Mixing
Rename multiple .txt files changing some characters in specific positions
Clash Royale CLAN TAG#URR8PPP
up vote
5
down vote
favorite
I have a collections of hundreds of .txt files in the same folder in Ubuntu 16.04, and they're named with strings and index numbers, like that:
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
...
a20_s10_e02_skeleton.txt
...
I must remove the 0 (zeros) from every .txt file where the number is smaller than 10, so in the end I'll have:
instead of : a01_s01_e01_skeleton.txt
it will be: a1_s1_e1_skeleton.txt #notice that the 0s are gone.
EDIT
The position of the numbers is always the same, like in the examples. The files have a logic of order, so the renaming process must be totally correct.
How could I do that using the command line?
command-line bash files batch-rename
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
asked Aug 30 at 15:24
Elisa Maria Alves
314
add a comment |Â
up vote
5
down vote
favorite
I have a collections of hundreds of .txt files in the same folder in Ubuntu 16.04, and they're named with strings and index numbers, like that:
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
...
a20_s10_e02_skeleton.txt
...
I must remove the 0 (zeros) from every .txt file where the number is smaller than 10, so in the end I'll have:
instead of : a01_s01_e01_skeleton.txt
it will be: a1_s1_e1_skeleton.txt #notice that the 0s are gone.
EDIT
The position of the numbers is always the same, like in the examples. The files have a logic of order, so the renaming process must be totally correct.
How could I do that using the command line?
command-line bash files batch-rename
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
asked Aug 30 at 15:24
Elisa Maria Alves
314
Useful additional info would be if the position of the numbers in the string is always the same or not, and if possible dupes might occur after renaming. If so, what do do then.
– Jacob Vlijm
Aug 30 at 16:05
The position of the numbers in the string is always the same.
– Elisa Maria Alves
Aug 30 at 16:10
2
Have you tried anything for yourself? Or are you expecting us to write this for you?
– j-money
Aug 30 at 16:41
add a comment |Â
up vote
5
down vote
favorite
up vote
5
down vote
favorite
I have a collections of hundreds of .txt files in the same folder in Ubuntu 16.04, and they're named with strings and index numbers, like that:
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
...
a20_s10_e02_skeleton.txt
...
I must remove the 0 (zeros) from every .txt file where the number is smaller than 10, so in the end I'll have:
instead of : a01_s01_e01_skeleton.txt
it will be: a1_s1_e1_skeleton.txt #notice that the 0s are gone.
EDIT
The position of the numbers is always the same, like in the examples. The files have a logic of order, so the renaming process must be totally correct.
How could I do that using the command line?
command-line bash files batch-rename
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
asked Aug 30 at 15:24
Elisa Maria Alves
314
I have a collections of hundreds of .txt files in the same folder in Ubuntu 16.04, and they're named with strings and index numbers, like that:
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
...
a20_s10_e02_skeleton.txt
...
I must remove the 0 (zeros) from every .txt file where the number is smaller than 10, so in the end I'll have:
instead of : a01_s01_e01_skeleton.txt
it will be: a1_s1_e1_skeleton.txt #notice that the 0s are gone.
EDIT
The position of the numbers is always the same, like in the examples. The files have a logic of order, so the renaming process must be totally correct.
How could I do that using the command line?
command-line bash files batch-rename
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
asked Aug 30 at 15:24
Elisa Maria Alves
314
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
edited Aug 30 at 16:56
Jacob Vlijm
61.8k9120214
61.8k9120214
asked Aug 30 at 15:24
Elisa Maria Alves
314
asked Aug 30 at 15:24
Elisa Maria Alves
314
asked Aug 30 at 15:24
Elisa Maria Alves
314
314
Useful additional info would be if the position of the numbers in the string is always the same or not, and if possible dupes might occur after renaming. If so, what do do then.
– Jacob Vlijm
Aug 30 at 16:05
The position of the numbers in the string is always the same.
– Elisa Maria Alves
Aug 30 at 16:10
2
Have you tried anything for yourself? Or are you expecting us to write this for you?
