Find the determinant of a $3AA^t$

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I am trying to find the determinant of $3AA^t$ or $|3AA^t|$



where



$$A = beginbmatrix -1 & 2 \ 2 & 3endbmatrix$$



So I wind up getting:



$$|A| = -3 - 4 = -7 = A^t$$



so $$|3AA^t| = -3 * -7 * -7 = 147$$



Is this right?



My check fails though. I try to find $3AA^t$ and I get this:



$$3AA^t = 3 * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix $$



$$ =beginbmatrix -3 & 6 \ 6 & 9 endbmatrix * beginbmatrix -1 & 2
\ 2 & 3 endbmatrix $$



$$= beginbmatrix -15 & 12 \ 12 & 39 endbmatrix $$



$$= 441$$



which does not $= 147$. Where did I go wrong?







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    up vote
    2
    down vote

    favorite












    I am trying to find the determinant of $3AA^t$ or $|3AA^t|$



    where



    $$A = beginbmatrix -1 & 2 \ 2 & 3endbmatrix$$



    So I wind up getting:



    $$|A| = -3 - 4 = -7 = A^t$$



    so $$|3AA^t| = -3 * -7 * -7 = 147$$



    Is this right?



    My check fails though. I try to find $3AA^t$ and I get this:



    $$3AA^t = 3 * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix $$



    $$ =beginbmatrix -3 & 6 \ 6 & 9 endbmatrix * beginbmatrix -1 & 2
    \ 2 & 3 endbmatrix $$



    $$= beginbmatrix -15 & 12 \ 12 & 39 endbmatrix $$



    $$= 441$$



    which does not $= 147$. Where did I go wrong?







    share|cite|improve this question
























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I am trying to find the determinant of $3AA^t$ or $|3AA^t|$



      where



      $$A = beginbmatrix -1 & 2 \ 2 & 3endbmatrix$$



      So I wind up getting:



      $$|A| = -3 - 4 = -7 = A^t$$



      so $$|3AA^t| = -3 * -7 * -7 = 147$$



      Is this right?



      My check fails though. I try to find $3AA^t$ and I get this:



      $$3AA^t = 3 * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix $$



      $$ =beginbmatrix -3 & 6 \ 6 & 9 endbmatrix * beginbmatrix -1 & 2
      \ 2 & 3 endbmatrix $$



      $$= beginbmatrix -15 & 12 \ 12 & 39 endbmatrix $$



      $$= 441$$



      which does not $= 147$. Where did I go wrong?







      share|cite|improve this question














      I am trying to find the determinant of $3AA^t$ or $|3AA^t|$



      where



      $$A = beginbmatrix -1 & 2 \ 2 & 3endbmatrix$$



      So I wind up getting:



      $$|A| = -3 - 4 = -7 = A^t$$



      so $$|3AA^t| = -3 * -7 * -7 = 147$$



      Is this right?



      My check fails though. I try to find $3AA^t$ and I get this:



      $$3AA^t = 3 * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix * beginbmatrix -1 & 2 \ 2 & 3 endbmatrix $$



      $$ =beginbmatrix -3 & 6 \ 6 & 9 endbmatrix * beginbmatrix -1 & 2
      \ 2 & 3 endbmatrix $$



      $$= beginbmatrix -15 & 12 \ 12 & 39 endbmatrix $$



      $$= 441$$



      which does not $= 147$. Where did I go wrong?









      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Aug 31 at 6:45









      Asaf Karagila♦

      294k31410737




      294k31410737










      asked Aug 30 at 22:18









      Jwan622

      1,75711224




      1,75711224




















          3 Answers
          3






          active

          oldest

          votes

















          up vote
          9
          down vote



          accepted










          If $A$ is an $n times n$ matrix, $det(3A) = det(3I) det(A) = 3^n det(A)$, not $3 det(A)$.






          share|cite|improve this answer



























            up vote
            5
            down vote













            Because if $lambda$ is a scalar and $A$ is a $ntimes n$ matrix, then $det(lambda A)=lambda^ndet A$. That's why you only got $frac13$ of the right answer.






            share|cite|improve this answer



























              up vote
              1
              down vote













              $3$ is a scalar and A is a $2×2$ matrix,then $det(3A)=3^2det(A)$.$$|3AA^t|=3^2×|AA^t|$$
              $$|AA^t|=det left( beginbmatrix -1 & 2 \ 2 & 3 endbmatrix × beginbmatrix -1 & 2 \ 2 & 3 endbmatrix right)=detleft(beginbmatrix
              5 & 4
              \ 4 & 13endbmatrix right)=49$$ $|3AA^t|=9×49=441$.
              Sorry if i do any mistake.






