How to I print out the byte size of each file in my bash script?

up vote
2
down vote

favorite

My current code is like so:

scan.sh:

#!/bin/bash
while IFS= read -r line;
do
 byte = $(stat -c%s "$line");
 echo "$line : $byte";
done< <(ls *.$1)

The output would be like this:

./scan.sh cpp
./scan.sh: line 4: byte: command not found
arraysum.cpp :
./scan.sh: line 4: byte: command not found
countLines.cpp :
./scan.sh: line 4: byte: command not found
createtext.cpp :
./scan.sh: line 4: byte: command not found
multiproc1.cpp :
./scan.sh: line 4: byte: command not found
myWc.cpp :
./scan.sh: line 4: byte: command not found
test.cpp :

Basically my code will take 1 syntax and will search the directory based on that syntax, problem is I want it to print out "name of file" + "byte size of file" only I can't seem to get that working.

edited 27 mins ago

Jeff Schaller

33.6k851113

asked 37 mins ago

Li Wang

111

New contributor

It should be byte=$(.... -- get rid of the spaces around the = sign.
â€“Â Stephen Harris
30 mins ago

add a commentÂ |Â

up vote
2
down vote

favorite

My current code is like so:

scan.sh:

#!/bin/bash
while IFS= read -r line;
do
 byte = $(stat -c%s "$line");
 echo "$line : $byte";
done< <(ls *.$1)

The output would be like this:

./scan.sh cpp
./scan.sh: line 4: byte: command not found
arraysum.cpp :
./scan.sh: line 4: byte: command not found
countLines.cpp :
./scan.sh: line 4: byte: command not found
createtext.cpp :
./scan.sh: line 4: byte: command not found
multiproc1.cpp :
./scan.sh: line 4: byte: command not found
myWc.cpp :
./scan.sh: line 4: byte: command not found
test.cpp :

Basically my code will take 1 syntax and will search the directory based on that syntax, problem is I want it to print out "name of file" + "byte size of file" only I can't seem to get that working.

edited 27 mins ago

Jeff Schaller

33.6k851113

asked 37 mins ago

Li Wang

111

New contributor

It should be byte=$(.... -- get rid of the spaces around the = sign.
â€“Â Stephen Harris
30 mins ago

add a commentÂ |Â

up vote
2
down vote

favorite

My current code is like so:

scan.sh:

#!/bin/bash
while IFS= read -r line;
do
 byte = $(stat -c%s "$line");
 echo "$line : $byte";
done< <(ls *.$1)

The output would be like this:

./scan.sh cpp
./scan.sh: line 4: byte: command not found
arraysum.cpp :
./scan.sh: line 4: byte: command not found
countLines.cpp :
./scan.sh: line 4: byte: command not found
createtext.cpp :
./scan.sh: line 4: byte: command not found
multiproc1.cpp :
./scan.sh: line 4: byte: command not found
myWc.cpp :
./scan.sh: line 4: byte: command not found
test.cpp :

Basically my code will take 1 syntax and will search the directory based on that syntax, problem is I want it to print out "name of file" + "byte size of file" only I can't seem to get that working.

edited 27 mins ago

Jeff Schaller

33.6k851113

asked 37 mins ago

Li Wang

111

New contributor

My current code is like so:

scan.sh:

#!/bin/bash
while IFS= read -r line;
do
 byte = $(stat -c%s "$line");
 echo "$line : $byte";
done< <(ls *.$1)

The output would be like this:

./scan.sh cpp
./scan.sh: line 4: byte: command not found
arraysum.cpp :
./scan.sh: line 4: byte: command not found
countLines.cpp :
./scan.sh: line 4: byte: command not found
createtext.cpp :
./scan.sh: line 4: byte: command not found
multiproc1.cpp :
./scan.sh: line 4: byte: command not found
myWc.cpp :
./scan.sh: line 4: byte: command not found
test.cpp :

Basically my code will take 1 syntax and will search the directory based on that syntax, problem is I want it to print out "name of file" + "byte size of file" only I can't seem to get that working.

