Combining calc and perpendicular coordinates in tikz

up vote
7
down vote

favorite

As it is described there, the following does not compile:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ( ($ (node1.south) + (1,0) $) |- node2.north);

endtikzpicture
enddocument

Why? How to make it work?

asked Aug 27 at 10:07

iago-lito

610411

add a commentÂ |Â

up vote
7
down vote

favorite

As it is described there, the following does not compile:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ( ($ (node1.south) + (1,0) $) |- node2.north);

endtikzpicture
enddocument

Why? How to make it work?

asked Aug 27 at 10:07

iago-lito

610411

add a commentÂ |Â

up vote
7
down vote

favorite

As it is described there, the following does not compile:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ( ($ (node1.south) + (1,0) $) |- node2.north);

endtikzpicture
enddocument

Why? How to make it work?

asked Aug 27 at 10:07

iago-lito

610411

As it is described there, the following does not compile:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ( ($ (node1.south) + (1,0) $) |- node2.north);

endtikzpicture
enddocument

Why? How to make it work?

asked Aug 27 at 10:07

iago-lito

610411

asked Aug 27 at 10:07

iago-lito

610411

asked Aug 27 at 10:07

iago-lito

610411

asked Aug 27 at 10:07

iago-lito

610411

add a commentÂ |Â

3 Answers
3

active

oldest

votes

up vote
8
down vote

accepted

The syntax of the line to operation given in the manual is to place |- between two coordinates:

Sometimes you want to connect two points via straight lines that are only horizontal and vertical. For this, you can use two path construction operations.

path . . . -|< coordinate or cycle> . . . ;

This operation means
Ã¢Â€Âœfirst horizontal, then vertical.Ã¢Â€Â

Following by these example:

begintikzpicture
draw (0,0) node(a) [draw] A (1,1) node(b) [draw] B;
draw (a.north) |- (b.west);
draw[color=red] (a.east) -| (2,1.5) -| (b.north);
endtikzpicture

and these drawing:
two-path

Thus, this two-path operation is not intended to make a translation from one point to another.
This is a handy shortcut when you need to draw horizontal lines followed by vertical lines or vice versa.

You just have to write (syntactically) in your code:

draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);

instead of

draw ($ (node1.south) + (1,0) $) to ( ( ( $ (node1.south) + (1,0) $) |- node2.north);`

Your code becomes like this:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
%draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% now working too:
draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);
endtikzpicture
enddocument

To have the same path as the one you want, you must build your path as indicated by @marmot or @ignasi.

edited Aug 27 at 14:00

answered Aug 27 at 10:10

AndrÃ©C

2,912728

Not clear what is the use of ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) in the second path.
â€“Â Kpym
Aug 27 at 12:00

@Kpym yes, i edited my answer
â€“Â AndrÃ©C
Aug 27 at 15:18

add a commentÂ |Â

up vote
7
down vote

Just for completeness: a version that is really the equivalent of the first. AndreC's nice answer is correct but I don't see how the second path, which has a corner, is the shifted version of the first one.

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ([xshift=1cm] node1.south |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 11:01

marmot

55.8k461121

1

Interesting, this adds semantics to the syntactic correction, thanks :)
â€“Â iago-lito
Aug 27 at 11:05

add a commentÂ |Â

up vote
4
down vote

You can always declare an auxiliary coordinate and use it. This way you don't need to remember which is the working syntax ;-)

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% working:
draw ($ (node1.south) + (1,0) $) coordinate (aux) to (aux |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 12:10

Ignasi

86.7k4154287

That is true. I was rather willing to avoid this (the lazyness is about 'picking an unused name for the auxiliary coordinate' XD), but it is a useful workaround. Cheers :)
â€“Â iago-lito
Aug 27 at 12:13

1

@iago-lito you just need to declare a non used name if all previously declared are relevant later on, otherwise you can reuse them.
â€“Â Ignasi
Aug 27 at 12:20

Yes, this is how I also do it in the general case.... ;-) +1
â€“Â marmot
Aug 27 at 12:23

Correct. This is an easy choice when working on a neat document. Not when rushing to produce a big dirty one. I hate this but sometimes your environment dictates it's better you don't ponder anything :'( I usually enforce aux, tp, etc. never to be "relevant later on".. until one day I'll wonder "what's happening?!" XD
â€“Â iago-lito
Aug 27 at 12:29

add a commentÂ |Â

Your Answer

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "85"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);

