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Can velocity in y axis be equal with velocity in x axis?
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So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?
classical-mechanics mathematical-physics
asked 47 mins ago
ado sar
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up vote
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So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?
classical-mechanics mathematical-physics
asked 47 mins ago
ado sar
111
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
up vote
2
down vote
favorite
up vote
2
down vote
favorite
So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?
classical-mechanics mathematical-physics
asked 47 mins ago
ado sar
111
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
So if uy=30 m/s and ux=30 m/s can we say that uy=ux ? my confusion is because velocity is vector they are not equal ( equal in magnitude but not dimension) . But can we say that they are equal in magnitude ?
classical-mechanics mathematical-physics
classical-mechanics mathematical-physics
asked 47 mins ago
ado sar
111
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 47 mins ago
ado sar
111
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 47 mins ago
ado sar
111
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 47 mins ago
ado sar
111
asked 47 mins ago
ado sar
111
111
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ado sar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |Â
add a comment |Â
3 Answers
3
active
oldest
votes
up vote
2
down vote
$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.
answered 29 mins ago
my2cts
3,5082416
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up vote
1
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Yes, one can say that $u_y=u_x$.
$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.
When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.
answered 28 mins ago
Philip Wood
6,9293615
1
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
add a comment |Â
up vote
-1
down vote
Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.
answered 33 mins ago
Trebor
2348
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
add a comment |Â
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
2
down vote
$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.
answered 29 mins ago
my2cts
3,5082416
add a comment |Â
up vote
2
down vote
$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.
answered 29 mins ago
my2cts
3,5082416
add a comment |Â
up vote
2
down vote
up vote
2
down vote
$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.
answered 29 mins ago
my2cts
3,5082416
$u_x$ and $u_y$ are components of a vector and are numbers. In order to write the vector these numbers must be multiplied with unit vectors $hat x$ and $hat y$. Thus one can say that $u_x = u_y$.
answered 29 mins ago
my2cts
3,5082416
answered 29 mins ago
my2cts
3,5082416
answered 29 mins ago
my2cts
3,5082416
answered 29 mins ago
my2cts
3,5082416
3,5082416
add a comment |Â
add a comment |Â
up vote
1
down vote
Yes, one can say that $u_y=u_x$.
$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.
When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.
answered 28 mins ago
Philip Wood
6,9293615
1
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
add a comment |Â
up vote
1
down vote
Yes, one can say that $u_y=u_x$.
$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.
When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.
answered 28 mins ago
Philip Wood
6,9293615
1
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Yes, one can say that $u_y=u_x$.
$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.
When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.
answered 28 mins ago
Philip Wood
6,9293615
Yes, one can say that $u_y=u_x$.
$u_y$ and $u_x$ are scalars. You multiply them by the unit vectors, $vecj$ and $veci$, to get the actual vectors, $u_yvecj$ and $u_xveci$.
When writers refer to 'components' of velocity (or any other vector), you usually have to work out from context whether they mean the scalar coefficients ($u_y$ and $u_x$ in your case) or the vector components, $u_yvecj$ and $u_yveci$. Your context told me that your question was about scalar coefficients.
answered 28 mins ago
Philip Wood
6,9293615
edited 7 mins ago
answered 28 mins ago
Philip Wood
6,9293615
answered 28 mins ago
Philip Wood
6,9293615
answered 28 mins ago
Philip Wood
6,9293615
6,9293615
1
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
add a comment |Â
1
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
1
1
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
The components of a vector aren't scalars. Scalars don't change under coordinate transformations.
– user7777777
20 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
@user7777777 The way you represent components can change under transformation, but if you are working in a certain coordinate system the components can be thought of as scalars.
– Aaron Stevens
16 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
I was using the terms 'scalar component' and 'vector component' as defined by Synge and Griffiths (Principles of Mechanics). But I've changed 'scalar component' to 'scalar coefficient' in my answer, as I think that 'coefficient' is a better word here.
– Philip Wood
8 mins ago
add a comment |Â
up vote
-1
down vote
Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.
answered 33 mins ago
Trebor
2348
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
add a comment |Â
up vote
-1
down vote
Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.
answered 33 mins ago
Trebor
2348
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
add a comment |Â
up vote
-1
down vote
up vote
-1
down vote
Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.
answered 33 mins ago
Trebor
2348
Basically you are right. Velocities are vectors that have directions and magnitudes. When you are referring to the magnitude only, use "speed", which is a scalar.
answered 33 mins ago
Trebor
2348
answered 33 mins ago
Trebor
2348
answered 33 mins ago
Trebor
2348
answered 33 mins ago
Trebor
2348
2348
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
add a comment |Â
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
This does not answer the question, which asks about comparing components of vectors which is a legitimate thing to do.
– jacob1729
6 mins ago
add a comment |Â
ado sar is a new contributor. Be nice, and check out our Code of Conduct.
ado sar is a new contributor. Be nice, and check out our Code of Conduct.
ado sar is a new contributor. Be nice, and check out our Code of Conduct.
ado sar is a new contributor. Be nice, and check out our Code of Conduct.
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