– j-money
Aug 30 at 16:41
add a comment |Â
Useful additional info would be if the position of the numbers in the string is always the same or not, and if possible dupes might occur after renaming. If so, what do do then.
– Jacob Vlijm
Aug 30 at 16:05
The position of the numbers in the string is always the same.
– Elisa Maria Alves
Aug 30 at 16:10
2
Have you tried anything for yourself? Or are you expecting us to write this for you?
– j-money
Aug 30 at 16:41
Useful additional info would be if the position of the numbers in the string is always the same or not, and if possible dupes might occur after renaming. If so, what do do then.
– Jacob Vlijm
Aug 30 at 16:05
Useful additional info would be if the position of the numbers in the string is always the same or not, and if possible dupes might occur after renaming. If so, what do do then.
– Jacob Vlijm
Aug 30 at 16:05
The position of the numbers in the string is always the same.
– Elisa Maria Alves
Aug 30 at 16:10
The position of the numbers in the string is always the same.
– Elisa Maria Alves
Aug 30 at 16:10
2
2
Have you tried anything for yourself? Or are you expecting us to write this for you?
– j-money
Aug 30 at 16:41
Have you tried anything for yourself? Or are you expecting us to write this for you?
– j-money
Aug 30 at 16:41
add a comment |Â
5 Answers
5
active
oldest
votes
up vote
5
down vote
accepted
Ok, just for fun, no doubt there are shorter cli solutions, but in python, the script below does the job if the directory is "flat" (as you say) and all files in it are valid files to rename. If not, we need to add an exception, so here we go:
import shutil
import sys
import os
dr = sys.argv[1]
for f in os.listdir(dr):
sections = f.split("_")
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
shutil.move(os.path.join(dr, f), os.path.join(dr, newname))
To use:
- Copy the code into an empty file, save it as
rename_stuff.py Run it with the directory as argument:
python3 /path/to/rename_stuff.py </directory/with/files>
As always, first try on a sample directory.
Explanation
Read the files in the directory:
for f in os.listdir(dr):Split the name by "_":
sections = f.split("_")On the first three sections, replace the two (or more) -digit number by its int- ("real") value, so 01 -> 1, 10 -> 10, 020 -> 20, 000300 -> 300 and so on.
Subsequently, glue the sections together again:
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
add a comment |Â
up vote
8
down vote
With the perl rename, you can remove zeroes that occur between a non-digit and a digit.
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ rename -n 's/(?<=D)0+(?=d)//g' *.txt
rename(a01_s01_e01_skeleton.txt, a1_s1_e1_skeleton.txt)
rename(a01_s01_e02_skeleton.txt, a1_s1_e2_skeleton.txt)
rename(a01_s01_e03_skeleton.txt, a1_s1_e3_skeleton.txt)
rename(a01_s02_e01_skeleton.txt, a1_s2_e1_skeleton.txt)
rename(a20_s10_e02_skeleton.txt, a20_s10_e2_skeleton.txt)
rename may or may not be the perl version. On my system it is called file-rename and it has an alternatives symlink as /usr/bin/rename
answered Aug 30 at 16:45
glenn jackman
11.8k2341
add a comment |Â
up vote
5
down vote
Shellscript
Using rename alias rename.ul installed from the package util-linux, I made the following bash shellscript, that I think can do the job for you.
#!/bin/bash
#####################
doer ()
# removes "0" from the string "parameter0"
# for example a0 --> a
rename "s/$10/$1/" *
#####################
# main
#####################
doer a
doer s
doer e
Let us call the shellscript renamer and give it execute permissions.
If zeros to be removed are preceded by other letters than a,s,e, please add a call of doer with those letters into the script and modify the shellscript, if there are instances, not shown by your sample file names, which need more details in the substitute specification (the function doer).
Test
Create and check 'original' files
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ ls -1
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
a20_s10_e02_skeleton.txt
renamer
Run the shellscript
$ ./renamer
Check the result
$ ls -1
a1_s1_e1_skeleton.txt
a1_s1_e2_skeleton.txt
a1_s1_e3_skeleton.txt
a1_s2_e1_skeleton.txt
a20_s10_e2_skeleton.txt
renamer
$
answered Aug 30 at 16:50
sudodus
20.2k32667
1
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.rename "s/[ase]0/$1/" *all by itself does the trick.