);

draft saved

draft discarded

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f447936%2fcombining-calc-and-perpendicular-coordinates-in-tikz%23new-answer', 'question_page');

);

Post as a guest

Name

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

up vote
8
down vote

accepted

The syntax of the line to operation given in the manual is to place |- between two coordinates:

Sometimes you want to connect two points via straight lines that are only horizontal and vertical. For this, you can use two path construction operations.

path . . . -|< coordinate or cycle> . . . ;

This operation means
Ã¢Â€Âœfirst horizontal, then vertical.Ã¢Â€Â

Following by these example:

begintikzpicture
draw (0,0) node(a) [draw] A (1,1) node(b) [draw] B;
draw (a.north) |- (b.west);
draw[color=red] (a.east) -| (2,1.5) -| (b.north);
endtikzpicture

and these drawing:
two-path

You just have to write (syntactically) in your code:

draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);

instead of

draw ($ (node1.south) + (1,0) $) to ( ( ( $ (node1.south) + (1,0) $) |- node2.north);`

Your code becomes like this:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
%draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% now working too:
draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);
endtikzpicture
enddocument

To have the same path as the one you want, you must build your path as indicated by @marmot or @ignasi.

edited Aug 27 at 14:00

answered Aug 27 at 10:10

AndrÃ©C

2,912728

Not clear what is the use of ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) in the second path.
â€“Â Kpym
Aug 27 at 12:00

@Kpym yes, i edited my answer
â€“Â AndrÃ©C
Aug 27 at 15:18

add a commentÂ |Â

up vote
8
down vote

accepted

The syntax of the line to operation given in the manual is to place |- between two coordinates:

Sometimes you want to connect two points via straight lines that are only horizontal and vertical. For this, you can use two path construction operations.

path . . . -|< coordinate or cycle> . . . ;

This operation means
Ã¢Â€Âœfirst horizontal, then vertical.Ã¢Â€Â

Following by these example:

begintikzpicture
draw (0,0) node(a) [draw] A (1,1) node(b) [draw] B;
draw (a.north) |- (b.west);
draw[color=red] (a.east) -| (2,1.5) -| (b.north);
endtikzpicture

and these drawing:
two-path

You just have to write (syntactically) in your code:

draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);

instead of

draw ($ (node1.south) + (1,0) $) to ( ( ( $ (node1.south) + (1,0) $) |- node2.north);`

Your code becomes like this:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
%draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% now working too:
draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);
endtikzpicture
enddocument

To have the same path as the one you want, you must build your path as indicated by @marmot or @ignasi.

edited Aug 27 at 14:00

answered Aug 27 at 10:10

AndrÃ©C

2,912728

Not clear what is the use of ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) in the second path.
â€“Â Kpym
Aug 27 at 12:00

@Kpym yes, i edited my answer
â€“Â AndrÃ©C
Aug 27 at 15:18

add a commentÂ |Â

up vote
8
down vote

accepted

The syntax of the line to operation given in the manual is to place |- between two coordinates:

Sometimes you want to connect two points via straight lines that are only horizontal and vertical. For this, you can use two path construction operations.

path . . . -|< coordinate or cycle> . . . ;

This operation means
Ã¢Â€Âœfirst horizontal, then vertical.Ã¢Â€Â

Following by these example:

begintikzpicture
draw (0,0) node(a) [draw] A (1,1) node(b) [draw] B;
draw (a.north) |- (b.west);
draw[color=red] (a.east) -| (2,1.5) -| (b.north);
endtikzpicture

and these drawing:
two-path

You just have to write (syntactically) in your code:

draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);

instead of

draw ($ (node1.south) + (1,0) $) to ( ( ( $ (node1.south) + (1,0) $) |- node2.north);`

Your code becomes like this:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
%draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% now working too:
draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);
endtikzpicture
enddocument

To have the same path as the one you want, you must build your path as indicated by @marmot or @ignasi.

edited Aug 27 at 14:00

answered Aug 27 at 10:10

AndrÃ©C

2,912728

The syntax of the line to operation given in the manual is to place |- between two coordinates:

Sometimes you want to connect two points via straight lines that are only horizontal and vertical. For this, you can use two path construction operations.

path . . . -|< coordinate or cycle> . . . ;

This operation means
Ã¢Â€Âœfirst horizontal, then vertical.Ã¢Â€Â

Following by these example:

begintikzpicture
draw (0,0) node(a) [draw] A (1,1) node(b) [draw] B;
draw (a.north) |- (b.west);
draw[color=red] (a.east) -| (2,1.5) -| (b.north);
endtikzpicture

and these drawing:
two-path

You just have to write (syntactically) in your code:

draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);

instead of

draw ($ (node1.south) + (1,0) $) to ( ( ( $ (node1.south) + (1,0) $) |- node2.north);`