              share|cite|improve this answer






















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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes








                up vote
                9
                down vote



                accepted










                If $A$ is an $n times n$ matrix, $det(3A) = det(3I) det(A) = 3^n det(A)$, not $3 det(A)$.






                share|cite|improve this answer
























                  up vote
                  9
                  down vote



                  accepted










                  If $A$ is an $n times n$ matrix, $det(3A) = det(3I) det(A) = 3^n det(A)$, not $3 det(A)$.






                  share|cite|improve this answer






















                    up vote
                    9
                    down vote



                    accepted







                    up vote
                    9
                    down vote



                    accepted






                    If $A$ is an $n times n$ matrix, $det(3A) = det(3I) det(A) = 3^n det(A)$, not $3 det(A)$.






                    share|cite|improve this answer












                    If $A$ is an $n times n$ matrix, $det(3A) = det(3I) det(A) = 3^n det(A)$, not $3 det(A)$.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Aug 30 at 22:21









                    Robert Israel

                    306k22201443




                    306k22201443




















                        up vote
                        5
                        down vote













                        Because if $lambda$ is a scalar and $A$ is a $ntimes n$ matrix, then $det(lambda A)=lambda^ndet A$. That's why you only got $frac13$ of the right answer.






                        share|cite|improve this answer
























                          up vote
                          5
                          down vote













                          Because if $lambda$ is a scalar and $A$ is a $ntimes n$ matrix, then $det(lambda A)=lambda^ndet A$. That's why you only got $frac13$ of the right answer.






                          share|cite|improve this answer






















                            up vote
                            5
                            down vote










                            up vote
                            5
                            down vote









                            Because if $lambda$ is a scalar and $A$ is a $ntimes n$ matrix, then $det(lambda A)=lambda^ndet A$. That's why you only got $frac13$ of the right answer.






                            share|cite|improve this answer












                            Because if $lambda$ is a scalar and $A$ is a $ntimes n$ matrix, then $det(lambda A)=lambda^ndet A$. That's why you only got $frac13$ of the right answer.







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Aug 30 at 22:23









                            José Carlos Santos

                            120k16101182




                            120k16101182




















                                up vote
                                1
                                down vote













                                $3$ is a scalar and A is a $2×2$ matrix,then $det(3A)=3^2det(A)$.$$|3AA^t|=3^2×|AA^t|$$
                                $$|AA^t|=det left( beginbmatrix -1 & 2 \ 2 & 3 endbmatrix × beginbmatrix -1 & 2 \ 2 & 3 endbmatrix right)=detleft(beginbmatrix
                                5 & 4
                                \ 4 & 13endbmatrix right)=49$$ $|3AA^t|=9×49=441$.
                                Sorry if i do any mistake.






                                share|cite|improve this answer


























                                  up vote
                                  1
                                  down vote













                                  $3$ is a scalar and A is a $2×2$ matrix,then $det(3A)=3^2det(A)$.$$|3AA^t|=3^2×|AA^t|$$
                                  $$|AA^t|=det left( beginbmatrix -1 & 2 \ 2 & 3 endbmatrix × beginbmatrix -1 & 2 \ 2 & 3 endbmatrix right)=detleft(beginbmatrix
                                  5 & 4
                                  \ 4 & 13endbmatrix right)=49$$ $|3AA^t|=9×49=441$.
                                  Sorry if i do any mistake.






                                  share|cite|improve this answer
























                                    up vote
                                    1
                                    down vote










                                    up vote
                                    1
                                    down vote









                                    $3$ is a scalar and A is a $2×2$ matrix,then $det(3A)=3^2det(A)$.$$|3AA^t|=3^2×|AA^t|$$
                                    $$|AA^t|=det left( beginbmatrix -1 & 2 \ 2 & 3 endbmatrix × beginbmatrix -1 & 2 \ 2 & 3 endbmatrix right)=detleft(beginbmatrix
                                    5 & 4
                                    \ 4 & 13endbmatrix right)=49$$ $|3AA^t|=9×49=441$.
                                    Sorry if i do any mistake.






                                    share|cite|improve this answer














                                    $3$ is a scalar and A is a $2×2$ matrix,then $det(3A)=3^2det(A)$.$$|3AA^t|=3^2×|AA^t|$$
                                    $$|AA^t|=det left( beginbmatrix -1 & 2 \ 2 & 3 endbmatrix × beginbmatrix -1 & 2 \ 2 & 3 endbmatrix right)=detleft(beginbmatrix
                                    5 & 4
                                    \ 4 & 13endbmatrix right)=49$$ $|3AA^t|=9×49=441$.
                                    Sorry if i do any mistake.







                                    share|cite|improve this answer














                                    share|cite|improve this answer



                                    share|cite|improve this answer








                                    edited Aug 31 at 14:17

























                                    answered Aug 31 at 7:25









                                    md emon

                                    878




                                    878



























                                         

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