– Dennis Williamson
Aug 30 at 21:39
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
@ElisaMariaAlves,renamealiasrename-ulcomes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are otherrenameprograms, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)
– sudodus
Aug 31 at 15:24
 |Â
show 3 more comments
up vote
2
down vote
Perl's rename utility is the best option for this, I think.
rename 's/(w)0(d)/$1$2/g' *.txt
This command will replace all occurrences of a letter followed by a zero followed by a digit, retaining the letter and the digit while discarding the zero, for every text file in the current directory.
answered Sep 4 at 3:20
Bruce H
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
add a comment |Â
up vote
1
down vote
Using zsh:
autoload zmv
zmv 'a(<->)_s(<->)_e(<->)_skeleton.txt' 'a$1#0_s$2#0_e$3#0_skeleton.txt'
answered Aug 30 at 22:10
Roman Odaisky
1112
1
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
1
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
add a comment |Â
5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
Ok, just for fun, no doubt there are shorter cli solutions, but in python, the script below does the job if the directory is "flat" (as you say) and all files in it are valid files to rename. If not, we need to add an exception, so here we go:
import shutil
import sys
import os
dr = sys.argv[1]
for f in os.listdir(dr):
sections = f.split("_")
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
shutil.move(os.path.join(dr, f), os.path.join(dr, newname))
To use:
- Copy the code into an empty file, save it as
rename_stuff.py Run it with the directory as argument:
python3 /path/to/rename_stuff.py </directory/with/files>
As always, first try on a sample directory.
Explanation
Read the files in the directory:
for f in os.listdir(dr):Split the name by "_":
sections = f.split("_")On the first three sections, replace the two (or more) -digit number by its int- ("real") value, so 01 -> 1, 10 -> 10, 020 -> 20, 000300 -> 300 and so on.
Subsequently, glue the sections together again:
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
add a comment |Â
up vote
5
down vote
accepted
Ok, just for fun, no doubt there are shorter cli solutions, but in python, the script below does the job if the directory is "flat" (as you say) and all files in it are valid files to rename. If not, we need to add an exception, so here we go:
import shutil
import sys
import os
dr = sys.argv[1]
for f in os.listdir(dr):
sections = f.split("_")
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
shutil.move(os.path.join(dr, f), os.path.join(dr, newname))
To use:
- Copy the code into an empty file, save it as
rename_stuff.py Run it with the directory as argument:
python3 /path/to/rename_stuff.py </directory/with/files>
As always, first try on a sample directory.
Explanation
Read the files in the directory:
for f in os.listdir(dr):Split the name by "_":
sections = f.split("_")On the first three sections, replace the two (or more) -digit number by its int- ("real") value, so 01 -> 1, 10 -> 10, 020 -> 20, 000300 -> 300 and so on.
Subsequently, glue the sections together again:
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
add a comment |Â
up vote
5
down vote
accepted
up vote
5
down vote
accepted
Ok, just for fun, no doubt there are shorter cli solutions, but in python, the script below does the job if the directory is "flat" (as you say) and all files in it are valid files to rename. If not, we need to add an exception, so here we go:
import shutil
import sys
import os
dr = sys.argv[1]
for f in os.listdir(dr):
sections = f.split("_")
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
shutil.move(os.path.join(dr, f), os.path.join(dr, newname))
To use:
- Copy the code into an empty file, save it as
rename_stuff.py Run it with the directory as argument:
python3 /path/to/rename_stuff.py </directory/with/files>
As always, first try on a sample directory.
Explanation
Read the files in the directory:
for f in os.listdir(dr):Split the name by "_":
sections = f.split("_")On the first three sections, replace the two (or more) -digit number by its int- ("real") value, so 01 -> 1, 10 -> 10, 020 -> 20, 000300 -> 300 and so on.