shell-script files size

edited 27 mins ago

Jeff Schaller

33.6k851113

asked 37 mins ago

Li Wang

111

New contributor

edited 27 mins ago

Jeff Schaller

33.6k851113

asked 37 mins ago

Li Wang

111

New contributor

edited 27 mins ago

Jeff Schaller

33.6k851113

edited 27 mins ago

Jeff Schaller

33.6k851113

edited 27 mins ago

Jeff Schaller

33.6k851113

asked 37 mins ago

Li Wang

111

New contributor

asked 37 mins ago

Li Wang

111

asked 37 mins ago

Li Wang

111

New contributor

Li Wang is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

It should be byte=$(.... -- get rid of the spaces around the = sign.
â€“Â Stephen Harris
30 mins ago

add a commentÂ |Â

It should be byte=$(.... -- get rid of the spaces around the = sign.
â€“Â Stephen Harris
30 mins ago

It should be byte=$(.... -- get rid of the spaces around the = sign.
â€“Â Stephen Harris
30 mins ago

add a commentÂ |Â

1 Answer
1

active

oldest

votes

up vote
3
down vote

In the syntax of Bourne-like shells like bash, there must not be any space around the = sign in assignments.

byte=value

Here though, parsing the output of ls is a bad idea.

You can just write it:

#! /bin/sh -
stat -c '%n: %s' -- *."$1"

If you do need a loop, just write it:

#! /bin/zsh -
for file in *.$1; do
 stat -c '%n: %s' -- $file
done

Or if you have to use bash:

#! /bin/bash -
shopt -s failglob
for file in *."$1"; do
 stat -c '%n: %s' -- "$file"
done

answered 29 mins ago

StÃ©phane Chazelas

287k53530867

add a commentÂ |Â

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1 Answer
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active

oldest

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1 Answer
1

active

oldest

votes

up vote
3
down vote

In the syntax of Bourne-like shells like bash, there must not be any space around the = sign in assignments.

byte=value

Here though, parsing the output of ls is a bad idea.

You can just write it:

#! /bin/sh -
stat -c '%n: %s' -- *."$1"

If you do need a loop, just write it:

#! /bin/zsh -
for file in *.$1; do
 stat -c '%n: %s' -- $file
done

Or if you have to use bash:

#! /bin/bash -
shopt -s failglob
for file in *."$1"; do
 stat -c '%n: %s' -- "$file"
done

answered 29 mins ago

StÃ©phane Chazelas

287k53530867

add a commentÂ |Â

up vote
3
down vote

In the syntax of Bourne-like shells like bash, there must not be any space around the = sign in assignments.

byte=value

Here though, parsing the output of ls is a bad idea.

You can just write it:

#! /bin/sh -
stat -c '%n: %s' -- *."$1"

If you do need a loop, just write it:

#! /bin/zsh -
for file in *.$1; do
 stat -c '%n: %s' -- $file
done

Or if you have to use bash:

#! /bin/bash -
shopt -s failglob
for file in *."$1"; do
 stat -c '%n: %s' -- "$file"
done

answered 29 mins ago

287k53530867

add a commentÂ |Â

up vote
3
down vote

In the syntax of Bourne-like shells like bash, there must not be any space around the = sign in assignments.

byte=value

Here though, parsing the output of ls is a bad idea.

You can just write it:

#! /bin/sh -
stat -c '%n: %s' -- *."$1"

If you do need a loop, just write it:

#! /bin/zsh -
for file in *.$1; do
 stat -c '%n: %s' -- $file
done

Or if you have to use bash:

#! /bin/bash -
shopt -s failglob
for file in *."$1"; do
 stat -c '%n: %s' -- "$file"
done

answered 29 mins ago

287k53530867

In the syntax of Bourne-like shells like bash, there must not be any space around the = sign in assignments.

byte=value

Here though, parsing the output of ls is a bad idea.

You can just write it:

#! /bin/sh -
stat -c '%n: %s' -- *."$1"

If you do need a loop, just write it:

#! /bin/zsh -
for file in *.$1; do
 stat -c '%n: %s' -- $file
done

Or if you have to use bash:

#! /bin/bash -
shopt -s failglob
for file in *."$1"; do
 stat -c '%n: %s' -- "$file"
done

answered 29 mins ago

287k53530867

answered 29 mins ago

287k53530867

answered 29 mins ago

287k53530867

answered 29 mins ago

287k53530867

add a commentÂ |Â

Li Wang is a new contributor. Be nice, and check out our Code of Conduct.

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