Your code becomes like this:

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
%draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% now working too:
draw ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) |- (node2.north);
endtikzpicture
enddocument

To have the same path as the one you want, you must build your path as indicated by @marmot or @ignasi.

edited Aug 27 at 14:00

answered Aug 27 at 10:10

AndrÃ©C

2,912728

edited Aug 27 at 14:00

answered Aug 27 at 10:10

AndrÃ©C

2,912728

answered Aug 27 at 10:10

AndrÃ©C

2,912728

answered Aug 27 at 10:10

AndrÃ©C

2,912728

Not clear what is the use of ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) in the second path.
â€“Â Kpym
Aug 27 at 12:00

@Kpym yes, i edited my answer
â€“Â AndrÃ©C
Aug 27 at 15:18

add a commentÂ |Â

Not clear what is the use of ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) in the second path.
â€“Â Kpym
Aug 27 at 12:00

@Kpym yes, i edited my answer
â€“Â AndrÃ©C
Aug 27 at 15:18

Not clear what is the use of ($ (node1.south) + (1,0) $) to ($ (node1.south) + (1,0) $) in the second path.
â€“Â Kpym
Aug 27 at 12:00

@Kpym yes, i edited my answer
â€“Â AndrÃ©C
Aug 27 at 15:18

add a commentÂ |Â

up vote
7
down vote

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ([xshift=1cm] node1.south |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 11:01

marmot

55.8k461121

1

Interesting, this adds semantics to the syntactic correction, thanks :)
â€“Â iago-lito
Aug 27 at 11:05

add a commentÂ |Â

up vote
7
down vote

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ([xshift=1cm] node1.south |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 11:01

marmot

55.8k461121

1

Interesting, this adds semantics to the syntactic correction, thanks :)
â€“Â iago-lito
Aug 27 at 11:05

add a commentÂ |Â

up vote
7
down vote

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ([xshift=1cm] node1.south |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 11:01

marmot

55.8k461121

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% not working:
draw ($ (node1.south) + (1,0) $) to ([xshift=1cm] node1.south |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 11:01

marmot

55.8k461121

answered Aug 27 at 11:01

marmot

55.8k461121

answered Aug 27 at 11:01

marmot

55.8k461121

answered Aug 27 at 11:01

marmot

55.8k461121

1

Interesting, this adds semantics to the syntactic correction, thanks :)
â€“Â iago-lito
Aug 27 at 11:05

add a commentÂ |Â

1

Interesting, this adds semantics to the syntactic correction, thanks :)
â€“Â iago-lito
Aug 27 at 11:05

Interesting, this adds semantics to the syntactic correction, thanks :)
â€“Â iago-lito
Aug 27 at 11:05

add a commentÂ |Â

up vote
4
down vote

You can always declare an auxiliary coordinate and use it. This way you don't need to remember which is the working syntax ;-)

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% working:
draw ($ (node1.south) + (1,0) $) coordinate (aux) to (aux |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 12:10

Ignasi

86.7k4154287

That is true. I was rather willing to avoid this (the lazyness is about 'picking an unused name for the auxiliary coordinate' XD), but it is a useful workaround. Cheers :)
â€“Â iago-lito
Aug 27 at 12:13

1

@iago-lito you just need to declare a non used name if all previously declared are relevant later on, otherwise you can reuse them.
â€“Â Ignasi
Aug 27 at 12:20

Yes, this is how I also do it in the general case.... ;-) +1
â€“Â marmot
Aug 27 at 12:23

Correct. This is an easy choice when working on a neat document. Not when rushing to produce a big dirty one. I hate this but sometimes your environment dictates it's better you don't ponder anything :'( I usually enforce aux, tp, etc. never to be "relevant later on".. until one day I'll wonder "what's happening?!" XD
â€“Â iago-lito
Aug 27 at 12:29

add a commentÂ |Â

up vote
4
down vote

You can always declare an auxiliary coordinate and use it. This way you don't need to remember which is the working syntax ;-)

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% working:
draw ($ (node1.south) + (1,0) $) coordinate (aux) to (aux |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 12:10

Ignasi

86.7k4154287

That is true. I was rather willing to avoid this (the lazyness is about 'picking an unused name for the auxiliary coordinate' XD), but it is a useful workaround. Cheers :)
â€“Â iago-lito
Aug 27 at 12:13

