Using bash to swap first and second columns in CSV

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1
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I'm using bash. I have a CSV file with two columns of data that looks roughly like this



 num_logins,day
 253,2016-07-01
 127,2016-07-02


I want to swap the first and second columns (making the date column the first one). So I tried this



awk ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv


However, the results are outputting the same . What am I missing in my awk statement above to get things to switch properly?




shell-script text-processing awk csv




share|improve this question






















  • Bash isn’t a text editor...
    – Jeff Schaller
    Aug 6 at 20:21














up vote
1
down vote

favorite












I'm using bash. I have a CSV file with two columns of data that looks roughly like this



 num_logins,day
 253,2016-07-01
 127,2016-07-02


I want to swap the first and second columns (making the date column the first one). So I tried this



awk ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv


However, the results are outputting the same . What am I missing in my awk statement above to get things to switch properly?




shell-script text-processing awk csv




share|improve this question






















  • Bash isn’t a text editor...
    – Jeff Schaller
    Aug 6 at 20:21












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I'm using bash. I have a CSV file with two columns of data that looks roughly like this



 num_logins,day
 253,2016-07-01
 127,2016-07-02


I want to swap the first and second columns (making the date column the first one). So I tried this



awk ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv


However, the results are outputting the same . What am I missing in my awk statement above to get things to switch properly?




shell-script text-processing awk csv




share|improve this question














I'm using bash. I have a CSV file with two columns of data that looks roughly like this



 num_logins,day
 253,2016-07-01
 127,2016-07-02


I want to swap the first and second columns (making the date column the first one). So I tried this



awk ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv


However, the results are outputting the same . What am I missing in my awk statement above to get things to switch properly?





shell-script text-processing awk csv





share|improve this question













share|improve this question




share|improve this question








edited Aug 6 at 20:22









Jeff Schaller

31.2k846105




31.2k846105










asked Aug 6 at 19:15









Dave

368827




368827











  • Bash isn’t a text editor...
    – Jeff Schaller
    Aug 6 at 20:21
















  • Bash isn’t a text editor...
    – Jeff Schaller
    Aug 6 at 20:21















Bash isn’t a text editor...
– Jeff Schaller
Aug 6 at 20:21




Bash isn’t a text editor...
– Jeff Schaller
Aug 6 at 20:21










2 Answers
2






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up vote
3
down vote



accepted










Here you go :



 awk ' FS="," print $2 "," $1 ' sampleData.csv





share|improve this answer



























    up vote
    5
    down vote













    Because default delimiter is space/tab. Not comma. Taking your original code, and adding a -F, solves it.



    $ awk -F, ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv
    day num_logins
    2016-07-01 253
    2016-07-02 127
    $


    Stripping it down to $0=$2" "$11 gets same result.



    $ awk -F, '$0=$2" "$11' /tmp/2016_logins.csv
    day num_logins
    2016-07-01 253
    2016-07-02 127
    $





    share|improve this answer


















    • 2




      Set OFS to get commas in the output too.
      – Kusalananda
      Aug 6 at 19:30










    • And this one would leave columns 3+ alone, rather than throwing them away.
      – Monty Harder
      Aug 6 at 22:47










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    2 Answers
    2






    active

    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    Here you go :



     awk ' FS="," print $2 "," $1 ' sampleData.csv





    share|improve this answer
























      up vote
      3
      down vote



      accepted










      Here you go :



       awk ' FS="," print $2 "," $1 ' sampleData.csv





      share|improve this answer






















        up vote
        3
        down vote



        accepted







        up vote
        3
        down vote



        accepted






        Here you go :



         awk ' FS="," print $2 "," $1 ' sampleData.csv





        share|improve this answer












        Here you go :



         awk ' FS="," print $2 "," $1 ' sampleData.csv






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Aug 6 at 19:20









        Joe M

        5964




        5964






















            up vote
            5
            down vote













            Because default delimiter is space/tab. Not comma. Taking your original code, and adding a -F, solves it.



            $ awk -F, ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $


            Stripping it down to $0=$2" "$11 gets same result.



            $ awk -F, '$0=$2" "$11' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $





            share|improve this answer


















            • 2




              Set OFS to get commas in the output too.
              – Kusalananda
              Aug 6 at 19:30










            • And this one would leave columns 3+ alone, rather than throwing them away.
              – Monty Harder
              Aug 6 at 22:47














            up vote
            5
            down vote













            Because default delimiter is space/tab. Not comma. Taking your original code, and adding a -F, solves it.



            $ awk -F, ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $


            Stripping it down to $0=$2" "$11 gets same result.



            $ awk -F, '$0=$2" "$11' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $





            share|improve this answer


















            • 2




              Set OFS to get commas in the output too.
              – Kusalananda
              Aug 6 at 19:30










            • And this one would leave columns 3+ alone, rather than throwing them away.
              – Monty Harder
              Aug 6 at 22:47












            up vote
            5
            down vote










            up vote
            5
            down vote









            Because default delimiter is space/tab. Not comma. Taking your original code, and adding a -F, solves it.



            $ awk -F, ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $


            Stripping it down to $0=$2" "$11 gets same result.



            $ awk -F, '$0=$2" "$11' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $





            share|improve this answer














            Because default delimiter is space/tab. Not comma. Taking your original code, and adding a -F, solves it.



            $ awk -F, ' t = $1; $1 = $2; $2 = t; print; ' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $


            Stripping it down to $0=$2" "$11 gets same result.



            $ awk -F, '$0=$2" "$11' /tmp/2016_logins.csv
            day num_logins
            2016-07-01 253
            2016-07-02 127
            $






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Aug 6 at 21:19

























            answered Aug 6 at 19:20









            steve

            12.3k22048




            12.3k22048







            • 2




              Set OFS to get commas in the output too.
              – Kusalananda
              Aug 6 at 19:30










            • And this one would leave columns 3+ alone, rather than throwing them away.
              – Monty Harder
              Aug 6 at 22:47












            • 2




              Set OFS to get commas in the output too.
              – Kusalananda
              Aug 6 at 19:30










            • And this one would leave columns 3+ alone, rather than throwing them away.
              – Monty Harder
              Aug 6 at 22:47







            2




            2




            Set OFS to get commas in the output too.
            – Kusalananda
            Aug 6 at 19:30




            Set OFS to get commas in the output too.
            – Kusalananda
            Aug 6 at 19:30












            And this one would leave columns 3+ alone, rather than throwing them away.
            – Monty Harder
            Aug 6 at 22:47




            And this one would leave columns 3+ alone, rather than throwing them away.
            – Monty Harder
            Aug 6 at 22:47












             

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