath -- (tikzinputsegmentlast)
,
curveto code=
xdefsavedpathsavedpath .. controls (tikzinputsegmentsupporta) and (tikzinputsegmentsupportb) ..(tikzinputsegmentlast)
,
closepath code=
xdefsavedpathsavedpath -- cycle
,
decorate
,
store path/.style = add path,
store path/.prefix code=xdefsavedpath,
callouts/.style=
store path,
append after command=
foreach target in #1
let p1=($(target.center)-(callout)$),n1=atan2(y1,x1)+180
in
($(callout)!2pt!-90:(target.center)$)--(target.n1) --
($(callout)!2pt!90:(target.center)$)
savedpath
,
alias=callout
,
custom style/.style=fill=blue!20,text=,
begindocument
begintikzpicture[
[baserect/.style=text width=0.5cm,align=left,draw,,
diam/.style=diamond,draw,align=left,text width=1cm,inner sep=1.5pt,fill=yellow,text=white,minimum size=2cm,
basecirc/.style=circle,draw,align=center,text width=1.5cm,
circ/.style=basecirc,fill=blue!60,text=black]
node [diam] (1) asdf;
node [circ, right=5 of 1] (2) asdf;
node [diam, below=2 of 2] (3) asdf;
path[custom style] (3,1) node[callouts=1,2,3]blah blah;
endtikzpicture
enddocument
answered Sep 9 at 21:20
marmot
56.8k462124
answered Sep 9 at 21:20
marmot
56.8k462124
answered Sep 9 at 21:20
marmot
56.8k462124
answered Sep 9 at 21:20
marmot
56.8k462124
56.8k462124
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
@ESV In this version, you could just give the coordinates names withcoordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer usingpgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.
– marmot
2 days ago
@marmot Feel free to answer this question, I don't know enough about thesystem layerto answer this problem.
– AndréC
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
add a comment |Â
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
@ESV In this version, you could just give the coordinates names withcoordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer usingpgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.
– marmot
2 days ago
@marmot Feel free to answer this question, I don't know enough about thesystem layerto answer this problem.
– AndréC
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
Thanks marmot! I would like to use for one callout normal coordinates. If I just replace the name of the nodes by coordinates it doesn't work. What do I have to do so I can use normal coordinates aswell?
– ESV
2 days ago
@ESV In this version, you could just give the coordinates names with
coordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer using pgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.– marmot
2 days ago
@ESV In this version, you could just give the coordinates names with
coordinate (X) at .... I am actually hoping that Symbol 1 spells out an answer using pgfpointshapeborder. This is the correct way to go. That's why this is only a temporary answer, and I do not want to "steal" the answer from Symbol 1 and/or AndréC.– marmot
2 days ago
@marmot Feel free to answer this question, I don't know enough about the
system layer to answer this problem.– AndréC
2 days ago
@marmot Feel free to answer this question, I don't know enough about the
system layer to answer this problem.– AndréC
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
@AndréC & marmot Thank you both for your answers. The trick with the coordinates works fine for the moment. When I have more time I'll read the respective chapter in the manual and see if I understand it. Otherwise I'll just ask again ;-)
– ESV
2 days ago
add a comment |Â
ESV is a new contributor. Be nice, and check out our Code of Conduct.
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ESV is a new contributor. Be nice, and check out our Code of Conduct.
ESV is a new contributor. Be nice, and check out our Code of Conduct.
ESV is a new contributor. Be nice, and check out our Code of Conduct.
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2
pgfpointshapebordermight solve part of your question. For instance the shortest path fromblahto the blue circle is fromblah.south easttopgfpointshapeborderblue circleblah.south east. For shortest paths between rectangles, they are usually from corner to corner.– Symbol 1
Sep 9 at 20:11