1

@iago-lito you just need to declare a non used name if all previously declared are relevant later on, otherwise you can reuse them.
â€“Â Ignasi
Aug 27 at 12:20

Yes, this is how I also do it in the general case.... ;-) +1
â€“Â marmot
Aug 27 at 12:23

Correct. This is an easy choice when working on a neat document. Not when rushing to produce a big dirty one. I hate this but sometimes your environment dictates it's better you don't ponder anything :'( I usually enforce aux, tp, etc. never to be "relevant later on".. until one day I'll wonder "what's happening?!" XD
â€“Â iago-lito
Aug 27 at 12:29

add a commentÂ |Â

up vote
4
down vote

You can always declare an auxiliary coordinate and use it. This way you don't need to remember which is the working syntax ;-)

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% working:
draw ($ (node1.south) + (1,0) $) coordinate (aux) to (aux |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 12:10

Ignasi

86.7k4154287

You can always declare an auxiliary coordinate and use it. This way you don't need to remember which is the working syntax ;-)

documentclassreport

usepackagetikz
usetikzlibrarycalc

begindocument
begintikzpicture
node at (0, 0) (node1) Hello;
node at (0, -2) (node2) World;

% working:
draw ($ (node1.south) + (1,0) $) to ( node1.south |- node2.north);

% working:
draw ($ (node1.south) + (1,0) $) coordinate (aux) to (aux |- node2.north);

endtikzpicture
enddocument

answered Aug 27 at 12:10

Ignasi

86.7k4154287

answered Aug 27 at 12:10

Ignasi

86.7k4154287

answered Aug 27 at 12:10

Ignasi

86.7k4154287

answered Aug 27 at 12:10

Ignasi

86.7k4154287

That is true. I was rather willing to avoid this (the lazyness is about 'picking an unused name for the auxiliary coordinate' XD), but it is a useful workaround. Cheers :)
â€“Â iago-lito
Aug 27 at 12:13

1

@iago-lito you just need to declare a non used name if all previously declared are relevant later on, otherwise you can reuse them.
â€“Â Ignasi
Aug 27 at 12:20

Yes, this is how I also do it in the general case.... ;-) +1
â€“Â marmot
Aug 27 at 12:23

Correct. This is an easy choice when working on a neat document. Not when rushing to produce a big dirty one. I hate this but sometimes your environment dictates it's better you don't ponder anything :'( I usually enforce aux, tp, etc. never to be "relevant later on".. until one day I'll wonder "what's happening?!" XD
â€“Â iago-lito
Aug 27 at 12:29

add a commentÂ |Â

That is true. I was rather willing to avoid this (the lazyness is about 'picking an unused name for the auxiliary coordinate' XD), but it is a useful workaround. Cheers :)
â€“Â iago-lito
Aug 27 at 12:13

1

@iago-lito you just need to declare a non used name if all previously declared are relevant later on, otherwise you can reuse them.
â€“Â Ignasi
Aug 27 at 12:20

Yes, this is how I also do it in the general case.... ;-) +1
â€“Â marmot
Aug 27 at 12:23

Correct. This is an easy choice when working on a neat document. Not when rushing to produce a big dirty one. I hate this but sometimes your environment dictates it's better you don't ponder anything :'( I usually enforce aux, tp, etc. never to be "relevant later on".. until one day I'll wonder "what's happening?!" XD
â€“Â iago-lito
Aug 27 at 12:29

That is true. I was rather willing to avoid this (the lazyness is about 'picking an unused name for the auxiliary coordinate' XD), but it is a useful workaround. Cheers :)
â€“Â iago-lito
Aug 27 at 12:13

@iago-lito you just need to declare a non used name if all previously declared are relevant later on, otherwise you can reuse them.
â€“Â Ignasi
Aug 27 at 12:20

Yes, this is how I also do it in the general case.... ;-) +1
â€“Â marmot
Aug 27 at 12:23

Correct. This is an easy choice when working on a neat document. Not when rushing to produce a big dirty one. I hate this but sometimes your environment dictates it's better you don't ponder anything :'( I usually enforce aux, tp, etc. never to be "relevant later on".. until one day I'll wonder "what's happening?!" XD
â€“Â iago-lito
Aug 27 at 12:29

add a commentÂ |Â

draft saved

draft discarded

draft saved

draft discarded

Post as a guest

Name

Search This Blog

Iyfjky