Subsequently, glue the sections together again:
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
Ok, just for fun, no doubt there are shorter cli solutions, but in python, the script below does the job if the directory is "flat" (as you say) and all files in it are valid files to rename. If not, we need to add an exception, so here we go:
import shutil
import sys
import os
dr = sys.argv[1]
for f in os.listdir(dr):
sections = f.split("_")
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
shutil.move(os.path.join(dr, f), os.path.join(dr, newname))
To use:
- Copy the code into an empty file, save it as
rename_stuff.py Run it with the directory as argument:
python3 /path/to/rename_stuff.py </directory/with/files>
As always, first try on a sample directory.
Explanation
Read the files in the directory:
for f in os.listdir(dr):Split the name by "_":
sections = f.split("_")On the first three sections, replace the two (or more) -digit number by its int- ("real") value, so 01 -> 1, 10 -> 10, 020 -> 20, 000300 -> 300 and so on.
Subsequently, glue the sections together again:
newname = "_".join(
[s[0] + str(int(s[1:])) for s in sections[:3]] + [sections[-1]]
)
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
edited Sep 2 at 19:32
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
answered Aug 30 at 16:45
Jacob Vlijm
61.8k9120214
61.8k9120214
add a comment |Â
add a comment |Â
up vote
8
down vote
With the perl rename, you can remove zeroes that occur between a non-digit and a digit.
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ rename -n 's/(?<=D)0+(?=d)//g' *.txt
rename(a01_s01_e01_skeleton.txt, a1_s1_e1_skeleton.txt)
rename(a01_s01_e02_skeleton.txt, a1_s1_e2_skeleton.txt)
rename(a01_s01_e03_skeleton.txt, a1_s1_e3_skeleton.txt)
rename(a01_s02_e01_skeleton.txt, a1_s2_e1_skeleton.txt)
rename(a20_s10_e02_skeleton.txt, a20_s10_e2_skeleton.txt)
rename may or may not be the perl version. On my system it is called file-rename and it has an alternatives symlink as /usr/bin/rename
answered Aug 30 at 16:45
glenn jackman
11.8k2341
add a comment |Â
up vote
8
down vote
With the perl rename, you can remove zeroes that occur between a non-digit and a digit.
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ rename -n 's/(?<=D)0+(?=d)//g' *.txt
rename(a01_s01_e01_skeleton.txt, a1_s1_e1_skeleton.txt)
rename(a01_s01_e02_skeleton.txt, a1_s1_e2_skeleton.txt)
rename(a01_s01_e03_skeleton.txt, a1_s1_e3_skeleton.txt)
rename(a01_s02_e01_skeleton.txt, a1_s2_e1_skeleton.txt)
rename(a20_s10_e02_skeleton.txt, a20_s10_e2_skeleton.txt)
rename may or may not be the perl version. On my system it is called file-rename and it has an alternatives symlink as /usr/bin/rename
answered Aug 30 at 16:45
glenn jackman
11.8k2341
add a comment |Â
up vote
8
down vote
up vote
8
down vote
With the perl rename, you can remove zeroes that occur between a non-digit and a digit.
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ rename -n 's/(?<=D)0+(?=d)//g' *.txt
rename(a01_s01_e01_skeleton.txt, a1_s1_e1_skeleton.txt)
rename(a01_s01_e02_skeleton.txt, a1_s1_e2_skeleton.txt)
rename(a01_s01_e03_skeleton.txt, a1_s1_e3_skeleton.txt)
rename(a01_s02_e01_skeleton.txt, a1_s2_e1_skeleton.txt)
rename(a20_s10_e02_skeleton.txt, a20_s10_e2_skeleton.txt)
rename may or may not be the perl version. On my system it is called file-rename and it has an alternatives symlink as /usr/bin/rename
answered Aug 30 at 16:45
glenn jackman
11.8k2341
With the perl rename, you can remove zeroes that occur between a non-digit and a digit.
