How can I map associations to expressions?

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I have a list of associations, and I would like to make it so that an expression automatically reads the associated data from the associations list, that has the same name, into the expression. An example would be better than words:

The expression:

-0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

The associations:

<|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

I would like the f and p, from the associations list, to be automatically mapped into the expression, so that, in the expression, f would have the value -0.225, and p would have the value 0.26.

Is there any way to do this? Thanks!

replacement associations

share|improve this question

edited Sep 9 at 17:35

kglr

159k8184384

asked Sep 9 at 17:15

Jmeeks29ig

1475

add a comment | 

up vote
7
down vote

favorite

1

I have a list of associations, and I would like to make it so that an expression automatically reads the associated data from the associations list, that has the same name, into the expression. An example would be better than words:

The expression:

-0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

The associations:

<|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

I would like the f and p, from the associations list, to be automatically mapped into the expression, so that, in the expression, f would have the value -0.225, and p would have the value 0.26.

Is there any way to do this? Thanks!

replacement associations

share|improve this question

edited Sep 9 at 17:35

kglr

159k8184384

asked Sep 9 at 17:15

Jmeeks29ig

1475

add a comment | 

up vote
7
down vote

favorite

1

up vote
7
down vote

favorite

1

1

I have a list of associations, and I would like to make it so that an expression automatically reads the associated data from the associations list, that has the same name, into the expression. An example would be better than words:

The expression:

-0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

The associations:

<|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

I would like the f and p, from the associations list, to be automatically mapped into the expression, so that, in the expression, f would have the value -0.225, and p would have the value 0.26.

Is there any way to do this? Thanks!

replacement associations

share|improve this question

edited Sep 9 at 17:35

kglr

159k8184384

asked Sep 9 at 17:15

Jmeeks29ig

1475

I have a list of associations, and I would like to make it so that an expression automatically reads the associated data from the associations list, that has the same name, into the expression. An example would be better than words:

The expression:

-0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

The associations:

<|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

I would like the f and p, from the associations list, to be automatically mapped into the expression, so that, in the expression, f would have the value -0.225, and p would have the value 0.26.

Is there any way to do this? Thanks!

replacement associations

replacement associations

share|improve this question

edited Sep 9 at 17:35

kglr

159k8184384

asked Sep 9 at 17:15

Jmeeks29ig

1475

share|improve this question

edited Sep 9 at 17:35

kglr

159k8184384

asked Sep 9 at 17:15

Jmeeks29ig

1475

share|improve this question

share|improve this question

edited Sep 9 at 17:35

kglr

159k8184384

edited Sep 9 at 17:35

kglr

159k8184384

edited Sep 9 at 17:35

kglr

159k8184384

159k8184384

asked Sep 9 at 17:15

Jmeeks29ig

1475

asked Sep 9 at 17:15

Jmeeks29ig

1475

asked Sep 9 at 17:15

Jmeeks29ig

1475

1475

add a comment | 

add a comment | 

2 Answers
2

active

oldest

votes

up vote
8
down vote



accepted

You can simply use your association as a list of rules to be passed to ReplaceAll, also known as /..

expr = -0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

assoc = <|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

Now

expr /. assoc

or

ReplaceAll[expr, assoc]

will give you the answer, in this case -0.0683299.

share|improve this answer

answered Sep 9 at 17:23

Carl Lange

1,053214

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a bunch, it worked!
  – Jmeeks29ig
  Sep 9 at 17:35
  

  
  
  
  

add a comment | 

up vote
5
down vote

Also

With[f = assoc[f], p = assoc[p], Evaluate @ expr] 

-0.0683299

share|improve this answer

answered Sep 9 at 18:42

kglr

159k8184384

add a comment | 

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
8
down vote



accepted

You can simply use your association as a list of rules to be passed to ReplaceAll, also known as /..

expr = -0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

assoc = <|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

Now

expr /. assoc

or

ReplaceAll[expr, assoc]

will give you the answer, in this case -0.0683299.

