Can velocity in y axis be equal with velocity in x axis?

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So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?

classical-mechanics mathematical-physics

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asked 47 mins ago

ado sar

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up vote
2
down vote

favorite

So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?

classical-mechanics mathematical-physics

share|cite|improve this question

asked 47 mins ago

ado sar

111

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

up vote
2
down vote

favorite

up vote
2
down vote

favorite

So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?

classical-mechanics mathematical-physics

share|cite|improve this question

asked 47 mins ago

ado sar

111

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?

classical-mechanics mathematical-physics

classical-mechanics mathematical-physics

share|cite|improve this question

asked 47 mins ago

ado sar

111

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|cite|improve this question

asked 47 mins ago

ado sar

111

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|cite|improve this question

share|cite|improve this question

asked 47 mins ago

ado sar

111

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 47 mins ago

ado sar

111

asked 47 mins ago

ado sar

111

111

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

New contributor

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

add a comment | 

3 Answers
3

active

oldest

votes

up vote
2
down vote

$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.

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answered 29 mins ago

my2cts

3,5082416

add a comment | 

up vote
1
down vote

Yes, one can say that $u_y=u_x$.

$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.

When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.

share|cite|improve this answer

edited 7 mins ago

answered 28 mins ago

Philip Wood

6,9293615

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
  – user7777777
  20 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
  – Aaron Stevens
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
  – Philip Wood
  8 mins ago
  
  

  
  
  
  

add a comment | 

up vote
-1
down vote

Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.

share|cite|improve this answer

answered 33 mins ago

Trebor

2348

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
  – jacob1729
  6 mins ago
  

  
  
  
  

add a comment | 

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3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

active

oldest

votes

active

oldest

votes

up vote
2
down vote

$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.

share|cite|improve this answer

answered 29 mins ago

my2cts

3,5082416

add a comment | 

up vote
2
down vote

$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.

share|cite|improve this answer

answered 29 mins ago

my2cts

3,5082416

add a comment | 

up vote
2
down vote

up vote
2
down vote

$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.

share|cite|improve this answer

answered 29 mins ago

my2cts

3,5082416

$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.

share|cite|improve this answer

answered 29 mins ago

my2cts

3,5082416

share|cite|improve this answer

share|cite|improve this answer

answered 29 mins ago

my2cts

3,5082416

answered 29 mins ago

my2cts

3,5082416

answered 29 mins ago

my2cts

3,5082416

3,5082416

add a comment | 

add a comment | 

up vote
1
down vote

Yes, one can say that $u_y=u_x$.

$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.

When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.

share|cite|improve this answer

edited 7 mins ago

answered 28 mins ago

Philip Wood

6,9293615

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
  – user7777777
  20 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
  – Aaron Stevens
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
  – Philip Wood
  8 mins ago
  
  

  
  
  
  

add a comment | 

up vote
1
down vote

Yes, one can say that $u_y=u_x$.

$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.

When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.

share|cite|improve this answer

edited 7 mins ago

answered 28 mins ago

Philip Wood

6,9293615

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
  – user7777777
  20 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
  – Aaron Stevens
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
  – Philip Wood
  8 mins ago
  
  

  
  
  
  

add a comment | 

up vote
1
down vote

up vote
1
down vote

Yes, one can say that $u_y=u_x$.

$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.

When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.

share|cite|improve this answer

edited 7 mins ago

answered 28 mins ago

Philip Wood

6,9293615

Yes, one can say that $u_y=u_x$.

$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.

When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.

share|cite|improve this answer

edited 7 mins ago

answered 28 mins ago

Philip Wood

6,9293615

share|cite|improve this answer

share|cite|improve this answer

edited 7 mins ago

edited 7 mins ago

edited 7 mins ago

answered 28 mins ago

Philip Wood

6,9293615

answered 28 mins ago

Philip Wood

6,9293615

answered 28 mins ago

Philip Wood

6,9293615

6,9293615

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
  – user7777777
  20 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
  – Aaron Stevens
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
  – Philip Wood
  8 mins ago
  
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
  – user7777777
  20 mins ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  @user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
  – Aaron Stevens
  16 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
  – Philip Wood
  8 mins ago
  
  

  
  
  
  

1

1

The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago

The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago

@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago

@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago

I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago

I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago

add a comment | 

up vote
-1
down vote

Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.

share|cite|improve this answer

answered 33 mins ago

Trebor

2348

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
  – jacob1729
  6 mins ago
  

  
  
  
  

add a comment | 

up vote
-1
down vote

Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.

share|cite|improve this answer

answered 33 mins ago

Trebor

2348

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
  – jacob1729
  6 mins ago
  

  
  
  
  

add a comment | 

up vote
-1
down vote

up vote
-1
down vote

Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.

share|cite|improve this answer

answered 33 mins ago

Trebor

2348

Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.

share|cite|improve this answer

answered 33 mins ago

Trebor

2348

share|cite|improve this answer

share|cite|improve this answer

answered 33 mins ago

Trebor

2348

answered 33 mins ago

Trebor

2348

answered 33 mins ago

Trebor

2348

2348

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
  – jacob1729
  6 mins ago
  

  
  
  
  

add a comment | 

• 
  
  
  

  
  

  
  
  
  
  
  

  
  This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
  – jacob1729
  6 mins ago
  

  
  
  
  

This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago

This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago

add a comment | 

ado sar is a new contributor. Be nice, and check out our Code of Conduct.

 

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