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ rename -n 's/(?<=D)0+(?=d)//g' *.txt
rename(a01_s01_e01_skeleton.txt, a1_s1_e1_skeleton.txt)
rename(a01_s01_e02_skeleton.txt, a1_s1_e2_skeleton.txt)
rename(a01_s01_e03_skeleton.txt, a1_s1_e3_skeleton.txt)
rename(a01_s02_e01_skeleton.txt, a1_s2_e1_skeleton.txt)
rename(a20_s10_e02_skeleton.txt, a20_s10_e2_skeleton.txt)
rename may or may not be the perl version. On my system it is called file-rename and it has an alternatives symlink as /usr/bin/rename
answered Aug 30 at 16:45
glenn jackman
11.8k2341
answered Aug 30 at 16:45
glenn jackman
11.8k2341
answered Aug 30 at 16:45
glenn jackman
11.8k2341
answered Aug 30 at 16:45
glenn jackman
11.8k2341
11.8k2341
add a comment |Â
add a comment |Â
up vote
5
down vote
Shellscript
Using rename alias rename.ul installed from the package util-linux, I made the following bash shellscript, that I think can do the job for you.
#!/bin/bash
#####################
doer ()
# removes "0" from the string "parameter0"
# for example a0 --> a
rename "s/$10/$1/" *
#####################
# main
#####################
doer a
doer s
doer e
Let us call the shellscript renamer and give it execute permissions.
If zeros to be removed are preceded by other letters than a,s,e, please add a call of doer with those letters into the script and modify the shellscript, if there are instances, not shown by your sample file names, which need more details in the substitute specification (the function doer).
Test
Create and check 'original' files
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ ls -1
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
a20_s10_e02_skeleton.txt
renamer
Run the shellscript
$ ./renamer
Check the result
$ ls -1
a1_s1_e1_skeleton.txt
a1_s1_e2_skeleton.txt
a1_s1_e3_skeleton.txt
a1_s2_e1_skeleton.txt
a20_s10_e2_skeleton.txt
renamer
$
answered Aug 30 at 16:50
sudodus
20.2k32667
1
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.rename "s/[ase]0/$1/" *all by itself does the trick.
– Dennis Williamson
Aug 30 at 21:39
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
@ElisaMariaAlves,renamealiasrename-ulcomes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are otherrenameprograms, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)
– sudodus
Aug 31 at 15:24
 |Â
show 3 more comments
up vote
5
down vote
Shellscript
Using rename alias rename.ul installed from the package util-linux, I made the following bash shellscript, that I think can do the job for you.
#!/bin/bash
#####################
doer ()
# removes "0" from the string "parameter0"
# for example a0 --> a
rename "s/$10/$1/" *
#####################
# main
#####################
doer a
doer s
doer e
Let us call the shellscript renamer and give it execute permissions.
If zeros to be removed are preceded by other letters than a,s,e, please add a call of doer with those letters into the script and modify the shellscript, if there are instances, not shown by your sample file names, which need more details in the substitute specification (the function doer).
Test
Create and check 'original' files
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ ls -1
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
a20_s10_e02_skeleton.txt
renamer
Run the shellscript
$ ./renamer
Check the result
$ ls -1
a1_s1_e1_skeleton.txt
a1_s1_e2_skeleton.txt
a1_s1_e3_skeleton.txt
a1_s2_e1_skeleton.txt
a20_s10_e2_skeleton.txt
renamer
$
answered Aug 30 at 16:50
sudodus
20.2k32667
1
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.rename "s/[ase]0/$1/" *all by itself does the trick.
– Dennis Williamson
Aug 30 at 21:39
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
@ElisaMariaAlves,renamealiasrename-ulcomes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are otherrenameprograms, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)
– sudodus
Aug 31 at 15:24
 |Â
show 3 more comments
up vote
5
down vote
up vote
5
down vote
Shellscript
Using rename alias rename.ul installed from the package util-linux, I made the following bash shellscript, that I think can do the job for you.
#!/bin/bash
#####################
doer ()
# removes "0" from the string "parameter0"
# for example a0 --> a
rename "s/$10/$1/" *
#####################
# main
#####################
doer a
doer s
doer e
Let us call the shellscript renamer and give it execute permissions.
If zeros to be removed are preceded by other letters than a,s,e, please add a call of doer with those letters into the script and modify the shellscript, if there are instances, not shown by your sample file names, which need more details in the substitute specification (the function doer).