share|improve this answer

answered Sep 9 at 17:23

Carl Lange

1,053214

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a bunch, it worked!
  – Jmeeks29ig
  Sep 9 at 17:35
  

  
  
  
  

add a comment | 

up vote
8
down vote



accepted

You can simply use your association as a list of rules to be passed to ReplaceAll, also known as /..

expr = -0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

assoc = <|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

Now

expr /. assoc

or

ReplaceAll[expr, assoc]

will give you the answer, in this case -0.0683299.

share|improve this answer

answered Sep 9 at 17:23

Carl Lange

1,053214

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a bunch, it worked!
  – Jmeeks29ig
  Sep 9 at 17:35
  

  
  
  
  

add a comment | 

up vote
8
down vote



accepted

up vote
8
down vote



accepted

You can simply use your association as a list of rules to be passed to ReplaceAll, also known as /..

expr = -0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

assoc = <|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

Now

expr /. assoc

or

ReplaceAll[expr, assoc]

will give you the answer, in this case -0.0683299.

share|improve this answer

answered Sep 9 at 17:23

Carl Lange

1,053214

You can simply use your association as a list of rules to be passed to ReplaceAll, also known as /..

expr = -0.0441268 (-0.905134 - f + (3.24967 + p)^0.638117)

assoc = <|a -> -0.497445, b -> -0.12459, c -> 0.59053, d -> 0.26936, 
 e -> 0.745094, f -> -0.225087, g -> 0.744386, h -> 0.915999, 
 i -> 0.540287, j -> 0.406811, k -> -0.664433, l -> 0.355135, 
 m -> -0.880653, n -> -0.559651, o -> -0.23426, p -> 0.260966, 
 q -> 0.435459, r -> -0.105631, s -> 0.544961, t -> 0.347138, 
 u -> 0.958919, v -> 0.200587, w -> -0.656598, x -> 0.553327, 
 y -> -0.282113, z -> 0.178719|>

Now

expr /. assoc

or

ReplaceAll[expr, assoc]

will give you the answer, in this case -0.0683299.

share|improve this answer

answered Sep 9 at 17:23

Carl Lange

1,053214

share|improve this answer

share|improve this answer

answered Sep 9 at 17:23

Carl Lange

1,053214

answered Sep 9 at 17:23

Carl Lange

1,053214

answered Sep 9 at 17:23

Carl Lange

1,053214

1,053214

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a bunch, it worked!
  – Jmeeks29ig
  Sep 9 at 17:35
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  Thanks a bunch, it worked!
  – Jmeeks29ig
  Sep 9 at 17:35
  

  
  
  
  

Thanks a bunch, it worked!
– Jmeeks29ig
Sep 9 at 17:35

Thanks a bunch, it worked!
– Jmeeks29ig
Sep 9 at 17:35

add a comment | 

up vote
5
down vote

Also

With[f = assoc[f], p = assoc[p], Evaluate @ expr] 

-0.0683299

share|improve this answer

answered Sep 9 at 18:42

kglr

159k8184384

add a comment | 

up vote
5
down vote

Also

With[f = assoc[f], p = assoc[p], Evaluate @ expr] 

-0.0683299

share|improve this answer

answered Sep 9 at 18:42

kglr

159k8184384

add a comment | 

up vote
5
down vote

up vote
5
down vote

Also

With[f = assoc[f], p = assoc[p], Evaluate @ expr] 

-0.0683299

share|improve this answer

answered Sep 9 at 18:42

kglr

159k8184384

Also

With[f = assoc[f], p = assoc[p], Evaluate @ expr] 

-0.0683299

share|improve this answer

answered Sep 9 at 18:42

kglr

159k8184384

share|improve this answer

share|improve this answer

answered Sep 9 at 18:42

kglr

159k8184384

answered Sep 9 at 18:42

kglr

159k8184384

answered Sep 9 at 18:42

kglr

159k8184384

159k8184384

add a comment | 

add a comment | 

 

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