Test
Create and check 'original' files
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ ls -1
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
a20_s10_e02_skeleton.txt
renamer
Run the shellscript
$ ./renamer
Check the result
$ ls -1
a1_s1_e1_skeleton.txt
a1_s1_e2_skeleton.txt
a1_s1_e3_skeleton.txt
a1_s2_e1_skeleton.txt
a20_s10_e2_skeleton.txt
renamer
$
answered Aug 30 at 16:50
sudodus
20.2k32667
Shellscript
Using rename alias rename.ul installed from the package util-linux, I made the following bash shellscript, that I think can do the job for you.
#!/bin/bash
#####################
doer ()
# removes "0" from the string "parameter0"
# for example a0 --> a
rename "s/$10/$1/" *
#####################
# main
#####################
doer a
doer s
doer e
Let us call the shellscript renamer and give it execute permissions.
If zeros to be removed are preceded by other letters than a,s,e, please add a call of doer with those letters into the script and modify the shellscript, if there are instances, not shown by your sample file names, which need more details in the substitute specification (the function doer).
Test
Create and check 'original' files
$ touch a01_s01_e01_skeleton.txt a01_s01_e02_skeleton.txt a01_s01_e03_skeleton.txt a01_s02_e01_skeleton.txt a20_s10_e02_skeleton.txt
$ ls -1
a01_s01_e01_skeleton.txt
a01_s01_e02_skeleton.txt
a01_s01_e03_skeleton.txt
a01_s02_e01_skeleton.txt
a20_s10_e02_skeleton.txt
renamer
Run the shellscript
$ ./renamer
Check the result
$ ls -1
a1_s1_e1_skeleton.txt
a1_s1_e2_skeleton.txt
a1_s1_e3_skeleton.txt
a1_s2_e1_skeleton.txt
a20_s10_e2_skeleton.txt
renamer
$
answered Aug 30 at 16:50
sudodus
20.2k32667
edited Aug 30 at 18:45
answered Aug 30 at 16:50
sudodus
20.2k32667
answered Aug 30 at 16:50
sudodus
20.2k32667
answered Aug 30 at 16:50
sudodus
20.2k32667
20.2k32667
1
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.rename "s/[ase]0/$1/" *all by itself does the trick.
– Dennis Williamson
Aug 30 at 21:39
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
@ElisaMariaAlves,renamealiasrename-ulcomes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are otherrenameprograms, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)
– sudodus
Aug 31 at 15:24
 |Â
show 3 more comments
1
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.rename "s/[ase]0/$1/" *all by itself does the trick.
– Dennis Williamson
Aug 30 at 21:39
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
@ElisaMariaAlves,renamealiasrename-ulcomes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are otherrenameprograms, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)
– sudodus
Aug 31 at 15:24
1
1
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.
rename "s/[ase]0/$1/" * all by itself does the trick.– Dennis Williamson
Aug 30 at 21:39
why not change your regex to include all your alpha arguments and only run the function once (without any arguments)? Or better yet, just skip defining the function.
rename "s/[ase]0/$1/" * all by itself does the trick.– Dennis Williamson
Aug 30 at 21:39
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
@DennisWilliamson, The command that you suggest does not work for me. I could change my regex to something more complicated or difficult to understand, but if my current script solves the problem of the OP, why make it more complicated? (There is no indication from the OP yet, which answer is preferred for the real case.)
– sudodus
Aug 31 at 4:43
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry I missed that you were also using the argument on the right hand side. You could simply change the whole thing to use capture groups.
– Dennis Williamson
Aug 31 at 12:58
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
Sorry in advance, but I've never worked with shellscript bash files before, and I'm confused about where to save the rename.ul file and how to make it run through the command line.
– Elisa Maria Alves
Aug 31 at 14:42
@ElisaMariaAlves,
rename alias rename-ul comes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are other rename programs, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)– sudodus
Aug 31 at 15:24
@ElisaMariaAlves,
rename alias rename-ul comes with the package util-linux, which is normally installed by default in Ubuntu. So you need not worry about installing it. I mentioned it because there are other rename programs, that might work differently. So it runs when called (by the command line with it) as described in my answer. -- But I understand that you prefer another answer, which is OK for me. That answer is a good one. -- Good luck :-)– sudodus
Aug 31 at 15:24
 |Â
show 3 more comments
up vote
2
down vote
Perl's rename utility is the best option for this, I think.
rename 's/(w)0(d)/$1$2/g' *.txt
This command will replace all occurrences of a letter followed by a zero followed by a digit, retaining the letter and the digit while discarding the zero, for every text file in the current directory.
answered Sep 4 at 3:20
Bruce H
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
add a comment |Â
up vote
2
down vote
Perl's rename utility is the best option for this, I think.
rename 's/(w)0(d)/$1$2/g' *.txt
This command will replace all occurrences of a letter followed by a zero followed by a digit, retaining the letter and the digit while discarding the zero, for every text file in the current directory.
answered Sep 4 at 3:20
Bruce H
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
add a comment |Â
up vote
2
down vote
up vote
2
down vote
Perl's rename utility is the best option for this, I think.
rename 's/(w)0(d)/$1$2/g' *.txt
This command will replace all occurrences of a letter followed by a zero followed by a digit, retaining the letter and the digit while discarding the zero, for every text file in the current directory.
answered Sep 4 at 3:20
Bruce H
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Perl's rename utility is the best option for this, I think.
rename 's/(w)0(d)/$1$2/g' *.txt
This command will replace all occurrences of a letter followed by a zero followed by a digit, retaining the letter and the digit while discarding the zero, for every text file in the current directory.
answered Sep 4 at 3:20
Bruce H
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Sep 4 at 3:20
Bruce H
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered Sep 4 at 3:20
Bruce H
211
answered Sep 4 at 3:20
Bruce H
211
211
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Bruce H is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
add a comment |Â
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
Thanks, I'll test it too.
– Elisa Maria Alves
Sep 4 at 17:50
add a comment |Â
up vote
1
down vote
Using zsh:
autoload zmv
zmv 'a(<->)_s(<->)_e(<->)_skeleton.txt' 'a$1#0_s$2#0_e$3#0_skeleton.txt'
answered Aug 30 at 22:10
Roman Odaisky
1112
1
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
1
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
add a comment |Â
up vote
1
down vote
Using zsh:
autoload zmv
zmv 'a(<->)_s(<->)_e(<->)_skeleton.txt' 'a$1#0_s$2#0_e$3#0_skeleton.txt'
answered Aug 30 at 22:10
Roman Odaisky
1112
1
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
1
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Using zsh:
autoload zmv
zmv 'a(<->)_s(<->)_e(<->)_skeleton.txt' 'a$1#0_s$2#0_e$3#0_skeleton.txt'
answered Aug 30 at 22:10
Roman Odaisky
1112
Using zsh:
autoload zmv
zmv 'a(<->)_s(<->)_e(<->)_skeleton.txt' 'a$1#0_s$2#0_e$3#0_skeleton.txt'
answered Aug 30 at 22:10
Roman Odaisky
1112
edited Aug 31 at 16:04
answered Aug 30 at 22:10
Roman Odaisky
1112
answered Aug 30 at 22:10
Roman Odaisky
1112
answered Aug 30 at 22:10
Roman Odaisky
1112
1112
1
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
1
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
add a comment |Â
1
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
1
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
1
1
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
I do not get it
– Pierre.Vriens
Aug 31 at 4:21
1
1
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
Welcome to Ask Ubuntu :-) Please edit your answer and provide a bit more information on how your command works as a ton of people don't get it (bash is the standard) and then your answer is likely to be deleted because of "low quality" even though it's 100% correct. ¯_(ツ)_/¯
– Fabby
Aug 31 at 23:35
add a comment |Â
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2faskubuntu.com%2fquestions%2f1070540%2frename-multiple-txt-files-changing-some-characters-in-specific-positions%23new-answer', 'question_page');
);
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Useful additional info would be if the position of the numbers in the string is always the same or not, and if possible dupes might occur after renaming. If so, what do do then.
– Jacob Vlijm
Aug 30 at 16:05
The position of the numbers in the string is always the same.
– Elisa Maria Alves
Aug 30 at 16:10
2
Have you tried anything for yourself? Or are you expecting us to write this for you?
– j-money
Aug 30 at 16:41